Query regarding future developement tool used to customize siebel apps

Hi,
i am girish.
i am a siebel developer, working in areas of siebel configuration,Siebel EAI,WORKFLOW,Scripting.
i want to know how would future oracle applications will affect my future.
currently i am working in siebel tools which is specific to customizing siebel application only.
in oracle applications which will be rolled out in 2008, i would like to know that the developement environment for customizing siebel applications would be siebel tools or JDeveloper?
or siebel tools will be the environment for cusomizing siebel and fusion mw will come into picture only for SOA, Integration only?
should i start learning java even if i am not working in fusion middleware?
is JDeveloper going to be the tool for future developement of Oracle CRM Applications.
please explain ?
it would help me in getting ready for the future?
Regards,
Girish

Girish,
The Applicataion strategy for Fusion Applications is being planned.
As of now, you will need to use Siebel tools for Siebel integration work, and Oracle JDeveloper will be the unified design-time environment for all development related to Oracle SOA Suite and Fusion Middleware.
Regards,
Hari

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Ok, I will clear myself with the following example :
class First
int a;
static int b;
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b) Whether the object on which synchronization is based is a static, or a non-static member of the class.
Now, first my-thoughts; kindly correct me if I am wrong :
a) In case 1, we have a non-static function, synchronized on a non-static object. Thus, effectively, there is no-synchronisation, since in case obj1 and obj2 happen to call the func_one at the same time, obj1 will obtain lock for obj1.a; and obj2 will obtain lock to obj2.a; and both can go inside the supposed-to-be-synchronized-function-but-actually-is-not merrily.
Kindly correct me I am wrong anywhere in the above.
b) In case 2, we have a non-static function, synchronized on a static object. Here, again if obj1, and obj2 happen to call the function at the same time, obj1 will try to obtain lock for obj1.a; while obj2 will try to obtain lock for obj2.a. However, since obj1.a and obj2.a are the same, thus we will indeed obtain sychronisation.
Kindly correct me I am wrong anywhere in the above.
c) In case 3, we have a static function , synchronized on a non-static object. However, Java does not allow functions of this type, so we may safely move forward.
d) In case 4, we have a static function, synchronized on a static object.
Here, again if obj1, and obj2 happen to call the function at the same time, obj1 will try to obtain lock for obj1.a; while obj2 will try to obtain lock for obj2.a. However, since obj1.a and obj2.a are the same, thus we will indeed obtain sychronisation. But we are only partly done for this case.
First, Kindly correct me I am wrong anywhere in the above.
Now, I have a query : what happens if the call is made in a classically static manner, i.e. using the statement "First.func_four;".
Another query : so far we have been assuming that the only objects contending for the synchronized function are obj1, and obj2, in a single thread. Now, consider this, suppose we have the same reference obj1, in two threads, and the call "obj1.func_four;" happens to occur at the same time from each of these threads. Thus, we have obj1 rying to obtain lock for obj1.a; and again obj1 trying to obtain lock for obj1.a, which are the same locks. So, if obj1.a of the first thread obtains the lock, then it will enter the function no-doubt, but the call from the second thread will also succeed. Thus, effectively, our synchronisation is broken.
Or am I being dumb ?
Looking forward to replies..
Ashutosh

a) In case 1, we have a non-static function, synchronized on a non-static object. Thus, effectively, there is no-synchronisationThere is no synchronization between distinct First objects, but that's what you specified. Apart from the coding bug noted below, there would be synchronization between different threads using the same instance of First.
b) In case 2, we have a non-static function, synchronized on a static object. Here, again if obj1, and obj2 happen to call the function at the same time, obj1 will try to obtain lock for obj1.a; while obj2 will try to obtain lock for obj2.a.obj1/2 don't call methods or try to obtain locks. The two different threads do that. And you mean First.b, not obj1.b and obj2.b, but see also below.
d) In case 4, we have a static function, synchronized on a static object. Here, again if obj1, and obj2 happen to call the function at the same time, obj1 will try to obtain lock for obj1.a; while obj2 will try to obtain lock for obj2.a.Again, obj1/2 don't call methods or try to obtain locks. The two different threads do that. And again, you mean First.b. obj1.b and obj2.b are the same as First.b. Does that make it clearer?
Now, I have a query : what happens if the call is made in a classically static manner, i.e. using the statement "First.func_four;".That's what happens in any case whether you write obj1.func_four(), obj2.func)four(), or First.func_four(). All these are identical when func_four(0 is static.
Now, consider this, suppose we have the same reference obj1, in two threads, and the call "obj1.func_four;" happens to occur at the same time from each of these threads. Thus, we have obj1 rying to obtain lock for obj1.aNo we don't, we have a thread trying to obtain the lock on First.b.
and again obj1 trying to obtain lock for obj1.aYou mean obj2 and First.b, but obj2 doesn't obtain the lock, the thread does.
which are the same locks. So, if obj1.a of the first thread obtains the lock, then it will enter the function no-doubt, but the call from the second thread will also succeed.Of course it won't. Your reasoning here makes zero sense..Once First.b is locked it is locked. End of story.
Thus, effectively, our synchronisation is broken.No it isn't. The second thread will wait on the same First.b object that the first thread has locked.
However in any case you have a much bigger problem here. You're autoboxing your local 'int' variable to a possibly brand-new Integer object every call, so there may be no synchronization at all.
You need:
Object a = new Object();
static Object b = new Object();

Query regarding future developement tool used to customize siebel apps

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