Random number game

Question

I am writing a random numbre game which produces 6 random numbers which all must be different and within a certain range. Currently all I can get output is 6 numbers where I have duplicates e.g.
6
6
6
36
45
32
How do I make the 6 numbers different ?
Here's a small sample of the code to give you the basic idea:
import java.util.*;
public class Random
private String rNumber;
     public Random()
     String[] numlist = new String[2];
numlist[0] = "1";
numlist[1] = "2";
Random rand = new Random();
     int x = (int) (0 + (Math.abs(rand.nextInt()) % 1 )) ;
     rNumber = number[x];
     public String getrNumber()
     return rNumber;
public static void main(String args[])
     for (int i=0; i<6; i++){
     String rn;
     Random num = new Random();
rn = num.getrNumber();
System.out.println(rn);
}

Answer 1

Use a simple if statement that calls a method that will return a boolean value based on the random number generated(and now in english).
(1)Generate your number.
(2)Use the number as a parameter to a method.(This method checks to see if the number is already in the data structure(array,stack, whatever).
/** Checks if the given number is already contained in the given array **/
public boolean isDuplicate(int num,int[] array) {
// I have passed an array just to make it clearer.
for(int i=0;i<array.length;i++) {
if(array[i] == num) return true;
return false; // if the number is not a duplicate we know it is okay to put in our array.
// remember to keep some kind of reference to the array position.
(3) Now we just put this in the next number position in our array.
Hope this helps, by the way you wouldn't be trying to generate some numbers for a Lottery would you?(I remember when I tried that and guess what-yeah still broke)
Also call it something like RNGenerator not Random as this is already a Java class and it becomes a nightmare.