Regarding opening a new pop up window

Question

In order to open open in a new window I have used the following two approaches
1.public void FormHelpUrl(ActionEvent actionEvent) throws Exception {
FacesContext context = FacesContext.getCurrentInstance();
ExternalContext ectx = context.getExternalContext();
HttpServletRequest request=(HttpServletRequest)ectx.getRequest();
StringBuffer serverName=request.getRequestURL();
String serverName1=serverName.substring(0, serverName.indexOf("workflow"));
HttpServletResponse response =
(HttpServletResponse)ectx.getResponse();
response.sendRedirect(serverName1+"/dashboard_help/guide?topic="+topic+"&locale=en");
The first approach opens in the same window only.
2.public String formHelpUrl() {
FacesContext context = FacesContext.getCurrentInstance();
ViewHandler viewHandler = context.getApplication().getViewHandler();
UIViewRoot dialog1=new UIViewRoot();
UIViewRoot dialog = viewHandler.createView(context, "/dashboard/ohguide?topic=ohj_about_ui.htm&locale=en");
HashMap properties = new HashMap();
AdfFacesContext afContext = AdfFacesContext.getCurrentInstance();
afContext.launchDialog(dialog,
null, null, // no particular parameters
true,
properties);
return null;
The second approach above opens in a window - but it is not taking the new context root
UIViewRoot dialog = viewHandler.createView(context, "/dashboard/ohguide?topic=ohj_about_ui.htm&locale=en");
here in the above code , it has to start with '/' , so unable to change context root . please help me out

Answer 1

Hi Dean,
The item names and item values are passed as comma delimited lists in the url, so your url should be:
url = 'f?p=&APP_ID.:49:&APP_SESSION.::::P49_DETAIL_ID,P49_FLAG:'+p_val[b]+',0';
Regards
Andy