Query to find employee annual salary or pay rate for a pay period (Bi-Week)

Hi Guru's,
need your help for finding annual salary or pay rate for pay period for an employee.
I have below query returning some thousand line which I cant understand. Can someone correct the query please.
SELECT ppp.proposed_salary_n salary From per_pay_proposals ppp,apps.per_all_people_f papf,apps.per_all_assignments_f paaf,apps.per_all_people_f papf1 WHERE papf.person_id = paaf.person_id AND paaf.primary_flag = 'Y' AND paaf.assignment_type = 'E' AND paaf.supervisor_id = papf1.person_id AND papf1.current_employee_flag = 'Y'AND papf.business_group_id = paaf.business_group_id AND SYSDATE BETWEEN papf.effective_start_date and papf.effective_end_date AND SYSDATE BETWEEN paaf.effective_start_date AND paaf.effective_end_date AND SYSDATE BETWEEN papf1.effective_start_date AND papf1.effective_end_date AND papf.employee_number='1234';
SALARY
17.4346
16.0846
17.4346
13.78
13.78
15.07
13.78
13.78
13.78
3305.59
14.859
SALARY
5507.25
2731.01
2690.51
13.78
13.35
13.35
1960
4192
     17
4927
2525.02
SALARY
2652
13.35
15.07
2686.67
2964
13.78
17.4635
20.4981
16.0846
13.78
17.4635
SALARY
2666.68
13.78
15.07
13.78
16.0846
17.4635
4353.99
4562.51
17.4346
16.0846
6727.41
SALARY
2780.99
     20
17.4346
16.0846
2970
2315.01
17.4635
2629.85
14.5705
5635
17.4346
Thanks
Sandeep

I used table hrpy_rgdir  to get sequence number for the given pernr, payroll area and dates.
Using the sequence number, I am calling Function PYXX_READ_PAYROLL_RESULT to extract the payroll results.
SELECT * INTO CORRESPONDING FIELDS OF TABLE it_hrpy_rgdir
  FROM hrpy_rgdir
  WHERE srtza = 'A'             
    AND paydt IN sopaydt
    AND abkrs IN soabkrs
    AND pernr IN sopernr.
LOOP AT it_hrpy_rgdir.
  PERFORM get_rt USING it_hrpy_rgdir-pernr it_hrpy_rgdir-seqnr.
ENDLOOP.
*&      Form  get_rt
*       text
*      -->PERNR      text
*      -->SEQNR      text
FORM get_rt USING pernr seqnr.
  CLEAR: it_payroll_result.
  CALL FUNCTION 'PYXX_READ_PAYROLL_RESULT'
    EXPORTING
      clusterid                    = 'RQ'
      employeenumber               = pernr
      sequencenumber               = seqnr
    CHANGING
      payroll_result               = it_payroll_result
    EXCEPTIONS
      illegal_isocode_or_clusterid = 1
      error_generating_import      = 2
      import_mismatch_error        = 3
      subpool_dir_full             = 4
      no_read_authority            = 5
      no_record_found              = 6
      versions_do_not_match        = 7
      error_reading_archive        = 8
      error_reading_relid          = 9
      OTHERS                       = 10.
ENDFORM.                   
For any period, the function module just returns sy-subrc = 6 [no_record_found].
We are on Australian Payroll.  Could you please let me know what I might be missing or is there an alternative way of getting the information ?
Thank you

Similar Messages

  • Query to find Employee Salary Details

    Hi,
    Could anyone help in writing the query to find employee salary details.
    Thanks in advance.

    This should get you started:
    SELECT papf.full_name
    ,papf.email_address
    ,ppp.proposed_salary_n salary
    FROM per_pay_proposals ppp
    ,per_all_assignments_f paaf
    ,per_all_people_f papf
    WHERE ppp.assignment_id = paaf.assignment_id
    AND paaf.assignment_type = 'E'
    AND paaf.primary_flag = 'Y'
    AND paaf.person_id = papf.person_id
    AND nvl(papf.current_employee_flag, 'N') = 'Y'
    AND trunc(sysdate) BETWEEN
    ppp.change_date AND ppp.date_to
    AND trunc(sysdate) BETWEEN
    paaf.effective_start_date AND paaf.effective_end_date
    AND trunc(sysdate) BETWEEN
    papf.effective_start_date AND papf.effective_end_date;

