Reading xml in java

please help me
how to read xml file in java
how to parse xml file
thanks

http://java.sun.com/webservices/jaxp/index.jsp

Similar Messages

  • Reading XML using Java

    I want to read all <temp >nodes map them to some variable and create one more XML.
    I am stuck up in the first place itself where i need to read the data :( . I am getting null pointer exception, please find the code also.
    <?xml version="1.0" encoding="UTF-8"?>
    <ftpl id="47" name="XXXXXXXX xxx xxxxxxxx">
    <abc-cab name="Systems" id="43434">
    <abc-dr name="zzzzz" id="4545454">
    <temp key="Type">null</param>
    <temp key="Folder">/ZVZ/XXXXX - xyz</param>
    <temp key="Author">XYZ,ABC</param>
    <temp key="Comments">null</param>
    <temp key="Mailed_By">XYZ,ABC</param>
    <temp key="Subject">null</param>
    <temp key="Key_Words">null</param>
    <abc-page name="1" id="3524012">
    <file text="/asas/asasa/asa/asas/Oxxxxxx2276744.txt" count="1"/>
    </abc-page>
    </abc-dr>
    </abc-cab>
    </ftpl>
    try {
    File file = new File("source-file");
    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
    DocumentBuilder db = dbf.newDocumentBuilder();
    Document doc = db.parse(file);
    doc.getDocumentElement().normalize();
    System.out.println("Root element " + doc.getDocumentElement().getNodeName());
    NodeList nodeLst = doc.getElementsByTagName("abc-dr");
    for (int s = 0; s < nodeLst.getLength(); s++) {
    Node fstNode = nodeLst.item(s);
    if (fstNode.getNodeType() == Node.ELEMENT_NODE) {
    Element fstElmnt = (Element) fstNode;
    NodeList fstNmElmntLst = fstElmnt.getElementsByTagName("abc-dr");
    Element fstNmElmnt = (Element) fstNmElmntLst.item(1);
    NodeList fstNm = fstNmElmnt.getChildNodes();
    System.out.println("First Node : " + ((Node) fstNm.item(1)).getNodeValue());
    NodeList lstNmElmntLst = fstElmnt.getElementsByTagName("Folder");
    Element lstNmElmnt = (Element) lstNmElmntLst.item(0);
    NodeList lstNm = lstNmElmnt.getChildNodes();
    } catch (Exception e) {
    e.printStackTrace();
    Please help.. let me know the code which read XML I have tried with all SAX/DOM i am getting same NUllPointerExcetion
    Message was edited by:
    JavaNewUser

    Hi
    Thanks patricknz
    pls find the XMl and the java code
    I have again modified the code .. but got the same result as below
    [temp: null]----------------------param =
    [temp: null]----------------------param =
    [temp: null]----------------------param =
    [temp: null]----------------------param =
    [temp: null]----------------------param =
    [temp: null]----------------------param =
    [temp: null]----------------------param =
    [abc-page: null]----------------------abc-page=
    import javax.xml.parsers.DocumentBuilder;
    import javax.xml.parsers.DocumentBuilderFactory;
    import org.w3c.dom.Document;
    import org.w3c.dom.Node;
    import org.w3c.dom.NodeList;
    import org.w3c.dom.Element;
    import java.lang.*;
    public class SampleDOM
        public static void main(String s[]){
            try{
                DocumentBuilder docBuilder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
                Document document = docBuilder.parse("C:\\demo.xml");
                   NodeList nodeList = document.getElementsByTagName("abc-dr");
          for (int i = 0, length1 = nodeList.getLength(); i < length1; i++) {
            final Element rDoc = (Element)nodeList.item(i);
            final NodeList rDocC = rDoc.getChildNodes();
            for (int j = 0, length2 = rDocC.getLength(); j < length2; j++) {
              final Node child = rDocC.item(j);
            if (child.getNodeType() == Node.ELEMENT_NODE) {
                Element element = (Element)child;
                System.out.println(element.getChildNodes() + "----------------------" +
                                          new StringBuffer(element.getNodeName()).append(" = "));
            }catch(Exception e){
                e.printStackTrace();
    }XML FIle:-
    <?xml version="1.0" encoding="UTF-8"?>
    <ftpl id="47" name="XXXXXXXX xxx xxxxxxxx">
         <abc-cab name="Systems" id="43434">
              <abc-dr name="zzzzz" id="4545454">
                   <temp key="Type">null</param>
                   <temp key="Folder">/ZVZ/XXXXX - xyz</param>
                   <temp key="Author">XYZ,ABC</param>
                   <temp key="Comments">null</param>
                   <temp key="Mailed_By">XYZ,ABC</param>
                   <temp key="Subject">null</param>
                   <temp key="Key_Words">null</param>
                   <abc-page name="1" id="3524012">
                        <file text="/asas/asasa/asa/asas/Oxxxxxx2276744.txt" count="1"/>
                   </abc-page>
              </abc-dr>
         </abc-cab>
    </ftpl>Message was edited by:
    JavaNewUser
    Message was edited by:
    JavaNewUser

