Query regarding Regular expressions

Help me in regular expression for “one or two digits must followed by : and one or two digits”

user8701050 wrote:
thanqI assume you meant "thank you." Please use real words.
In any case, you're welcome. So now that you know, your best course of action would be to study that tutorial, and/or this one: http://www.regular-expressions.info/tutorial.html, take your best shot, then post again if you get stuck, showing what you tried and explaining clearly the problems you encountered.
Good luck!

Similar Messages

Help in query using regular expression

HI,
I need a help to get the below output using regular expression query. Please help me.
SELECT REGEXP_SUBSTR ('PWRPKG(P/W+P/L+CC)', '[^+]+', 1, lvl) val, lvl
FROM DUAL,(SELECT LEVEL lvl FROM DUAL
CONNECT BY LEVEL <=(SELECT MAX ( LENGTH ('PWRPKG(P/W+P/L+CC)') - LENGTH (REPLACE ('PWRPKG(P/W+P/L+CC)','+',NULL))+ 1) FROM DUAL));
I need the output as
correct result:
==============
val lvl
P/W 1
P/L 2
CC 3
But i tried the above it is not coming the above result. Please help me where i did a mistake.
Thanks in advance

Frank gave you a solution in your other thread. You could simplify it if you are on 11g:
SQL> select * from table_x
2 /
TXT
TECHPKG(INTELLI CC+FRT SONAR)
PWRPKG(P/W+P/L+CC)
select txt,
        regexp_substr(
                      txt,
                      '(.*\()*([^+)]+)',
                      1,
                      column_value,
                      null,
                      2
                     ) element,
        column_value element_number
from table_x,
        table(
              cast(
                   multiset(
                            select level
                              from dual
                              connect by level <= regexp_count(txt,'\+') + 1
                   as sys.OdciNumberList
order by rowid,
           column_value
TXT                                      ELEMENT    ELEMENT_NUMBER
TECHPKG(INTELLI CC+FRT SONAR)            INTELLI CC              1
TECHPKG(INTELLI CC+FRT SONAR)            FRT SONAR               2
PWRPKG(P/W+P/L+CC)                       P/W                     1
PWRPKG(P/W+P/L+CC)                       P/L                     2
PWRPKG(P/W+P/L+CC)                       CC                      3
SQL> SY.

Help regarding regular expression

HI All ,
Please see the following string
String s = "IF ((NOT NUM4 IS ALPHABETIC ) AND NUM3 IS ALPHABETIC-UPPER AND (NUM5 IS GREATER OR EQUAL TO 3) AND (NUM5 IS NOT GREATER THAN 3) AND (NUM3 GREATER THAN 46) AND (NUM5 GREATER THAN NUM3) OR NUM3 LESS THAN 78) .";
My problem is: i want to capture the part of this line which contains "ALPHABETIC ,ALPHABETIC-UPPER for ex :NOT NUM4 IS ALPHABETIC , NUM3 IS ALPHABETIC-UPPER.from that I have to capture the word num4 , num3 which are in these phrases only ;from the whole string whereever it exists along with the phrase,Can any one help me out by suggesting something.num4 and num3 are variable names

