Query Varray help please

Is there a way that I can write a query so that a varray column is simply returned as some sort of delimited string, or even as just binary?
Any help is greatly appreciated.

Example for you:
[email protected]> create type num_array is varray(10) of number
3 /
Type created.
[email protected]> create table t902(id int,tab num_array);
Table created.
[email protected]> ed
Wrote file afiedt.buf
1 declare
2 v_tab num_array := num_array();
3 begin
4 v_tab.extend(2);
5 v_tab(1) := 1;
6 v_tab(2) := 2;
7 insert into t902 values(1,v_tab);
8 commit;
9* end;
[email protected]> /
PL/SQL procedure successfully completed.
[email protected]> select * from t902;
ID TAB
1 NUM_ARRAY(1, 2)
Best Regards
Krystian Zieja / mob

Similar Messages

MS Query - Repost, Help please!

I have built a query in Access that I am accessing via .asp
pages (VB
Script). The query brings back related records (from another
table) , and
also has a count of these records against this relationship.
Heres the SQL that Access creates
SELECT sections.SectionID, sections.Section_Name,
Count(articles.ArticleID)
AS CountOfArticleID
FROM sections INNER JOIN articles ON sections.SectionID =
articles.SectionID
GROUP BY sections.SectionID, sections.Section_Name;
i.e.
Table 1
Sec 1
Sec 2
Sec 3
Table Two
Article 1, Sec1
Article 2, Sec1
Article 3, Sec 2
SO the query displays
Sec1, Article Count = 2
Sec2, Article Count =1
The problem I have is that how do I return Sec 3 within the
Query with a 0
(Zero) against it, it only seems to bring back the Sections
with related
record?
Any help or links to tutorial would be grateful
Thanks in advance

I believe if you replace:
INNER JOIN
with
LEFT OUTER JOIN
It will work.
Try it and let us know.
"The 'Ox'" <[email protected]> wrote in message
news:eqsr0b$10l$[email protected]..
>I have built a query in Access that I am accessing via
.asp pages (VB
> Script). The query brings back related records (from
another table) , and
> also has a count of these records against this
relationship.
>
> Heres the SQL that Access creates
>
> SELECT sections.SectionID, sections.Section_Name,
> Count(articles.ArticleID)
> AS CountOfArticleID
> FROM sections INNER JOIN articles ON sections.SectionID
=
> articles.SectionID
> GROUP BY sections.SectionID, sections.Section_Name;
>
>
> i.e.
>
> Table 1
> Sec 1
> Sec 2
> Sec 3
>
> Table Two
> Article 1, Sec1
> Article 2, Sec1
> Article 3, Sec 2
>
> SO the query displays
> Sec1, Article Count = 2
> Sec2, Article Count =1
>
> The problem I have is that how do I return Sec 3 within
the Query with a 0
> (Zero) against it, it only seems to bring back the
Sections with related
> record?
>
> Any help or links to tutorial would be grateful
>
> Thanks in advance
>
>
>
>

Heirarchy query - Need help please!

DB ver: Oracle DB 10g Rel2
I have data as follows
LAST_NAME EMPLOYEE_ID MANAGER_ID
King 100 null
Cambrault 148 100
Bates 172 148
Bloom 169 148
Fox 170 148
Ozer 168 172
Smith 171 172
De Haan 102 169
Hunold 103 169
Austin 105 169
Ernst 104 170
When Cambrault(emp.id:148) logs in he should see the reporting structure as follows
- Cambrault
-- Bates
--- Ozer
--- Smith
-- Bloom
--- De Haan
--- Hunold
--- Austin
-- Fox
--- Ernst
Similerly when Bates(Emp.Id:172) logs in he should see as follows
- Bates
-- Ozer
-- Smith
How to write a query to get output of records as above?
I could write it as follows but getting all the records.
SELECT e1.ename||' works for Supervisor '||e2.ename
FROM emp e1, emp e2
WHERE e1.mgr = e2.empno;
Any help is highly appreciated. Thanks in advance.
movva
Edited by: cmovva on 27-Oct-2011 12:07 PM

