Problem with socket connections through a proxy server.

People,
I set the system properties to use a proxy server so my application can fetch data from servers located outside my local network:
System.setProperty("socksProxyPort", port);
System.setProperty("socksProxyHost", proxy_addy);Then, when I attempt to stabilish a connection:
s = new Socket(this.getHost(), port);It hangs.
I appreciate any help since my available Java documentation is quite obscure regarding proxy servers.

Is the proxy on another machine? Try it's IP. If
not, replace 'proxy' with 'localhost'.
- SaishYes, it is another machine.
            byte x[] = {(byte)aaa,(byte)bbb,(byte)ccc,(byte)ddd};
            s = new Socket(new Proxy(Proxy.Type.SOCKS, new InetSocketAddress(InetAddress.getByAddress(x), 8080)));
            s.connect(new InetSocketAddress(this.getHost(), port));Again, it hung.

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Server: We are running a simple Socket Server program from command prompt.
The code below works fine as long as we do not try to receive a response from the server (Commented Code).
If we uncomment the code and try to receive a response, it refuses to create an instance for the BPEL Process. And sometimes restarts the BPEL Server.
Client Code:
String msg="NONE";
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org.w3c.dom.Element input = (org.w3c.dom.Element) getVariableData("inputVariable","payload","/client:clientProcessRequest/client:input");
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msg=cin1.readLine();
setVariableData("outputVariable","payload","/client:result",new String(msg));
clientsoc.close();
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System.err.println("Don't know about host: dev.");
System.exit(1);
catch (IOException e)
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Repost

