Regular expression or regex

Hi all,
can i use regular expression or regex in 4.7 r/3 sever.
if yes then pls tell me how to use regex for differentsiate between table name and fieldname for dynamically select query like
SELECT T000MTEXT AS A FROM T000 WHERE T000MANDT IN ( SELECT T000MANDT FROM T000 WHERE T000MWAER = 'DEM')
or
SELECT MARAMATNR AS A MAKTMAKTX AS B FROM MAKT INNER JOIN MARA ON MAKTMATNR = MARAMATNR WHERE MARAMATKL = '013' AND MAKTSPRAS = 'E'
or many.
regards

Got myself.
RegEx or Regular Expressions is only supported in NetWeaver 7.0.

Similar Messages

Regular Expression help needed plzzz

Hi,
I am trying to form a regular expression in order to search for say two char patterns and both the patterns should be present. Say I have a string example = "ModeleerComponent.java,1.1"I am using a regular expression to find whether the user input matches with it or not. For example the user can enter Mod and 1.1...now since the string contains Mod and 1.1 the result should be true.
This is how my regular expression looks regex = ^(?=.*?Mod)(?=.*?1\.1).*$ so now the result is true is okay. But if I enter code]regex = ^(?=.*?asdfg)(?=.*?1\.1).*$ it should return false but it returns true. As 1.1 is present. Could someone tell me how I could use an AND that is when both Mod and 1.1 are present then only return true.
I hope whatever I have written is understandable.
Thank you very much.

Or this:
public class TestRegex {
    public static void main(String[] args) {
            String example = "ModeleerComponent.java,1.1";
            System.out.println(example.indexOf("Mod") != -1 && example.indexOf("1.1") != -1);
}returns:
true

Quick regular expression question/help

Can someone help me with two regular expressions I need. I could spend a while trying to figure it out myself, however times short and I really would like to get a fool proof optimal solution (my attempt would be buggy).
Sample sentence
The population, is projected to reach 200,000, or more (by 2020).[7] This is {dummy} text.
The first regular expression
I need all brackets and every thing between them to be removed from a sentence.
Brackets such as: ( ), [ ] and { } .
I.e. Given the above sentence the following would be returned:
The population, is projected to reach 200,000, or more. This is text.
The second regular expression
If a word has a trailing comma character I need to add a whitespace between the word and the comma.
I.e. Given the sentence returned from the first regular expression, this regex would return:
The population *,* is projected to reach 200,000 *,* or more. This is text.
Many thanks to anyonewho can help me with this!
Edited by: Myles on Jan 18, 2008 8:12 AM

http://java.sun.com/docs/books/tutorial/extra/regex/index.html
http://www.regular-expressions.info

Regular Expressions with Java Regex

Hi,
I'm playing around with regex and there's something I can't get to work. What I need, is to capture words between 2 other words and the words captured has to be higher than 5 characters, so for example:
Pattern "Just testing on something with regular expressions" and suppose I'll try to match all the words between "testing" and "regular", then only the word "something" should come out because "on" and "with" are not larger than 5 chars.
Now I'm quite new to regexps and I know that ((?<=\btesting\b).*(?=\bregular\b)) will return " on something with "
But I can't seem to come up with an expression that would only output the word "something". I've tried a few expressions like ((?<=\btesting\b)((?:[\s\w{1,3}])*(\b\w{4,}\b)*(?:[\s\w{1,3}])*)*(?=\bregular\b)) which also returns " on something with " The others I tried would either return the whole " on something with " or return "Not Found!"
Does anyone have a tip for me? I'm well aware that it's not too hard to do something like this in Java, but I'm really looking to study regular expressions and would like to accomplish this using a regular expression.
The Java program I use is the following:
C:\Program Files\Java\jdk1.5.0_16\bin>java RegexTest "((?<=\btesting\b).*(?=\bregular\b))" "Just testing on something with regular expressions"
public class RegexTest {
 public static void main(String[] args) {
 Pattern RegexCompile = Pattern.compile(args[0]);
 Matcher m = RegexCompile.matcher(args[1]);
 boolean found = m.find(); // Perhaps there's another function to find () that would do the job?
 if (found)
 System.out.println(m.group()); // Perhaps group() is not the right function for this case?
 else
 System.out.println("Not Found!");
Edited by: dli2k3 on Sep 19, 2008 11:32 AM
Edited by: dli2k3 on Sep 19, 2008 11:33 AM

You're talking about a two-stage operation: find everything between those two words, then filter out anything that's less than five letters long. There's no single regex that will accomplish all that in one step.
By the way, please use {code} tags when you post source code.