maybe this example might help.
SQL> select * from emp;
EMPNO ENAME      JOB         MGR HIREDATE          SAL      COMM DEPTNO
7902 FORD       ANALYST    7782 03-Dec-81     3000.00               20
7839 KING       PRESIDENT       17-Nov-81     5000.00               10
7698 BLAKE      MANAGER    7839 01-May-81     2850.00               30
7782 CLARK      MANAGER    7839 09-Jun-81     2450.00               10
7788 SCOTT      ANALYST    7782 09-Dec-82     3000.00               20
7844 TURNER     SALESMAN   7698 08-Sep-81     1500.00      0.00     30
7876 ADAMS      CLERK      7782 12-Jan-83     1100.00               20
7900 JAMES      CLERK      7698 03-Dec-81      950.00               30
7934 MILLER     CLERK      7782 23-Jan-82     1300.00               10
7945 CINDY      SALESMAN   7698 16-Jan-83     1800.00               30
7950 TINA       SALESMAN   7698 18-Jan-83     1850.00               30
11 rows selected
SQL>
SQL> select substr(lpad(' ',2*(level-1)) || ename,1,40) employee_name, job, hiredate, sal
2    from emp
3    start with mgr is null
4    connect by prior empno = mgr;
EMPLOYEE_NAME                            JOB       HIREDATE          SAL
KING                                     PRESIDENT 17-Nov-81     5000.00
BLAKE                                  MANAGER   01-May-81     2850.00
    TURNER                               SALESMAN 08-Sep-81     1500.00
    JAMES                                CLERK     03-Dec-81      950.00
    CINDY                                SALESMAN 16-Jan-83     1800.00
    TINA                                 SALESMAN 18-Jan-83     1850.00
CLARK                                  MANAGER   09-Jun-81     2450.00
    SCOTT                                ANALYST   09-Dec-82     3000.00
    ADAMS                                CLERK     12-Jan-83     1100.00
    FORD                                 ANALYST   03-Dec-81     3000.00
    MILLER                               CLERK     23-Jan-82     1300.00
11 rows selected
SQL> using your sample data something like this:
SQL> select *
2    from (select 'King'      last_name, 100 employee_id, null manager_id from dual union all
3          select 'Cambrault' last_name, 148 employee_id, 100 manager_id from dual union all
4          select 'Bates'     last_name, 172 employee_id, 148 manager_id from dual union all
5          select 'Bloom'     last_name, 169 employee_id, 148 manager_id from dual union all
6          select 'Fox'       last_name, 170 employee_id, 148 manager_id from dual union all
7          select 'Ozer'      last_name, 168 employee_id, 172 manager_id from dual union all
8          select 'Smith'     last_name, 171 employee_id, 172 manager_id from dual union all
9          select 'De,Haan'   last_name, 102 employee_id, 169 manager_id from dual union all
10          select 'Hunold'    last_name, 103 employee_id, 169 manager_id from dual union all
11          select 'Austin'    last_name, 105 employee_id, 169 manager_id from dual union all
12          select 'Ernst'     last_name, 104 employee_id, 170 manager_id from dual) e;
LAST_NAME EMPLOYEE_ID MANAGER_ID
King              100
Cambrault         148        100
Bates             172        148
Bloom             169        148
Fox               170        148
Ozer              168        172
Smith             171        172
De,Haan           102        169
Hunold            103        169
Austin            105        169
Ernst             104        170
11 rows selected
SQL>
SQL> select substr(lpad(' ',2*(level-1)) || e.last_name,1,40) last_name,
2         e.employee_id,
3         e.manager_id
4    from (select 'King'      last_name, 100 employee_id, null manager_id from dual union all
5          select 'Cambrault' last_name, 148 employee_id, 100 manager_id from dual union all
6          select 'Bates'     last_name, 172 employee_id, 148 manager_id from dual union all
7          select 'Bloom'     last_name, 169 employee_id, 148 manager_id from dual union all
8          select 'Fox'       last_name, 170 employee_id, 148 manager_id from dual union all
9          select 'Ozer'      last_name, 168 employee_id, 172 manager_id from dual union all
10          select 'Smith'     last_name, 171 employee_id, 172 manager_id from dual union all
11          select 'De,Haan'   last_name, 102 employee_id, 169 manager_id from dual union all
12          select 'Hunold'    last_name, 103 employee_id, 169 manager_id from dual union all
13          select 'Austin'    last_name, 105 employee_id, 169 manager_id from dual union all
14          select 'Ernst'     last_name, 104 employee_id, 170 manager_id from dual) e
15    start with e.manager_id is null
16    connect by prior e.employee_id = e.manager_id;
LAST_NAME                                EMPLOYEE_ID MANAGER_ID
King                                             100
Cambrault                                      148        100
    Bloom                                        169        148
      De,Haan                                    102        169
      Hunold                                     103        169
      Austin                                     105        169
    Fox                                          170        148
      Ernst                                      104        170
    Bates                                        172        148
      Ozer                                       168        172
      Smith                                      171        172
11 rows selected
SQL>