  • Query to find employees who are managers for 3 or more employees

    Hi,
    I am using emp table in scott schema for this query.
    select * from emp
    where empno in
    (select e.mgr
    from emp e, emp m
    where e.mgr = m.empno
    group by e.mgr
    having count(*) >= 3);
    It gives all employee details where he is manager for more than or equal 3 employees. Please suggest all possible queries which gives same output.
    Thanks
    Raghu

    select * from emp
    select a.empno, a.ename , a.mgr, b.ename reported_to
    from emp a, emp b
    where a.mgr = b.empno
    --start with keyword
    SELECT empno, ename, mgr, LEVEL
    FROM emp
    START WITH empno = 7788
    CONNECT BY PRIOR empno = mgr
    ORDER siblings BY ename;
    -- employee reported to
    SELECT ename || ' reports to ' ||
    PRIOR ename "Walk Top Down"
    FROM emp
    START WITH ename = 'KING'
    CONNECT BY PRIOR empno = mgr
    -- use of PRIOR in different places
    SELECT ename || ' reports to ' ||
    PRIOR ename "Walk Top Down"
    FROM emp
    START WITH ename = 'KING' --'SCOTT'
    CONNECT BY PRIOR empno = mgr
    -- using prior type 2
    SELECT ename || ' reports to ' ||
    PRIOR ename "Walk Top Down"
    FROM emp
    START WITH ename = 'CLARK' --'SCOTT'
    CONNECT BY empno = PRIOR mgr
    -- top down
    SELECT empno, ename, job, mgr
    FROM emp
    START WITH ename = 'SMITH'
    CONNECT BY PRIOR mgr = empno ;
    -- bottom up
    SELECT empno, ename, job, mgr
    FROM emp
    START WITH ename = 'SMITH'
    CONNECT BY PRIOR empno = mgr ;
    --level chart
    SELECT LPAD(ename, LENGTH(ename) + (LEVEL * 2 ) - 1, '_ '), level
    AS org_chart
    FROM emp
    START WITH ename='KING' --'SCOTT'
    CONNECT BY PRIOR empno = mgr
    --Using WHERE clause to eliminate a node.
    SELECT deptno, empno,ename, job, sal
    FROM emp
    WHERE ename != 'FORD'
    START WITH mgr IS NULL
    CONNECT BY PRIOR empno = mgr;
    -- Using CONNECT BY clause to eliminate a branch.
    SELECT deptno, empno,ename, job, sal
    FROM emp
    START WITH mgr IS NULL
    CONNECT BY PRIOR empno = mgr
    AND ename != 'FORD'
    SELECT EName "Employee",
    LEVEL,
    SYS_CONNECT_BY_PATH(ename, ' /') "Path"
    FROM emp
    START WITH mgr is null
    CONNECT BY PRIOR empno = mgr;
    -- 10g features
    -- connect by isleaf
    Select Ename "Employee", Connect_by_isleaf "IsLeaf", Level,
    Sys_connect_by_path (Ename, ' /') "Path"
    From Emp
    Start With Mgr Is Null
    Connect By Prior Empno = Mgr;
    -- connect by iscycle
    SELECT EName "Employee",
    CONNECT_BY_ISLEAF "IsLeaf",
    CONNECT_BY_ISCYCLE "IsCycle",
    LEVEL,
    SYS_CONNECT_BY_PATH(ename, ' /') "Path"
    FROM emp
    START WITH mgr is null
    CONNECT BY nocycle prior empno = mgr;
    -- connect by root
    SELECT ename "Employee", CONNECT_BY_ROOT ename "Manager",
    LEVEL-1 "Pathlen", SYS_CONNECT_BY_PATH(ename, '/') "Path"
    FROM emp
    WHERE LEVEL > 1 and deptno = 10
    CONNECT BY PRIOR empno = mgr;

  • Problem: query to find employees at one plant for specified year

    Problem: how to determine if an employee was working at a specific plant during a specific year using this limited amount of data in a "job changes" table. No matter what I've tried, I keep getting the wrong number of records and it's driving me nuts. I thought this would be a simple query but it's not (for me anyway!) so I need a "clue" to point me in the right direction. Help? :-)
    Sample records:
    EMPLID  PLANT   EFF_DATE    HIRE_DATE   TERM_DATE
    123456  23      01-JAN-00   22-MAR-88   NULL
    123456  29      30-JUL-02   22-MAR-88   NULL
    123456  22      21-AUG-03   22-MAR-88   NULL
    456789  29      11-JUL-01   11-JUL-01   NULL
    456789  22      30-JUL-03   11-JUL-01   NULLFor example, how do I write the query so that employee 123456 will show up for years 1999 and 2001 in plant 23?

