Replace a part of a string beginning with $

I have a Varchar2 column containing some text description and some words beginning with $.... For example :
Hello, I have installed an Oracle database called $name. It runs under $platform environement.
Il would like to replace all words beginning with $... using another string.
Something like : select replace(textcolumn,'$%','data') from table;
Could you give me some advice about how to do this ?
Thanks...
Lionel

select replace(replace(txt, '$name', 'FRED'), '$platform', 'MS DOS 6') from
(select 'Hello, I have installed an Oracle database called $name. It runs under $platform environement.' as txt from dual) x

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Replacing a part of a String with a new String

Hi everybody,
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king regards
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do check java 1.4 api, I think there is a method in it, however for jdk1.3 you can use
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Cheers, APC
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call method textedit- >replace_all
exporting
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changing
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exceptions
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Dear All,
This is not a business requirement, just trying to practice regexp.
Suppose we want to replace a part of a regular expression from a string. As an example, in the string 'THIS Number 124356 Is to Change.This Number 5 Also', I am trying to replace the last digit of each number with $ sign.
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Will this be possible using a single regexp_replce?
Thanks in advance.

MichaelS wrote:
I am trying to achieve this using a SINGLE regexp_replace.Here we go:
SQL> with t as (
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STR                                                     STR2
ABC124556def568gh236klJ258                              ABC12455$def56$gh23$klJ25$
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Nice..
Learning for me ..
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Nalif wrote:
Right - All real 5 digit numbers are between 10000 and 99999. If we're looking at palindromes, though, wouldn't 01210 also be five digits? That's not a number. It's a string.
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Try this:
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Replace a part of a string beginning with $

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