Program execution time

Hi all,
i have created a report which inlclude posting dates. if i enter the period of 1 year it takes abt 3 mins. to execute it, as i tried the same in table from where the data comes , the table is aslo taking almost same time but it will not do, so just plzz tel me that is there any tips or trick so that i can reduce this execution time..??
thanx..

>
Vinod Reddy Vemuru wrote:
> Hi Nilesh,
> First send us your select query with out seeing which its very dificult to draw the solution. There might be many reasons for performance issues. Suppose a select in CDHDR/CDPOS table u can't improve much by what ever care u take.
>
> A select on BSEG can be improved by getting data from index tables BSAD/BSID/BSAK/BSIK table.
> So first post ur query.
>
> Thanks,
> Vinod.
thanx..
this is query..
select budat belnr into (itab-budat,itab-belnr) from bkpf
where budat between budat-low and budat-high and bukrs in bukrs

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Anybody experience difference in Labview program execution time on Asian Windows O/S?

I have written a Labview Program that uses GPIB to control an Agilent Spectrum Analyzer and Power Meter. It communicates with and controls the D.U.T. via Telnet. It was debugged here in Massachusetts under Windows 2000. Here the test takes ~ 43 seconds. In Thailand on an equivalent computer running Windows 2000 (Thai) the same test takes ~ 66 seconds. Time is measured by capturing start time and stop time from the O/S. Any clues to account for the difference? The time differential is the same in the development environment and the distribution environment.

"RMK at Netopia" wrote in message
news:[email protected]..
> I have written a Labview Program that uses GPIB to control an Agilent
> Spectrum Analyzer and Power Meter. It communicates with and controls
> the D.U.T. via Telnet. It was debugged here in Massachusetts under
> Windows 2000. Here the test takes ~ 43 seconds. In Thailand on an
> equivalent computer running Windows 2000 (Thai) the same test takes ~
> 66 seconds. Time is measured by capturing start time and stop time
> from the O/S. Any clues to account for the difference? The time
> differential is the same in the development environment and the
> distribution environment.
Suggest you break the test down to its individual steps to see which part o
f
the test is changed. You may even find that it is the test equipment that
is taking longer.

Execution time increase

hai guys,
Im currently developing a code that run 24 hours 7 days a week. My problem is the execution time increases as days pass by. As im tracing down the execution time ,the 1st day i start the to run the program execution time is 0.04 second but after 3 day it increases to 4.5 seconds .
then i indually tracked down the subvi that causing problem and find out that the problem is on writing to ini file.
The subvi function is to REPLACE the data (20 data )in a file every 10 second*not accumulating data just replace the old data . I open file replace data and close file every itteration and as day pass the execution time for this subvi increases.
Can any one help me to get a solution for the problem as time is a very important factor in my programming. the execution time is limited for less that 10 second.
thanks
regards
kokula

As David said, post the code.
Is there any reason why your are loggin to an .ini file? Does that mean you are using the LabVIEW config file functions?
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I bet if you let your program run long enough, it would eventually crash due to running out of memory.
By the way 47MB to 350 MB of memory consumption means the same thing as RAM usage increasing.

How to extend the execution time of an ABAP Program using the Process chain

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And we can achieve this by using the process chains.
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Hi,,,,,,,,,,
Besides Process Chain There is another way out for this........
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"CALL FUNCTION 'TH_REDISPATCH'."
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Execution time of same program makes big difference

