Problem searching array
I have an array in a column that I extracted from a data file. I want
to search the array for particular values and return the index which
is easily implemented by the search 1d array subvi. However, when I
input the values to search, it returns a -1 for some values and others
it finds fine where I know all the values exist. To be more precise,
my array is about 80 values between -2 and 2 in steps of 0.05. When I
search for -2, -1.5, -1, etc., I get the correct index. When I search
for other numbers like -1.8, -1.7, -1.85, etc., I get a return value
of -1. It is really strange and I am not sure of the problem. Anyone
have any ideas? Does it have anything to do with the precision or how
I read the spreadsheet file to extract the column?
T
hanks
Heather
Thanks for all your help. I ended up converting both the search array
and the search element to strings with 2 decimal point precision and
it works fine.
You guys are the best.
Heather
[email protected] (H) wrote in message news:<[email protected]>...
> I have an array in a column that I extracted from a data file. I want
> to search the array for particular values and return the index which
> is easily implemented by the search 1d array subvi. However, when I
> input the values to search, it returns a -1 for some values and others
> it finds fine where I know all the values exist. To be more precise,
> my array is about 80 values between -2 and 2 in steps of 0.05. When I
> search for -2, -1.5, -1, etc., I get the correct index. When I
search
> for other numbers like -1.8, -1.7, -1.85, etc., I get a return value
> of -1. It is really strange and I am not sure of the problem. Anyone
> have any ideas? Does it have anything to do with the precision or how
> I read the spreadsheet file to extract the column?
>
> Thanks
> Heather
Similar Messages
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Hello all,
I have a problem regarding to search array.
It seems like he is unable to find certain elements in the 1D array I deliver.
Because it outputs -1.
I attached my vi + the file
Koen
UnCertified LabVIEW Student
Mistakes are for learning, that's why suggestions are always welcome!
Solved!
Go to Solution.
Attachments:
Problem.vi 17 KB
test2.txt 135 KBYou can't accurately do an equals comparison with floating point numbers. It is just a limitation of floating points in gereral (all computer languages have this issue). What you should do instead is check to see if a value is in a certain range to account for this limitation.
There are only two ways to tell somebody thanks: Kudos and Marked Solutions
Unofficial Forum Rules and Guidelines -
I'm having problem searching data from a table.
I'm able to search every single row but when it gets to the last one, it keeps going to the last result.
I want it to search everytime I press the button and once it gets to the last result I want a message to popup saying that there is no more results. I also want to add the ScrollPane to change along with the search.
here is the code.
searchText = new String(search.getText());
int rows = mainTable.getRowCount();
int columns = mainTable.getColumnCount();
Object value = null;
lastindex= -1;
for(int i=0; i<rows; i++)
for(int j=0; j<columns; j++)
value = mainTable.getValueAt(i,j);
//System.out.println(i + " " + value);
if (value == null ? searchText == null :
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mainTable.setRowSelectionInterval(i, i);
mainTable.setColumnSelectionInterval(j, j);
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return;
}//if()
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}//for
JOptionPane.showMessageDialog(null, "No More Players ",
"Search",
JOptionPane.INFORMATION_MESSAGE);Sure,
Can u send a test mail to this user id
[email protected]...will look into ur issue.
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Search Array with multiple values
Hello,
I've been helped with the prototype below by blemmo (thanks).
It allows me to search my array using one property == a
value.
Now, I'd like to use it to:
if ((prop1 == val1) &&(prop2 == val2) &&
(prop3 == val3) {
// search array for all values in array with the values of
val1, val2 and val3
Also, a way to search if one of the prop and val's are blank,
ie...
((prop1 == val1) &&(prop2 == val2) && (prop3
== val3)
where prop2 and val2 are "undefined"
so the search will only search for the prop and val that are
not "undefined"
make since? Don't know where to start.
help and thanks in advance.it is an array like this.. but with more properties... also,
is it better to use XML to load large arrays or is it ok to use
actionscript in the file.
which is faster to load? say if I had an array of 150
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pic:"1.jpg",pic1:"2.jpg",pic2:"3.jpg",pic3:"4.jpg"},
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Having problems searching for music
I just recently encountered a problem searching for music on the Itunes store. I searched under song title, and it didn't bring up any results. Then I searched for the same music under artist, and the music came up. What's weird here is that the music was always there, but it's not showing up when I try to search under song title. Can someone tell me what's going on here?
