Random selection of materials
Hi Experts,
In a selection Screen i have material in select-options and a Parameter item count, now i have to select N materials randomly from the material range choosen in the selection screen and N is the number in the iten count field.
please tell me how to choose N numbers randomly, we can select upto n numbers from a table but how to select N random materials. the query written for N materials is
SELECT matnr lgort lvorm INTO CORRESPONDING FIELDS OF TABLE it_mard
FROM mard UP TO p_count rows
WHERE matnr IN p_matnr
AND werks IN p_plant
AND lvorm EQ ' '.
please send me if u have any sample code regarding that. or let me know what to write for random selection
Regards,
Nikhil
DO n TIMES.
CALL FUNCTION 'QF05_RANDOM_INTEGER'
(check its parameters by yourself).
READ TABLE it_tab INDEX random_number.
do_something with it.
ENDDO.
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Ware house Management - Bin selection by materials is random
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If you're trying to decide between using POP and IMAP, we encourage you to use IMAP.
Unlike POP, IMAP offers two-way communication between your web Gmail and your email client. This means when you log in to Gmail using a web browser, actions you perform on email clients and mobile devices (ex: putting mail in a 'work' folder) will instantly and automatically appear in Gmail (ex: it will already have a 'work' label on that email the next time you sign in).
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That is from the page that you linked- does highlighted part of message ring a bell? -
I’m setting up a multiple-choice question, and I want to re-arrange the position of the button sprites representing the correct answer and distractors.
I can randomly select one of the sprites via gDistractorLoc = random(4). The random function fails me after that.
Is there a means of randomly selecting one of the entries from a list, e.g. gDistractorList = [1, 2, 4] or [1, 4]?
I realize that I am perhaps complicating the process, and I'd be grateful for a simpler approach.I don't know if this is simpler or not, but here is a method for grabbing a random item from a list:
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How to efficiently get hold of N randomly selected keys out of X?
I am writing some benchmark programs for Coherence caches and would need a way to as efficently as possible get hold of a "fairly random" selection of N keys from the cache out of the total X keys (where X >> N).
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First i tried picking the first N keys obtained when iterating the key-set but they all seemed to come from just a few partitions (perhaps iteration is performed partition by partition?). Next I tried some algortihms I have used in the past to pick random keys from in memory-map (where one basically iterate and if a randomly generated value between 0.0 and 1.0 exceed a percentage calculatwed as the factor N/X the key is included. This does work (one may occasionally need to iterate the map more than once) but is VERY slow since iterating the key-set of a large cache remotly is kind of expensive.
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Edited by: MagnusE on Aug 7, 2009 10:21 AMHi Magnus,
you can go the other way round:
With key-association you can ensure that your request goes to the partition you want it to go. You just need to generate a reverse mapping array between partition ids and integer associated key values which are mapped to that partititon.
You can use this method for it:
public static int[] generateReverseAssociatedKeysForService(DistributedCacheService service) {
KeyPartitioningStrategy keyPartitioningStrategy = service.getKeyPartitioningStrategy();
int partitionCount = service.getPartitionCount();
int[] reverseKeys = new int[partitionCount];
int i=1;
while (partitionCount > 0) {
Integer associatedKey = new Integer(i);
int partitionId = keyPartitioningStrategy.getKeyPartition(associatedKey);
if (reverseKeys[partitionId] == 0) {
reverseKeys[partitionId] = i;
--partitionCount;
++i;
return reverseKeys;
}After this, you generate an equal amount of entries for each partitions with composite keys which implement key association in a way that it returns an integer which maps to your designated partition id to serve as your data. Alternatively you can sort an existing key-set into per-partition keysets.
After this, you just generate evenly spread random numbers between 0 and (partitionCount - 1) (both inclusive) which random number you use as an index to the reverse map to get an associated key value. Then you can generate another random number if you have multiple keys within a partition, or choose a key from the per-partition keyset for that partition if you have a set of existing keys.
This way you get keys which are as evenly spread between partitions as your random generator generating your associated key indexes is spread.
Best regards,
Robert
Edited by: robvarga on Aug 7, 2009 11:55 AM
Added some more ideas and method implementation. -
Oracle 11g:Query to return only 1 to 1 relationship & random selection
Hi
I have a complex query to modify but I have below the sample tables and data with only very few fields(only affected fields).
Query based on 2 tables b_test and s_test.