Hello all,
The execution time of same program in PRD system and QAS system makes big difference.
The difference of data is not much(as system copy was run on a regular time schedule. And the system enviroments are exactly the same. However, while the program only cost 2-3 seconds in QAS, it cost 7-8 minutes in PRD.
It only happens when trying to join some tables together.
I've checked the execution plans of same search, they are different:
QAS:
SQL Statement
SELECT
T_00.RANL , T_00.XALLB , T_00.REPKE , T_00.REWHR , T_00.HKONT ,   T_00.ZTMNAIBRX , T_00.GSART ,
T_00.ZTMHOYMNX , T_00.ZTMSBKBNX ,   T_00.ZTMSHDAYZ , T_00.ZTMMBHZKP , T_01.BAL_SH_CUR ,
T_01.ZTMSIHONP ,   T_02.SECURITY_ID , T_02.SECURITY_ACCOUNT
FROM
ZTM0108 T_00, ZTM0135 T_01, TRACV_POSCONTEXT T_02
WHERE
T_00.MANDT = '350' AND   T_00.BUKRS = 'MC51' AND   T_00.ZTMMCSNGX = '200806' AND
T_02.SECURITY_ACCOUNT = '0001' AND   T_01.MANDT = '350' AND   T_01.BUKRS = T_00.BUKRS AND
T_01.ZTMMCSNGX = T_00.ZTMMCSNGX AND   T_01.PARTNER = T_00.REPKE AND   T_02.MANDT = '350' AND
T_02.SECURITY_ID = T_00.RANL
Execution Plan
SELECT STATEMENT ( Estimated Costs = 666 , Estimated #Rows = 72 )
---   12 HASH JOIN
( Estim. Costs = 666 , Estim. #Rows = 72 )
Estim. CPU-Costs = 37,505,220 Estim. IO-Costs = 663
Access Predicates
--   9 HASH JOIN
( Estim. Costs = 268 , Estim. #Rows = 51 )
Estim. CPU-Costs = 18,679,663 Estim. IO-Costs = 267
Access Predicates
--   6 NESTED LOOPS
( Estim. Costs = 25 , Estim. #Rows = 38 )
Estim. CPU-Costs = 264,164 Estim. IO-Costs = 25
--   4 NESTED LOOPS
( Estim. Costs = 25 , Estim. #Rows = 27 )
Estim. CPU-Costs = 258,494 Estim. IO-Costs = 25
--   2 TABLE ACCESS BY INDEX ROWID DIFT_POS_IDENT
( Estim. Costs = 25 , Estim. #Rows = 24 )
Estim. CPU-Costs = 253,454 Estim. IO-Costs = 25
Filter Predicates
1 INDEX RANGE SCAN DIFT_POS_IDENT~SA
( Estim. Costs = 1 , Estim. #Rows = 554 )
Search Columns: 1
Estim. CPU-Costs = 29,801 Estim. IO-Costs = 1
Access Predicates
3 INDEX RANGE SCAN TRACT_POSCONTEXTID
Search Columns: 2
Estim. CPU-Costs = 210 Estim. IO-Costs = 0
Access Predicates
5 INDEX UNIQUE SCAN TZPA~0
Search Columns: 2
Estim. CPU-Costs = 210 Estim. IO-Costs = 0
Access Predicates
---   8 TABLE ACCESS BY INDEX ROWID ZTM0108
( Estim. Costs = 242 , Estim. #Rows = 2,540 )
Estim. CPU-Costs = 10,811,361 Estim. IO-Costs = 241
7 INDEX RANGE SCAN ZTM0108~0
( Estim. Costs = 207 , Estim. #Rows = 2,540 )
Search Columns: 3
Estim. CPU-Costs = 9,790,330 Estim. IO-Costs = 207
Access Predicates Filter Predicates
      ---   11 TABLE ACCESS BY INDEX ROWID ZTM0135
( Estim. Costs = 397 , Estim. #Rows = 2,380 )
Estim. CPU-Costs = 11,235,469 Estim. IO-Costs = 396
10 INDEX RANGE SCAN ZTM0135~0
                   ( Estim. Costs = 323 , Estim. #Rows = 2,380 )
                   Search Columns: 3
                   Estim. CPU-Costs = 10,288,477 Estim. IO-Costs = 323
                   Access Predicates Filter Predicates
PRD:
Execution Plan
SELECT STATEMENT ( Estimated Costs = 209 , Estimated #Rows = 1 )
---   12 NESTED LOOPS
( Estim. Costs = 208 , Estim. #Rows = 1 )
Estim. CPU-Costs = 18.996.864 Estim. IO-Costs = 207
--   9 NESTED LOOPS
( Estim. Costs = 120 , Estim. #Rows = 1 )
Estim. CPU-Costs = 10.171.528 Estim. IO-Costs = 119
--   6 NESTED LOOPS
Estim. CPU-Costs = 27.634 Estim. IO-Costs = 0
--   4 NESTED LOOPS
Estim. CPU-Costs = 27.424 Estim. IO-Costs = 0
1 INDEX RANGE SCAN TZPA~0
Search Columns: 1
Estim. CPU-Costs = 5.584 Estim. IO-Costs = 0
Access Predicates
---   3 TABLE ACCESS BY INDEX ROWID DIFT_POS_IDENT
Estim. CPU-Costs = 210 Estim. IO-Costs = 0
Filter Predicates
2 INDEX RANGE SCAN DIFT_POS_IDENT~PT
Search Columns: 1
Estim. CPU-Costs = 210 Estim. IO-Costs = 0
Access Predicates
5 INDEX RANGE SCAN TRACT_POSCONTEXTID
Search Columns: 2
Estim. CPU-Costs = 210 Estim. IO-Costs = 0
Access Predicates
---   8 TABLE ACCESS BY INDEX ROWID ZTM0108
( Estim. Costs = 120 , Estim. #Rows = 1 )
Estim. CPU-Costs = 10.143.893 Estim. IO-Costs = 119
7 INDEX RANGE SCAN ZTM0108~0
( Estim. Costs = 119 , Estim. #Rows = 1 )
Search Columns: 4
Estim. CPU-Costs = 10.142.167 Estim. IO-Costs = 119
Access Predicates Filter Predicates
      ---   11 TABLE ACCESS BY INDEX ROWID ZTM0135
( Estim. Costs = 89 , Estim. #Rows = 1 )
Estim. CPU-Costs = 8.825.337 Estim. IO-Costs = 88
10 INDEX RANGE SCAN ZTM0135~0
                   ( Estim. Costs = 88 , Estim. #Rows = 1 )
                   Search Columns: 4
                   Estim. CPU-Costs = 8.823.742 Estim. IO-Costs = 88
                   Access Predicates Filter Predicates
Could anyone tell me the reason? I've found note 724545 but not sure.
And, how to read the execution plan?(1 first or 12 first?)
Best Regards,
Robin