I suppose it is the problem with socket connection,Please help

Hi,
I'm trying to build a chat server in Java on Linux OS.I've created basically 2 classes in the client program.The first one shows the login window.When we enter the Login ID & password & click on the ok button,the data is sent to the server for verification.If the login is true,the second class is invoked,which displays the messenger window.This class again access the server
for collecting the IDs of the online persons.But this statement which reads from the server causes an exception in the program.If we invoke the second class independently(ie not from 1st class) then there is no problem & the required data is read from the server.Can anyone please help me in getting this program right.I'm working on a p4 machine with JDK1.4.
The Exceptions caused are given below
java.net.SocketException: Connection reset by peer: Connection reset by peer
at java.net.SocketInputStream.SocketRead0(Native Method)
at java.net.SocketInputStream.read(SocketInputStream.java:119)
     at java.io.InputStreamReader$CharsetFiller.readBytes(InputStreanReader.java :339)
     at java.io.InputStreamReader$CharsetFiller.fill(InputStreamReader.java:374)
     at java.io.InputStreamReader.read(InputStreamReader.java:511)
     at java.io.BufferedReader.fill(BufferedReader.java:139)
     at java.io.BufferedReader.readLine(BufferedReader.java:299)
     at java.io.BufferedReader.readLine(BufferedReader.java:362)
     at Login.LoginData(Login.java:330)
     at Login.test(Login.java:155)
     at Login$Buttonhandler.actionPerformed(Login.java:138)
     at javax.swing.AbstractButton.fireActionPerformed(AbstractButton.java:1722)
     at javax.swing.AbstractButton$ForwardActionEvents.actionPerformed(AbstractButton.java:17775)
     at javax.swing.DefaultButtonModel.fireActionPerformed(DefaultButtonModel.java:4141)
     at javax.swing.DefaultButtonModel.setPressed(DefaultButtonModel.java:253)
     at javax.swing.plaf.basic.BasicButtonListener.mouseReleased(BasicButtonListener.java:261)
     at java.awt.Component.processMouseEvent(Component.java:4906)
     at java.awt.Component.processEvent(component.java:4732)
     at java.awt.Container.processEvent(Container.java:1337)
     at java.awt.component.dispatchEventImpl(Component.java:3476)
     at java.awt.Container.dispatchEventImpl(Container.java:1399)
     at java.awt.Component.dispatchEvent(Component.java:3343)
     at java.awt.LightweightDispatcher.retargetMouseEvent(Container.java:3302)
     at java.awt.LightweightDispatcher.processMouseEvent(Container.java:3014)
     at java.awt.LightweightDispatcher.dispatchEvent(Container.java:2967)
     at java.awt.Container.dispatchEventImpl(Container.java:1373)
     at java.awt.window.dispatchEventImpl(Window.java:1459)
     at java.awt.Component.dispatchEvent(Component.java:3343)
     at java.awt.EventQueue.dispatchEvent(EventQueue.java:439)
     at java.awt.EventDispatchThread.pumpOneEvent(EventDispatchThread.java:150)
     at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:136)
     at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:131)
     at java.awt.EventDispatchThread.run(EventDispatchThread.java:99)
     My program looks somewhat like this :
1st class definition:
public class Login extends Jframe// Login is the name of the first class;
Socket connection;
DataOutputStream outStream;
BufferedReader inStream;
Frame is set up here
public class Buttonhandler implements ActionListener
public void actionPerformed(ActionEvent e) {
String comm = e.getActionCommand();
if(comm.equals("ok")) {
check=LoginCheck(ID,paswd);
test();
public void test() //checks whether the login is true
if(check)
new Messenger(ID);// the second class is invoked
public boolean LoginCheck(String user,String passwd)
//Enter the Server's IP & port below
String destination="localhost";
int port=1234;
try
connection=new Socket(destination,port);
}catch (UnknownHostException ex){
error("Unknown host");
catch (IOException ex){
ex.printStackTrace ();
error("IO error creating socket ");
try{
inStream = new BufferedReader(new InputStreamReader(connection.getInputStream()));
outStream=new DataOutputStream(connection.getOutputStream());
}catch (IOException ex){
error("IO error getting streams");
ex.printStackTrace();
System.out.println("connected to "+destination+" at port "+port+".");
BufferedReader keyboardInput=new BufferedReader(new InputStreamReader(System.in));
String receive=new String();
try{
receive=inStream.readLine();
}catch(IOException ex){ error("Error reading from server");}
if(receive.equals("Logintrue"))
check=true;
else
check=false;
try{
inStream.close();
outStream.close();
connection.close();
}catch (IOException ex){
error("IO error closing socket");
return(check);
// second class is defined below
public class Messenger
Socket connect;
DataOutputStream outStr;
BufferedReader inStr;
public static void main(String args[])
{ Messenger mes = new Messenger(args[0]);}
Messenger(String strg)
CreateWindow();
setupEvents();
LoginData(strg);
fram.show();
void setupEvents()
fram.addWindowListener(new WindowHandler());
login.addActionListener(new MenuItemHandler());
quit.addActionListener(new MenuItemHandler());
button.addActionListener(new Buttonhandle());
public void LoginData(String name)
//Enter the Server's IP & port below
String dest="localhost";
int port=1234;
int r=0;
String str[]=new String[40];
try
connect=new Socket(dest,port);
}catch (UnknownHostException ex){
error("Unknown host");
catch (IOException ex){
ex.printStackTrace ();
error("IO error creating socket ");
try{
inStr = new BufferedReader(new InputStreamReader(connect.getInputStream()));
outStr=new DataOutputStream(connect.getOutputStream());
}catch (IOException ex){
error("IO error getting streams");
ex.printStackTrace();
String codeln=new String("\n");
try{
outStr.flush();
outStr.writeBytes("!@*&!@#$%^");//code for sending logged in users
outStr.writeBytes(codeln);
outStr.write(13);
outStr.flush();
String check="qkpltx";
String receive=new String();
try{
while((receive=inStr.readLine())!=null) //the statement that causes the exception
if(receive.equals(check))
break;
else
     str[r]=receive;
     r++;
}catch(IOException ex){ex.printStackTrace();error("Error reading from socket");}
catch(NullPointerException ex){ex.printStackTrace();}
} catch (IOException ex){ex.printStackTrace();
error("Error reading from keyboard or socket ");
try{
inStr.close();
outStr.close();
connect.close();
}catch (IOException ex){
error("IO error closing socket");
for(int l=0,k=1;l<r;l=l+2,k++)
if(!(str[l].equals(name)))
stud[k]=" "+str[l];
else
k--;
public class Buttonhandle implements ActionListener
public void actionPerformed(ActionEvent e) {
//chat with the selected user;
public class MenuItemHandler implements ActionListener
public void actionPerformed(ActionEvent e)
String cmd=e.getActionCommand();
if(cmd.equals("Disconnect"))
//Disconnect from the server
else if(cmd.equals("Change User"))
     //Disconnect from the server & call the login window
else if(cmd.equals("View Connection Details"))
//show connection details;
public class WindowHandler extends WindowAdapter
public void windowClosing(WindowEvent e){
//Disconnect from server & then exit;
System.exit(0);}
I�ll be very thankful if anyone corrects the mistake for me.Please help.