Regular Expressions (java.util.regex)

I am developing using a product that must
use java 1.2.2_05a but I want to use regular
expressions, does anybody know where I can
get of the package java.util.regex without
having to download the whole java 1.4 release.
Or does someone know of an alternative that
I can use ?

There is another regex pack for java available from Apache Foundation Project. You can try it.
Take a look at http://jakarta.apache.org/

Java.util.regex vs jarkata-oro on regular expression

hi, all
Both java utility (java.util.regex) and jarkata-oro (org.apache.oro.text.perl) provide supports of Perl5 compatible regular expressions. What are your opinions of which one do you choose?
I've searched in this forum and others online. I don't see this topic. Maybe I miss something...
Anyway, your opinions/experences are more than welcome.
thx
Tim

One big difference:
java.util.regex is JAVA 1.4+ only.
jarkata-oro is JAVA 1.2+

Regular expression (regex) help!

I am trying to write a correct regular expression but am having difficulties.
I have a webpage saved as a string and want to extract all the links (urls) from the webpage string.
The trouble I am having is that some websites surround links using double quotes " " and some use single quotes ' ' around links in html:
Double quotes around url:
<a href="www.example.com"></a>
And single quotes:
<a href="www.example.com"></a>
So far I have a regex which extract links if they are surrounded with double quotes (see below), however if a page uses single quotes it screws up ;)
Pattern.compile("<a\\s+href\\s*=\\s*\"?(.*?)[\"|>]", Pattern.CASE_INSENSITIVE);So is there a way to say look for double quotes OR single quotes?
Many thanks
null

There's no need to escape the single-quote (or apostrophe) in a regex. The only reason it was necessary to escape the double-quote (or quotation mark) is because the regex was written in the form of a String literal. Neither the single-quote or the double-quote has any special meaning in regexes.

Logical AND in Java Regular Expressions

I'm trying to implement logical AND using Java Regular Expressions.
I couldn't figure out how to do it after reading Java docs and textbooks. I can do something like "abc.*def", which means that I'm looking for strings which have "abc", then anything, then "def", but it is not "pure" logical AND - I will not find "def.*abc" this way.
Any ideas, how to do it ?
Baken

First off, looks like you're really talking about an "OR", not an "AND" - you want it to match abc.*def OR def.*abc right? If you tried to match abc.*def AND def.*abc nothing would ever match that, as no string can begin with both "abc" and "def", just like no numeric value can be both 2 and 5.
Anyway, maybe regex isn't the right tool for this job. Can you not simply programmatically match it yourself using String methods? You want it to match if the string "starts with" abc and "ends with" def, or vice-versa. Just write some simple code.

Help in Regular expression

Hello..
I wanted to write a regular expression to match the foll string..
 
 NEW ORLEANS, Louisiana (CNN) 
-- Two years after Hurricane Katrina devastated coastal areas of Louisiana and Mississippi, residents say much of America has forgotten their plight.
 
I tried doing..
Matcher matcher= Pattern.compile(" ([^<^>]+?)", Pattern.CASE_INSENSITIVE).matcher(story);
Its not working...
is there any other soln?

Theres probably a better way to do this but here's a way that works.
import java.util.regex.*;
public class RegexTester{
public static void main(String[] args){
 String text =
 " " +
 " NEW ORLEANS, Louisiana (CNN) " +
 "-- Two years after Hurricane Katrina devastated coastal areas of Louisiana and Mississippi," +
 "residents say much of America has forgotten their plight." +
 " ";
 String regex = ">((?:\\s*[\\S&&[^<>]]+\\s*)*?)<";
 Pattern p = Pattern.compile(regex);
 Matcher m = p.matcher(text);
 while(m.find()){
 System.out.println("Match: '" + m.group(1) + "'");
}