  • READING XML FROM JAVA

    I am developing web services based GIS, I have XML file which was generated from Geoserver. I dont know how to link Java with XML and query XML from Java. I need help pls.
    PAI

    there are apis to parse xml using java,
    http://www.cafeconleche.org/books/xmljava/chapters/ch09s06.html
    try this link..
    regards
    Shanu

  • Reading Xml from Java--urgent

    Hello
    I nead thyis realy very urgen.I have XmlParser and xml.jar.
    I unpacked xml.jar. When I tried to compile xmp\lparser i got 10 errors.
    He can't find packages(w3c,dom).
    What to do?
    If you know adress where i can find api for Xml it would be great help.
    I nead very simlpe thing to read value of 2 nodes whish are always there asme and iI am very new in XML.
    I have to finish my graduation project tonight (i ma writeing jsp aplication).
    thank you a lot for any help.

    Take a look at Xerces at xml.apache.org.
    Alan Yackel

  • Importing XML into Java.  Help needed Please!!!

    Hi,
    I have downloaded j2sdk1.4.1_05 and want to configure it to import XML files into a DOM in Java. I am having trouble doing this and need help. I read that version 1.4 support JAXP 1.1 but I am having trouble finding the JAXP-api.jar file. It says to put all the other Jar files into a folder and leave the JAXP-api.jar.
    Could you please tell me how to set up Java so that I can import an XML file. I also downloaded JAXP 1.2. But there seems to be no installer.
    Thanx John

    You can learn about reading xml in java by reading the J2EE tutorial at
    http://java.sun.com/j2ee/1.4/docs/tutorial/doc/
    Here is sample program to read XML file into a DOM taken from this tutorial
    (http://java.sun.com/j2ee/1.4/docs/tutorial/doc/JAXPXSLT4.html)
    import javax.xml.parsers.DocumentBuilder;
    import javax.xml.parsers.DocumentBuilderFactory;
    import javax.xml.parsers.FactoryConfigurationError;
    import javax.xml.parsers.ParserConfigurationException;
    import org.xml.sax.SAXException;
    import org.xml.sax.SAXParseException;
    import org.w3c.dom.Document;
    import org.w3c.dom.DOMException;
    import java.io.*;
    public class TransformationApp
      static Document document;
      public static void main(String argv[])
        if (argv.length != 1) {
          System.err.println (
            "Usage: java TransformationApp filename");
          System.exit (1);
        DocumentBuilderFactory factory =
          DocumentBuilderFactory.newInstance();
        //factory.setNamespaceAware(true);
        //factory.setValidating(true);
        try {
          File f = new File(argv[0]);
          DocumentBuilder builder =
            factory.newDocumentBuilder();
          document = builder.parse(f);
        } catch (SAXParseException spe) {
          // Error generated by the parser
          System.out.println("\n** Parsing error"
            + ", line " + spe.getLineNumber()
            + ", uri " + spe.getSystemId());
          System.out.println("  " + spe.getMessage() );
          // Use the contained exception, if any
          Exception x = spe;
          if (spe.getException() != null)
            x = spe.getException();
          x.printStackTrace();
        } catch (SAXException sxe) {
          // Error generated by this application
          // (or a parser-initialization error)
          Exception x = sxe;
          if (sxe.getException() != null)
            x = sxe.getException();
          x.printStackTrace();
        } catch (ParserConfigurationException pce) {
          // Parser with specified options can't be built
          pce.printStackTrace();
        } catch (IOException ioe) {
          // I/O error
          ioe.printStackTrace();
      } // main
    } If you have java 1.4 sdk installed everything should compile and run. Separate
    JAXP package is nor required - JAXP is included in rt.jar in java-home-directory/jre/lib.