Hello Michael.
Thank you.
However, the sql statement is same:
QAS:
SQL Statement
SELECT
T_00.RANL , T_00.XALLB , T_00.REPKE , T_00.REWHR , T_00.HKONT ,   T_00.ZTMNAIBRX , T_00.GSART ,
T_00.ZTMHOYMNX , T_00.ZTMSBKBNX ,   T_00.ZTMSHDAYZ , T_00.ZTMMBHZKP , T_01.BAL_SH_CUR ,
T_01.ZTMSIHONP ,   T_02.SECURITY_ID , T_02.SECURITY_ACCOUNT
FROM
ZTM0108 T_00, ZTM0135 T_01, TRACV_POSCONTEXT T_02
WHERE
T_00.MANDT = '350' AND   T_00.BUKRS = 'MC51' AND   T_00.ZTMMCSNGX = '200806' AND
T_02.SECURITY_ACCOUNT = '0001' AND   T_01.MANDT = '350' AND   T_01.BUKRS = T_00.BUKRS AND
T_01.ZTMMCSNGX = T_00.ZTMMCSNGX AND   T_01.PARTNER = T_00.REPKE AND   T_02.MANDT = '350' AND
T_02.SECURITY_ID = T_00.RANL
Execution Plan
SELECT STATEMENT ( Estimated Costs = 666 , Estimated #Rows = 72 )
---   12 HASH JOIN
( Estim. Costs = 666 , Estim. #Rows = 72 )
Estim. CPU-Costs = 37,505,220 Estim. IO-Costs = 663
Access Predicates
--   9 HASH JOIN
( Estim. Costs = 268 , Estim. #Rows = 51 )
Estim. CPU-Costs = 18,679,663 Estim. IO-Costs = 267
Access Predicates
--   6 NESTED LOOPS
( Estim. Costs = 25 , Estim. #Rows = 38 )
Estim. CPU-Costs = 264,164 Estim. IO-Costs = 25
--   4 NESTED LOOPS
( Estim. Costs = 25 , Estim. #Rows = 27 )
Estim. CPU-Costs = 258,494 Estim. IO-Costs = 25
--   2 TABLE ACCESS BY INDEX ROWID DIFT_POS_IDENT
( Estim. Costs = 25 , Estim. #Rows = 24 )
Estim. CPU-Costs = 253,454 Estim. IO-Costs = 25
Filter Predicates
1 INDEX RANGE SCAN DIFT_POS_IDENT~SA
( Estim. Costs = 1 , Estim. #Rows = 554 )
Search Columns: 1
Estim. CPU-Costs = 29,801 Estim. IO-Costs = 1
Access Predicates
3 INDEX RANGE SCAN TRACT_POSCONTEXTID
Search Columns: 2
Estim. CPU-Costs = 210 Estim. IO-Costs = 0
Access Predicates
5 INDEX UNIQUE SCAN TZPA~0
Search Columns: 2
Estim. CPU-Costs = 210 Estim. IO-Costs = 0
Access Predicates
---   8 TABLE ACCESS BY INDEX ROWID ZTM0108
( Estim. Costs = 242 , Estim. #Rows = 2,540 )
Estim. CPU-Costs = 10,811,361 Estim. IO-Costs = 241
7 INDEX RANGE SCAN ZTM0108~0
( Estim. Costs = 207 , Estim. #Rows = 2,540 )
Search Columns: 3
Estim. CPU-Costs = 9,790,330 Estim. IO-Costs = 207
Access Predicates Filter Predicates
      ---   11 TABLE ACCESS BY INDEX ROWID ZTM0135
( Estim. Costs = 397 , Estim. #Rows = 2,380 )
Estim. CPU-Costs = 11,235,469 Estim. IO-Costs = 396
10 INDEX RANGE SCAN ZTM0135~0
                   ( Estim. Costs = 323 , Estim. #Rows = 2,380 )
                   Search Columns: 3
                   Estim. CPU-Costs = 10,288,477 Estim. IO-Costs = 323
                   Access Predicates Filter Predicates
PRD:
SQL Statement
SELECT
T_00.RANL , T_00.XALLB , T_00.REPKE , T_00.REWHR , T_00.HKONT ,   T_00.ZTMNAIBRX , T_00.GSART ,
T_00.ZTMHOYMNX , T_00.ZTMSBKBNX ,   T_00.ZTMSHDAYZ , T_00.ZTMMBHZKP , T_01.BAL_SH_CUR ,
T_01.ZTMSIHONP ,   T_02.SECURITY_ID , T_02.SECURITY_ACCOUNT
