Replace a character in a String array

I have an array of strings and am trying to replace the ' character with a space. I keep getting either a cannot be applied or cannot resolve symbol error. Can anyone help?
String arrayList = request.getParameter("field");
String newList = arrayList.replace("\'", " ");

the replace method of the String class takes two parameters and both of them are characters not strings use it like this
arrayList.replace('\'', ' ');that should fix it

Similar Messages

Replacing a character in a string to another character

hi,
i need to write a function or procedure to replace the character of a string value suppose:
l_error:= 'abcdefghijklmnop' is a string
i need write a function or procedure to replace the character "c" to "z"
that data in l_error is not in any table.
thanks,
AJ

I want to Replace all the Existence of the word - "Test" in a string with "Test1" whereever a space exits before the word Test and someother alphabet after "Test" i.e. Test will be replaced with Test1 if a word starts with Test and contains more alphabets also. For example - TestName should be replaced with Test1Name while MyTest should not be updated to MyTest1.
I have tried to use below query which uses oracle regular expressions -
SELECT REGEXP_REPLACE('MYCOMPANY TEST TESTGEET INDIA PVT LTD TEST','\s(TEST)\w',' TEST1') FROM DUAL
Output -
"MYCOMPANY TEST *TEST1EET* INDIA PVT LTD TEST"
Here, it has also replaced the G also from TESTGEET and resulted in TEST1EET while i want TEST1GEET.
Can someone please suggest how can i do this..... may b m doing some silly mistake but sorry m a newbie to regular expression...
Thanks in advance..

How to replace a character in a string with blank space.

Hi,
How to replace a character in a string with blank space.
Note:
I have to change string CL_DS_1===========CM01 to CL_DS_1 CM01.
i.e) I have to replace '=' with ' '.
I have already tried with REPLACE ALL OCCURRENCES OF '=' IN temp_fill_string WITH ' '
Its not working.

Hi,
Try with this..
call method textedit- >replace_all
exporting
 case_sensitive_mode = case_sensitive_mode
 replace_string = replace_string
 search_string = search_string
 whole_word_mode = whole_word_mode
changing
 counter = counter
exceptions
 error_cntl_call_method = 1
 invalid_parameter = 2.
Parameters Description Possible values
case_sensitive_mode Upper-/lowercase false Do not observe (default value)
 true Observe
replace_string Text to replace the
 occurrences of
 SEARCH_STRING
search_string Text to be replaced
whole_word_mode Only replace whole words false Find whole words and
parts of words (default
value)
 true Only find whole words
counter Return value specifying how
 many times the search string
 was replaced
Regards,
Jayaram...

Replacing the \ character in a string

I'm having trouble replacing a backslash in a string. I use .indexOf() to find the character, but I have to use an escape character and write .index("\\"), but it doesn't work - it returns -1.
Also, replace() doesn't work - gives me an java.util.regex.PatternSyntaxException. Any ideas?
thx

The escape is for the compiler, I think, and then you need to escape the backslash.
Try "\\\\".
� {�

Replacing a character in a String

Hi All,
How can I replace a character ' which appears in a String into \'

There is a method in String that replaces all
occurrences of one character with anothercharacter.
It's called, hold your breath now, "replace".But tho OP wants to replace one character with two
characters :)You're right, I missed that. Well, serves me right for being sarcastic. :-)

Replace a character in a string

Hi,
I've been tearing my hair out trying to do something very simple, replace a backslash character in a string with an underscore. I've searched online and discovered the -replace parameter which you would think would work fine but no, it seems to get in a
tizzy because the character I want to replace is a backslash and I get an error: "Invalid regualr expression pattern".
Here's what I have which produces the error:
$str = 'start\end'
$str = $str -replace '\','_'
Can someone tell me how to do this? I simply want to replace a backslash with an underscore.
thanks
Jamie
http://sqlblog.com/blogs/jamie_thomson/ |
@jamiet |
About me

sod's law. I spend half an hour trying to figure this out and then as soon as I post this thread I figure it. The following works:
$str = 'start\end'
$str = $str -replace '\\','_'
$str
http://sqlblog.com/blogs/jamie_thomson/ |
@jamiet |
About me
"-replace" requires a regular expression for each argument, which is why you needed to escape your backslash with another backslash. If you use the replace() string method, you are not required to use regular expressions:
$str = $str.replace('\','_') will work exactly as you expect it to.

Replace a character in the string using JavaScript

Hello,
I would like to ask for help. I have a field in the xml file, which contains a string, that is bound to a text box on the form.
What would be the syntax to replace a special character in the string with the carriage return?
Thank you.

