Replace tab character from string in ABAP

hi experts,
I have a string like this "a<tab character>b<tab character>c<tab character>d". for my processing i want the output like "abcd". How can i replace all occurances of this tab character from my string.
tab character = a hexa decimal character. I dont know the hex value for this.
regards
Raghav

hi you joined SCN in 2007 its a way long time to say.. ur new.. any ways.
after declaring the lv_tab as I said...
REPLACE ALL OCCURRENCES OF lv_tab in <string> with space.

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If you are in 9i:
Then you got to split the string into based on the nth position.
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Hi,
Try with this..
call method textedit- >replace_all
exporting
 case_sensitive_mode = case_sensitive_mode
 replace_string = replace_string
 search_string = search_string
 whole_word_mode = whole_word_mode
changing
 counter = counter
exceptions
 error_cntl_call_method = 1
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parts of words (default
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Regards,
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String arrayList = request.getParameter("field");
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the replace method of the String class takes two parameters and both of them are characters not strings use it like this
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Hi,
I have Oracle 10.2 on Windows 2003. I have recently started working on a project that requires encrypting information before sending it over. I have got 64 character long string to use it as a key.
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<pre>
declare
input_string VARCHAR2 (200) := 'SomeText';
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decrypted_raw RAW (2000); -- stores decrypted binary text
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key => key_bytes_raw
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Please let me know hot to convert 64 character long string in to 256bit key.
Thanks
-Smith