Pls see below.
create table b_test(building_id number not null,invalid varchar2(1));
create table s_test(sub_building_id number not null,building_id number ,invalid varchar2(1),sequence_no number);
insert into b_test values (1000,'N');
insert into b_test values(2000,'N');
insert into b_test values(3000,'N');
commit;
insert into s_test values(1,1000,'N',90);
insert into s_test values(2,1000,'N',91);
insert into s_test values(3,1000,'N',92);
insert into s_test values(4,1000,'Y',93);
insert into s_test values(5,NULL,'N',NULL);
insert into s_test values(1,2000,'N',94);
insert into s_test values(2,2000,'N',95);
insert into s_test values(3,2000,'N',96);
insert into s_test values(4,2000,'N',97);
insert into s_test values(5,2000,'N',98);
insert into s_test values(6,NULL,'N',NULL);
insert into s_test values(10,3000,'N',99);
insert into s_test values(11,3000,'N',100);
commit;The query below returns all rows required:(also see results:)
select b.building_id,b.invalid,s.sub_building_id,s.sequence_no from b_test b,
(select * from s_test where invalid='N') s
where b.building_id = s.building_id(+)
and b.invalid='N'
Results:
BUILDING_ID INVALID SUB_BUILDING_ID SEQUENCE_NO
1000 N 1 90
1000 N 2 91
1000 N 3 92
2000 N 1 94
2000 N 2 95
2000 N 3 96
2000 N 4 97
2000 N 5 98
3000 N 10 99
3000 N 11 100Now there are 2 requirements:
1)How can the above query be changed so that 1:1 relationship if sub_building_id is returned?i.e For 1 building_id, only show 1 sub_building(This could be a random selection)
(Pls help with query)
The results would be like
BUILDING_ID INVALID SUB_BUILDING_ID SEQUENCE_NO
1000 N 1 90
2000 N 1 94
3000 N 11 1002)How can the same SEQUENCE_NO be shown for all sub_buildings for the same building? (Pls help with query)
The results will be:
BUILDING_ID INVALID SUB_BUILDING_ID SEQUENCE_NO
1000 N 1 90
1000 N 2 90
1000 N 3 90
2000 N 1 94
2000 N 2 94
2000 N 3 94
2000 N 4 94
2000 N 5 94
3000 N 10 99
3000 N 11 99Many thanks!
Edited by: Krithi on 08-Nov-2012 08:48
Edited by: Krithi on 08-Nov-2012 08:55Krithi wrote:
Hi
I have a complex query to modify but I have below the sample tables and data with only very few fields(only affected fields).
Query based on 2 tables b_test and s_test.
Pls see below.
create table b_test(building_id number not null,invalid varchar2(1));
Thanks for posting the CREATE TABLE and INSERT statements, and your existing query; that's very helpful.
The query below returns all rows required:(also see results:)
select b.building_id,b.invalid,s.sub_building_id,s.sequence_no from b_test b,
(select * from s_test where invalid='N') s
where b.building_id = s.building_id(+)
and b.invalid='N'
Results:
BUILDING_ID INVALID SUB_BUILDING_ID SEQUENCE_NO
1000 N 1 90
1000 N 2 91
1000 N 3 92
2000 N 1 94
2000 N 2 95
2000 N 3 96
2000 N 4 97
2000 N 5 98
3000 N 10 99
3000 N 11 100
When I run your query, I get NULL for sequence_no on the last 2 rows, where building_id=3000. The numbers 99 and 100 don't seem to occur in either table. Did you post the worng sample data and/or results?
>
Now there are 2 requirements:
1)How can the above query be changed so that 1:1 relationship if sub_building_id is returned?i.e For 1 building_id, only show 1 sub_building(This could be a random selection)
(Pls help with query) Here's one way:
WITH got_r_num AS
SELECT sub_building_id
, building_id
, sequence_no
, ROW_NUMBER () OVER ( PARTITION BY building_id
ORDER BY sequence_no
) AS r_num
FROM s_test
WHERE invalid = 'N'
SELECT b.building_id
, b.invalid
, r.sub_building_id
, r.sequence_no
FROM b_test b
LEFT OUTER JOIN got_r_num r ON r.building_id = b.building_id
WHERE NVL ( r.r_num
, 1
) = 1
ORDER BY b.building_id
;This is called a Top-N Query , because we're picking N items (N = 1 in this case) from the top of an ordered list. What makes one item the "top", and another one "lower"? That's determined by the analytic ORDER BY clause, in this case
ORDER BY sequence_noThat means the row with the lowest sequence_no (for each building_id) will get r_num=1. If you want a random row from that building_id to be chosen as #1, then you can change the analytic ORDER BY clause to
ORDER BY dbms_random.valueYou can ORDER BY anything you like, even a constant, but you must have an analytic ORDER BY clause. ROW_NUMBER requires an analytic ORDER BY clause.