Query Error - Help Please

The query below returns this error message: "ORA-00918: column ambiguously defined" It points to the last line of the query, at 'Colour' before the equals....
WITH ranked_data As
     SELECT Members_Order.Catalogue_ID, Item.Item_Description, Item.Colour, Item.Hire_Charge, Members_Order.Number_of_Days, (Hire_Charge * Number_of_Days) AS Total, Item.Colour, RANK () OVER (ORDER BY Hire_Charge * Number_of_Days DESC) AS rnk
     FROM Members_Order, Item
     WHERE Members_Order.Item_ID = Item.Item_ID
SELECT * FROM ranked_data
WHERE Colour = (SELECT Colour FROM ranked_data WHERE rnk = 1);Could anyone help?
Edited by: user10945931 on 16-Apr-2009 10:54

Hi,
TRy this code.
REgards Salim.
WITH ranked_data AS
     (SELECT members_order.catalogue_id, item.item_description, item.colour,
             item.hire_charge, members_order.number_of_days,
             (hire_charge * number_of_days) AS total, item.colour,
             RANK () OVER (ORDER BY hire_charge * number_of_days DESC) AS rnk
        FROM members_order, item
       WHERE members_order.item_id = item.item_id)
SELECT t.*
FROM ranked_data t
WHERE t.colour = (SELECT t1.colour
                   FROM ranked_data t1
                  WHERE t1.rnk = 1);