Urgent!!! Problem in regular expression for matching braces

Hi,
For the example below, can I write a regular expression to store getting key, value pairs.
example: ((abc def) (ghi jkl) (a ((b c) (d e))) (mno pqr) (a ((abc def))))
in the above example
abc is key & def is value
ghi is key & jkl is value
a is key & ((b c) (d e)) is value
and so on.
can anybody pls help me in resolving this problem using regular expressions...
Thanks in advance

"((key1 value1) (key2 value2) (key3 ((key4 value4)
(key5 value5))) (key6 value6) (key7 ((key8 value8)
(key9 value9))))"
I want to write a regular expression in java to parse
the above string and store the result in hash table
as below
key1 value1
key2 value2
key3 ((key4 value4) (key5 value5))
key4 value4
key5 value5
key6 value6
key7 ((key8 value8) (key9 value9))
key8 value8
key9 value9
please let me know, if it is not possible with
regular expressions the effective way of solving itYes, it is possible with a recursive regular expression.
Unfortunately Java does not provide a recursive regular expression construct.
$_ = "((key1 value1) (key2 value2) (key3 ((key4 value4) (key5 value5))) (key6 value6) (key7 ((key8 value8) (key9 value9))))";
my $paren;
   $paren = qr/
           [^()]+ # Not parens
         |
           (??{ $paren }) # Another balanced group (not interpolated yet)
    /x;
my $r = qr/^(.*?)$(\w+?) (\w+?|(??{$paren}))$\s*(.*?)$/;
while ($_) {
     match()
# operates on $_
sub match {
     my @v;
     @v = m/$r/;
     if (defined $v[3]) {
          $_ = $v[2];
          while (/\(/) {
               match();
          print "\"",$v[1],"\" \"",$v[2],"\"";
          $_ = $v[0].$v[3];
     else { $_ = ""; }
C:\usr\schodtt\src\java\forum\n00b\regex>perl recurse.pl
"key1" "value1"
"key2" "value2"
"key4" "value4"
"key5" "value5"
"key3" "((key4 value4) (key5 value5))"
"key6" "value6"
"key8" "value8"
"key9" "value9"
"key7" "((key8 value8) (key9 value9))"
C:\usr\schodtt\src\java\forum\n00b\regex>

Need help with regular expression

I'm trying to use the java.util.regex package to extract URLs from html files.
The URLs that I am interested in extracting from the HTML look like the following:
http://forum.java.sun.com -
So, the URL is always preceeded by:

and then followed by a space character and then a hyphen character. I want to be able to put all these URLs in a Vector object. This doesn't seem like it should be too difficult but for some reason I can't get anywhere with it. Any help would be greatly appreciated. Thanks!

hi gupta am not sure of the java syntax but i can tell u about the regular expression...try this....
(http:\/\/[a-zA-Z0-9.]+) [-]
i dont know the java methods to call...just the reg exp...
Sanjay Acharya

Help regarding regular expression

HI All ,
Please see the following string
String s = "IF ((NOT NUM4 IS ALPHABETIC ) AND NUM3 IS ALPHABETIC-UPPER AND (NUM5 IS GREATER OR EQUAL TO 3) AND (NUM5 IS NOT GREATER THAN 3) AND (NUM3 GREATER THAN 46) AND (NUM5 GREATER THAN NUM3) OR NUM3 LESS THAN 78) .";
My problem is: i want to capture the part of this line which contains "ALPHABETIC ,ALPHABETIC-UPPER for ex :NOT NUM4 IS ALPHABETIC , NUM3 IS ALPHABETIC-UPPER.from that I have to capture the word num4 , num3 which are in these phrases only ;from the whole string whereever it exists along with the phrase,Can any one help me out by suggesting something.num4 and num3 are variable names

