Regexp_replace not able to convert

Question

Hi Team,
I am using once query using regexp_replace plz find below query.
Data for Address_1_v is 1@81, and Address_2_v is @@PO BOX ST289 SOUTHERTON
SELECT ACCOUNT_LINK_CODE_N,
    XMLELEMENT("ADDRESS_DTLS",XMLATTRIBUTES(
    NVL(regexp_replace(ADDRESS_1_V,'[^0-9 A-Z a-z/,()''"@&]',''),'ADDR1')  AS "ADDRESS1",
    NVL(regexp_replace(ADDRESS_2_V,'[^0-9 A-Z a-z/,''()"@&]',''),'ADDR2')  AS "ADDRESS2"
    )) "ADDRESS_X"
    FROM CB_ADDRESS where account_link_code_n=8293277;
o/p
ACCOUNT_LINK_CODE_N ADDRESS_X                                                                     
            8293277 <ADDRESS_DTLS ADDRESS1="1@81" ADDRESS2="@@PO BOX ST289 SOUTHERTON"></ADDRESS_DTL
Why it doesn't replace? Previously it is replacing.

Answer 1

The "^" character at the start of the set of characters specificed, tells it that you want to pattern match everything NOT in the set of characters.
So, if you string contains something that is not in that set.... e.g..
SQL> ed
Wrote file afiedt.buf
  1  with t as (select 'This is my test ? string.' as addr1 from dual)
  2  --
  3  -- end of test data
  4  --
  5  select regexp_replace(addr1, '[^0-9 A-Z a-z/,()''"@&]','') as result
  6* from t
SQL> /
RESULT
This is my test  string
then those characters will get replaced.  In this case, the "?" and the "." characters were removed.