Query Tuning Help please

I ran the below query two times . first this query run within 4 minutes now it is running withing 20 minutes only . and how can I reduce the running time of this query.
my first table TABLE1 has partitioned day wise.
Total 14 partition in TABLE1 so if it runs for total 14 partitions it will take 14*20= 280 minutes.
Index created for TABLE1 and TABLE2
CREATE INDEX TABLE1_COL_A_INX ON TABLE1(COL_A);
CREATE INDEX TABLE1_COL_B_INX ON TABLE1(COL_B);
CREATE INDEX TABLE2_BNO_TYP_INX ON TABLE2(COL_B,RECORD_TYP);TABLE1 contain 3 billion records
TABLE2 contain 87 thousand records
INSERT INTO TARGET_TABLE
SELECT   t1.col_A,
                         t1.col_b,
                         t1.record_typ,
                         TO_date('14/06/2012','DD/MM/YYYY') ,
                         MIN( start_dt) AS First_Seen,
                         MAX( start_dt) AS Last_Seen
                FROM     TABLE1 t1,
                         TABLE2 t2
                WHERE    t1.start_dt = TO_date('14/06/2012','DD/MM/YYYY') - 12
                         AND t1.col_b = t2.col_b
                         AND t1.record_typ = t2.record_typ
                GROUP BY t1.col_a,t1.col_b,t1.record_typ,TO_date('14/06/2012','DD/MM/YYYY') ;Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - 64bit Production
PL/SQL Release 11.2.0.1.0 - Production
CORE 11.2.0.1.0 Production
TNS for 64-bit Windows: Version 11.2.0.1.0 - Production
NLSRTL Version 11.2.0.1.0 - Production
Explain plan with statistics
SQL>
117794 rows selected.
Execution Plan
Plan hash value: 1844245574
| Id | Operation                           | Name                    | Rows | Bytes |TempSpc| Cost (%CPU)| Time     | Pstart| Pstop |
|   0 | SELECT STATEMENT                    |                         |   147K| 7362K|       |   615K (1)| 02:03:05 |       |       |
|   1 | HASH GROUP BY                      |                         |   147K| 7362K| 9320K|   615K (1)| 02:03:05 |       |       |
|   2 |   NESTED LOOPS                      |                         |       |       |       |         |             |       |       |
|   3 |    NESTED LOOPS                     |                         |   147K| 7362K|       |   613K (1)| 02:02:43 |       |       |
|   4 |     TABLE ACCESS FULL               | TABEL2                  | 87586 | 1282K|       |   137   (1)| 00:00:02 |       |       |
|   5 |     PARTITION RANGE SINGLE          |                         |     3 |       |       |     3   (0)| 00:00:01 |     4 |     4 |
|* 6 |      INDEX RANGE SCAN               | TABLE1_COL_B_INX        |     3 |       |       |     3   (0)| 00:00:01 |     4 |     4 |
|* 7 |    TABLE ACCESS BY LOCAL INDEX ROWID| TABLE1                  |     2 |    72 |       |     7   (0)| 00:00:01 |     4 |     4 |
Predicate Information (identified by operation id):
   6 - access("T1"."COL_B"="T2"."COL_B")
   7 - filter("T1"."START_DT"=TO_DATE(' 2012-06-02 00:00:00', 'syyyy-mm-dd hh24:mi:ss') AND
              "T1"."RECORD_TYP"="T2"."RECORD_TYP")
Statistics
        105 recursive calls
          0 db block gets
     640720 consistent gets
     363307 physical reads
     635656 redo size
    3896682 bytes sent via SQL*Net to client
      86718 bytes received via SQL*Net from client
       7854 SQL*Net roundtrips to/from client
          2 sorts (memory)
          0 sorts (disk)
     117794 rows processed
SQL>TKPROF
SELECT   t1.COL_A,
                         t1.COL_B,
                         t1.record_typ,
                         TO_date('14/06/2012','DD/MM/YYYY') ,
                         MIN(start_dt) AS First_Seen,
                         MAX(start_dt) AS Last_Seen
                FROM     TABLE1 t1,
                         TABLE2 t2
                WHERE    t1.start_dt = TO_date('14/06/2012','DD/MM/YYYY') - 12
                         AND
                         t1.COL_B = t2.COL_B
                         AND t1.record_typ = t2.record_typ
                GROUP BY t1.col_a,t1.col_b,t1.record_typ,TO_date('14/06/2012','DD/MM/YYYY')
call     count       cpu    elapsed       disk      query    current        rows
Parse        0      0.00       0.00          0          0          0           0
Execute      0      0.00       0.00          0          0          0           0
Fetch     7853      0.15       0.28          0          0          0      117793
total     7853      0.15       0.28          0          0          0      117793
Misses in library cache during parse: 0
Parsing user id: 85 Which parameters or settings I want to check , because this query run before 4 minutes. now it takes 20 minutes... or in anyway I can rewrite this query using multiple staging table or something like that...

Hi,
1) you didn't trace the session correctly -- you probably switched tracing off before the session finished fetching all rows. Do it again, and this time end tracing by exiting the session (this way you make sure that the cursor is closed and plan stats are dumped to the trace file)
2) the plan seems to be sensible -- it costs you only 600k reads to retrieve 150k rows, that's good read-to-row ratio. You can improve it if you get read of TABLE ACCESS BY ROWID operation, but that would require creating an index on all the columns that the query needs (both in WHERE clause and in column projection) which looks like a big overhead (especially given that this is a table with 3 billion records)
3) autotrace stats seem to agree with the plan -- you're making 600k gets and half of them result in single-block disk reads. Assuming 5ms per read that's close to 20 min that you are getting. Of course, 50% buffer cache ratio is far from being perfect, and better caching is most likely the reason why the query was performing better in the past. Look at the the buffer hit ratio trend for the database -- perhaps some other activity is trashing the buffer cache, resulting in performance degradation of this query as well
Best regards,
Nikolay

Query quote help-Please ignore this thread

Dear all,
Please ignore this thread.
Thanks for understanding
Kai
Edited by: KaiS on Nov 12, 2009 9:33 AM

try
and A.subno =''' || subno || ''' ;' from usr_inf where rownum <300;
those are two single quotes ('), not double quotes.