smith_apex wrote:
My client is using Java and they are saying that they are using this key for their AES256 Encryption and working fine. I have asked them to provide me 32 bytes key as in Oracle 256bit is 32 character string.
Let me see what they have to say.
I was wondering why Java has 64 bytes for 256 AES encryption when Oracle need only 32 bytes for same encryption.I am not sure I completely understand how those built-in packages work but the doc example produces the raw key that is same in length (in terms of number of characters) as the one you are using.
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Documentation example:
SQL> select * from v$version ;
BANNER
Oracle Database 10g Release 10.2.0.5.0 - Production
PL/SQL Release 10.2.0.5.0 - Production
CORE 10.2.0.5.0 Production
TNS for Linux: Version 10.2.0.5.0 - Production
NLSRTL Version 10.2.0.5.0 - Production
declare
 input_string VARCHAR2 (200) := 'Secret Message';
 output_string VARCHAR2 (200);
 encrypted_raw RAW (2000); -- stores encrypted binary text
 decrypted_raw RAW (2000); -- stores decrypted binary text
 num_key_bytes NUMBER := 256/8; -- key length 256 bits (32 bytes)
 key_bytes_raw RAW (32); -- stores 256-bit encryption key
 encryption_type PLS_INTEGER := -- total encryption type
 DBMS_CRYPTO.ENCRYPT_AES256
 + DBMS_CRYPTO.CHAIN_CBC
 + DBMS_CRYPTO.PAD_PKCS5;
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 DBMS_OUTPUT.PUT_LINE ('Encryption Type: ' || encryption_type);
 key_bytes_raw := DBMS_CRYPTO.RANDOMBYTES (num_key_bytes);
 DBMS_OUTPUT.PUT_LINE ('Key Bytes(RAW): ' || key_bytes_raw);
 encrypted_raw := DBMS_CRYPTO.ENCRYPT
 src => UTL_I18N.STRING_TO_RAW (input_string, 'AL32UTF8'),
 typ => encryption_type,
 key => key_bytes_raw
 DBMS_OUTPUT.PUT_LINE ('Encrypted string: ' || encrypted_raw);
 -- The encrypted value in the encrypted_raw variable can be used here
 decrypted_raw := DBMS_CRYPTO.DECRYPT
 src => encrypted_raw,
 typ => encryption_type,
 key => key_bytes_raw
 output_string := UTL_I18N.RAW_TO_CHAR (decrypted_raw, 'AL32UTF8');
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32 33 34 /
Original string: Secret Message
Encryption Type: 4360
Key Bytes(RAW): 52EC66508FDF1E5DE5FD38EC2467FAA91009B738A2926AA870E142C080C72EBF
Encrypted string: 0BDDC2B94F7044700D85624297A39025
Decrypted string: Secret Message
PL/SQL procedure successfully completed.
SQL> select length('52EC66508FDF1E5DE5FD38EC2467FAA91009B738A2926AA870E142C080C72EBF') from dual ;
LENGTH('52EC66508FDF1E5DE5FD38EC2467FAA91009B738A2926AA870E142C080C72EBF')
 64
SQL> select dump('52EC66508FDF1E5DE5FD38EC2467FAA91009B738A2926AA870E142C080C72EBF') from dual ;
DUMP('52EC66508FDF1E5DE5FD38EC2467FAA91009B738A2926AA870E142C080C72EBF')
Typ=96 Len=64: 53,50,69,67,54,54,53,48,56,70,68,70,49,69,53,68,69,53,70,68,51,56,69,67,50,52,54,55,70,65,65,57,49,48,48,57,66,55,51,56,65,50,57,50,54,65,65,56,55,48,69,49,
52,50,67,48,56,48,67,55,50,69,66,70Your example:
declare
 input_string VARCHAR2 (200) := 'SomeText';
 output_string VARCHAR2 (200);
 encrypted_raw RAW (2000); -- stores encrypted binary text
 decrypted_raw RAW (2000); -- stores decrypted binary text
 key_bytes_raw RAW (32); -- stores 256-bit encryption key
 encryption_type PLS_INTEGER; -- total encryption type
begin
 DBMS_OUTPUT.PUT_LINE ('Original string: ' || input_string);
 encryption_type := DBMS_CRYPTO.ENCRYPT_AES256 + DBMS_CRYPTO.CHAIN_CBC + DBMS_CRYPTO.PAD_PKCS5;
 key_bytes_raw := UTL_I18N.STRING_TO_RAW('eiccmkjd94jfgniw03ljkdlfutcnv3209kfjd67023jlclmxzlmc9543ykflseu6', 'AL32UTF8');
 DBMS_OUTPUT.PUT_LINE ('Key Bytes(RAW): ' || key_bytes_raw);
 encrypted_raw := DBMS_CRYPTO.ENCRYPT
 src => UTL_I18N.STRING_TO_RAW (input_string, 'AL32UTF8'),
 typ => encryption_type,
 key => key_bytes_raw
 -- The encrypted value in the encrypted_raw variable can be used here
 decrypted_raw := DBMS_CRYPTO.DECRYPT
 src => encrypted_raw,
 typ => encryption_type,
 key => key_bytes_raw
 output_string := UTL_I18N.RAW_TO_CHAR (decrypted_raw, 'AL32UTF8');
 DBMS_OUTPUT.PUT_LINE ('Decrypted string: ' || output_string);
end;
27 28 29 30 /
Original string: SomeText
declare
ERROR at line 1:
ORA-06502: PL/SQL: numeric or value error: raw variable length too long
ORA-06512: at line 12
SQL> select length('eiccmkjd94jfgniw03ljkdlfutcnv3209kfjd67023jlclmxzlmc9543ykflseu6') from dual ;
LENGTH('EICCMKJD94JFGNIW03LJKDLFUTCNV3209KFJD67023JLCLMXZLMC9543YKFLSEU6')
 64
SQL> select dump('eiccmkjd94jfgniw03ljkdlfutcnv3209kfjd67023jlclmxzlmc9543ykflseu6') from dual ;
DUMP('EICCMKJD94JFGNIW03LJKDLFUTCNV3209KFJD67023JLCLMXZLMC9543YKFLSEU6')
Typ=96 Len=64: 101,105,99,99,109,107,106,100,57,52,106,102,103,110,105,119,48,51,108,106,107,100,108,102,117,116,99,110,118,51,50,48,57,107,102,106,100,54,55,48,50,51,106,
108,99,108,109,120,122,108,109,99,57,53,52,51,121,107,102,108,115,101,117,54

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michellezee@comcast. wrote:
> I'm trying to create a string that will eventually be
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hi check the replace statement... hit F1 on replace and make ur code..
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Replace tab character from string in ABAP

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