Regexp return only the text inside quotes

I'm looking for a way to return only what is between text in a column, or a period if it's between two sets of quotes. There could be any number of occurrences within the text of the column.
"ENC"."CHECKOUT_TIME"[DATE,7], "ENC"."PAT_ENC_CSN_ID"[NUMBER,22], "ENC"."CHECKIN_TIME"[DATE,7]
Becomes
"ENC"."CHECKOUT_TIME""ENC"."PAT_ENC_CSN_ID""ENC"."CHECKIN_TIME"
Is this something that's possible with a regular expression?

Hi,
I'm not sure if that can be done with a single regular expression.
Here's a way that uses two functions:
SELECT  str
,       REGEXP_REPLACE ( REGEXP_SUBSTR ( str
                       , '("[^"]*"(\."[^"]*")?)[^"]*'
                       , '\1'
                       ) AS new_str
FROM    table_x
REGEXP_SUBSTR removes unquoted material before the first double-quote and after the last double-quote.

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