Help please deploying Crystal Decisions 10 to Microsoft 2008 R2 IIS 7

Folks, I need your help please. We've been using Crystal Decisions 10 with MS Server 2003. We're migrating to a VM envirionment with MS Server 2008 R2. I have everything working except for our crystal reports. We are a mostly an ASP Classic enviroment.
When the report is called it opens, the SP query does not fail but the data does not show in the activex viewer. If there is a tree view associated with the report, you can see the expandable data points on the left but the report does not actually appear. No errors are apparent either.
This thing is killing my production. Any help would be greatly appreaciated!

Hi Jack
I moved your post to the SAP Crystal Reports - Legacy SDKs SCN Space.
I really doubt that you will ever get this working. As Sastry mentioned, CR 10 did not support MS Server 2008 R2. The only version of CR (using classic ASP) to support anything close (WIN 7) was CR XI R2 (v. 11.5.x), Service Pack 6. See the following wiki for more details:
Crystal Reports v. 9.1 to SAP Crystal Reports, developer version for Microsoft Visual Studio Runtime Distribution and S…
For CR XI R2 SP 6 and WIN 7 I wrote a small blog - essentially collating info reported by customers on how to get ASP working - on WIN 7 (sometimes this works, other times...). See:
Report Designer Component (RDC) in classic ASP applications on Win 2008 Server and Win 7 - Possible Solutions
Please note that both CR 10.x and 11.5.x are out of support (have been for years). My recommendation, understanding that porting the app to more recent versions of CR and either the .NET or Java SDK is not possible:
Update to CR XI R2 and keep your fingers crossed. Your chances of getting this to work CR 10 are pretty well zero. Your chance of getting this to work with CR XI R2 SP 6 are better, but still approaching zero. You may be able to obtain CR XI R2 by calling sales (866-681-3435) or check the Worldwide Office Locations | SAP.
Last note. If you do manage to get CR XI R2, please so keep in mind that:
1) CR XI R2 is no longer supported.
2) You will be using CR XI R2 in an unsupported environment (Server 2008).
- Ludek
Senior Support Engineer AGS Product Support, Global Support Center Canada
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How to get reports cumulated balances? need help please

Dear all,
I need your help please in this issue.
I am creting a report using reports designer in oracle, well the fact is i don't know how to do the following:
if i have for example in the report the following to be diplayed :
Date Amount Balance
25/5/2011 2000
27/5/2011 5000 should be calculated and equal to 2000+5000=*7000*
28/5/2011 4000 calculated and equal to 7000 + 4000=*11000*
29/5/2011 1000 calculated equal to 11000 + 1000 = 12000
what is the method so i can get the balance values calculated 7000, 11000 and 12000? what do i do? any hints please
thanks for your help

Using analytic function can be done through query as below...
SQL> SELECT EMPNO, ENAME, SAL, SUM(SAL) OVER (ORDER BY SAL ROWS UNBOUNDED PRECEDING) RUNNING_BALANCE
2 FROM SCOTT.EMP
3 /
     EMPNO ENAME             SAL RUNNING_BALANCE
      7369 SMITH             800             800
      7900 JAMES             950            1750
      7876 ADAMS            1100            2850
      7521 WARD             1250            4100
      7654 MARTIN           1250            5350
      7934 MILLER           1300            6650
      7844 TURNER           1500            8150
      7499 ALLEN            1600            9750
      7782 CLARK            2450           12200
      7698 BLAKE            2850           15050
      7566 JONES            2975           18025
      7788 SCOTT            3000           21025
      7902 FORD             3000           24025
      7839 KING             5000           29025
14 rows selected.
SQL> -Ammad

BI query F4 Help on portal

Hi
I have the BI 7.0 Query as a Iview on portal . The problem which I am facing is that F4 help for Date in selection screen is not popping up with a calendar but it is just giving dates like 20.01.2003, 21.01.2003 etc
In bex when I press F4 for the same query calendar comes
Please advice

Hi,
May I know, on what logic you want to display selection values?
One way to achieve that is to restrict values in query, this will display your query result with only restricted value. But it will show all values in selection.
Another option can be of using authorization, user will see only his authorized values in the selection.
If you can describe your requirement in more details, more help can be provided.
Regards,
Ashish

I am unable to download pictures from my Sony Cybershot to my iMac, I have tried using the USB port as well as simply inserting the memory stick into the slot. I have been able to do this in the past as recently as a few weeks ago.... Help please..