You're connecting to the server twice. After you've successfully logged in, pass the Socket to the Messenger class.
public class Messenger {
    Socket connect;
    public static void main(String args[]) {
        Messenger mes = new Messenger(args[0]);
    Messenger(Socket s, String strg) {
        this.connect = s;
        CreateWindow();
        setupEvents();
        LoginData(strg);
        fram.show();
}

Problem with socket connection in midp 2.0

hello everyone.
I'm new one in j2me and I am learning socket connection in j2me. I'm using basic socket,datagram example wich is come with sun java wireless toolkit 2.5. for it i wrote small socket server program on c# and tested it example on my pc and its working fine. also socket server from another computer via internet working fine. But when i instal this socket example into my phone on nokia n78 (Also on nokia 5800) it's not working didn't connect to socket server.. On phone I'm using wi-fi internet. Can anybody help me with this problem? I hear it's need to modify manifest file and set appreciate pressions like this
MIDlet-Permissions: javax.microedition.io.Connector.socket,javax.microedition.io.Connector.file.write,javax.microedition.io.Connector.ssl,javax.microedition.io.Connector.file.read,javax.microedition.io.Connector.http,javax.microedition.io.Connector.https
is it true?
can anybody suggest me how can i solve this problem?
where can I read full information about socket connection specifiecs in j2me?
Thanks.

Maybe this can be helpful:
[http://download-llnw.oracle.com/javame/config/cldc/ref-impl/midp2.0/jsr118/index.html]
you can check there the Datagram interface anda DatagramConnection interface and learn a little about that.
If the client example runs fine in the wireless toolkit emulator, it should run the same way in your phone; i suggest to try to catch some exception that maybe is hapenning and display it on a Alert screen, this in the phone.

Problem with socket connection

have my gps reciver connected to the usb port - i have a daemon gpsd running which makes data available on tcp port 2947 for querying. when i do telnet, it gives proper data.
but when i open a socket connection using java, it does not print anything as output. actually telnet asks for an escape charatcer so i am sending "r" initially to the server but still the program does not print anything as output.
here is my java code -
import java.io.*;
import java.net.Socket;
public class test2
public static void main(String[] args)
try
Socket s = new Socket("localhost",2947);
PrintWriter out = new PrintWriter(new BufferedWriter(new OutputStreamWriter(
s.getOutputStream())),true);
out.println("r");
BufferedReader in = new BufferedReader(new InputStreamReader(s.getInputStream()));
String line;
while(true)
line = in.readLine();
System.out.println(line);
catch (Exception e)
or sometimes it even shows error as
Exception in thread "main" java.net.SocketException: Invalid argument or cannot assign requested address
at java.net.PlainSocketImpl.socketConnect(Native Method)
and this is the output which i get on telnet -
ot@localhost ~]# telnet localhost 2947
Trying 127.0.0.1...
Connected to localhost.
Escape character is '^]'.
r
GPSD,R=1
$GPRMC,000212,V,18000.0000,N,00000.0000,W,0.0000,180.000,101102,,*1A
$GPGSA,A,1,,,,,,,,,,,,,,,,*32
$PGRME,400.00,0.00,0.00*7B
$GPRMC,000213,V,18000.0000,N,00000.0000,W,0.0000,180.000,101102,,*1B
$GPGSA,A,1,,,,,,,,,,,,,,,,*32
$PGRME,400.00,0.00,0.00*7B
$GPRMC,000214,V,18000.0000,N,00000.0000,W,0.0000,180.000,101102,,*1C
$GPGSA,A,1,,,,,,,,,,,,,,,,*32