I suspect you're right, Sabre, but I can't resist...
import java.util.regex.*;
* A rewriter does a global substitution in the strings passed to its
* 'rewrite' method. It uses the pattern supplied to its constructor, and is
* like 'String.replaceAll' except for the fact that its replacement strings
* are generated by invoking a method you write, rather than from another
* string. This class is supposed to be equivalent to Ruby's 'gsub' when given
* a block. This is the nicest syntax I've managed to come up with in Java so
* far. It's not too bad, and might actually be preferable if you want to do
* the same rewriting to a number of strings in the same method or class. See
* the example 'main' for a sample of how to use this class.
* @author Elliott Hughes
public abstract class Rewriter
private Pattern pattern;
private Matcher matcher;
   * Constructs a rewriter using the given regular expression; the syntax is
   * the same as for 'Pattern.compile'.
public Rewriter(String regularExpression)
    this.pattern = Pattern.compile(regularExpression);
   * Returns the input subsequence captured by the given group during the
   * previous match operation.
public String group(int i)
    return matcher.group(i);
   * Overridden to compute a replacement for each match. Use the method
   * 'group' to access the captured groups.
public abstract String replacement();
   * Returns the result of rewriting 'original' by invoking the method
   * 'replacement' for each match of the regular expression supplied to the
   * constructor.
public String rewrite(CharSequence original)
    this.matcher = pattern.matcher(original);
    StringBuffer result = new StringBuffer(original.length());
    while (matcher.find())
      matcher.appendReplacement(result, "");
      result.append(replacement());
    matcher.appendTail(result);
    return result.toString();
public static void main(String[] args)
    String s = "IF ((NOT NUM4 IS ALPHABETIC ) " +
                "AND NUM3 IS ALPHABETIC-UPPER " +
                "AND (NUM5 IS GREATER OR EQUAL TO 3) " +
                "AND (NUM5 IS NOT GREATER THAN 3) " +
                "AND (NUM3 GREATER THAN 46) " +
                "AND NUM645 IS ALPHABETIC " +
                "AND (NUM5 GREATER THAN NUM3) " +
                "OR NUM3 LESS THAN 78 " +
                "AND NUM34 IS ALPHABETIC-UPPER " +
                "AND NUM92 IS ALPHABETIC-LOWER " +
                "AND NUM0987 IS ALPHABETIC-LOWER) .";
    String result =
      new Rewriter("(NUM\\d+) +IS +(ALPHABETIC(?:-(?:UPPER|LOWER))?)")
        public String replacement()
          String type = group(2);
          if (type.endsWith("UPPER"))
            return "Character.isUpper(" + group(1) + ")";
          else if (type.endsWith("LOWER"))
            return "Character.isLower(" + group(1) + ")";
          else
            return "Character.isLetter(" + group(1) + ")";
      }.rewrite(s);
    System.out.println(result);
}

Unix Log Monitoring regular expression not picking up alerts

Hi,
We are moving our unix monitoring to SCOM 2012 SP1 rollup 4.
What I have got working is indvidual alert logging of Unix Log alerts by exporting the MP and changing the <IndividualAlerts> value to true and removing the suppression xml section then reimporting the MP.
What I am trying to do is use the regular expression to peform the suppression of specific event (such as event codes).
The expression is:
((?i:warning)(?!(.*1222)|(.*1001)))
ie Search the log for "warning" (not case sensitive) then check if events 1222 or 1001 exist if so return no match, if they dont exist then return true.
I use the built in test function in SCOM when creating the rule and the tests come back as expected but when I inject test lines into the unix log, no alerts get generted.
I suspect it could be the syntax not being accepted on the system (its running RedHat 6 )
I have tested this with regex tools and works.
When I try and test it on the server i get:
[root@bld02 ~]# grep ((?i:Warning)(?!(.*1222)|(.*1001))) /var/log/messages
-bash: !: event not found
[root@bld02 ~]# tail /var/log/messages
Nov 13 15:07:26 bld02 root: SCOM Test Warning Event ID 1001 Round 18
Nov 13 15:07:29 bld02 root: SCOM Test Warning Event ID 1000 Round 18
Nov 13 15:07:35 bld02 root: SCOM Test Warning Event ID 1002 Round 18
So I am expecting 2 alerts to be generated.
SCOM tests to show expression working:
Test 1 Matching
Test 2 to exclude
Need some help with this, Thankyou in advance :)