I am unable to download pictures from my Sony Cybershot to my iMac, I have tried using the USB port as well as simply inserting the memory stick into the slot. I have been able to do this in the past as recently as a few weeks ago.... Help please..

Thanks Eric for responding.
I checked and it does not appear in the Applications folder.
I tried yesterday on an ethernet connection with a download speed of 2 Mbps but, unfortunately the connection died(It happened from the ISP end, which is out of my control) in between after which there was no trace of the download that happened for so long(till the internet connection death).
One more serious query which I am unable to understand. If the internet connection, dies in the midst of the download is in progress why is it so that the state does not persist and one has to restart the entire process again. Is there no solution for this?
I tried so many times and its the same case after some amount of download it vanishes. So many unsuccessful attempts. I am ****** off now. Is it not possible to see Mavericks? Why does different machines of Apple behave differently? Somewhere it goes smoothly and somewhere like my mine. Why did not Apple release a non apple store version? Is this not a bad sign of letting the users struggle when something is being offered for free?
The reason I asked as whether we can download the .app of Mavericks is that, there are so many applications that I have downloaded web and have installed. All that works fine. Can't we do the same here? You download a copy of Mavericks installer application and upload it for me in Google drive or like online storage places which can be downloaded and used by me? Help me understand.
Thanks again.

The query processor ran out of stack space during query optimization. Please simplify the query

Can you suggest me that what should i do in this case.
Actually i am having one table that is a MasterTable.I am referring this table in more than 300 tables that means i am having foreign key of this primary key in 300+ tables.
due to this i am getting following error during deleting any row,
doesn't matter that data is existing in reference table or not.
Error that i am getting is
"The query processor ran out of stack space during query optimization. Please simplify the query"
Can you suggest me that what should i do to avoid this error,because i am unable to delete this entry.
Apart from it,i am getting performance problem too,so is it due to such huge FK on it.
Please suggest me on following points
1. Is it worst way to handle it,if yes then please suggest me solution for it.
2. If it is a correct way then what should i do if getting error during deleting any record.
3. Is it right to create Foreign key on each table where i am saving data of this master. if no then how to manage integrity.
4. What people do in huge database when they wants to create foreign key for any primary key.
5. Can you suggest me that how DBA's are handling this in big database,where they are having huge no. of tables.

The most common reason of getting such error is having more than 253 foreign key constraints on a table.
The max limit is documented here:
http://msdn.microsoft.com/en-us/library/ms143432(SQL.90).aspx
Although a table can contain an unlimited number of FOREIGN KEY constraints, the recommended maximum is 253. Depending on the hardware configuration hosting SQL Server, specifying additional foreign key constraints may be expensive for the query
optimizer to process. If you are on 32 bit, then you might want to move to 64 bit to get little bigger stack space but eventually having 300 FK is not something which would work in long run.
Balmukund Lakhani | Please mark solved if I've answered your question, vote for it as helpful to help other users find a solution quicker
This posting is provided "AS IS" with no warranties, and confers no rights.
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Author: SQL Server 2012 AlwaysOn -
Paperback, Kindle

Dynamic Insert Help Please

quote:
<cfoutput query="stand">
<tr bgcolor="#IIf(CurrentRow Mod 2, DE('ffffff'),
DE('cccccc'))#">
<td>
<select name="score_identifierscore"
id="score_identifierscore">
<option value="0" selected>0</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
</select>
<input name="score_identifier" type="hidden"
id="score_identifier" value="#stand.ident_name#">
<input name="score_teacherid" type="hidden"
id="score_teacherid" value="#session.pstid#">
<input name="score_studentid" type="hidden"
id="score_studentid" value="#url.stid#">
<input name="score_vid" type="hidden" id="score_vid"
value="#url.vid#">
<input name="score_staid" type="hidden" id="score_staid"
value="#url.staid#">
<input name="score_studentname" type="hidden"
value="#studentname.first_name# #studentname.last_name#">
</td>
<td><div
align="center">#stand.ident_name#</div></td>
<td> #stand.ident_description#</td>
</tr>
</cfoutput>
Start off by saying I work for a school corp, so my knowledge
is limited to what I've taught myself and any help will be
appreciated.
Alright, here's what I have. I'm dynamically creating a list
of standards and for each standard I want to submit a score chosen
by the teacher and the identifier along with some other
information. My problem is that on the insert I can't figure out
how to match score with identifier. I can't possibly create a field
in the table for every identifier, so I need to take the list and
insert it into another table with score_identifer and
score_identifierscore and so on....the above way is not workign for
me.
How can I get this accomplished, I can usually work off of
examples, so please examples or any help please? If you have a
better way, I'm up for it, because this way isn't working.
Thanks in advance...