    Here is an example:
    SQL> SELECT * FROM EMP;
        EMPLID      PLANT EFF_DATE    HIRE_DATE   TERM_DATE
        123456         23 01-JAN-2000 22-MAR-1988
        123456         29 30-JUL-2002 22-MAR-1988
        123456         22 21-AUG-2003 22-MAR-1988
        456789         29 11-JUL-2001 11-JUL-2001
        456789         22 30-JUL-2003 11-JUL-2001
    5 rows selected.
    SQL> SELECT A.EMPLID,A.PLANT,A.EFF_DATE,A.END_DATE FROM
      2  (SELECT EMPLID,PLANT,EFF_DATE,LEAD(EFF_DATE,1) OVER(ORDER BY EMPLID,EFF_DATE) -1 END_DATE,
      3  HIRE_DATE FROM EMP
      4  WHERE EMPLID=123456
      5  ORDER BY EMPLID) A
      6  WHERE A.EFF_DATE >= TO_DATE('01-JAN-1999','DD-MON-YYYY')
      7  AND A.EFF_DATE <= TO_DATE('31-DEC-2001','DD-MON-YYYY')
      8  AND TO_DATE('31-DEC-2001','DD-MON-YYYY') <= END_DATE;
        EMPLID      PLANT EFF_DATE    END_DATE
        123456         23 01-JAN-2000 29-JUL-2002
    1 row selected.

  • Query to find out controls displayed as in UI for an applet,along with view

    Hi,
    I am looking for a query to find out list of all the controls as displayed in UI applet along with applet's view.
    Please note that in the query only mapped controls (those displayed in UI ) should come up.
    Regards,
    Kunal

    Hi,
    If the EUL is an apps mode (EBS) EUL then the eu_username column is the apps user id or apps resp id. If you want to show only the responsibilities and convert those ids to names then you need to use the EUL5_GET_APPS_USERRESP function like this:
    select ba_name, ba_developer_key, EUL5_GET_APPS_USERRESP(eu.eu_username, 'R') responsibility_name
    from eul5_bas ba
       , eul5_access_privs ap
       , eul5_eul_users eu
    where ba.ba_id = ap.gba_ba_id
    and ap.ap_type = 'GBA'
    and ap.ap_eu_id = eu.eu_id
    and eu.eu_role_flag=1
    order by 1,2,3Rod West

  • How to find what transaction an user was running for a given period

    hi
    could anybody tel me
    how to find what transaction a particular user was running for a given period
    in the past.............

    Hi,
    U need to findout the list of Tcode excuted by SAP user
    1) Tcode: ST03N
    2) Select Expert Mode option
               (there u find  Server Host name & Today)
       If u select Host name u find DAY/WEEK/Month (same thing will in Today option)
    3)Now u need to select the option of DAY,WEEK etc.
    Now u can find in two ways
    1) Transaction profile (Standard / EarlyWatch)
    2) User (user profile)
    If u select the Transaction profile
    Under these u find the option of Aggregation----application/package/tranasation etc.
    I hope these will help u to findout.
    Regards
    ASR

  • Query to find employee salary details in HRMS

    Hi,
    Could anyone one provide me the query to get the salary details of an employee.
    Thanks.