FROM
ZTM0108 T_00, ZTM0135 T_01, TRACV_POSCONTEXT T_02
WHERE
T_00.MANDT = '500' AND   T_00.BUKRS = 'MC51' AND   T_00.ZTMMCSNGX = '200806' AND
T_02.SECURITY_ACCOUNT = '0001' AND   T_01.MANDT = '500' AND   T_01.BUKRS = T_00.BUKRS AND
T_01.ZTMMCSNGX = T_00.ZTMMCSNGX AND   T_01.PARTNER = T_00.REPKE AND   T_02.MANDT = '500' AND
T_02.SECURITY_ID = T_00.RANL
Execution Plan
SELECT STATEMENT ( Estimated Costs = 209 , Estimated #Rows = 1 )
---   12 NESTED LOOPS
      |    ( Estim. Costs = 208 , Estim. #Rows = 1 )
      |    Estim. CPU-Costs = 18.996.864 Estim. IO-Costs = 207
      |--   9 NESTED LOOPS
      |   |   ( Estim. Costs = 120 , Estim. #Rows = 1 )
      |   |   Estim. CPU-Costs = 10.171.528 Estim. IO-Costs = 119
      |   |--   6 NESTED LOOPS
      |   |   |   Estim. CPU-Costs = 27.634 Estim. IO-Costs = 0
      |   |   |--   4 NESTED LOOPS
      |   |   |   |   Estim. CPU-Costs = 27.424 Estim. IO-Costs = 0
      |   |   |   |-----1 INDEX RANGE SCAN TZPA~0
      |   |   |   |       Search Columns: 1
      |   |   |   |       Estim. CPU-Costs = 5.584 Estim. IO-Costs = 0
      |   |   |   |       Access Predicates
      |   |   |   ---   3 TABLE ACCESS BY INDEX ROWID DIFT_POS_IDENT
      |   |   |       |   Estim. CPU-Costs = 210 Estim. IO-Costs = 0
      |   |   |       |   Filter Predicates
      |   |   |       -
2 INDEX RANGE SCAN DIFT_POS_IDENT~PT
      |   |   |               Search Columns: 1
      |   |   |               Estim. CPU-Costs = 210 Estim. IO-Costs = 0
      |   |   |               Access Predicates
      |   |   -
5 INDEX RANGE SCAN TRACT_POSCONTEXTID
      |   |           Search Columns: 2
      |   |           Estim. CPU-Costs = 210 Estim. IO-Costs = 0
      |   |           Access Predicates
      |   ---   8 TABLE ACCESS BY INDEX ROWID ZTM0108
      |       |   ( Estim. Costs = 120 , Estim. #Rows = 1 )
      |       |   Estim. CPU-Costs = 10.143.893 Estim. IO-Costs = 119
      |       -
7 INDEX RANGE SCAN ZTM0108~0
      |               ( Estim. Costs = 119 , Estim. #Rows = 1 )
      |               Search Columns: 4
      |               Estim. CPU-Costs = 10.142.167 Estim. IO-Costs = 119
      |               Access Predicates Filter Predicates
      ---   11 TABLE ACCESS BY INDEX ROWID ZTM0135
          |    ( Estim. Costs = 89 , Estim. #Rows = 1 )
          |    Estim. CPU-Costs = 8.825.337 Estim. IO-Costs = 88
10 INDEX RANGE SCAN ZTM0135~0
                   ( Estim. Costs = 88 , Estim. #Rows = 1 )
                   Search Columns: 4
                   Estim. CPU-Costs = 8.823.742 Estim. IO-Costs = 88
                   Access Predicates Filter Predicates
Only difference is the client.
I see that QAS use index SA on table DIFT_POS_IDENT first, while PRD deal with table TZPA first...Is it the reason?
Best Regards,
Robin