quote:
Originally posted by:
AlwaysWannaLearn
What does the INSERT statement look like?
Why can't you create a table with columns names as: PK,
score_identifierscore, score_identifier, score_teacherid,
score_studentid, score_vid, score_staid, score_studentname this way
you can also map any of these fields against other tables to create
a more robust query result set?
Almost exactly the way I have it setup. Small snippet of the
dynamically generate html code that the user inputs. The problem is
in my insert statement:
<tr bgcolor="ffffff">
<td>
<select name="score_identifierscore"
id="score_identifierscore">
<option value="0" selected>0</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
</select>
<input name="score_identifier" type="hidden"
id="score_identifier" value="F1.17.1 ">
</td>
<td><div align="center">F1.17.1
</div></td>
<td> Estimate and secure necessary supplies
</td>
</tr>
<tr bgcolor="cccccc">
<td>
<select name="score_identifierscore"
id="score_identifierscore">
<option value="0" selected>0</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
</select>
<input name="score_identifier" type="hidden"
id="score_identifier" value="F1.17.2">
</td>
<td><div align="center">F1.17.2
</div></td>
<td> Determine plants, shrubs, and tree
locations
</td>
</tr>
<input name="score_teacherid" type="hidden"
id="score_teacherid" value="#session.pstid#">
<input name="score_studentid" type="hidden"
id="score_studentid" value="#url.stid#">
<input name="score_vid" type="hidden" id="score_vid"
value="#url.vid#">
<input name="score_staid" type="hidden" id="score_staid"
value="#url.staid#">
<input name="score_studentname" type="hidden"
value="#studentname.first_name# #studentname.last_name#">
Here's my insert statement, but now that I've look at it,
that won't match the identifier with the score, so it's crap. Any
help is appreciated. Thanks
<cfloop index="I" list="#form.score_identifier#"
delimiters=",">
<cfquery datasource="whatever">
INSERT INTO voc_scores
(score_studentid, score_vid, score_staid, score_identifier,
score_teacherid, score_studentname,score_identifierscore)
VALUES('#FORM.score_studentid#','#FORM.score_vid#','#FORM.score_staid#','#I#','#FORM.score _teacherid#','#FORM.score_studentname#',
'#FORM.score_identifierscore#')
</cfquery>
</cfloop>

b font color ='red' Java JDBC and Oracle DB URGENT HELP PLEASE /font /b

Hello, I am a newbie. I'm very interested in Java in relation to JDBC, Oracle and SAP.I am trying to connect to an Oracle DB and I have problems to display the output on the consule in my application. What am I doing wrong here . Please help me. This is my code: Please Explain
import java.sql.*;
import java.sql.DriverManager;
import java.sql.Connection;
public class SqlConnection {
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          Connection con = DriverManager.getConnection
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               String man = rs.getString("1");
               String jean = rs.getString("2");
               String test = rs.getString("3");
               String kok = rs.getString("4");
               System.out.println( man, jean, test,kok );//here where my the
                                             //compiler gives me errors
          stmt.close();
          con.close();
}

<b><font color ='red'>Java JDBC and Oracle DB URGENT HELP PLEASE</font></b>Too bad your attempt at getting your subject to have greater attention failed :p

I keep being asked to update my Safari but when I do a Software update it scans but never gives me a list and just says no new updates. Help please!

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At the end of my IMovie I want to write some text: as in" Happy Birthday Mandy we had a great time with you. etc.. How do I go about this? Which icon in IMovie lets me have a place to write text?? help please

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Thanks

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Geoff.

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