Hello,
Here's an example of modifying the MP to exclude particular events. Firstly, I created a log file rule using the MP template that is fairly inclusive - matching the string Warning (with either a lower or upper case W).
I then exported the MP, and modified the rule. I set the IndividualAlerts = true and removed the AlertSuppression element, so that every matched line will fire a unique alert. You don't have to remove the AlertSuppression, but you should use
Individual alerts so that the exclusion logic doesn't exclude concurrent events that you actually want to match.
Implementing the exclusion logic involves the addition of a System.ExpressionFilter definition in the rule. This will use a conditional evaluation of the //row element of the data item. Here's an example of a dataitem matching an individual row:
<DataItem type="System.Event.Data"time="2013-11-15T10:33:14.8839662-08:00"sourceHealthServiceId="667FF365-70DD-6607-5B66-F9F95253B29F">
<EventOriginId>{86AB962D-2F44-29FD-A909-B99FF6FEB2C5}</EventOriginId>
<PublisherId>{EC7EA4B1-0EA5-7E8E-701F-82FEF3367BC4}</PublisherId>
<PublisherName>WSManEventProvider</PublisherName>
<EventSourceName>WSManEventProvider</EventSourceName>
<Channel>WSManEventProvider</Channel>
<LoggingComputer/>
<EventNumber>0</EventNumber>
<EventCategory>3</EventCategory>
<EventLevel>0</EventLevel>
<UserName/>
<RawDescription>Detected Entry: warning 1002</RawDescription>
<CollectDescription Type="Boolean">true</CollectDescription>
<EventData>
<DataItem type="SCXLogProviderDataSourceData"time="2013-11-15T10:33:14.8839662-08:00"sourceHealthServiceId="667FF365-70DD-6607-5B66-F9F95253B29F">
<SCXLogProviderDataSourceData>
<row>warning 1002</row>
</SCXLogProviderDataSourceData>
</DataItem>
</EventData>
<EventDisplayNumber>0</EventDisplayNumber>
<EventDescription>Detected Entry: warning 1002</EventDescription>
</DataItem>
Here is the rule in the MP XML. The <ConditionDetection>...</ConditionDetection> content was what I added to do the exclusion filtering:
<Rule ID="LogFileTemplate_66b86eaded094c309ffd2631b8367a32.Alert" Enabled="false" Target="Unix!Microsoft.Unix.Computer" ConfirmDelivery="false" Remotable="true" Priority="Normal" DiscardLevel="100">
<Category>EventCollection</Category>
<DataSources>
<DataSource ID="EventDS" TypeID="Unix!Microsoft.Unix.SCXLog.VarPriv.DataSource">
<Host>$Target/Property[Type="Unix!Microsoft.Unix.Computer"]/PrincipalName$</Host>
<LogFile>/tmp/test</LogFile>
<UserName>$RunAs[Name="Unix!Microsoft.Unix.ActionAccount"]/UserName$</UserName>
<Password>$RunAs[Name="Unix!Microsoft.Unix.ActionAccount"]/Password$</Password>
<RegExpFilter>warning</RegExpFilter>
<IndividualAlerts>true</IndividualAlerts>
</DataSource>
</DataSources>
<ConditionDetection TypeID="System!System.ExpressionFilter" ID="Filter">
<Expression>
<RegExExpression>
<ValueExpression>
<XPathQuery Type="String">//row</XPathQuery>
</ValueExpression>
<Operator>DoesNotContainSubstring</Operator>
<Pattern>1001</Pattern>
</RegExExpression>
</Expression>
</ConditionDetection>
<WriteActions>
<WriteAction ID="GenerateAlert" TypeID="Health!System.Health.GenerateAlert">
<Priority>1</Priority>
<Severity>2</Severity>
<AlertName>Log File Alert: ExclusionExample</AlertName>
<AlertDescription>$Data/EventDescription$</AlertDescription>
</WriteAction>
</WriteActions>
</Rule>
I traced this with the Workflow Analyzer as I tested, which shows the logic being applied. Here is the exclusion happening:
Here's more info on the definition of an ExpressionFilter:
http://msdn.microsoft.com/en-us/library/ee692979.aspx
And more information on Regular Expressions in MPs:
http://support.microsoft.com/kb/2702651/en-us
You can also have multiple Expressions in the ExpressionFilter joined by OR or AND operators.
Also, if you are comfortable with the MP authoring, you can just skip the step of creating the rules in the MP template and just author your own MP with the VSAE tool:
http://social.technet.microsoft.com/wiki/contents/articles/18085.scom-2012-authoring-unixlinux-log-file-monitoring-rules.aspx
www.operatingquadrant.com