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Long execution times for TestStand conditional statements

I have two test stations – one here, one at the factory in China that has been operating for about a year. The test program uses TestStand 3.1 and calls primarily dll's developed using CVI. Up until a couple months ago, both test stations performed in a similar manner, then the computer at the factory died and was replaced with a new, faster computer. Now the same test sequence at the factory take three times as long to execute (30 min at the facotry, 10min here).
I have recoded the execution time at various point during the execution, and have found that the extra times seems to be occurring during the evaluation of conditional statements in TestStand (i.e. for loops, if statements, case statements). For example, one particular ‘for’ evaluation takes 30 ms on the test station here, but takes 400 ms at the test station at the factory (note: this is just the evaluation of the for condition, not the execution of the steps contained within the for loop).
The actual dll calls seem to be slightly faster with the new computer.
Also the ‘Module Times’ reported don’t seem to match the actual time for the module for the computer at the factory. For example, for the following piece of TestStand code:
Label1
Subsequence Call
Label2
I record the execution time to the report text in both Label1 and Label2. Subtracting one from the other gives me about 18 seconds. However the ‘Module Time’ recorded for ‘Subsequence Call’ is only 3.43 seconds.
Any body have any ideas why the long execution time with the new computer? I always setup the computers in exactly the same way, but maybe there is a TestStand setting somewhere that I have missed? Keep in mind, both test stations are running exactly the same revision of code.

Got some more results from the factory this morning:
1) Task Manager shows that the TestExec.exe is the only thing using CPU to any significant degree. Also CPU Usage History show that the CPU Usage never reaches 100%.
2) I sent a new test program that will log test execution time in more places. Longer execution times are seen in nearly every area of the program, but one area where this is very dramatic is the time taken to return from one particular subsequence call. In this subsequence I log the time just before the <End Group> at then end of Main. There is nothing in Cleanup. I then log the time immediately after returning from this sequence. On the test system I have here this takes approximately 160 ms. On the test system at the factory this takes approximately 14.5 seconds! The program seems to be hanging here for some reason. Every time this function is called the same thing happens and for the same amount of time (and this function is called about 40 times in the test program, so this is kill me).

Program execution time

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