Question about running a servelt using HTML form.

Hi, Im new to Servlets , I have created a servelt with this code :
package oracle.servlets;
import java.io.IOException;
import java.io.PrintWriter;
import java.sql.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class LoginServlet extends HttpServlet {
    private static final String CONTENT_TYPE = "text/html; charset=windows-1252";
    private static final String DB_URL = "jdbc:oracle:thin:@localhost:1521:ahmaddb";
    private static final String DB_USERNAME = "fundinfo";
    private static final String DB_PASSWORD = "tadapps";
    private static Connection con;
    private String pass;
    private String name;
/*init() : invoked by the servlet engine before the servicing of client requests
- Can be used to retrieve initialization parameters
Takes a ServletConfig object as a parameter
Is invoked when the servlet instance is created
Is useful for obtaining database connections from a connection pool*/
    public void init(ServletConfig config) throws ServletException {
        super.init(config);
        //config.getInitParameter(arg0);
    public void doGet(HttpServletRequest request,
                      HttpServletResponse response) throws ServletException,
                                                           IOException {
response.setContentType(CONTENT_TYPE);
        //PrintWriter : Print formatted representations of objects to a text-output stream.
        //getWriter() : Returns a PrintWriter object that can send character text to the client.
        PrintWriter out = response.getWriter();
        out.println("<html>");
        out.println("<head><title>My First Servlet</title></head>");
        out.println("<body>");
        out.println("<p>The servlet has received a GET. This is the reply.</p>");
        out.println("</body></html>");
        out.close();
    public void doPost(HttpServletRequest request,
                       HttpServletResponse response) throws ServletException,
                                                            IOException {
        response.setContentType(CONTENT_TYPE);
        PrintWriter out = response.getWriter();
        name = request.getParameter("user_name");
        pass = request.getParameter("user_password");
        boolean result = verifyPassword(name, pass);
        out.println("<html>");
        out.println("<head><title>LoginServlet</title></head>");
        out.println("<body>");
        if (result == true){
        out.println ("Hello " + name + ": Your login module is working great!");
        else{
        out.println ("Invalid user name or password");
        out.println ("</body></html>");
        out.close();
        // out.println("<p>The servlet has received a POST. This is the reply.</p>");
        //out.println("</body></html>");
        //out.close();
    public void configureConnection() throws SQLException {
    try{
    Class.forName("oracle.jdbc.OracleDriver");
    con = DriverManager.getConnection(DB_URL, DB_USERNAME,DB_PASSWORD);
    con.setAutoCommit(true);
    catch (Exception e){
    System.out.println("Connection failed: " +e.toString());
    public Connection getConnection() throws SQLException
    configureConnection();
    return con;
    protected boolean verifyPassword(String theuser, String password) {
    String originalPassword = null;
    try {
    con = getConnection();
    Statement stmt = con.createStatement();
    stmt.executeQuery("select password from login where uname='"+theuser+"'");
    ResultSet rs = stmt.getResultSet();
    if(rs.next())
    //>>
    originalPassword = rs.getString(1);
    stmt.close();
    if(originalPassword.equals(password)) {
    return true;
    else {
    return false;
    catch (Exception e){
    System.out.println("Exception in verifyPassword()="+e.toString());
    return false;
}and created an HTML form to target this servlet
<form action="/loginservlet" method="post">,
when I enter the the credintials I get this output in the webpage :
Error 404--Not Found
From RFC 2068 Hypertext Transfer Protocol -- HTTP/1.1:
10.4.5 404 Not Found
The server has not found anything matching the Request-URI. No indication is given of whether the condition is temporary or permanent.
If the server does not wish to make this information available to the client, the status code 403 (Forbidden) can be used instead. The 410 (Gone) status code SHOULD be used if the server knows, through some internally configurable mechanism, that an old resource is permanently unavailable and has no forwarding address.

Thanks , yes it is added to the web.xml
<?xml version = '1.0' encoding = 'windows-1252'?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5" xmlns="http://java.sun.com/xml/ns/javaee">
    <description>Empty web.xml file for Web Application</description>
    <servlet>
        <servlet-name>LoginServlet</servlet-name>
        <servlet-class>oracle.servlets.LoginServlet</servlet-class>
    </servlet>
    <servlet-mapping>
        <servlet-name>LoginServlet</servlet-name>
        <url-pattern>/loginservlet</url-pattern>
    </servlet-mapping>
    <session-config>
        <session-timeout>35</session-timeout>
    </session-config>
    <mime-mapping>
        <extension>html</extension>
        <mime-type>text/html</mime-type>
    </mime-mapping>
    <mime-mapping>
        <extension>txt</extension>
        <mime-type>text/plain</mime-type>
    </mime-mapping>
</web-app>Anymore suggestions?