    Hi,
    Hope this work for you.
    SELECT pap.last_name last_name
    ,pap.first_name first_name
    ,pap.employee_number employee_id
    ,hlu2.meaning ethnic_origin
    ,hlu1.meaning eeo_category
    ,hlu5.meaning veteran_status
    ,pap.sex sex
    ,ROUND(pro.proposed_salary_n, 2) current_salary
    ,ROUND(pro.proposed_salary_n * ppb.pay_annualization_factor) current_yearly_salary
    ,pg.NAME grade
    ,pj.NAME job_name
    ,pjd.segment3 business_unit
    ,pjd.segment4 FUNCTION
    ,pjd.segment5 designation
    ,pjd.segment2 job_group
    ,pos.date_start hire_date
    ,NVL(pos.actual_termination_date, hr_general.end_of_time) termination_date
    ,hl.location_code LOCATION
    ,pap.full_name
    ,pj.job_information3 flsa_code
    ,hlu4.meaning employment_category_meaning
    ,pap.effective_start_date p_effective_start_date
    ,pap.effective_end_date p_effective_end_date
    ,paa.effective_start_date a_effective_start_date
    ,paa.effective_end_date a_effective_end_date
    ,pro.from_change_date s_effective_from_date
    ,NVL(pro.to_change_date, hr_general.end_of_time) s_effective_to_date
    ,pap.current_employee_flag
    FROM per_all_people_f pap
    ,per_all_assignments_f paa
    ,per_periods_of_service pos
    ,(SELECT pro1.approved
    ,pro1.assignment_id
    ,pro1.change_date from_change_date
    , pro_next.change_date - 1 to_change_date
    ,pro1.multiple_components
    ,pro1.last_change_date
    ,pro1.proposed_salary_n
    ,pro1.forced_ranking
    ,pro1.last_updated_by
    ,pro1.last_update_date
    ,pro1.event_id
    ,pro1.performance_review_id
    ,pro1.pay_proposal_id
    FROM per_pay_proposals pro1
    ,per_pay_proposals pro_next
    WHERE pro1.assignment_id = pro_next.assignment_id(+)
    AND pro1.change_date = pro_next.last_change_date(+)) pro
    ,per_jobs pj
    ,per_job_definitions pjd
    ,hr_locations hl
    ,per_grades pg
    ,(SELECT *
    FROM hr_lookups
    WHERE lookup_type = 'US_EEO1_JOB_CATEGORIES') hlu1
    ,(SELECT *
    FROM hr_lookups
    WHERE lookup_type = 'US_ETHNIC_GROUP') hlu2
    ,(SELECT *
    FROM hr_lookups
    WHERE lookup_type = 'US_EXEMPT_NON_EXEMPT') hlu3
    ,(SELECT *
    FROM hr_lookups
    WHERE lookup_type = 'EMP_CAT') hlu4
    ,(SELECT meaning
    ,lookup_code
    FROM hr_lookups
    WHERE lookup_type LIKE 'US_VETERAN_STATUS') hlu5
    ,per_pay_bases ppb
    ,(SELECT *
    FROM per_addresses
    WHERE primary_flag = 'Y'
    AND address_type = 'H'
    AND ( date_to IS NULL
    OR date_to > SYSDATE)) addr
    WHERE pap.person_id = paa.person_id
    AND paa.assignment_id = pro.assignment_id
    AND paa.job_id = pj.job_id
    AND paa.location_id = hl.location_id
    AND paa.grade_id = pg.grade_id(+)
    AND pos.person_id = pap.person_id
    AND ppb.pay_basis_id = paa.pay_basis_id
    AND pj.job_information1 = hlu1.lookup_code
    AND pj.job_definition_id = pjd.job_definition_id
    AND pap.per_information1 = hlu2.lookup_code(+)
    AND pap.per_information5 = hlu5.lookup_code(+)
    AND pj.job_information3 = hlu3.lookup_code(+)
    AND paa.employment_category = hlu4.lookup_code
    AND addr.person_id(+) = pap.person_id

  • Query to find Employee's Business group name

    Hi,
    I am new to HRMS module.
    I want to find the employee's (from per_all_people_f) business group details.
    I found a base table HR_ALL_ORGANIZATION_UNITS, but there are many records in that table with the same business_group_id as that by itself isnt a unique key.
    Could some one assist me in finding the link between employees and their BG.
    Thanks.

    the business group details are stored in the table "*PER_BUSINESS_GROUPS_PERF*" So you can use the following clause:
    where PER_ALL_PEOPLE_F.BUSINESS_GROUP_ID = PER_BUSINESS_GROUPS_PERF.BUSINESS_GROUP_ID
    Good Luck,

  • Query to find employee competence score and rating against each competence

    Hi Guys,
    I am looking for a query to retrieve the below information -
    1. Job competency requirement value ( stored in competency requirement screen)
    2. Actual competenct value ( stored in competence profile)
    Basically from these two values, we like to figure out the competency gap for the employee.
    Appreciate your help!
    thanks,
    AB

    any help guru's!!!!

  • Query to find employee of the month in year

    HI,
    Can anyone please help me in writing the following queries on Northwind database.
    1.We are going to motivate employees by creating 'Employee of Month' (employee who has made highest sale). Create Employee of Month List for year 1997. 
    2.We want to know how our products’ sales differ from each month. Get the list product which
    we sold the most and which we sold the least in quantity for each month of 1997.