The results would be like
BUILDING_ID INVALID SUB_BUILDING_ID SEQUENCE_NO
1000 N 1 90
2000 N 1 94
3000 N 11 100
Again, I don't see where the 100 comes from. The results I get are:
BUILDING_ID I SUB_BUILDING_ID SEQUENCE_NO
1000 N 1 90
2000 N 1 94
3000 N 11
2)How can the same SEQUENCE_NO be shown for all sub_buildings for the same building? (Pls help with query)
SELECT b.building_id
, b.invalid
, s.sub_building_id
, MIN (s.sequence_no) OVER ( PARTITION BY s.building_id)
AS seq_no
FROM b_test b
LEFT OUTER JOIN s_test s ON s.building_id = b.building_id
AND s.invalid = 'N'
The results will be:
BUILDING_ID INVALID SUB_BUILDING_ID SEQUENCE_NO
1000 N 1 90
1000 N 2 90
1000 N 3 90
2000 N 1 94
2000 N 2 94
2000 N 3 94
2000 N 4 94
2000 N 5 94
3000 N 10 99
3000 N 11 99
Again, I don't see where you get sequence_no = 99. The results I get are:
BUILDING_ID I SUB_BUILDING_ID SEQ_NO
1000 N 1 90
1000 N 2 90
1000 N 3 90
2000 N 1 94
2000 N 2 94
2000 N 5 94
2000 N 3 94
2000 N 4 94
3000 N 10
3000 N 11Edited by: Frank Kulash on Nov 8, 2012 12:12 PM
Added explanation and results
Edited by: Frank Kulash on Nov 8, 2012 12:28 PM
It looks like you cahnged your sample data from
insert into s_test values(10,3000,'N',NULL);
insert into s_test values(11,3000,'N',NULL);to
insert into s_test values(10,3000,'N',99);
insert into s_test values(11,3000,'N',100);The queries I posted are niow getting 99, like you requested. -
Can a script randomly select an action within a specific set for use on multiple images?
Hi there.
I have a folder of 200+ similar images (taken in a photobooth).
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If the images were sequecnially applied to action 1 then 2 then 3 and so on (repeating when back to 8) this would also be suitable.
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Many thanks.
Wil StevensSomething like this?
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function SaveAsJPEG( inFileName, inQuality, inEmbedICC ) {
var jpegOptions = new JPEGSaveOptions();
jpegOptions.quality = inQuality;
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app.activeDocument.saveAs( File( inFileName ), jpegOptions ); -
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Because the random selection only ever happens ONCE making it utterly useless.
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Also: this forum remains very broken (it is impossible to login using another Apple ID once logged into another ID) and the Bold, Italic and Underline buttons don't work (I'm using Camino Version 1.6b3pre (1.8.1.12pre 2008012000) ).Yeah, I've been to Doug's scripts before - great site.
As for just hitting the spacebar - no help when I want a falling asleep playlist. I don't want to wake up hours later to discover iTunes still playing in the middle of the night. Thanks anyway
You know - I do not properly comprehend the thinking behind having random selection mean random ONCE, then the same FOREVER -
ITunes has deleted random selection of library and refuses to import
A week after installing iTunes 9.1, it has deleted a large random proportion of my tirelessly preened library. Upon attempting to re-import my files, iTunes runs a loading bar as if it's accepting them, but imports only some randomly selected, if any.
Has anybody else encountered this problem upon installing iTunes 9.1?
I'm considering reinstalling an older version and importing my last saved library?
Any help would be o so very appreciated and rewarded handsomely
Thanks,
Diazcheck if you have read & write permissions for your iTunes music folder. in finder, right-click on it and +get info+. unlock the little padlock (you may have to enter your admin password) and change the permission settings. next, click on the little gear-shaped icon and +apply to enclosed items+ like so
you may also give everyone read & write access. if this doesn't help, try the same on your iTunes folder (not just the iTunes music folder).
any help ?
if not, try reinstalling iTunes the proper way. click here and follow the instructions.
if you want to install a previous version after all, here are the steps:
to downgrade to a previous iTunes version, you could try this user tip that seemed to have worked for some:
+1) Quit iTunes.+
+2) Delete iTunes from your Applications folder.+
+3) Go to your ~/Music/iTunes folder. Delete or rename the "iTunes Library" file.+
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+6) click here to download iTunes 8.2.1. The page says it's for G3, but the Read Me file says it'll run on G4, G5, and Intel too. Open the disk image and run the installer.+
+You should now be able to run iTunes 8.2.1 again.+
+And your iTunes will restore to before you upgraded and you won't lose anything+.
JGG
edited by the Jolly Green Giant (where Green stands for environmentally friendly) -
How to random select photos in slideshow mode with iPhoto 7 ?
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GaryYou need software for it. Do you have iPhoto installed? That is one possibility, but there are many others - you create the slideshow from your photos. Or, you can simply use Quicklook - see here:
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I have a query or SQL I am writing where I need to select records in this fashion.
At most 2 records for each username, and those 2 records should be random.
there are many fields that I am bringing in via my SQL; but the username there are typically around 20 unique usernames.