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Singapore (65) 6226 5886 | Malaysia (60) 3 7948 2000 | Thailand (66) 2 298 4800
Philippines (63) 2 659 1722 | Vietnam (84) 8 3911 3150 | Indonesia (62) 21 2924 1911

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1. If the drive really is Mac-formatted it should just appear. Firstly check that hard disks are set to appear on the desktop. In the Finder go to Finder > Preferences... >General tab and ensure that the box to show hard disks on the desktop is checked. If that doesn't work go to Macintosh HD > Applications > Utilities >Disk Utility. Select the drive in the left hand pane and then click on the "Erase" tab. Erase the disk and ensure the format is "Mac OS Extended (with Journalling)".
2. Partitioning is splitting the physically drive into two or more volumes. This will allow you to compartmentalise your data. You will have two or more icons appear on the desktop if you do partition. Although they are on the same physical disk you will be limited on each of the volumes to the size you set at the time of partitioning. If you do partition the drive be sure to use the "Apple Partition Map" not "GUID Partition Map". The latter is for Intel Macs.
3. Whatever you want. My experience is that too many partitions and you loose flexibility in your storage space. Personally on my external drive I have a partition that is exactly the same size as my internal hard drive. I then use that to do a regular clone backup. I then have a second partition for general use. This means I can put files on the external but still guarantee I have enough spare to backup fully.
4. No. Not without third party tools.
5. As I said above, in my opinion the best use is to create a partition for backup and a partition for all other use.
6. Yes absolutely. However if you plan on moving libraries like iTunes or iPhoto then you'll need to show the applications where the libraries are again.
7. Yes.
Some extra pointers:
A. Use Carbon Copy Cloner to backup your internal drive to the external. Clones are fantastic backups as even if the internal drive bursts into flames you will have an identical copy of all user data and settings: http://www.bombich.com/software/ccc.html (scroll to the very bottom for the version suitable for 10.2.8).
B. Don't use USB to connect the hard drive it's not very fast. Firewire 400 is significantly faster and will allow the iMac to be booted from the external drive in an emergency (USB will not boot a G4 Mac).
Hope that helps a little.
mrtotes

Question about implementing a clock using a Timer object

Hello all, I'm not sure if this is the correct forum to post this question but I think so, as it regards a Swing component. I want to add a timer (a clock that starts at 0:00 and keeps track of how long the app is running) to a frame. I am just curious if using a Timer is the proper way to keep track of time, and just repaint() the clock object every second? (or more frequently if desired)... or is there a better way to do this? Thanks in advance for any comments/feedback/help!
Brian

Hello,
Timer is not accurate. You can use Timer to display your component repeteadly, and System.currentTimeMillis() at each call to deduce the elapsed time.

Question about running RMIDemo

Hello everyone.
I tried running the RMIDemo by converting my own CAP files and generating the script files for loading into the script.
My question is, must the Generated RMI STUB which i generate using rmic command be converted together with the CAP files?
The problem now is that when i run the RMIDemo in the CREF simulator, it gives me a
java.rmi.RemoteException: Applet selection failed sw = 6d00.
It works fine in the JCWDE simulator though.
Does the problem lie in the rmi stub file or something else?
Can someone help me pls? been stuck at this for hours.... thanks in advance.

The RMI STUB file must NOT converted! There are only for the client application.
That means that the stub file must be visible to the client application.
In addition i think that you are not able to convert stub files
Now for the applet selection, I can't understand why you have that response, but I will try to guess:
After the conversion, you must add before RMIDemo.scr the Header.scr
and after the Footer.scr.
You will find them into JC_HOME\samples\src\demo\misc, try to make them txt to view the content.
ALSO you must add a line between RMIDemo.scr and Footer.scr, to create the applet like:
// create RMIDemo
0x80 0xB8 0x00 0x00 0x0c 0x0a 0xa0 0x00 0x00 0x00 0x62 0x03 0x01 0xc 0x5 0x01
The general patern is:
0x80 0xB8 0x00 0x00 0x0c (AID Bytes) 0x00 0x7F; (If i remember well)
try it and tell me if you need more help.
Friendly, Bill ;)

Question about Run-Time Shortcut Menus example

I am looking at the Run-Time Shortcut Menus.vi that ships with LabVIEW2011. There is an event case "Test List":Mouse Down that does nothing but generate a Val(Sgnl) event for the "Test List" control if the right mouse button was pressed. There is no value change event for that control.
Is there an obscure reason to do that? One thing I have learned about many of the examples is not to strictly use them as examples.
=====================
LabVIEW 2012
Solved!
Go to Solution.