Actually the problem does not seem to be in the code because i tried some basic client server programs (without any gpsd etc in picture) and even they are not working in linux though they work perfectly in windows (on the same machine). In linux it shows exception
My socket programs dont work in linux it shows error -
ot@localhost winc]# java parser
Exception in thread "main" java.net.SocketException: Invalid argument or cannot assign requested address
at java.net.PlainSocketImpl.socketConnect(Native Method)
at java.net.PlainSocketImpl.doConnect(PlainSocketImpl.java:305)
at java.net.PlainSocketImpl.connectToAddress(PlainSocketImpl.java:171)
at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:158)
at java.net.Socket.connect(Socket.java:452)
at java.net.Socket.connect(Socket.java:402)
at java.net.Socket.<init>(Socket.java:309)
at java.net.Socket.<init>(Socket.java:124)
at parser.main(parser.java:10)
i have removed the firewall settings etc and it still doesnot work in linux
what could be the cause for this?
Sowmya

Problem with Socket Connection and Out of Memory Exception in JavaME

Hi,
I am working on creating an application to check pop3 emails and send emails using smtp. I have implemented almost everything. It works fine if I run it with debugger [Step by step] but it fails when I run the application on emulator. It never connects to the pop3 server and runs out of memeory.
Help me on this issue.
Tarpinder

HI,
THanks for the reply..AM using workshop IDE and have tried the "clean" option also but of no use..Is there any other alternative to get rid of this exception ???
Regards

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Hi,
I am building a Java based TCP server socket class in Windows machine. The client is written in C running in Linux.
The client sends data in specified C struct: Eg.
{noformat}struct person {
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    int height;
} I am having problem reading it in Java Server. I am using DataInputStream to read byte and trying to decode it in age, float etc. the problem is I can read first two but I cannot properly decode the 'height'.
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regards,
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You are perpetrating mistake #1 here. Don't try to send C structs over the wire. The format is dependent on the hardware, the operating system, the compiler, the compiler version, compiler bugs, the #pragmas, and the compiler options in effect. Too many variables. What you should be doing is writing the primitive types to the network, in network byte order, and reading them inJava with the appropriate methods of DataInputStream.

Intermittent proxy error "There is a problem with the proxy server's security certificate. Outlook is unable to connect to the proxy server "

Hi all,
From time to time (at least once a day), the following message pops up on the user's screen:
"There is a problem with the proxy server's security certificate. Outlook is unable to connect to the proxy server . Error Code 80000000)."
If we click "OK" it goes away and everything continues to work although sometimes Outlook disconnects. It is quite annoying...
Any ideas?
Thank you in advance

Hi,
For the security alert issue, I'd like to recommend you check the name in the alert windows, and confirm if the name is in your certificate.
Additionally, to narrow down the cause, when the Outlook client cannot connect again, I recommand you firstly check the connectivity by using Test E-mail AutoConfiguration. For more information, you can refe to the following article:
http://social.technet.microsoft.com/Forums/en-US/54bc6b17-9b60-46a4-9dad-584836d15a02/troubleshooting-and-introduction-for-exchange-20072010-autodiscover-details-about-test-email?forum=exchangesvrgeneral
Thanks,
Angela Shi
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How can i create a socket connection through an http proxy