I suspect you're right, Sabre, but I can't resist...
import java.util.regex.*;
* A rewriter does a global substitution in the strings passed to its
* 'rewrite' method. It uses the pattern supplied to its constructor, and is
* like 'String.replaceAll' except for the fact that its replacement strings
* are generated by invoking a method you write, rather than from another
* string. This class is supposed to be equivalent to Ruby's 'gsub' when given
* a block. This is the nicest syntax I've managed to come up with in Java so
* far. It's not too bad, and might actually be preferable if you want to do
* the same rewriting to a number of strings in the same method or class. See
* the example 'main' for a sample of how to use this class.
* @author Elliott Hughes
public abstract class Rewriter
private Pattern pattern;
private Matcher matcher;
   * Constructs a rewriter using the given regular expression; the syntax is
   * the same as for 'Pattern.compile'.
public Rewriter(String regularExpression)
    this.pattern = Pattern.compile(regularExpression);
   * Returns the input subsequence captured by the given group during the
   * previous match operation.
public String group(int i)
    return matcher.group(i);
   * Overridden to compute a replacement for each match. Use the method
   * 'group' to access the captured groups.
public abstract String replacement();
   * Returns the result of rewriting 'original' by invoking the method
   * 'replacement' for each match of the regular expression supplied to the
   * constructor.
public String rewrite(CharSequence original)
    this.matcher = pattern.matcher(original);
    StringBuffer result = new StringBuffer(original.length());
    while (matcher.find())
      matcher.appendReplacement(result, "");
      result.append(replacement());
    matcher.appendTail(result);
    return result.toString();
public static void main(String[] args)
    String s = "IF ((NOT NUM4 IS ALPHABETIC ) " +
                "AND NUM3 IS ALPHABETIC-UPPER " +
                "AND (NUM5 IS GREATER OR EQUAL TO 3) " +
                "AND (NUM5 IS NOT GREATER THAN 3) " +
                "AND (NUM3 GREATER THAN 46) " +
                "AND NUM645 IS ALPHABETIC " +
                "AND (NUM5 GREATER THAN NUM3) " +
                "OR NUM3 LESS THAN 78 " +
                "AND NUM34 IS ALPHABETIC-UPPER " +
                "AND NUM92 IS ALPHABETIC-LOWER " +
                "AND NUM0987 IS ALPHABETIC-LOWER) .";
    String result =
      new Rewriter("(NUM\\d+) +IS +(ALPHABETIC(?:-(?:UPPER|LOWER))?)")
        public String replacement()
          String type = group(2);
          if (type.endsWith("UPPER"))
            return "Character.isUpper(" + group(1) + ")";
          else if (type.endsWith("LOWER"))
            return "Character.isLower(" + group(1) + ")";
          else
            return "Character.isLetter(" + group(1) + ")";
      }.rewrite(s);
    System.out.println(result);
}

Help needed regarding regular expressions

hello
i need to write a program that recieves a matematical expression and evaluates
it...in other words a calculator :)
i know i need to use regular expressions inorder to determine if the input is legal or not ,but i'm really having trouble setting the pattern
the expression can be in the form : Axxze2223+log(5)+(2*3)*(5+4)
where Axxze2223 is a variable(i.e a combination of letters and numbers.)
where as: l o g (5) or log() or Axxx33aaaa or () are illegal
i tried to set the pattern but i got exceptions or it just didnt work the way i wanted it .
here's what i tried to do at least for the varibale form:
"\\s*(*([a-zA-Z]+\\d)+)*\\s*";
i'm really new to this...and i can't seem to set the pattern by using regular expressions,how can i combine all the rules to one string?
any help or references would be appreciated
thanks

so i'll explain
let's say i got token "abc22c"(let's call it "token")
i wan't to check if it's legal
i define:
String varPattern = "\\s*[a-zA-Z]+\\d+\\s*";If you want to check a sequence of ASCII characters, longer than one, followed by a single digit, the whole possibly surrounded by spaces -- yes.
>
now i want to check if it's o.k
so i check:
token.matches(varPattern);
am i correct?Quite. It's better to compile the Pattern (Pattern.compile(String)), create a java.util.regex.Matcher (Pattern#matcher(CharSequence)), and test the Matcher for Matcher#matches().
(Class.method -> static method, Class#method -> instance method)
>
now i'm having problem defining pattern for log()
sin() cos()
that brackets are mandatory ,and there must be an
expression inside
how do i do that?First, I'd check the overall function syntax (a valid name, brackets), then whether what's inside the brackets is a valid expression (maybe empty), then whether that expression is valid for that function (presumably always?).
I might add I'm no expert on parsing, so that's more a supposition than a guide.