    And for the second problem try:
    WITH cte
    AS (
    SELECT OD.ProductID
    ,SUM(OD.Quantity) AS SoldQty
    ,datepart(month, O.OrderDate) AS MonthNumber
    ,datename(month, O.OrderDate) AS [Month Name]
    FROM dbo.Orders O
    INNER JOIN dbo.[Order Details] OD ON O.OrderID = OD.OrderID
    WHERE O.OrderDate >= '19970101'
    AND O.OrderDate < '19980101'
    GROUP BY datepart(month, O.OrderDate)
    ,datename(month, O.OrderDate)
    ,OD.ProductID
    ,cte1
    AS (
    SELECT P.ProductName
    ,P.ProductID
    ,cte.SoldQty
    ,cte.MonthNumber
    ,cte.[Month Name]
    ,ROW_NUMBER() OVER (
    PARTITION BY cte.MonthNumber ORDER BY SoldQty
    ) AS RnMin
    ,ROW_NUMBER() OVER (
    PARTITION BY cte.MonthNumber ORDER BY SoldQty DESC
    ) AS RnMax
    FROM cte
    INNER JOIN dbo.Products P ON cte.ProductID = P.ProductID
    SELECT [Month Name]
    ,MIN(CASE
    WHEN RnMin = 1
    THEN ProductName
    END) AS [Least Sold Product]
    ,MIN(CASE
    WHEN RnMin = 1
    THEN SoldQty
    END) AS [Least Sold Qty]
    ,MIN(CASE
    WHEN RnMax = 1
    THEN ProductName
    END) AS [Best Sold Product]
    ,MIN(CASE
    WHEN RnMax = 1
    THEN SoldQty
    END) AS [Best Sold Qty]
    FROM cte1
    GROUP BY [MonthNumber]
    ,[Month Name]
    ORDER BY [MonthNumber]
    For every expert, there is an equal and opposite expert. - Becker's Law
    My blog
    My TechNet articles

  • Query to find employees responsibilties in Department

    Dear All
    i need query which can give me list of responsibilties of users in a particular department.
    i am unable to link the organization id or the person id with responsibilty table or fnd_user table.
    Thanks

    Dear All
    i need query which can give me list of responsibilties of users in a particular department.
    i am unable to link the organization id or the person id with responsibilty table or fnd_user table.
    Thanks

  • Query to find the Salary table details  HRMS 11i

    I am looking  query to find the persons salary details in Oralce EBS 11i.
    I tried the below query bu it didn'ty work.
    SELECT papf.employee_number
    ,papf.full_name
    ,pj.NAME job
    ,haou.NAME ORGANIZATION
    ,ppp.proposed_salary_n salary
    FROM per_all_people_f papf
    ,per_all_assignments_f paaf
    ,per_jobs pj
    ,hr_all_organization_units haou
    ,per_position_definitions ppd
    ,per_all_positions pap
    ,per_pay_proposals ppp
    WHERE 1 = 1
    AND SYSDATE BETWEEN papf.effective_start_date AND papf.effective_end_date
    AND papf.current_employee_flag = 'Y'
    AND papf.employee_number IS NOT NULL
    AND paaf.person_id = papf.person_id
    AND SYSDATE BETWEEN paaf.effective_start_date AND paaf.effective_end_date
    AND paaf.job_id = pj.job_id
    AND paaf.organization_id = haou.organization_id
    AND paaf.position_id = pap.position_id
    AND pap.position_definition_id = ppd.position_definition_id
    AND ppp.pay_proposal_id = (SELECT MAX (pay_proposal_id)
    FROM per_pay_proposals
    WHERE assignment_id = paaf.assignment_id)
    In our case all the below tables have 0 records..
    select count(*) from PER_PAY_PROPOSALS ;
      COUNT(*)
             0
    select count(*) from pay_element_entry_values_f;
      COUNT(*)
             0
    select count(*) from PAY_ELEMENT_ENTRY_VALUES_F;
      COUNT(*)
             0
    select count(*) from PAY_ELEMENT_ENTRIES_F;
      COUNT(*)
             0

    Hi,
    Your results clearly states that there is no salary data which is been captured as well as there are no element entries which are assigned to any assignment.
    Please do the below which will insert records in salary as well as element entries table:
    1. Add a salary proposal to any active employee (People Enter and Maination --> Search for any employee --> Assignment --> Salary) - This will insert a record in PER_PAY_PROPOSALS table
    2. Add an element entry to any active assignment (People Enter and Maination --> Search for any employee --> Assignment --> Entries) - This will insert a record in PAY_ELEMENT_ENTRIES_F and PAY_ELEMENT_ENTRY_VALUES_F table
    Hope this clarifies.
    Thanks,
    Sanjay

  • Infotype 0008 - Annual salary is being recalculated (screen 2010)