i'm trying to make a socket connection send an email - i have code that works when you don't have to go through a proxy server but i can't make it pass the proxy server.
import java.net.*;
import java.io.*;
import java.util.*;
public class Mail
public String to_address = "[email protected]";
public String from_address = "[email protected]";
public String sendSub = "HeHeHe";
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BufferedReader in = new BufferedReader(
new InputStreamReader(System.in));
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String from_address, // sender's address
String sendSub, // subject
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Mail themail = new Mail();
}

i've tried that but it doesn't seem to do nething - this is how i implemented it...
import java.net.*;
import java.io.*;
import java.util.*;
public class Mail
public String to_address = "[email protected]";
public String from_address = "[email protected]";
public String sendSub = "HeHeHe";
public String sendBody = "hehehe - it worked";
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BufferedReader in = new BufferedReader(
new InputStreamReader(System.in));
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String from_address, // sender's address
String sendSub, // subject
String sendBody) // Message
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System.getProperties().put( "proxySet", "true" );
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     return ;
public static void main (String [] args) throws IOException
Mail themail = new Mail();
}

Exchange Server 2010 SP3 - Rollup 8 - Issue - Problems with client connections - MS Outlook 2013

Exchange Server 2010 SP3 - Rollup 8 - Issue - Problems with client connections - MS Outlook 2013
Detected Problems:
- Access denied for attached mailbox (department mailbox)
- Access denied for delete or move messages on own mailbox
- Can't send new messages with error (Error: [0x80004005-00000000-00000000])
Solution:
- Rollback to Exchange 2010 SP3 - Rollup 7
- You can rollback to Exchange 2010 SP3 - RollUp 7 in 30 min
Algunos de los destinatarios no recibieron su mensaje.
Asunto: Hola
Enviado el: 11/12/2014 8:35
No se puede localizar a los destinatarios siguientes:
'[email protected]' en 11/12/2014 8:35
Este mensaje no se pudo enviar. Inténtelo de nuevo más tarde, o póngase en contacto con el administrador de red.
Error: [0x80004005-00000000-00000000].

See the following forum thread:
https://social.technet.microsoft.com/Forums/en-US/1be9b816-b0ab-40ea-a43a-446239f8eae3/outlook-client-issues-following-exchange-2010-rollup-8

Mobile me/icloud find my iphone through a proxy server?

Hi All,
I'm not sure if this is the right place to post this so if it's not please let me know where is best.
I have a fleet of 600 ipads who are forced to run through a proxy server via a 3g connection. Up untill last week I could trace all these iPads via mobile me or icloud and use the find my iPhone feature. In this last week I seem to have lost this ability. All iPads are coming up with "no location". Mixture of iOS5 and variations of iOS4
If I turn off the proxy on the iPad I can trace the iPad.
me.com, apple.com amd icloud.com are all allowed through the proxy.
I cannot see anoy other banned traffic with a web address I can unblock.
I really just need to know what else I need to allow out via the proxy to get this working again? I'm guessing something has changed in Apple world as the proxy hasn't changed.
Thanks

Hi - did you have any luck with this? I have a similar problem, but only on a private APN through our proxy. I've managed to allow all the URLs to get the iCloud account registered for each device via the APN/proxy, but they do not appear on my icloud.com device view. If I remove the APN, therefore our network proxy is not used, it works fine.
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Outlook is unable to connect to the proxy server.(Error Code 10)

Hi,
I had problems with RPC proxy, I was trying to setup cutover migration.
So I read somewhere that i need to change the certprincipalname with Set-Outlookprovider.
But after this change my outlook was not working anymore
The settings before the change were:
Name Server CertPrincipalName TTL
EXCH
1
EXPR
1
WEB
1
So I set this back to the original (above) but this didn't helped...
Outlook 2013 and Exchange 2013
There is a problem with the proxy server's security certificate. The name on the security certificate is invalid or does not match the name of the target site mail.abc-company.com.
Outlook is unable to connect to the proxy server.(Error Code 10)

