Problem Running my servlet

Question

Hi,
I use Tomcat 5.5.17 to run servlets. I can run the example servlets that come with Tomcat successfully. I have configured the java_home and class path variables. When I create a new servlet in the webapps/servlets-examples folder, I can run it.
However, when I try creating a new folder under webapps (named trial) and when I try to run my servlet from there I get the 404 Servlet not found error.
The steps I followed are:
1.Created a new folder trial under C:\apache-tomcat 5.5.17\webapps
2.Created the WEB_INF folder under trial and then the classes folder under it.
3. Put my servlet HelloServlet.class under the classes folder.
4.Put WEB.XML under the C:\apache-tomcat 5.5.17\webapps\trial\WEB_INF folder and made the following entry
<servlet>
<servlet-name>HelloServlet</servlet-name>
<servlet-class>HelloServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>HelloServlet</servlet-name>
<url-pattern>/HelloServlet</url-pattern>
</servlet-mapping>
5. I tried to access my servlet using the following URL:
http://localhost:8080/trial/HelloServlet
and that gives the 404 error.
Are there any additional steps when we are running a servlet a folder we create?
I searched the internet and found something about setting the context path but I could not understand how to do it for Tomcat 5.5.17 as the documents I found on the net were for older versions.
I would be grateful if someone could help me out. Thanks in advance!
Aniticipating your help!
Thanks and Regards,
Asana

Answer 1

Hi.. You can check your application context path through Tomcat Manager application.
URL is :
http://localhost:8080/manager/list
or
http://localhost:8080/manager/html/list