Regular expression- insert into a string phrase "new" into correct position

Question

I have sample data in table T below, and i have sample output how i want the query to output over that data.
with T as
select 'CREATE OR REPLACE PACKAGE BODY "YYY"."PACKAGEONE" IS' s from dual union all
select 'Create or REPLACE PACKAGE BODY "ZZZ"."PACKAGETWO" IS' s from dual
select REGEXP_REPLACE(T.s, '^.PACKAGE BODY$','(\1)_new',1,1,'i') as s from T;
Expected output:
CREATE OR REPLACE PACKAGE BODY "YYY"."PACKAGEONE_new" IS
Create OR REPLACE PACKAGE BODY "ZZZ"."PACKAGETWO_new" IS
*/All data has following pattern:
CREATE OR REPLACE PACKAGE BODY "[owner]"."[name]" ISWhere [owner] can be any string. In sample data we have for example values XXX and YYY there.
And [name] can be any string. In sample data we have for example values PACKAGEONE and PACKAGETWO there.
Other parts of the string is fixed and stays as you see.
As shown in expected output query should replace substring "[owner]"."[name]" to "[owner]"."[name]_new"
How can i write such query?
I think i somehow should in regular expression count the positions of double quotes to achieve the expected result, but i don't know how.

Answer 1

Thx, but your solution doesn't work, it doesn't put phrase "new" into string. I use Oracle 10g.
with T as
select 'CREATE OR REPLACE PACKAGE BODY "YYY"."PACKAGEONE" IS...' s from dual union all
select '...Create or REPLACE PACKAGE BODY "ZZZ"."PACKAGETWO" ..."a"."b" procedure a IS..' s from dual
select
RegExp_Replace(s,'(" IS$)','_new\1') as new
from t;
CREATE OR REPLACE PACKAGE BODY "YYY"."PACKAGEONE" IS...
...Create or REPLACE PACKAGE BODY "ZZZ"."PACKAGETWO" ..."a"."b" procedure a IS..
{code}