Huh?
I didn't post my script...
It sure is no clean programming since I just took Steve's solutions and delted the ligns I didn't want (the app allert)
Though in the end I've taken the boolean out, or better replaced it with the replacement function, it repeats the replacement no matter how much "ü"'s are in there. (I needed the boolean though, since as long as it was true, the if should be executed.)
Somehow it worked... not 100% sure why, but it worked.
if (findChar(this.rawValue)) {
function findChar(str)
{ for (var i=0; i < str.length; i++)
if (str.charAt(i) == "ü")
this.rawValue = this.rawValue.replace(/ü/,"ue")

Is there an easy way to replace individual elements in one string array from another striing array?

I have a string array with elements as follows:
   00 00 00 00 00 00 00 00
   00 00 00 00 00 00 00 00
   00 00 00 00 5E 00 00 00
   00 00 50 00 30 00 33 00
   34 00 39 00 00 00 00 00
   00 00 00 00 00 00 00 00
   00 00 00 00 00 00 00 00
The array I want to use to replace values with is:
43 4E 31 30 30 33 30 30 31 41
Where 43 goes in the 3rd row fifth position
Where 4E goes in the 3rd row seventh position
Where 31 goes in the 4th row first position
Where 30 goes in the 4th row third position
Where 30 goes in the 4th row fifth position
Where 33 goes in the 4th row seventh position
Where 30 goes in the 5th row first position
Where 30 goes in the 5th row third position
Where 31 goes in the 5th row fifth position
Where 41 goes in the 5th row seventh position
So the final array looks as follows:
   00 00 00 00 00 00 00 00
   00 00 00 00 00 00 00 00
   00 00 00 00 43 00 4E 00
   31 00 30 00 30 00 33 00
   30 00 30 00 31 00 41 00
   00 00 00 00 00 00 00 00
   00 00 00 00 00 00 00 00
Is there an easy way to replace an element of a string within an array with another element of a string within a different array?
Thank you.
Solved!
Go to Solution.
Attachments:
CMM_Add_SCAN_SN_2_PAT_DATA (temp).vi ‏13 KB

Try this
Omar
Message Edited by Omar II on 03-24-2010 03:25 PM
Omar
Attachments:
CMM_Add_SCAN_SN_2_PAT_DATA%20(temp)[1].vi ‏17 KB

Replace a character from a string

Hi,
how can I replace a particular character from a string on a particular occurrence? Say for eg, if i wan to replace 'a' of second occurrence from 'abcabcabc', then what should i do? I guess the normal REPLACE function replaces every occurrence in a given string. So is there any other way to solve this?
Thanks!

If you are in 9i:
Then you got to split the string into based on the nth position.
SQL> select replace('abddefabc','a','x') from dual;
REPLACE('
xbddefxbc
SQL> select instr('abddefabc','a',2) from dual;
INSTR('ABDDEFABC','A',2)
7
SQL> select substr('abddefabc',1,instr('abddefabc','a',2)-1),substr('abddefabc',instr('abddefabc','a',2)) from dual;
SUBSTR SUB
abddef abc
SQL> select substr('abddefabc',1,instr('abddefabc','a',2)-1),replace(substr('abddefabc',instr('abddefabc','a',2)),'a','X') as replaced from dual;
SUBSTR REP
abddef XbcOfcourse, later on you can join the string..
Jithendra

Replace hex character in a string with another hex character

Hi Guys,
Heres a problem scenario, hex character 92 looks very much like hex character 27 (apostrophe).
I need to write a program that can replace all hex character 92 to hex 27 in a string.
Being a novice on the regular expressions, I would appreciate if somebody can show
the exact syntax to to perform this replacement.
Many Thanks
-Anil

I don't think you need to use regex to do this:
String s = something();
char a = 0x27;
char b = 0x92;
s.replace(a,b);
And don't forget that since Strings are immutable you need:
s = s.replace(a,b);to do anything useful.

How to replace a character in a string

Hello Powerusers
First i'me new in the applescripting so hope you can tell me a few hint to get on.
I Have been trying to find a way to replace characters in a string using applescript. but with no luck
Anybody having a script that can give me a clue on this.
I'me normally programming in windows.... yeah i know there is a first time for everything.

