RANDOM SEQUENCE
HI,
CAN I GET A RANDOM NUMBER USING A FUNCTION OR CALLING A SELECT...'SOMETHING' ... FROM DUAL ???
THANKS, MARCO.
Here is an example from site http//asktom.oracle.com
Randomly generate and unique is sort of an oxymoron.
What I've done in the past is to combine 3 or so numbers together to achieve this. One that I use alot is:
sequence_name.nextval | | to_char( sysdate, 'DDDSSSSS' )
You can do the same thing with a random number (replace the to_char(sysdate) with a random number of a FIXED length -- eg:
sequence_name.nextval | | to_char( random.rand,'fm00000' )
See
http://osi.oracle.com/~tkyte/Misc/Random.html
for howto generate a random number.
You need to combine a sequence or some other UNIQUE thing with the random number to get uniqueness.
Another option is to use the sys_guid() function available in 8i. For example:
ops$[email protected]> create table t as select sys_guid() u_id from dual;
Table created.
ops$[email protected]> desc t;
Name Null? Type
U_ID RAW(16)
ops$[email protected]> select * from t;
U_ID
722EF40A77F1386AE034080020A767E0
sys_guid() generates a 16byte globally unique key that is non-sequential.
If you need it as a number, it can be converted:
ops$[email protected]> set numformat
999999999999999999999999999999999999999999999999
ops$[email protected]> select to_number(
'722EF40A77F1386AE034080020A767E0',
'xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx' ) from dual;
ops$[email protected]> /
TO_NUMBER('722EF40A77F1386AE034080020A767E0','XXXXXXXXXXXXXX
151775786912318261447473874650479945696
ops$[email protected]> select sys_guid(),
2 to_number(sys_guid(),'xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx' )
from dual;
SYS_GUID()
TO_NUMBER(SYS_GUID(),'XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX')
722EF40A77F2386AE034080020A767E0
151775786912320679299113103908829358048
ops$[email protected]> /
SYS_GUID()
TO_NUMBER(SYS_GUID(),'XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX')
722EF40A77F4386AE034080020A767E0
151775786912323097150752333167178770400
Helena
Similar Messages
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How would i go about creating random sequences of with user supplied number and length, i am stuck as far as i can get is this:
/** creates random sequences */
public void randomSequence(int number, int length)
for(int i = 0; i < number; i++)// number of sequences to be made
for(int j = 0; i < length; j++){ // length of those sequences
if(numSeq >= seqArray.length){
seqArray = doubleArray();
seqArray[i] //here is where i get stuck!!!????
}My personal crusade against really bad "random"
numbers...Even your numbers are still not great ..., and there
is no reason at all to use "SecureRandom" if you don't
really care about the randomness you get. (i.e. it's
not for any statistical, cryptographical purpose ...)
And if you want "really" random numbers, have a look
at
http://www.random.org
http://www.fourmilab.com/hotbits/
and http://www.randomnumbers.info/
and if you feel like it
http://superhappycool.blogspot.com/2004/10/article-real
y-random-numbers.html
:)I know about (and use) a few of those, and others. It's not that util.Random is horrendous, it's just worse than should be acceptable ( http://www.alife.co.uk/nonrandom/ ). Also, you'll note that I said "at the very least use... [SecureRandom]."
~Cheers -
Hello All,
I want some help writing a method which generates a set of 100 numbers with values 0 and 1, but the input should be percent of number of 1's and 0's...I mean if I give 20% for 0's and 80% for 1's then in the generated sequence I should get 20, 0's and 80, 1's...randomly.....hope Iam clear with my question.....please help me
Thanks,
Raghu.Here is a utility you can use.. you just need to make the call to get the proper random number of ones and pass the size you want.. it returns an array of strings of ones and zero's but you can convert it to whatever type you need.
--John Putnam
import java.util.*;
* <p>Title: ShuffleBits</p>
* <p>Description: example of creating a string of 1's and 0's and shuffling them</p>
* <p>Copyright: Copyright (c) 2003</p>
* @author John Putnam
* May be use freely with inclusion of this copyright notice
* @version 1
public class ShuffleBits
* method to create an array of strings of 1's and zeros then shuffle them
* @param numberOfOnes exatly to include (the rest are zero's)
* @param maxNumberOfBits total number of ones and zeros.