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I am trying to solve a book problem. I created an array with letters and numbers and I'm supposed to figure out how to count the number of letters in the array. I tried the following code:
public class ArrayBasics1
public static void main(String[] args)
char[] myChar = {'1','2','3','a','b','c','d','e','f'};
int count = 0, uncount = 0, x = 0;
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if(myChar[x] > 96 && myChar[x] < 123)
count += 1;
else
uncount += 1;
System.out.println("The number of letters in myChar is " + count);
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} I think I'm searching the subscripts rather than the content of the array. Any help would be appreciated.I just ran your code and it gave the output:
The number of letters in myChar is 6
The number of characters in myChar which are not letters is 3
This looks good to me - what were you expecting? I'm not sure what you were trying to do with "//myChar[x] = (char)x; Doesn't work", but you don't need that line.
One improvement you might want to make is to use the Character.isLetter() method which also includes upper case letters. e.g. replace
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Search Array of String for exact match words
I need to create a search feature.
There will be a textfield where the user will input a word or words.
Then I need to check if the are any reference in the array of names.
namesArray ["ocean in the sky", "cean on sky", "cean is white"];
keywordsArray ["cean", "sky"];
matchCounter = 0;
If I input the word "cean" I dont want in my results "ocean in the sky", only "cean is sky".
I have the following code:
for (var j:int = 0; j < namesArray.length; ++j)
var tempStr:String = namesArray[j];
for (var k:int = 0; k < keywordsArray.length; ++k)
if (tempStr.indexOf(arrayKeywords[k]) != -1)
matchCounter++;
if(lengthKeywords == matchCounter)
trace("yeahhh... there's a match!!");
matchCounter = 0;
Is there a better way? How can I do this?There are few things but the main problem is that "new RegExp()" needs double escapes ("\\")
var namesArray:Array = ["ocean in the sky", "cean on sky", "cean is white"];
var keywordsArray:Array = ["cean", "sky"];
for (var j:int = 0; j < namesArray.length; j++){
var matchCounter:uint = 0;
var tempStr:String = namesArray[j];
for (var k:int = 0; k < keywordsArray.length; k++){
var regExp:RegExp = new RegExp("(\\s+|^)" + keywordsArray[k] + "(\\s+|$)");
if (tempStr.search(regExp) > -1){
matchCounter++;
if(keywordsArray.length == matchCounter){
trace("\"" + namesArray[j] + "\" matched all the keywords");
Traces:
"cean on sky" matched all the keywords -
Hallo
I have to compare a input data and the ideal data. so far i have understood how to do comparision but the problem create when ideal array have same element with different respective value , similarly input dat are appears to be also same but while doing search in final output array in 3 column looks different than as it should be.
hope you understand my problem
thanking you
BR
kalu
Solved!
Go to Solution.
Attachments:
array%20(modified)[1].vi 17 KBHi Kalu,
Check the attached VI. Let me know if it helps.
Regards,
Nitz
(Give Kudos to Good Answers, Mark it as a Solution if your Problem is Solved)
Attachments:
array (modified)[1].vi 17 KB -
If allowed you could write several Compartors and use Collections.sort()
If not then you will have to write several of your own sort methods. Whatever logic you would have placed in the Comparators you would place in your sort methods. If it is the logic you are having problems with:
Sort by X
If 1.X and 2.X are the same then sort by Y
If 1.Y and 2.Y are the same then sort by Z
etc.Hello,
Thanks for helping! I'm getting the logic you wrote. But when I sort by arrays, then I will need to run a for loop in order to shift the elements right? I'm not understanding how to set the condition for the 'for' loop. For example, if I have a total of 5 records in the inventory and only 3 of them satisfy the search..then I can run a loop as follows:
public void SortProduct()
for(int i=0;i<3;i++)
if(inventory.getProductName==inventory[i+1].getProductName)
sortModel();
But the number of searched elements may differ from time to time, right? Like when user enters another product, and only two records satisfy the criteria, then the loop condition should become for(int i=0;i<2;i++). I'm not getting how to dynamically change the value so the loop runs for any number of elements depending on the search results at that time.
Also, is my sort method right? I'm not too good at it.