    The previously saved annual salary in IT 0008 was entered manually in IT0008 (field ANSAL), the system
    calculates the period salary according to rules configured (in T511, T539 etc ) and stores in the wage type of the infotype record IT0008. When there is a change to the monthly working hours (in P0007-MOSTD), the system displays message (RP371) - 'Annual salary has changed, please check your entry'  in IT 0008 Basic Pay and the current saved record is overwritten with a recalculated annual salary based on the period salary.
    Example, Employee on full time work schedule, current IT 0008 (saved) - Annual salary is EUR 50000.00 and therefore WT Basic salary is EUR 4666.67.
    In a scenario where the employee moves from full time to part-time and where there is change to the monthly working hours, the annual salary is being recalculated based on the period salary (which is 4666.67) and displays EUR 50000.04 rather than EUR 50000.00.
    Any ideas why this is happening and any help is much appreciated.
    Regards, Terence

    How much is the change in monthly working hours? Even if it is a small change, Annual salary difference should be more than $0.04

  • Find Employee Worked 7 Consecutive days

    Hello All,
    I have a view with following columns
    (EMP #, Dept #, Total hours worked, Date of the total hours, Current Pay period st date, Current Pay period end date, Previous pay period start date, Previous pay period start date, Next pay period st date, next pay period end date)
    I need a query to find employees who worked consecutively for 7 Days
    within a date range.
    Please let me know...
    Thanks,
    Kottee
    kotteeswaran

    DECLARE @StartDate DATETIME
    DECLARE @EndDate  DATETIME
    SET @StartDate = '11/1/2010'
    SET @EndDate ='11/10/2010'
    SELECT        VP_ALLTOTALS.PERSONNUM,
            MIN(VP_ALLTOTALS.APPLYDATE) AS StartDate,
            MAX(VP_ALLTOTALS.APPLYDATE) AS Enddate
    FROM        (
                SELECT    V.PERSONNUM,
                    V.APPLYDATE,
                    DATEDIFF(DAY, '17530101', VP_ALLTOTALS.APPLYDATE) - ROW_NUMBER() OVER (PARTITION BY VP_ALLTOTALS.PERSONNUM ORDER BY VP_ALLTOTALS.APPLYDATE) AS GroupID
                FROM    VP_ALLTOTALS V
                WHERE    VP_ALLTOTALS.APPLYDATE BETWEEN @StartDate AND @EndDate
            ) AS t
    GROUP BY    VP_ALLTOTALS.PERSONNUM,
            GroupID
    HAVING        COUNT(*) >= 7
    I'm getting following errors
    Msg 4104, Level 16, State 1, Line 7
    The multi-part identifier "VP_ALLTOTALS.APPLYDATE" could not be bound.
    Msg 4104, Level 16, State 1, Line 7
    The multi-part identifier "VP_ALLTOTALS.APPLYDATE" could not be bound.
    Msg 4104, Level 16, State 1, Line 7
    The multi-part identifier "VP_ALLTOTALS.APPLYDATE" could not be bound.
    Msg 4104, Level 16, State 1, Line 7
    The multi-part identifier "VP_ALLTOTALS.PERSONNUM" could not be bound.
    Msg 4104, Level 16, State 1, Line 7
    The multi-part identifier "VP_ALLTOTALS.APPLYDATE" could not be bound.
    Msg 4104, Level 16, State 1, Line 7
    The multi-part identifier "VP_ALLTOTALS.PERSONNUM" could not be bound.
    Msg 4104, Level 16, State 1, Line 7
    The multi-part identifier "VP_ALLTOTALS.PERSONNUM" could not be bound.
    Msg 4104, Level 16, State 1, Line 7
    The multi-part identifier "VP_ALLTOTALS.APPLYDATE" could not be bound.
    Msg 4104, Level 16, State 1, Line 7
    The multi-part identifier "VP_ALLTOTALS.APPLYDATE" could not be bound.
    And Many Thanks for PESO and RAMIREDDY...
    Thanks,
    kotteesh
    kotteeswaran

  • Query to get the Cumulative salary from EMP

    SQL query to find out cumulative salary.
    EX:
    EMPNO ENAME SAL CUMSAL
    1 AAAA 1500 1500
    2 BBBB 1000 2500
    3 CCCC 1250 3750

    Hi Madhan,
    If you talking abt query to find the total sal of each employee i.e., SAL + CUMSAL then you can use the below query:
    select a.empno,a.ename,a.sal + b.cumsal totalsal from
    emp a, emp b
    where a.empno = b.empno;
    Regards,
    Murali Mohan

Maybe you are looking for