* @return randomized list of ones and zeros
public String[] randBits(int numberOfOnes, int maxNumberOfBits)
ArrayList bits = new ArrayList(maxNumberOfBits);
for(int i=0;i<numberOfOnes;i++) bits.add("1");
for(int j=0;j<(maxNumberOfBits-numberOfOnes);j++) bits.add("0");
Collections.shuffle(bits); //--do the shuffling of order
Iterator ib = bits.iterator();
String[] bitsBack = new String[maxNumberOfBits];
//--pull out the shuffled bits
int rb = 0;
while(ib.hasNext()) bitsBack[rb++] = (String)ib.next();
return bitsBack;
} //--end randBits
//--------------------------------unit testing main--------------------------------
public static void main(String[] args)
ShuffleBits test = new ShuffleBits();
int numOnes;
int maxNumber;
String[] bitsBack = null;
numOnes = 5;
maxNumber = 15;
bitsBack = test.randBits(numOnes,maxNumber);
System.out.println("\n--Test for #ones: " + numOnes + " max: " + maxNumber);
for(int i=0;i<maxNumber;i++) System.out.println("--I: " + i + " bit: " + bitsBack);
numOnes = 12;
maxNumber = 15;
bitsBack = test.randBits(numOnes,maxNumber);
System.out.println("\n--Test for #ones: " + numOnes + " max: " + maxNumber);
for(int i=0;i<maxNumber;i++) System.out.println("--I: " + i + " bit: " + bitsBack[i]);
numOnes = 12;
maxNumber = 15;
bitsBack = test.randBits(numOnes,maxNumber);
System.out.println("\n--Test for #ones: " + numOnes + " max: " + maxNumber);
for(int i=0;i<maxNumber;i++) System.out.println("--I: " + i + " bit: " + bitsBack[i]);
numOnes = 12;
maxNumber = 15;
bitsBack = test.randBits(numOnes,maxNumber);
System.out.println("\n--Test for #ones: " + numOnes + " max: " + maxNumber);
for(int i=0;i<maxNumber;i++) System.out.println("--I: " + i + " bit: " + bitsBack[i]);
} //--end main
} //--end shuffle bits
The output was.
--Test for #ones: 5 max: 15
--I: 0 bit: 0
--I: 1 bit: 1
--I: 2 bit: 0
--I: 3 bit: 0
--I: 4 bit: 1
--I: 5 bit: 0
--I: 6 bit: 0
--I: 7 bit: 0
--I: 8 bit: 0
--I: 9 bit: 1
--I: 10 bit: 0
--I: 11 bit: 0
--I: 12 bit: 1
--I: 13 bit: 1
--I: 14 bit: 0
--Test for #ones: 12 max: 15
--I: 0 bit: 1
--I: 1 bit: 1
--I: 2 bit: 0
--I: 3 bit: 0
--I: 4 bit: 1
--I: 5 bit: 1
--I: 6 bit: 0
--I: 7 bit: 1
--I: 8 bit: 1
--I: 9 bit: 1
--I: 10 bit: 1
--I: 11 bit: 1
--I: 12 bit: 1
--I: 13 bit: 1
--I: 14 bit: 1
--Test for #ones: 12 max: 15
--I: 0 bit: 1
--I: 1 bit: 1
--I: 2 bit: 0
--I: 3 bit: 1
--I: 4 bit: 1
--I: 5 bit: 0
--I: 6 bit: 1
--I: 7 bit: 1
--I: 8 bit: 0
--I: 9 bit: 1
--I: 10 bit: 1
--I: 11 bit: 1
--I: 12 bit: 1
--I: 13 bit: 1
--I: 14 bit: 1
--Test for #ones: 12 max: 15
--I: 0 bit: 1
--I: 1 bit: 1
--I: 2 bit: 1
--I: 3 bit: 1
--I: 4 bit: 1
--I: 5 bit: 1
--I: 6 bit: 1
--I: 7 bit: 0
--I: 8 bit: 0
--I: 9 bit: 1
--I: 10 bit: 1
--I: 11 bit: 1
--I: 12 bit: 1
--I: 13 bit: 0
--I: 14 bit: 1
notice the last few are the same sizes but come out in different order.
--John Putnam -
How to generate random sequence numbers
Hello experts
Iu2019m writing a custom program and pulling data from VBAK & VBAP. As per requirement I also need to generate a sequence number randomly and finally store all data in text file and upload at server. The hiccup is I donu2019t know how to generate sequence numbers. Can somebody please show me how I can accomplish it?