Nevermind - I found the obscure reason. Even though there is not a value change event, generating the value change event is required to change the value on right-click.
At least NI could have documented this in the example
=====================
LabVIEW 2012

Basic PL/SQL Question about running context

We are trying to create some generalized tools with PL/SQL procedures that would be used by a number of different Oracle Users/Schema. The idea was to store them in an administrative schema (call it ADMIN), create public synonyms for them, and grant execute to public. Then we could run them from the user schema (call it USER) to do the work.
It was my assumption, that while the procedures were stored in ADMIN, when they were run by USER they would run in the USER context. EG, a table (call it MYTABLE) that was referenced in the procedure without a schema reference (SELECT * FROM MYTABLE) would expect to find MYTABLE in the context of the schema which called the procedure. In other words, call the procedure from USER, I expected the procedure to look for MYTABLE in USER. However, we are getting errors that indicate that even though the procedure is called from USER, it is looking for the table in ADMIN (the procedures creation context), no in USER (the running context).
QUESTIONS: How is PL/SQL supposed to operate in this situation? Are there any options/parameters that can be set so the procedure will use the runtime context for table lookup, or do we have to write dynamic SQL which will fully qualify the table with the owner schema?
Thanks for your help
John Conroy

Hy,
from the manual:
The AUTHID clause is allowed only in the header of a stand-alone subprogram, a
package spec, or an object type spec. The header syntax is
-- stand-alone function
CREATE [OR REPLACE] FUNCTION [schema_name.]function_name
[(parameter_list)] RETURN datatype
[AUTHID {CURRENT_USER | DEFINER}] {IS | AS}
-- stand-alone procedure
CREATE [OR REPLACE] PROCEDURE [schema_name.]procedure_name
[(parameter_list)]
[AUTHID {CURRENT_USER | DEFINER}] {IS | AS}
-- package spec
CREATE [OR REPLACE] PACKAGE [schema_name.]package_name
[AUTHID {CURRENT_USER | DEFINER}] {IS | AS}
-- object type spec
CREATE [OR REPLACE] TYPE [schema_name.]object_type_name
[AUTHID {CURRENT_USER | DEFINER}] {IS | AS} OBJECT
where DEFINER is the default option. In a package or object type, the AUTHID
clause applies to all routines.
Note: Most supplied PL/SQL packages (such as DBMS_LOB, DBMS_PIPE, DBMS_
ROWID, DBMS_SQL, and UTL_REF) are invoker-rights packages.

When i use HTML forms in firefox 6, they dont work, but do in IE and safari and firefox 3.6

i have the following code in a php script, but in firefox 6 it fails, but works in firefox 3.6, safari, IE .......
<pre><nowiki>
echo ' <FORM method="post" action="FindPerGetNo.php">';
echo ' <tr>';
echo ' <SELECT name="SelectionString">';
echo '<OPTION selected value="12">12</option>';
while($row = mysql_fetch_array($query))
echo '<OPTION value=" -'.$row['sTableID'].'-">'.$row['sTableName'].'</OPTION>';
echo ' </SELECT> '; }
echo ' </tr>';
echo ' <tr> ';
echo ' <p align="left">';
echo ' <td colspan="2"><div align="left"><input type="submit" value="Submit"></div></td>';
echo ' </tr> ';
echo ' </FORM>';
</nowiki></pre><br />
<br />
the called script has no value for SelectionString in firefox 6, but it does in the other browsers i mentioned

A good place to ask questions and advice about web development is at the mozillaZine Web Development/Standards Evangelism forum.<br />
The helpers at that forum are more knowledgeable about web development issues.<br />
You need to register at the mozillaZine forum site in order to post at that forum.<br />
See http://forums.mozillazine.org/viewforum.php?f=25

Question about running a servelt using HTML form.

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