Query regarding cron expression in BPEL

Hi,
I am using the quartz scheduler in BPEL and using the cron expression in bpel.xml
but the problem I am facing is it is running for only one day it is not running for the next day
the expression I am writting in bpel.xml is
<activationAgents>
<activationAgent className="oracle.tip.adapter.fw.agent.jca.JCAActivationAgent" partnerLink="FileScBpel4" heartBeatInterval="10">
<property name="schedulerCallout">DefaultSchedulerCalloutImpl</property>
<property name="endpointScheduleOn">0 30 19 * * ?</property>
<property name="endpointScheduleOff">0 31 19 * * ?</property>
</activationAgent>
</activationAgents>
so if I deploy it in BPEL PM it will run for today at 19:30
but when I am changing the system date to the next day and changing the time to 19:30 it is not running again
can anybody plz help me out how can I schedule it for everyday 19:30

Hi Sailo,
If you use quartz as a servlet, you'll have to add the entry to you're web.xml, in addition to other servlets you create :
<servlet>
<servlet-name>QuartzInitializer</servlet-name>
<servlet-class>org.quartz.ee.servlet.QuartzInitializerServlet</servlet-class>
<load-on-startup>1</load-on-startup>
<init-param>
<param-name>config-file</param-name>
<param-value>quartz.properties</param-value>
</init-param>
<init-param>
<param-name>shutdown-on-unload</param-name>
<param-value>true</param-value>
</init-param>
<init-param>
<param-name>start-scheduler-on-load</param-name>
<param-value>true</param-value>
</init-param>
</servlet>
Cheers
Pucha Anirudh

Query regarding regx

Hi,
I have a query regarding regular expression.
what regular expression should I use which matches the following urls
http://www.abc.com/xyz
http://www.abc.com/xyz/abc.htm
http://www.abc.com/xyz/<any thing>
but it should not match
http://www.abc.com/xyz45d
http://www.abc.com/xyz<anything> if(anything does not start with /)
I wrote the regx as : (http://www.abc.com/xyz)(/\w)*
but it also matches the last url.
Thanks
Edited by: JL.Nayak on Jun 26, 2008 9:36 AM

prometheuzz wrote:
kajbj wrote:
No, that's also incorrect.I have always found it a bit odd that people continue to answer questions that already have been answered, and especially if they post an incorrect answer.Usually this can be explained by the fact that there are still some Dukes to be rewarded to the thread in question. That's not the case with this one: odd indeed.But does that mean that you shouldn't read the other replies before you post your reply?
(There must be a rule that says that you aren't allowed to read the other replies if you are posting in a certification thread, another odd thing)

Query help in regular expression

Hi all,
SELECT * FROM emp11
WHERE INSTR(ENAME,'A',1,2) >0;
Please let me know the equivalent query using regular expressions.
i have tried this after going through oracle regular expressions documentation.
SELECT * FROM emp11
WHERE regexp_LIKE(ename,'A{2}')
Any help in this regard would be highly appreciated .
Thanks,
P Prakash

please go here
Introduction to regular expressions ...
Thanks,
P Prakash

Regular expressions: find files with exactly 'n' digits in a row

Hi there,
I want to filter files that contain only a fixed number of digits, but not more (at least not in after the digits).
For example, I have
01.mp3
02.mp3
test10.txt
test000110101010.txt
04.flac
and for n=2 I want to get all files except 'test000110101010.txt'.
The following is not working, and I'm a total newb regarding regular expressions
ls -l | grep '^-' | awk '{print $9}' | grep '([0-9]\{2\})[^0-9]\{2\}'
Thanks for help.
Regards,
drm

Thanks!
I wrote a python script to scan e.g. a music folder for missing files and needed to extract the file numbers from the files to get the "highest" number.
You can get it from here: http://pastebin.com/Sg9yDHiw (Python3, expires in 1 month)
Regards,
drm
Edit: found a bug
Last edited by drm00 (2011-02-04 13:57:43)