Thanks a lot in advanceFind the below code,
data: lv_range type datatype-char0128.
call function 'RANDOM_C'
exporting
len_min = 20
len_max = 20
char_min = 1
char_max = 20
importing
rnd_value = lv_range.
LV_RANGE param will have a random value..
If you need number you can use the FM "RANDOM_I4"
Thanks,
Prathap -
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Hello,
create sequence centers_seq
start with 1234567 increment by 1;
This statement will create and start sequence from 1234567 and will increment by 1 whereas I am trying to generate random 7 digits and of course unique
Thanks in anticipation
Best regardsRaakh wrote:
I want to generate login ID but not in a sequence. The IDs are in 100's not more so I need to auto generate unique random IDs of 7 digitsWell, you can take a semi-random approach:
SQL> create sequence s start with 100 maxvalue 999
2 /
Sequence created.
SQL> select s.nextval * 10000 + trunc(dbms_random.value(1000,9999)) unique_semi_random_7_digit_num from dual
2 /
UNIQUE_SEMI_RANDOM_7_DIGIT_NUM
1007776
SQL> /
UNIQUE_SEMI_RANDOM_7_DIGIT_NUM
1017247
SQL> /
UNIQUE_SEMI_RANDOM_7_DIGIT_NUM
1025913
SQL> /
UNIQUE_SEMI_RANDOM_7_DIGIT_NUM
1033573
SQL> SY. -
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"Hi Sami,
This is Adobe Technical Support.
We are responding in reference to your case# 0185837302 regarding the Adobe Premiere Pro, I researched the issue and found out that the issue is reproducible on our end.
I have reported the issue to the higher level of support team. They will research on this issue and will try roll out a patch update to fix it." -
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When I press comma it types: h + p + l + o + k + left alt + left shift + left control
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Hi Everybody,
HI,
I am facing one issue Can you tell me how i can resolve it. please see the incoming file structure i am getting
010johnnewjersy
02001price
03002989
030039898
020011898
02001101
0309090
010johnks
where 010-keyfield
020-keyfield
030-keyfiled
here rows with 020 030 can repeatand whole set 010,020..unbound,030..unbound . 010 record can repeat once again which will treated as new set
hope you understand. need directions to configure my sender adapter.
Thanks for your time
bye
rajHi,
Pls do Content conversion in adapter as follows.
Module Key Parameter Name Parameter Value
Plain2XML xml.recordsetName MyRecordset
Plain2XML xml.recordsetStructure NameA,1,NameB,,NameC,
Plain2XML xml.keyFieldName MyKey
Plain2XML xml.keyFieldType CaseSensitiveString
Plain2XML xml.NameA.fieldNames MyKey,field-nameA
Plain2XML xml.NameA.fieldFixedLengths ex:2,10
Plain2XML xml.NameA.keyFieldValue 010
Plain2XML xml.NameB.fieldNames MyKey,field-nameB1,field-nameB2
Plain2XML xml.NameB.fieldFixedLengths ex:2,3,3
Plain2XML xml.NameB.keyFieldValue 020
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Plain2XML xml.NameC.fieldFixedLengths ex:2,5
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Please award marks if found useful.
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jsp.getVerticalScrollbar().setValue(0);after inserting and adding all your components. this will set the vertical scrollbar up to the very first line.