The data itself without a random statement added to it returns approximately 2000 records.
If someone could assist me in the syntax of the portion of the SQL that could attain the results I am looking for, I would appreciate it.
I've never delved into a Random selection method before.
Someone mentioned to me that I could use a rank() statement; but I have no clue how to use that.
then someone else mentioned to use dbms_random.value which is another one I don't know how to use.
Please let me know if you have any ideas that could assist me.
Thank youmy query just needs a slight modification:
SQL> select deptno, ename
from (select deptno, ename, row_number () over (partition by deptno order by dbms_random.value) rn
from emp)
where rn <= 2
DEPTNO ENAME
10 CLARK
10 KING
20 JONES
20 ADAMS
30 MARTIN
30 JAMES
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Digital clock which randomly selects different colors from Applet
Hi,
I relatively new to java, what I'm trying to do is list about five colours in my Applet and pass the colours into my java code, and maybe the font.....
I want to be able to Display a digital clock which randomly selects different colours which were passed from my Applet
Thanks for any help
Zip
Clock Code:
import java.awt.*;
import java.applet.*;
import java.util.*;
import java.text.*;
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Thread animThread = null;
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public void run(){
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catch(InterruptedException e){};
repaint();
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Random select using multiple tables
Hello World!!!
I'm trying to fix a form I modified last month and it's causing me fits!
I need to add another validation element (email address) to my password validation Form. The problem lies in the fact that I can't simply add an additional SELECT Statement to the query because it won't randomly select the same number that the first one did (records won't match). When I try to JOIN on the tables inside the inner SELECT, basically the same thing happens. I get an a result for the "e-mail" column but it doesn't match the same record as the first two.
Is there an easier way of doing this??? Here's the code I'm using that works for my first two column returns (from the agent_sec_questions Table). I'm trying to add one more column (email) from the agent_data Table.
Thanks in advance for any suggestions.
SELECT security_question, question_number
FROM (SELECT security_question, question_number
FROM agent_sec_questions
WHERE agent_id =
(SELECT agent_id
FROM agent_data
WHERE username = 'john doe')
ORDER BY DBMS_RANDOM.VALUE (1, 9))
WHERE ROWNUM = 1;Here's the solution I came up with if interested. I got the random number first, then joined my tables. If you have a better one, please let me know...
Chow!
M
SELECT DBMS_RANDOM.VALUE(1,3) INTO Sel_Num FROM DUAL;
MESSAGE ('Sel_Num= '||Sel_Num||' ID= '||UPPER(:LOGON_BLOCK.USERID));
pause;
SELECT b.email, a.security_question, a.question_number
INTO L_email, L_sec_q, L_q_num
FROM lookup.agent_sec_questions a, lookup.agent_data b
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How to randomly select links in e-tester and how to get VU# in e-load
1. How to randomly select one from links in a webpage in e-tester?
For example: there is a root-page. On it, there are about 2000 links to its subpages. They all have the following pattern:
<pre>
multiline<TD width="50%"><NOBR>
<img src="/images/tfold.gif" border="0" alt="GXC_.+?" align="texttop">
{a href="(.+?)"}<font class="titleorimageid1siteid0">GXC_.+?</font>{a} </NOBR>
</TD>
</pre>
So how can randomly select one link and then navigate to it?
2.how to get VU# in e-load?
For example: we launch 4000 VU to load-stress our server. But we want to use different user names to login for different VU#. such as VU#1's username is ADF1, VU#2's username is ADF2, VU#100's username is ADF100 and so on. How can we implement the feature?
Thanks a lot.
Edited by: user783927 on Dec 1, 2008 5:57 AM
Edited by: user783927 on Dec 1, 2008 5:59 AMThanks a lot for VU#. Also i got an idea about how to randomly select a link:
Private Sub RSWVBAPage_afterPlay()
Dim objReg As New RegExp
Dim objMatchCol As MatchCollection
Dim objMatch As Match
Dim objSubMatch As SubMatches
Dim doc As String
Dim str As String
Dim rNumb As Integer
RSWApp.GetHtml doc
With objReg
.Global = True
.IgnoreCase = True
'the kind of urls have the following special pattern
.Pattern = "pageid=34,([\d]{5})"
End With
Set objMatchCol = objReg.execute(doc)
Randomize
rNumb = objMatchCol.Count * Rnd
If objMatchCol.Count >= 1 Then
If rNumb = objMatchCol.Count Then
rNumb = objMatchCol.Count - 1
End If
End If
Set objMatch = objMatchCol.Item(rNumb)
Set objSubMatch = objMatch.SubMatches
str = objSubMatch.Item(0)
Call RSWApp.setCustomVariable("var_url", str)
RSWApp.WriteToLog str
Set objMatchCol = Nothing
Set objMatch = Nothing
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