  • How to read XML Values using JAVA

    Hi FRNDS,
    I uploaded one XML File in imported Archieves, i have to read the value form XML uisng JAVA code,
    using XSL able to read  like  xsl variable name='TimeZone' select =$linkDoc//...........*
    But using java i have to read the value from XML,is it possible to read the value??
    please give me some sample code.
    regards,
    Raja Sekhar

    But using java i have to read the value from XML,is it possible to read the value??
    Check the below JAVA code from help:
    http://help.sap.com/saphelp_nwpi71/helpdata/en/55/7ef3003fc411d6b1f700508b5d5211/content.htm
    you can ignore the XSLT part and configure only the JAVA code...check if this suits your needs.
    Regards,
    Abhishek.

  • Read, Modify and Apply Report XML using Java Script

    Hi Guys,
    Is there any way that we can Pragmatically Read, Modify and Apply Report XML using Java Script or some other way.
    Thanks
    Kaushik
    Edited by: Kaushik K on Jun 20, 2012 8:36 PM

    Requirement ::
    Users should be able to add Column to the Report Dynamically at Runtime.
    (There are around 1000+ Users, Answers Approach is not acceptable)
    So we are planning to provide a Multi Select / Shuttle Box Option for Users to add Columns dynamically. (Only for Table View)
    What we planned to DO ::
    Create a Presentation Variable Prompt, Which reads the Metadata Table (Presentation Table.Column Name, populated using the Metadata Dictionary)
    And Create a report with One Column and the Column Fx like @{var_dynamic_columns}{'"Time"."Year","Time"."Month"'}
    With this, OBIEE is rewriting the Logical SQL Currently as "Select "Time"."Year","Time"."Month" from "A - Sample Sales" "
    But getting an error
    The number of columns returned in retrieving column metadata was invalid (expected: 1; received: 2)
    So we want to see, if we can rewrite the Advanced XML of the Report to have dynamic columns based on the Values from the Presentation Variable.
    Please help me if this is a viable solution or any other better solution.

  • How to read  and write XML in java

    I have a code that reads a large XML file, splits it into smaller files, filters and then writes it into a new XML file. My problem is that I had coded the input file name into the code, so that only the specified file can be read. How can I rewrite my code to be able to take any input xml and perform the same operation? Here's a portion of my code below:
                            File file = new File("c:\\APAdjustmentJVDoc_FINAL.xml");
                        output = new BufferedWriter(new FileWriter(file));
                        for (int i = 1; i < 79; i++) {
                             fIStream = new FileInputStream("c:\\APAdjustmentJVDoc_new" + i + ".xml");
                             loRead = new InputStreamReader(fIStream);
                             doc = XMLUtil.transformToNode(loRead, false);
                             System.out.println("Reading from file " + "c:\\APAdjustmentJVDoc_new" + i + ".xml");
                             writeFile(doc, docIdList, output);
                             fIStream.close();
                             loRead.close();
                        System.out.println("Output file complete");
                   } catch (Exception e) {
                        e.printStackTrace();
                   } finally {
                        if (output != null) {
                             output.close();
                        if (fIStream != null) {
                             fIStream.close();
              } catch (Exception e) {
                   e.printStackTrace();
                 

    You need to pass your filename String as a parameter to your functionality. It depends how you're currently set up though. We can't really see the top of your call so it's difficult to determine what you are calling and we don't really know from where you're calling either.
    If you're running standalone, then on launch of the application, you can feed in a file name as an argument that you can read in in String args[] in the main function and pass down to your XML splitter.
    If you're a method in a class that's part of a bigger pile, you can feed the file name as a String to the method from wherever you call from if it makes sense architecturally.
    You might also want to pass down a File object if that makes sense in your current code (i.e. if you're using your file for other purposes prior to the split, to avoid recreating closing/opening for no reason).
    Depends what you're trying to do. If I put together a piece like this, I would probably create an <yourcurrentrootpackage>.xml.splitter package.
    Also, on a side note, you're problem isn't really reading and writing XML in java, but seems more to be making your functionality generic so that any XML file can be split with your code.
    Regards
    JFM

  • XML in Java: does encoding matter when it's only used for data?