Edited by: Beginner_Troubles on Apr 17, 2008 7:59 AM -
CRM IC Webclient - Massive Performance Problems Searching in Agent Inbox
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can somebody help me. We have massive Search Performance problems in Interaction Center Webclient in Agent Inbox. When agents searching, for example for open emails, the time to get a result takes approx. 2-3 minutes.
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Could somebody help me with ideas to solve this big performance problem. Have somebody the same problems?
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We use Interaction Center Webclient on CRM Release 5.0
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Problem in array output, pls help!
i made an array:
public class Estudyante
String studentNo;
String studentName;
String address;
String phone;
String email;
public void displayDetails()
System.out.println(studentNo);
System.out.println(studentName);
System.out.println(address);
System.out.println(phone);
System.out.println(email);
public class StudentFinder
//define the variables of the class
Estudyante estObjects[];
//initialize the variables
public StudentFinder()
//creating an array of 3 estudyantes
estObjects = new Estudyante[3];
//creating objects of all the three elements in an array
for(int ctr = 0; ctr !=estObjects.length;ctr++)
estObjects[ctr] = new Estudyante();
//assigning test values
//estudyante 1 details
estObjects[0].studentNo = "0001";
estObjects[0].studentName = "Rez";
estObjects[0].address = "Pasig";
estObjects[0].phone = "111-1111";
estObjects[0].email = "[email protected]";
//estudyante 2 details
estObjects[1].studentNo = "0002";
estObjects[1].studentName = "Reza";
estObjects[1].address = "Manila";
estObjects[1].phone = "222-2222";
estObjects[1].email = "[email protected]";
//estudyante 3 details
estObjects[2].studentNo = "0003";
estObjects[2].studentName = "Reza Ric";
estObjects[2].address = "Malate";
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public void displayFinder()
//add the code for displaying estudyante details
for (int ctr = 0;ctr != estObjects.length;ctr++)
estObjects[ctr].displayDetails();
//the displayDetails() method is present in the Estudyante class
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public static void main(String args[])
StudentFinder finderObject;
finderObject = new StudentFinder();
finderObject.displayFinder();
problem:
when i run this in command prompt, it displays all the 3 sets of details
question:
how will i display the set of details i want and not all of them?
eg: i only want the details of studentNo = "0001"
so in command prompt i execute
java StudentFinder 0001
how will i be able to get the details for studentNo = "0001" only and how will i display "No such student" if the studentNo asked for is not in any of the details.Hi KikiMon,
In your displayFinder() method you'll have to take an argument, specifying which Student to display. Like this:
public void displayFinder(String target)
for (int ctr = 0;ctr != estObjects.length;ctr++)
if(estObjects[ctr].studentNo.equals(target)) {
estObjects[ctr].displayDetails();
An in your main you'll have to forward a commandline argument like this:
public static void main(String args[])
StudentFinder finderObject;
finderObject = new StudentFinder();
finderObject.displayFinder(args[0]);
Later,
Klaus -
I am facing a problem with the array of JCheckBox. Without array it works but when I use array it gives NullPointerException. No compile time error. I am using Null Layout. But I need to use the array. How can I solve this?
Here is the code.
JCheckBox jCheckBox_Questions[] = new JCheckBox[3];
JCheckBox box = new JCheckBox();
Dimension d[] = new Dimension[3] ;
String strQuestions[] = {"No Child ?","Jaundice ?","Migraine ?"};
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// This works
box.setText(strQuestions[0]);
add(box);
d[1]= box.getPreferredSize();
box.setBounds(j,k,d[1].width,d[1].height);
k=k+20;
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jCheckBox_Questions[0]. setText(strQuestions[1]);// in this line
add(jCheckBox_Questions[0]);
d[2]= jCheckBox_Questions[0].getPreferredSize();
jCheckBox_Questions[0].setBounds(j,k,d[2].width,d[2].height);Hi,
classic error: in fact the code
JCheckBox jCheckBox_Questions[] = new JCheckBox[3]; doesn't instantiate the checkboxes, it's only allocating 3 memory pointers (inited to null), ready to receive the futures instances of checkboxes. So you should have typed:
JCheckBox jCheckBox_Questions[] = new JCheckBox[3];
// Here we create the 3 objects
for (int i=0;i<3;i++) jCheckBox_Questions[ i ] = new JCheckBox();
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A basic question/problem with array element as undefined
Hello everybody,
thank you for looking at my problem. I'm very new to scripting and javaScript and I've encountered a strange problem. I'm always trying to solve all my problem myself, with documentation (it help to learn) or in the last instance with help of google. But in this case I am stuck. I'm sure its something very simple and elementary.