Faulty Regular Expression

Hi all,
I have a question regarding regular expressions.. I am refactoring a method named isPasswordValid() and removing a bunch of ugly Java code that enforces the following rules:
Does it begin with an upper or lowercase letter?
Does it contain at least one lowercase letter?
Does it contain at leasr one uppercase letter?
Does it contain at least one number?
Does it contain at least one special character from the following: !@#$%^&*-_+=
Is it at least 15 characters?I have extracted my regular expression into a dummy class for easier testing:
public class RegExTest {
     public static void main(String[] args) {
          String password ="qwerty34#$QWERTY";
          if (password.matches("^[a-zA-Z]{1}.{14,}")
                    && password.matches(".*[a-z]+.*")
                    && password.matches(".*[A-Z]+.*")
                    && password.matches(".*[0-9]+.*")
                       && password.matches(".*[!@#$%^&*-_+=]+.*")) {
               System.out.println("This is a match");
}This regular expression works as intended except for an issue with special characters. It accepts every special character specified as well as others like the tilda (~) and parenthesis. I even tried escaping the ones that needed escaping but nothing seems to work. What am I missing here? Also, do you see anything else I should be concerned with? Of course, any help would be greatly appreciated!
Thanks!

When not placed at the start or end of a character class, the hyphen is a range operator:
[a-d]    // matches 'a', 'b', 'c' or 'd'
[ad-]    // matches 'a', 'd' or '-'
[-ad]    // matches '-', 'a' or 'd'Or escape it:
[a\-d]    // matches 'a', '-' or 'd'

Regular Expression Abbreviation of Words

Suppose I have got data in my column like
Balla Ram Chog Mal College
Maharishi Dayanand University
Cambridge Public School
Now I want to write a query using regular expressions to find out the abbreviations. e.g the resulting data set should be:
BRCMC
MDU
CPS
How should I write regexp for it ?

One way, using SUBSTR and INSTR, tested on 10g.
with data as
select 'Balla Ram Chog Mal College' col from dual union all
select 'Maharishi Dayanand University' col from dual union all
select 'Cambridge Public School' col from dual
select col, replace(ltrim(max(sys_connect_by_path(str, ',')) keep (dense_rank last order by r), ','), ',') abbr
from (
select col, substr(col, decode(level, 1, 1, instr(col, ' ', 1, level - 1) + 1), 1) str, level, row_number() over (partition by col order by level) r
from data
connect by level <= length(col) - length(replace(col, ' ')) + 1
       and col = prior col
       and prior sys_guid() is not null
order by col, level
group by col
start with r = 1
connect by r - 1 = prior r
       and col = prior col
       and prior sys_guid() is not null;
COL                           ABBR
Balla Ram Chog Mal College    BRCMC
Cambridge Public School       CPS
Maharishi Dayanand University MDU
With 11g, you will not require the Outer query to concatenate the results, you can directly use LISTAGG as demonstrated by Hashim.

Regular Expressions Query!! -- Help

Hi,
I'm writing a SQL query using Regualar Expressions in Oracle 10g.
select entry_id,entry_value, from entry_logbook where REGEXP_LIKE(entry_value,'^[a-z]|[0-9]|[A-Z]')
I expect the result contains only records with values starting with alphabets or integers.
But I'm getting values like '** Something **', '#123445' etc.
Please let me know what I'm missing here.
Regards,
Venkat

SQL> with sample as
2 (select '##@Sarma123%$%$' col from dual
3 union all
4 select 'sarma' from dual
5 union all
6 select '123SARMA' from dual
7 union all
8 select 'RADHA' from dual
9 )
10 select col
11 from sample
12 where regexp_like (col, '^[a-z0-9A-Z]')
13 /
COL
sarma
123SARMA
RADHA
SQL>Cheers
Sarma.

Regular expression to convert sqlite query to 'normal' query.

How would go about using this regular expression
strftime$[^'"]['"]([^"']+)['"], [^ ]+[^$]\)to return a value like
DATE_FORMAT( backreference1, backreference2 )Basically I need to do something like:             ResultSet waarnemingen = stat.executeQuery( "SELECT strftime( '%Y%m%d', datum ) as dtm, minTemp, maxTemp, etmaalneerslag FROM waarnemingen " +
                       "WHERE stationsnummer = '"+stationsnummer+"' "+
                       "AND strftime( '%Y%m', datum ) = '"+jaar+maand+"'" );
//             ResultSet waarnemingen = stat.executeQuery( "SELECT DATE_FORMAT( datum, '%Y%m%d' ) as dtm, minTemp, maxTemp, etmaalneerslag FROM waarnemingen " +
//                       "WHERE stationsnummer = '"+stationsnummer+"' "+
//                       "AND DATE_FORMAT( datum, '%Y%m' ) = '"+jaar+maand+"'" ); Where the commented part is what it's supposed to become.
Edited by: Axeia on May 22, 2009 8:50 AM