    Hi everybody,
    I have a text document that I've converted into XML, and that I read into my Java program. The encoding I have to use to support accented characters, iso-8859-1, doesn't support certain characters, like curly quotes or em dashes. I'm not planning on displaying my XML document on a web page, just to use it as a data format for ease of access. (By the way, to everybody who's mentioned XML to me in the past, I finally realize how cool it is!)
    Anyhow, after all that rambling, my question is: since I'm using characters that aren't supported by my encoding set, does it matter that the XML isn't "perfect" and has some characters in it that are technically illegal? Eventually I'm going to read it into a different Java program and just parse it, where I'll need those characters. I sort of got the impression that it didn't matter if you're not planning on displaying the XML on the web.
    EDIT: I forgot one thing -- if it doesn't matter, does that mean I wouldn't need to have the "xml version" line at the top of the document?
    Any clarification on this would be great!
    Thanks,
    Jezzica85
    Message was edited by:
    jezzica85

    You would have to make a cable that will plug into the Nano and serve as an antenna (the headphone cable serves this purpose) and triggers the radio without touching the headphone contact. There are some custom shops that can probably make such a custom jack/cable for you, should not cost you much more than $100 or so USD. But you will still have the problem that the jack you have made will preclude you from docking your Nano with the Anywhere 2.
    A much more inexpensive solution would be to buy a cable like this: http://www.monstercable.com/productdisplay.asp?pin=4572 and connect it to the headphone jack on your Nano and to the audio in jack on the back of the Anywhere 2. The longer the cable the better antenna. You won't be able to charge the Nano while you listen, but you can do that after you are done listening to FM.

  • How can i read XML string in a loop???

    i changed xml file reader to xml string reader by
    looking around this and other forums.
    here is the code.
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        public static void main(String[] args) {
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            java.io.Reader reader = new java.io.StringReader(s);
            org.xml.sax.InputSource source = new org.xml.sax.InputSource(reader);
            org.w3c.dom.Document doc = null;
            javax.xml.parsers.DocumentBuilderFactory fact = javax.xml.parsers.DocumentBuilderFactory.newInstance();
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                doc = builder.parse(source);
            } catch (javax.xml.parsers.ParserConfigurationException pce) {
            } catch (org.xml.sax.SAXException se) {
            } catch (java.io.IOException ioe) {
            } finally {
                try {
                    reader.close();
                } catch (java.io.IOException ignored) {
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                InputSource source = new InputSource(reader);
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                try {
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                } catch (ParserConfigurationException pce) {
                // -->
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                    System.out.println("readLine() : {" + inputLine + "}");
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                    source.setCharacterStream(reader);
                    try {
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                        se.printStackTrace();
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                        System.out.println("IOException : " + ioe);
                    } finally {
                        try {
                            reader.close();
                        } catch (IOException ignored) {
                    reader = null;i know putting new in the loop is VERY bad.
    i gotto get ride of this new from the loop.
    can anyone help me?

    i know putting new in the loop is VERY bad.
    i gotto get ride of this new from the loop.Don't design your application based on one-liners you heard somewhere. Do some timings to see if it matters. My guess would be that parsing an XML file would take a fair bit longer than creating a StringReader object. And you do need a new StringReader each time, they aren't reusable, so the alternatives are not obvious. And don't accept my guess about the timings, check it for yourself.

  • Is there any way to read XML directly from a Web Page ??

    i have a url, which on sending request, shows XML in browser.
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    the average Java XML parser will accept an InputStream, so just open an URLConnection to the webpage, get the inputstream from it and feed that inputstream to the XML parser. If the URL has valid XML data, it will get parsed without problems.