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Reading a Random Line from a Text File
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Here is my code, and the text file that the program reads from is called 'wordFile'
import java.awt.*;
import java.awt.geom.*;
import javax.swing.*;
import java.awt.event.*;
import java.io.*;
import java.util.*;
public class WordColor extends JFrame{
public WordColor(){
super("WordColor");
setSize(1000,500);
setVisible(true);
add(new WordPanel());
public static void main(String[]r){
JFrame f = new WordColor();
class WordPanel extends JPanel implements KeyListener{
private Graphics2D pane;
private Image img;
private char[]characterList;
private CharacterPosition[]positions;
private int charcounter = 0;
private String initialWord;
private File wordFile = new File("C:\\Documents and Settings\\My Documents\\Java\\projects\\WordColorWords.txt");
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private javax.swing.Timer timer;
public final static int START = 20;
public final static int delay = 10;
public final static int BOTTOMLINE = 375;
public final static int buffer = 15;
public final static int distance = 4;
public final static Color[] colors = new Color[]{Color.red,Color.blue,Color.green,Color.yellow,Color.cyan,
Color.magenta,Color.orange,Color.pink};
public static String[] words;
public static int descent;
public static int YAXIS = 75;
public static int SIZE = 72;
public WordPanel(){
words = readWords();
setLayout(new BorderLayout());
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characterList = new char[initialWord.length()];
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characterList[i] = initialWord.charAt(i);
setFocusable(true);
addKeyListener(this);
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public void actionPerformed(ActionEvent evt){
YAXIS += 1;
drawWords();
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if (allColorsOn()) win();
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super.paintComponent(g);
if (img == null){
img = createImage(getWidth(),getHeight());
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pane.fillRect(0,0,getWidth(),getHeight());
pane.setFont(new Font("Arial",Font.BOLD,SIZE));
pane.setColor(Color.black);
drawThickLine(pane,getWidth(),5);
fm = g.getFontMetrics(new Font("Arial",Font.BOLD,SIZE));
descent = fm.getDescent();
distributePositions();
drawWords();
timer.start();
g.drawImage(img,0,0,this);
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int xaxis = START;
positions = new CharacterPosition[characterList.length];
int counter = 0;
for (char c: characterList){
CharacterPosition cp = new CharacterPosition(c,xaxis, Color.black);
positions[counter] = cp;
counter++;
xaxis += fm.charWidth(c)+distance;
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pane.setColor(Color.black);
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pane.drawLine(0,j,width,j);
private void drawWords(){
pane.setColor(Color.white);
pane.fillRect(0,0,getWidth(),getHeight());
drawThickLine(pane,getWidth(),5);
for (CharacterPosition cp: positions){
int x = cp.getX();
char print = cp.getChar();
pane.setColor(cp.getColor());
pane.drawString(""+print,x,YAXIS);
repaint();
private boolean allColorsOn(){
for (CharacterPosition cp: positions){
if (cp.getColor() == Color.black) return false;
return true;
private Color randomColor(){
int rand = (int)(Math.random()*colors.length);
return colors[rand];
private void restart(){
charcounter = 0;
for (CharacterPosition cp: positions){
cp.setColor(Color.black);
private void win(){
timer.stop();
newWord();
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repaint();
drawThickLine(pane,getWidth(),5);
YAXIS = 75;
initialWord = getWord();
characterList = new char[initialWord.length()];
for (int i=0; i<initialWord.length();i++){
characterList[i] = initialWord.charAt(i);
distributePositions();
charcounter = 0;
drawWords();
timer.start();
private void lose(){
timer.stop();
pane.setColor(Color.white);
pane.fillRect(0,0,getWidth(),getHeight());
pane.setColor(Color.red);
pane.drawString("Sorry, You Lose!",50,150);
repaint();
removeKeyListener(this);
final JPanel p1 = new JPanel();
JButton again = new JButton("Play Again?");
p1.add(again);
add(p1,"South");
p1.setBackground(Color.white);
validate();
again.addActionListener(new ActionListener(){
public void actionPerformed(ActionEvent evt){
remove(p1);
addKeyListener(WordPanel.this);
newWord();
private String getWord(){
int rand = (int)(Math.random()*words.length);
return words[rand];
private String[] readWords(){
ArrayList<String> arr = new ArrayList<String>();
try{
BufferedReader buff = new BufferedReader(new FileReader(wordFile));
try{
String line = null;
while (( line = buff.readLine()) != null){
line = line.toUpperCase();
arr.add(line);
finally{
buff.close();
catch(Exception e){e.printStackTrace();}
Object[] objects = arr.toArray();
String[] words = new String[objects.length];
int count = 0;
for (Object o: objects){
words[count] = (String)o;
count++;
return words;
public void keyPressed(KeyEvent evt){
char tempchar = evt.getKeyChar();
String character = ""+tempchar;
if (character.equalsIgnoreCase(""+positions[charcounter].getChar())){
positions[charcounter].setColor(randomColor());
charcounter++;
else if (evt.isShiftDown()){
evt.consume();
else{
restart();
drawWords();
public void keyTyped(KeyEvent evt){}
public void keyReleased(KeyEvent evt){}
class CharacterPosition{
private int xaxis;
private char character;
private Color color;
public CharacterPosition(char c, int x, Color col){
xaxis = x;
character = c;
color = col;
public int getX(){
return xaxis;
public char getChar(){
return character;
public Color getColor(){
return color;
public void setColor(Color c){
color = c;
}I thought that maybe serializing the ArrayList might be faster than creating the ArrayList by iterating over each line in the text file. But alas, I was wrong. Here's my code anyway:
class WordList extends ArrayList<String>{
long updated;
WordList readWordList(File file) throws Exception{
WordList list = new WordList();
BufferedReader in = new BufferedReader(new FileReader(file));
String line = null;
while ((line = in.readLine()) != null){
list.add(line);
in.close();
list.updated = file.lastModified();
return list;
WordList wordList;
File datFile = new File("words.dat");
File txtFile = new File("input.txt");
if (datFile.exists()){
ObjectInputStream input = new ObjectInputStream(new FileInputStream(datFile));
wordList = (WordList)input.readObject();
if (wordList.updated < txtFile.lastModified()){
//if the text file has been updated, re-read it
wordList = readWordList(txtFile);
ObjectOutputStream output = new ObjectOutputStream(new FileOutputStream(datFile));
output.writeObject(wordList);
output.close();
} else {
//serialized list does not exist--create it
wordList = readWordList(txtFile);
ObjectOutputStream output = new ObjectOutputStream(new FileOutputStream(datFile));
output.writeObject(wordList);
output.close();
}The text file contained one random sequence of letters per line. For example:
hwnuu
nhpgaucah
zfbylzt
hwnc
gicgwkhStats:
Text file size: 892K
Serialized file size: 1.1MB
Time to read from text file: 795ms
Time to read from serialized file: 1216ms -
A simple question on random number generation?