Here I have a code which simply loads a text file (txt), loads the content of the file in to a "var content". This text file contents a font family name, each name on a separate line, like:
Albertus
Antenna
Antique
Arial
Arimo
Avant
Barber1
Barber2
Barber3
Barber4
Birch
Blackoak ...etc
Now, I loop trough the content variable, extract each letter and add it to the "fontList[i]" array. If the character is a line break the fontList[i] array adds another element (i = i + 1); That's how I separate every single name into its own array element;
The problem which I am having is, when I loop trough the fontList array and $.writeln(fontList[i]) the result in the console is:
undefinedAlbertus
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undefinedAntique
undefinedArial ...etc.
I seriously don't get it, where the undefined is coming from? As far as I have tested each digit being added into the array element, I can't see anything out of ordinary.
Here is my code:
#target illustrator
var doc = app.documents.add();
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var openFile = myFile.open("r");
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if(openFile == true){
$.writeln("The file has loaded")}
else {$.writeln("The file did not load, check the name or the path");}
//load the file content into a variable
var content = myFile.read();
myFile.close();
var ch;
var x = 0;
var fontList = [];
for (var i = 0; i < content.length; i++) {
ch = content.charAt (i);
if((ch) !== (String.fromCharCode(10))) {
fontList[x] += ch;
else {
x ++;
for ( i = 0; i < fontList.length; i++) {
$.writeln(fontList[i]);
doc.close (SaveOptions.DONOTSAVECHANGES);
Thank you for any help or explanation. If you have any advice on how to improve my practices or any hint, please feel free to say. Thank youCarlosCantos wrote an amazing script a while back (2013) that may help you in your endeavor. Below is his code, I had nothing to do with this other then give him praise and I hope it doesn't offend him since it was pasted on the forums here.
This has helped me do something similar to what your doing.
Thanks again CarlosCanto
// script.name = fontList.jsx;
// script.description = creates a document and makes a list of all fonts seen by Illustrator;
// script.requirements = none; // runs on CS4 and newer;
// script.parent = CarlosCanto // 02/17/2013;
// script.elegant = false;
#target illustrator
var edgeSpacing = 10;
var columnSpacing = 195;
var docPreset = new DocumentPreset;
docPreset.width = 800;
docPreset.height = 600;
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var yyy = (idoc.height - edgeSpacing);
var fontCount = textFonts.length;
var col = 1;
var ABcount = 1;
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var itext = idoc.textFrames.add();
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itext.contents = sFontName;
//$.writeln(yyy);
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itext.left = x;
itext.textRange.characterAttributes.textFont = textFonts.getByName(textFonts[i].name);
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col++;
if (col>4) {
var ab = idoc.artboards[ABcount-1].artboardRect;
var abtop = ab[1];
var ableft = ab[0];
var abright = ab[2];
var abbottom = ab[3];
var ntop = abtop;
var nleft = abright+edgeSpacing;
var nbottom = abbottom;
var nright = abright-ableft+nleft;
var abRect = [nleft, ntop, nright, nbottom];
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//else yyy-=(itext.height); -
HP Proliant ML350G4 server - problem with array
Hi, I have HP Proliant ML350 G4 server. The problem is that I can not configure the array for SCSI hard drives. When I run the Array Configuration Utility from the SmartStart CD, I get the message: "ACU did not detect any supported controllers in your system." How do I solve this problem?
Hi:
You may also want to post your question on the HP Business Support Forum -- ML Servers section.
http://h30499.www3.hp.com/t5/ProLiant-Servers-ML-DL-SL/bd-p/itrc-264#.U48mculOW9I -
I have lots of tabs of eBay search pages which I update every day and from last night (26th Sep) and even now 27th they still have the same problem that the search does not continue but goes to a eBay home page !
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(1) Bypass Firefox's Cache
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Alternately, you also can clear Firefox's cache completely using:
orange Firefox button (or Tools menu) > Options > Advanced
On the Network mini-tab > Cached Web Content : "Clear Now"
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