  • Reading XML file using BAPI and then uploading that xml file data into SAP

    I am getting a xml file from Java server. I need to take
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    <b>SDIXML_DATA_TO_DOM</b> Convert SAP data (elementary/structured/table types) into DOM (XML
    <b>SDIXML_DOM_TO_XML</b>  Convert DOM (XML) into string of bytes that can be downloaded to PC or application server
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    data: it_table like t001 occurs 0.
    data: l_dom      TYPE REF TO IF_IXML_ELEMENT,
          m_document TYPE REF TO IF_IXML_DOCUMENT,
          g_ixml     TYPE REF TO IF_IXML,
          w_string   TYPE XSTRING,
          w_size     TYPE I,
          w_result   TYPE I,
          w_line     TYPE STRING,
          it_xml     TYPE DCXMLLINES,
          s_xml      like line of it_xml,
          w_rc       like sy-subrc.
    start-of-selection.
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    end-of-selection.
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      class cl_ixml definition load.
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      write: 'ok'.
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      write: / 'converting DATA TO DOM 1:'.
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          NAME               = 'IT_TABLE'
          DATAOBJECT         = it_table[]
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        CHANGING
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          ILLEGAL_NAME       = 1
          OTHERS             = 2.
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      endif.
      check not l_dom is initial.
      write: / 'appending DOM to iXML doc:'.
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      else.                write: 'Err =', w_rc.
      endif.
    visualize iXML (DOM)               ****
      write: / 'displaying DOM:'.
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          OTHERS            = 2.
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      else.             write: 'Err =', sy-subrc.
      endif.
    convert DOM to XML doc (table)     ****
      write: / 'converting DOM TO XML:'.
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          DOCUMENT            = m_document
        PRETTY_PRINT        = ' '
        IMPORTING
          XML_AS_STRING       = w_string
          SIZE                = w_size
        TABLES
          XML_AS_TABLE        = it_xml
        EXCEPTIONS
          NO_DOCUMENT         = 1
          OTHERS              = 2.
      if sy-subrc = 0.   write  'ok'.
      else.              write: 'Err =', sy-subrc.
      endif.
      write: / 'XML as string of size:', w_size, / w_string.
      describe table it_xml lines w_result.
      write: / 'XML as table of', w_result, 'lines:'..
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        write s_xml.
      endloop.
      write: / 'end of processing'.
    end of code
    Hope this will be useful.
    regards
    vinod

  • How to get previous tag name from a xml in java

    Hai
          I need to get the previous tag name from a xml in java.
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        NodeList parentactionList = lParentRule.getElementsByTagName(
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    </parentruledetails>
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    </SingleParentRule>
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    <ParentCompliance>
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    Can any one help me,

    still i am not able to get the correct value...
    i used the way wat u said it is not even going inside the if condition
    below is my actual xml as before i asked i need the before tag name of <parentactiondetails>
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    <?xml version="1.0" encoding="UTF-8"?>
    <GRC>
    <ParentInventory>
    <Vendor comment="" createdBy="root" vendorCode="1001" vendorName="Cisco">
    <DeviceType createdBy="root" devTypeCode="1001" devTypeName="Router" vendorCode="1001">
    <Series createdBy="root" devTypeCode="1002" seriesCode="1110" seriesName="2800" vendorCode="1001">
    <Model createdBy="root" devTypeCode="1002" modelCode="1459" modelName="4506" seriesCode="1110" vendorCode="1001">
    <Sub createdBy="root" devTypeCode="1002" modelCode="1459" seriesCode="1110" subCode="1695" subName="CAT4500-SUP4" vendorCode="1001">
    <CodeVersion createdBy="root" devTypeCode="1002" modelCode="1459" seriesCode="1110" startCode="2207" startName="12.2(25)EWA2" subCode="1695" vendorCode="1001">
    <ImageName createdBy="root" devTypeCode="1002" endCode="5508" endName="Standard" modelCode="1459" seriesCode="1110" startCode="2207" subCode="1695" vendorCode="1001"/>
    </CodeVersion>
    <CodeVersion createdBy="root" devTypeCode="1002" modelCode="1459" seriesCode="1110" startCode="2225" startName="12.2(5)T" subCode="1695" vendorCode="1001"/>
    </Sub>
    </Model>
    </Series>
    </DeviceType>
    </Vendor>
    </ParentInventory>
    <Parentrule>
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