public static void main(String[] args)
        final String theQuery = "ResultSet waarnemingen = stat.executeQuery( \"SELECT strftime( '%Y%m%d', datum ) as dtm, minTemp, maxTemp, etmaalneerslag FROM waarnemingen \" +"
                                + "\"WHERE stationsnummer = '\"+stationsnummer+\"' \"+"
                                + "\"AND strftime( '%Y%m', datum ) = '\"+jaar+maand+\"'\" );";
        final Pattern thePattern = Pattern.compile("(strftime\$([^,]+),([^\$]+)\\))");
        System.out.println(thePattern.matcher(theQuery).replaceAll("DATE_FORMAT($3,$2)"));
    }Would it be something like that that you are looking for?
Regards.

Regarding Line Break Expression (New to Regular Expression)

Hi,
I am new to regular expression.
I have a query.Suppose I have a
String str = Anshuk
Anshuk1
Anshuk2
Anshuk3
Anshuk4
where we have a line break after Anshuk and then again after Anshuk1 and so on.Actually, we have different records in different lines.
how do I make it possible usign regex that to make him inderastand that those are in different lines (meaning different records)?
I m trying...but not getting it..wat should be the code?
anshuk

What do you mean? What have you done?
Have you set the pattern to use MULTILINE?
Kaj

Urgent help regarding Java regular expressions.

hello everyone,
I am trying to parse a html file which contains
dyn.Img("http://www.boston.com/news/nation/articles/2007/06/21/bill_clinton_takes_bigger_campaign_role&h=306&w=410&sz=13&hl=en&start=43","","QFo9lqKeMR7uzM:","http://cache.boston.com/resize/bonzai-fba/AP_Photo/2007/06/21/1182410228_1931/410w.jpg","125","93","\x3cb\x3eBill Clinton\x3c/b\x3e takes bigger campaign \x3cb\x3e...\x3c/b\x3e","","","410 x 306 - 13k","jpg","www.boston.com","","","http://tbn0.google.com/images","1")
the given above function many times. I have to fetch the whole functions into an array. So i have to write a regular expression which recognises the whole above string.
Can anyone please help me.
Thank you,
chaitanya

well if this is all you want
http://cache.boston.com/resize/bonzai-fba/AP_Photo/2007/06/21/1182410228_1931/410w.jpg
You can always substring it like chuck said
***BUT all the images would have to be .jpg for this to work***
back = we.indexOf(".jpg");
int x = 0;
while (back < web.lastIndexOf(".jpg"))
                back = web.indexOf("http",back+1);
                picture[x] = web.substring(front, back);
                x++;
                front = back;
              }       Might not be the best code but it worked with a website i had to parse
Message was edited by:
mark07

Regarding The regular expression

Hi all:
there is an error in the following statement , the error messge while activating the system says
The regular expression '|' is invalid character at position 1., could u pls tell me how exactly correct the following statements.
REPLACE ALL OCCURRENCES of REGEX '|' in s_name1 with ''.
REPLACE ALL OCCURRENCES of REGEX '?' in s_name1 with ''.
REPLACE ALL OCCURRENCES of REGEX '*' in s_name1 with ''.
Thank u vrey much for any reply

hi ,
I agree with thomas , u dont have to specify REGEX ...
For Ex :
data : g_str2(100) type c value '12:30:40'.
REPLACE ALL OCCURRENCES OF ':' IN G_STR2 WITH SPACE.
Result : g_str2 = 12 30 40.
All occurances of g_str2 will be replaced by space.
Cheers !
Soumya Ranjan

Query regarding Regular expressions

Similar Messages

Maybe you are looking for