Problem selecting DataProvider.

I encountered a problem adding a DataProvider which already exists. This is what happened.
I wanted bind a table component to data; in the Add Data Provider dialog box, I selected Data Sources > fitwise > Tables > company and clicked Add; In the Add New Data Provider with RowSet for Table company dialog box, I had to select a DataProvider because I had already added the company table to other tables twice. I selected the second radio button and clicked OK. The IDE added the first DataProvider to my table. I tried to add the second DataProvider again and again, but the IDE kept adding the first DataProvider in the list, the one not bound to the selected radio button, but to the not selected radio button. Has anyone encountered the same problem? Is there a solution? For instance is there another way to bind a table to an existing DataProvider.
Kind regards,
Annet.

I think you may have to try what I'm about to try - resetting the Prefs - delete the Preferences folder and let Illustrator rebuild it when you restart it.
I can't get the Arrange commands to run - only thing I can think to try is resetting the Preferences...it usually clears up strange glitches like yours and mine.
[edit: Well resetting the Preferences did nothing for me. Hope you found a solution to your problem]

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    Hoiw can I achive that the internal table holds the three highest DELTAVERS for each LOCNR (Store).
    Or what would be the best solution here !? Remember we talking here about 1000+ Stores.
    Please help !!
    Thanks in advance,
    Chris

    Hi Forum
    me again, I believe that I somewhat missunderstood the concept of GROUP BY and HAVING clause.
    Both might prove completely useless in this case.
    Would actually aa simple UP TO N ROWS do the tricking providing that the Select is done per store !?
    How can I ensure that it gets always the TOP N entries!??
    Thanks,
    Chris
    > Hi Forum,
    >
    > I have a problem regarding a complicated (at least
    > for me) Select statement. It uses a customer Z-table
    > to read certain data.
    >
    > But my goal is to read only a certain number of top
    > entries per store.
    > The number can change from one run to the other.
    >
    > To make it clearer here is the simplified defintion
    > of the database table

    > MANDT
    > LOCNR
    > DELTAVERS

    >
    >
    > LOCNR is a store and DELTAVERS is a version (simple
    > counter 001,002,..)of that entry. Both fields are key
    > fields.
    > Of course there additional fields with values that I
    > interested in. But they are left out here to let
    > focus on the problem.
    >
    > My goal is to read a certain #number of top DELTAVERS
    > (versions) for each LOCNR(Store). I do not know the
    > stores or the # of DELTAVERS.
    >
    > The select should provide a internal table showing
    > the X highest DELTAVERS with the related store
    >
    > e.g. A Select that should show the 3 highest
    > DELTAVERS per Store LOCNR, if available
    >
    >
    > LOCNR: DELTAVERS:
    > N001 0013
    > N001 0023
    > N001 0024
    > B235 0021
    > B235 0056
    > ....
    >
    >
    >
    > Note: In this example B235 has only two entries
    >
    >
    >
    > Code:
    >
    >            
    >      l_having_by_cond = "count( DELTAVERS ) le  3".
    >
    >        SELECT
    >                   locnr
    >                   deltavers
    >
    >                   FROM z_locnr_version
    >                  
    > APPENDING CORRESPONDING FIELDS OF
    > SPONDING FIELDS OF TABLE
    >                   lt_locnr_version                 
    >                
    >                   GROUP BY locnr deltavers
    >                   HAVING (l_having_by_cond).
    > ORDER BY locnr deltavers
    > BY locnr deltavers DESCENDING.

    >
    >
    > lt_locnr_version should hold the desired result.
    >
    > It seems to use the count for all entries and not
    > just for each LOCNR.
    > Hoiw can I achive that the internal table holds the
    > three highest DELTAVERS for each LOCNR (Store).
    >
    > Or what would be the best solution here !? Remember
    > we talking here about 1000+ Stores.
    >
    > Please help !!
    >
    > Thanks in advance,
    >
    > Chris

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