Random number between a range
hi all!
how can i find random number between an specified range
for example b/w 5-10
thanks to all
smh
Here's a practical instance;-import java.util.Random; // Maybe you forgot this
public class ImplementRandom {
public void getRandom(int from, int range) {
int newRandom;
Random random = new Random();
newRandom = from + random.nextInt(range);
System.out.print(newRandom);
public static void main(String[] args) {
ImplementRandom IC = new ImplementRandom();
IC.getRandom(1, 100);
}Actually that uses public void rather than public int as you cannot reference a non-static (return-type) method from a static context.
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How to get a random number in a range?
as title
how to get a random number in a range?
like 2000~3000 thks :)int between 10 and 20 with the method Math.random():
public class Rnd
// Test
public static void main(String[] args)
int start=10, end = 30;
for (int i = 0; i < 10; i++)
int n = (int)(start + Math.random() * (end-start));
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how can I get random number between 1 and int number
like between 1 and 10 etc.
10xUse the nextFloat() method of the Random class, this returns a random number between 0.0 and 1.0. To get and integer range from that multiply the return value of that method call by the integer range you need (in this case 10), and add the starting number you want returned in the range (1 in this case). The code below works for numbers 1-10.
Random r = new Random();
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Random Number between 10 and 30
I'm just curious how to generate a random number between 10 and 30. I know I use the Math.Random function, but I'm not certain how to do it when the starting number is >1 (i.e. 1 to 30). Thanks.
Random Number in an Interval:
((int) (randomGeneratedNumber * difference)) + startIndex + 1
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Example:
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Are their any classes which can produce a random number within a set of numbers i specify?
If their are no predefined java classes then it doesnt matter.
ThanksNo as far as I know, but its easy to create one:
double low_Limit, super_Limit;
double interval = super_Limit - low_Limit;
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double random_number = Math.random();
//Now we generate a random numbre between 0 and intervalo:
random_number = random_number * intervalo;
// now we generate a random number between low_Limit super_Limit:
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//done :)
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Build a VI that generates a random number between 1 and 80
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If the inputted number is zero, the VI program should turn on a LED in the front-panel to indicate a divide by zero error.
Solved!
Go to Solution.One quick question Edward, was the answer just in time for your monday morning class.
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VirumRandom rnd = new Random();
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Need an easy way to generate a random "number" from an ABAP program... that is a combination of numbers and alphabetic characters.
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I wrote a little method to generate a random number between 1 and 100 (can be modified to allow bigger range of numbers). The code is below... It basically gets a timestamp into a field of type timestampl (note the letter L at the end of the type). The method signature consists of a single returning parameter called RANDOM_NUMBER (type I). After much testing, the random sequence of numbers is extremely varied (even without a seed).
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Cheers,
James G.
METHOD GENERATE_RANDOM_NUMBER .
DATA:
delay_cnt TYPE i,
lc_ran_seed TYPE p,
lc_time TYPE timestampl,
ran_num TYPE p DECIMALS 7.
* Get the long time stamp (nano second level)
GET TIME STAMP FIELD lc_time.
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* (e.g. if called in a do loop to generate many random numbers)
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* shift it to the left 2 decimal places, and add 1 to the result.
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RECEIVING
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