Regular Expressions with Java Regex

Question

Hi,
I'm playing around with regex and there's something I can't get to work. What I need, is to capture words between 2 other words and the words captured has to be higher than 5 characters, so for example:
Pattern "Just testing on something with regular expressions" and suppose I'll try to match all the words between "testing" and "regular", then only the word "something" should come out because "on" and "with" are not larger than 5 chars.
Now I'm quite new to regexps and I know that ((?<=\btesting\b).*(?=\bregular\b)) will return " on something with "
But I can't seem to come up with an expression that would only output the word "something". I've tried a few expressions like ((?<=\btesting\b)((?:[\s\w{1,3}])*(\b\w{4,}\b)*(?:[\s\w{1,3}])*)*(?=\bregular\b)) which also returns " on something with " The others I tried would either return the whole " on something with " or return "Not Found!"
Does anyone have a tip for me? I'm well aware that it's not too hard to do something like this in Java, but I'm really looking to study regular expressions and would like to accomplish this using a regular expression.
The Java program I use is the following:
C:\Program Files\Java\jdk1.5.0_16\bin>java RegexTest "((?<=\btesting\b).*(?=\bregular\b))" "Just testing on something with regular expressions"
public class RegexTest {
     public static void main(String[] args) {
          Pattern RegexCompile = Pattern.compile(args[0]);
          Matcher m = RegexCompile.matcher(args[1]);
          boolean found = m.find(); // Perhaps there's another function to find () that would do the job?
          if (found)
          System.out.println(m.group()); // Perhaps group() is not the right function for this case?
          else
          System.out.println("Not Found!");
Edited by: dli2k3 on Sep 19, 2008 11:32 AM
Edited by: dli2k3 on Sep 19, 2008 11:33 AM

Answer 1

You're talking about a two-stage operation: find everything between those two words, then filter out anything that's less than five letters long. There's no single regex that will accomplish all that in one step.
By the way, please use &#x7B;code} tags when you post source code.