Hi,
Please make sure the mail.abc-company.com is included in your Exchange certificate which has been assigned with IIS service.
If possible, please run the following command for double check:
Get-ExchangeCertificate | FL
For Autodiscover service, please run
Test E-mail AutoConfiguration to check if the connection is successful in Log tab and confirm the other services URL can use proper namespace in Results tab for request access.
If the Autodiscover service fails, please create a SRV record with mail.abc-company.com for Autodiscover service to have a try:
http://support2.microsoft.com/kb/940881/en-us
Regards,
Winnie Liang
TechNet Community Support

Outlook is unable to connect to the proxy server. (Error code 0)

Hello,
I have just commenced a Exchange 2007 SP3 to Exchange 2013 SP1 migration following the following guide: http://blogs.technet.com/b/meamcs/archive/2013/07/25/part-1-step-by-step-exchange-2007-to-2013-migration.aspx
As per the above guide, my 2007 environment is now known as legacy.company.com and my 2013, webmail.company.com.
I'm using the same certificate on both boxes and it has the names autodiscover.company.com, webmail.company.com and legacy.company.com. All that seems to be working fine.
OWA is functioning perfectly, hitting https://webmail.company.com will pass the user off to https://legacy.company.com if the mailbox is on 2007. Alongside this, Outlook also has no issues connecting to 2007 mailboxes with the client proxy settings
being reconfigured to https://legacy.company.com automatically.
My problem comes when a mailbox is migrated to 2013. OWA functions fine and presents the mailbox but Outlook is unable to connect, presenting the error:
There is a problem with the proxy server's security certificate.
The name on the security certificate is invalid or does not match the name of the target site webmail.company.com.
Outlook is unable to connect to the proxy server. (Error Code 0)
If I modify the Outlook client's settings and disable "Only connect to proxy servers that have this principal name in their certificate: msstd:webmail.company.com", Outlook connects and functions fine.
I'm at a loss and have tried everything I can think and find on google. Any suggestions would be greatly appreciated.

Hi,
Please refer to the following article :
http://support.microsoft.com/kb/923575
Cause:
This issue may occur if one or more of the following conditions are true:
The connection to the server requires a certification authority (CA).
You have not trusted the certification authority at the root.
The certificate may be invalid or revoked.
The certificate does not match the name of the site.
A third-party add-in is preventing access.
Solution:
To examine the certificate, follow these steps:
In Microsoft Internet Explorer, connect to the RPC server or to the secure server. For example, type
https://www.<var>server_name</var>.com/rpc in the Address bar of the Web browser, and then press ENTER.
Note The <var>server_name</var> placeholder references the RPC server name or the secure server name.
Double-click the padlock icon that is located in the lower-right corner of the Web browser.
Click the Details tab.
Note the information in the following fields:
Valid to
The Valid to field indicates the date until which the certificate is valid.
Subject
The data in the Subject field should match the site name.
Hope this helps!
Thanks.
Niko Cheng
TechNet Community Support

Outlook is unable to connect to the proxy server.(Error Code 10) when users opened Outlook 2010

Hi All
Exchange Server - 2013 CU2 (Windows 2012 Standard)
AD Server - 2003 R2 SP2
exchange-svr01.domain.com - internal name
mail.company.net - external name
When users opened Outlook 2010, they will encountered
"There is a problem with the proxy server's security certificate. The name on the security certificate is invalid or does not match the name of the target site exchange-svr01.domain.com.
Outlook is unable to connect to the proxy server.(Error Code 10)"
I also used the Microsoft Remote Connectivity Analyzer to test RPC/HTTP connectivity.
The RPC/HTTP test completed successfully.
    Validating the certificate name.
    Certificate name validation failed.
     Host name company.net doesn't match any name found on the server certificate CN=AMAZONA-U59HG9G.
Testing SSL mutual authentication with the RPC proxy server.
    The test passed with some warnings encountered.
The certificate common name company.net doesn't match the mutual authentication string provided mail.company.net; however, a match was found in the subject alternative name extension.
please help.