URL paths and regular expressions in ASDM

Some background info - I've recently switched to an ASA 5510 on 8.4(3) coming from a Checkpoint NGX platform (let's say fairly quickly and without much warning ). I have a couple questions and they're kind of similar so I'll post them up. I've read docs about regex and creating them both via command line and ASDM, but the examples always seem to include info I don't need or honestly something I don't understand yet (mainly related to defining class\inspect maps). If someone could provide a simple example of how to do these in ASDM that would help a lot in understanding how regular expressions are properly configured. So here we go.
I know this is basic but I need to make sure I understand this properly - I have a single web server (so this won't be a global policy) where I need to allow access to a specific URL path\file and that's it. So we'll call it \test\testfile.doc. Any other access to any other path should be dropped. What's the best way to do this in ASDM (6.4)? I think if I saw a basic example for this I could figure out next few questions but I'll post them as well just in case.
I have another single public web server (again this won't be a global policy) where I'd like to specify blocking file types, like .php, .exe., etc... again a basic example would be great.
Lastly, and this is kind of related, but we have a single office/domain and sometimes we get spam from forged addresses appearing to be from our domain. On Checkpoint I used to use its built-in SMTP security server and could define if it received mail from *@mydomain.com to drop it because we would never receive mail externally from our own domain name. I saw something similar with ESMTP in ASDM and it looks kind of like how you set up the URL access mentioned above. Can I configure this in ASDM as well, and if so how?
TIA for your help,
Jordan

/bump

Get all groups from a regular expression match

Please help me understand how to use Java regular expressions:
I have an expression similar to this:
{noformat}"([^X]+)(X[^X]*)+"{noformat}This should match stuff like "asaasaXdfdfdfXXsdsfd".
How does one access all the matches for the second group (the second groups has a Kleene operator
added so it is not really just one group --- but match.groupCount() is always 2)
Here is roughly the code:
{noformat}java.util.regex.Pattern pattern = {noformat}{noformat}java.util.regex.Pattern.compile({noformat}{noformat}"([^X]+)(X[^X]*)+",{noformat}{noformat}java.util.regex.Pattern.MULTILINE{noformat}{noformat});{noformat}{noformat}java.util.regex.Matcher matcher = pattern.matcher(text);{noformat}{noformat}matcher.find();{noformat}{noformat}int groupcount = matcher.groupCount();{noformat}
Also, without matcher.find() I get an illegalStateException .. which I also get if I use matcher.matches() instead
of matcher.find().
I am obviously missing something here. There is always at least one "X" in the string so shouldn't that pattern always
match the whole string? Since there are often multiple X, shouldnt I get a group for each occurrence of X, followed
by 0 or more other characters?
{noformat}But when I try to match everything by using "^([^X]+)(X[^X]*)+$" I get an "IllegalStateException: No match available" again.{noformat}
What is the correct way to do this?
Edited by: johann_p on May 16, 2008 10:39 AM

I am sorry I messed this up. Here is a SSCCE:
import java.util.regex.Pattern;
import java.util.regex.Matcher;
class RegExp1 {
 public static void main(String[] args) {
 String testString = "first|aaaa | bbbb\n|cccc|ddddd";
 Pattern pattern = Pattern.compile("^([^|]+)(\\|[^|]*)+$");
 Matcher matcher = pattern.matcher(testString);
 matcher.find();
 int groupcount = matcher.groupCount();
 System.out.println("Found "+groupcount+" groups");
 System.out.println("Matcher: "+matcher);
 for (int i = 1; i <= groupcount; i++) {
 System.out.println("Match "+i+": "+testString.substring(matcher.start(i),matcher.end(i)));
}I figured out a small bug in my first code that explains some of the exception oddities, but my principal question remains:
how do I access all the matches that correspond to the second capturing group?
In the example I would get "first" for Match 1 and "|ddddd" for Match 2, but how do I access all the matches??
Thank you for your help!

Regular expression or regex

Similar Messages

Maybe you are looking for