Rendering a column before the nodeStamp column in an af:treeTable

Question

I have a requirement to show a column before the nodeStamp column in a treeTable.
Is there a way to achieve this?
Code looks like the following -
<af:column id="t3c1" width="50px" headerText="#{dbdiscoveryuiBundle.SELECT}" align="center">
<af:selectBooleanCheckbox .... />
</af:column>
<f:facet name="nodeStamp">
<af:column id="t3c2" rowHeader="unstyled" headerText="#{dbdiscoveryuiBundle.TARGET_NAME}" width="80%" align="start">
  <af:outputText ...." />
</af:column>
</f:facet>
Expected order -> Checkbox first followed by OutputText
NOTE - Making rowHeader=true is not an option because of accessibility violations
Thanks,
Vishwesh

Answer 1

Hi user,
Do you need the header for the select one choice? you could so something like:
<af:column id="c1">
                        <af:panelGroupLayout id="pgl1" layout="horizontal">
                            <af:selectOneChoice value="#{bindings.DepartmentsView1.inputValue}"
                                                label="#{bindings.DepartmentsView1.label}"
                                                required="#{bindings.DepartmentsView1.hints.mandatory}"
                                                shortDesc="#{bindings.DepartmentsView1.hints.tooltip}" id="soc1">
                                <f:selectItems value="#{bindings.DepartmentsView1.items}" id="si1"/>
                                <f:validator binding="#{bindings.DepartmentsView1.validator}"/>
                            </af:selectOneChoice>
                            <af:outputText value="#{node}" id="ot1"/>
                        </af:panelGroupLayout>
                    </af:column>
But that will be all in the same column so I guess you tried that already.