Hi,
This is a rather simple question and shows my newbieness quite blatantly!
I'm trying to generate a random number in a part of a test I have.
So, I have a little method which looks like this:
public int getRandomNumber(int number){
Random random = new Random(number);
return random.nextInt(number);
}And in my code I do int random = getRandomNumber(blah)...where blah is always the same number.
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hey forum, i wonder if anyone can help me out with a small problem with my university coursework (yep its homework!!!)
heres my problem, i am writing one of them 8 puzzle problems (the one based around sam lloyds 15 puzzler), i can successfully generate one random sequence of numbers with no duplicates, but whenever i call the random method again it keeps producing the same results
heres the code
in my main class file
if(e.getSource() == randomButton) {
new RandomPuzzle();
System.out.println(random.randState);
//startStateString = new RandomPuzzle();
}heres my number generator class file
import java.util.Random;
import java.io.*;
public class RandomPuzzle
/** Base Random number generator */
Random rn = new Random();
/** Puzzle holder */
byte b[];
long number = 0;
String randState = "";
/** Default constructor */
public RandomPuzzle() {
rn.setSeed(number);
b = new byte[9];
randState = randomString();
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int n = hi - lo + 1;
int i = rn.nextInt() % n;
if (i < 0)
i = -i;
return lo + i;
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public int rand( int hi){
int n = hi;
return n;
/** Check for duplicate values within the same configuration */
boolean valueExists( byte value ) {
int i = b.length;
boolean exists = false;
for( int j = 0; j < i; j++ ){
if( b[j] == value )
exists = true;
return exists;
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public String randomString(int lo, int hi) {
int n = rand( 9 );
//boolean valueEntered = false;
for (int i = 0; i < 9; i++) {
boolean valueEntered = false;
byte temp = (byte)rand('0', '8');
while( valueEntered == false ) {
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valueEntered = true;
else
temp = (byte)rand('0', '8');
return new String(b, 0);
/** calls above function */
public String randomString() {
return randomString(0, 8);
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thanx in advance
korbitzthanx for the help paulcw, but when i removed the seed code it done the same
but i added this to my main class and now it works fine
if(e.getSource() == randomButton) {
RandomPuzzle temp = new RandomPuzzle();
System.out.println(temp.randState);
//startStateString = new RandomPuzzle();
}thanx again for your help -
Create Slideshow Display sequence property doesn't work
Create Slideshow Display sequence property doesn't work,
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transType='Random' transTime='1' firstImage='1' dispSequence='1'>
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sHello,
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juno -
How do I rearrange the sequence of pictures within "All Photos" album?
I've just upgraded to Photos. I have 35322 photos and it seems to handle it better than iPhoto.
I'm finding the "All Photos" album is showing out of chronological sequence, with various "moments" photos intersperced into a variety of different "moments".
I can't seem to find a way to rearrange the "All Photos" album to be a true chronological sequence, instead of the random sequence it has become.
What am I missing?at top of listings the should be a heading "Track#" if not go to view, veiw options and tick track number the it will show on main screen click this new heading and the tracks should alter to the correct order. Hope this helps
Windows XP
Windows XP
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