Hi PS CL
[PS] C:\Windows\system32>Get-OutlookAnywhere
RunspaceId                         : c457e8aa-a0f3-4a0f-aa02-9eff24d02821
ServerName                         : exchange-svr01
SSLOffloading                      : True
ExternalHostname                   : mail.company.net
InternalHostname                   : exchange-svr01.domain.com
ExternalClientAuthenticationMethod : Negotiate
InternalClientAuthenticationMethod : Ntlm
IISAuthenticationMethods           : {Basic, Ntlm, Negotiate}
XropUrl                            :
ExternalClientsRequireSsl          : True
InternalClientsRequireSsl          : True
MetabasePath                       : IIS://exchange-svr01.domain.COM/W3SVC/1/ROOT/Rpc
Path                               : C:\Program Files\Microsoft\Exchange Server\V15\FrontEnd\HttpProxy\rpc
ExtendedProtectionTokenChecking    : None
ExtendedProtectionFlags            : {}
ExtendedProtectionSPNList          : {}
AdminDisplayVersion                : Version 15.0 (Build 712.22)
Server                             : exchange-svr01
AdminDisplayName                   :
ExchangeVersion                    : 0.20 (15.0.0.0)
Name                               : Rpc (Default Web Site)
DistinguishedName                  : CN=Rpc (Default Web
                                     Site),CN=HTTP,CN=Protocols,CN=exchange-svr01,CN=Servers,CN=Exchange
Administrative
                                     Group (FYDIBOHF23SPDLT),CN=Administrative
Groups,CN=domain,CN=Microsoft
                                     Exchange,CN=Services,CN=Configuration,DC=domain,DC=COM
Identity                           : exchange-svr01\Rpc (Default Web Site)
Guid                               : 33c3cb74-e490-487d-844c-4072334089a1
ObjectCategory                     : domain.COM/Configuration/Schema/ms-Exch-Rpc-Http-Virtual-Directory
ObjectClass                        : {top, msExchVirtualDirectory, msExchRpcHttpVirtualDirectory}
WhenChanged                        : 8/17/2013 10:14:55 AM
WhenCreated                        : 6/25/2013 1:47:50 PM
WhenChangedUTC                     : 8/17/2013 2:14:55 AM
WhenCreatedUTC                     : 6/25/2013 5:47:50 AM
OrganizationId                     :
OriginatingServer                  : ADserver.domain.COM
IsValid                            : True
ObjectState                        : Changed

Client connecting through a proxy

hi
i'm new to RMI programming, i need to clear some things up
. is RMI a standalone protocol like http or does it require another protocol so
it can run over it ?
. how does an RMI connection get through a proxy server, ie. if the client is behind a proxy server and the server is a known public host, can the client still get to the server, or does this have to be done in the proxy configuration?
Is there certain types of proxy servers RMI can't go through or ( they won't let it pass through ) .
i need those infos because i've been stuck with an RMI server deployed on the net and a client behind a web proxy, the same box ( IP ) hosting the RMI server also hosts a WEB server from which javaWS starts the application but this application exits at a certain point sayin it cannot find the RMI server.
i didn't have the chance to test through a direct connection, but have tested
in an intranet environment and it was workin great,
thanks for any help

. is RMI a standalone protocol like http or does it
require another protocol so
it can run over it ?The question doesn't make much sense. HTTP runs over TCP, and so does RMI. RMI also uses the Serialization protocol.
how does an RMI connection get through a proxy
server, ie. if the client is behind a proxy server
and the server is a known public host, can the
client still get to the server, or does this have to
be done in the proxy configuration?http://java.sun.com/j2se/1.5.0/docs/guide/rmi/faq.html#firewallOut
s there certain types of proxy servers RMI can't go
through or ( they won't let it pass through ) .Java supports SOCKS and HTTP proxies.

Problem with socket connections through a proxy server.

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