Okay i solved my problem but why arent the folder renamed?
property oldfolder : ""
property newfolder : ""
property SS : "."
property RS : " "
to replaceText(someText, oldItem, newItem)
     replace all occurances of oldItem with newItem
          parameters -     someText [text]: the text containing the item(s) to change
                    oldItem [text, list of text]: the item to be replaced
                    newItem [text]: the item to replace with
          returns [text]:     the text with the item(s) replaced
          set {tempTID, AppleScript's text item delimiters} to {AppleScript's text item delimiters, oldItem}
          try
                    set {itemList, AppleScript's text item delimiters} to {text items of someText, newItem}
                    set {someText, AppleScript's text item delimiters} to {itemList as text, tempTID}
          on error errorMessage number errorNumber -- oops
                    set AppleScript's text item delimiters to tempTID
                    error errorMessage number errorNumber -- pass it on
          end try
          return someText
end replaceText
tell application "Finder"
          set these_items to the selection
end tell
repeat with i from 1 to the count of these_items
          set this_item to (item i of these_items) as alias
          set this_info to info for this_item
          set oldfolder to name of this_info
          set newfolder to replaceText(oldfolder, SS, RS)
          set name of this_info to newfolder
end repeat

From JTextField into string array

hello,
Me and my friend are currently doing a cryptography project for UNI. We are required to read in a word from the JTextField into an array. the problem is the whole word seems to be going into the array as one element. Is there any way to read in each letter in the word into a seperate element of the array??

Well you can always read the value in the textfield, convert it to a character array and then as you transfer each character to your string array you add a blank string to it, so then it becomes a string.
Example:
String sentence = "hello, I am a really loooooooooong string";
String[] stringArray = new String[sentence.length()];
char[] charArray = sentence.toCharArray();
for (int count = 0; count < sentence.length(); count++)
stringArray[count] = charArray[count] + "";I hope this helps.

Search given string array and replace with another string array using Regex

Hi All,
I want to search the given string array and replace with another string array using regex in java
for example,
String news = "If you wish to search for any of these characters, they must be preceded by the character to be interpreted"
String fromValue[] = {"you", "search", "for", "any"}
String toValue[] = {"me", "dont search", "never", "trip"}
so the string "you" needs to be converted to "me" i.e you --> me. Similarly
you --> me
search --> don't search
for --> never
any --> trip
I want a SINGLE Regular Expression with search and replaces and returns a SINGLE String after replacing all.
I don't like to iterate one by one and applying regex for each from and to value. Instead i want to iterate the array and form a SINGLE Regulare expression and use to replace the contents of the Entire String.
One Single regular expression which matches the pattern and solve the issue.
the output should be as:
If me wish to don't search never trip etc...,
Please help me to resolve this.
Thanks In Advance,
Kathir

As stated, no, it can't be done. But that doesn't mean you have to make a separate pass over the input for each word you want to replace. You can employ a regex that matches any word, then use the lower-level Matcher methods to replace the word or not depending on what was matched. Here's an example: import java.util.*;
import java.util.regex.*;
public class Test
static final List<String> oldWords =
 Arrays.asList("you", "search", "for", "any");
static final List<String> newWords =
 Arrays.asList("me", "dont search", "never", "trip");
public static void main(String[] args) throws Exception
 String str = "If you wish to search for any of these characters, "
 + "they must be preceded by the character to be interpreted";
 System.out.println(doReplace(str));
public static String doReplace(String str)
 Pattern p = Pattern.compile("\\b\\w+\\b");
 Matcher m = p.matcher(str);
 StringBuffer sb = new StringBuffer();
 while (m.find())
 int pos = oldWords.indexOf(m.group());
 if (pos > -1)
 m.appendReplacement(sb, "");
 sb.append(newWords.get(pos));
 m.appendTail(sb);
 return sb.toString();
} This is just a demonstration of the technique; a real-world solution would require a more complicated regex, and I would probably use a Map instead of the two Lists (or arrays).

Getting one character at a certain position from a string array

Hi, i'm new at learning java, but have strong experience at C++ and asm. How would i get one character at a certain positon from a string array.
for example:
String Phrases[] = {"To be or not to be, that is the question","The Simpsons","The Mole","Terminator three rise of the machines","The matrix"};
that is my string array above.
lets say i wanted to get the first character from the first element of the array which is "T", how would i get this

ok well that didn't work, but i found getChars function can do what i want. One problem, how do i check the contents of char array defined as char Inchar[];

Replacing a special character in a string with another string

Hi
I need to replace a special character in a string with another string.
Say there is a string - "abc's def's are alphabets"
and i need to replace all the ' (apostrophe) with &apos& ..which should look like as below
"abc&apos&s def&apos&s are alphabets" .
Kindly let me know how this requirement can be met.
Regards
Sukumari

REPLACE
Syntax Forms
Pattern-based replacement
1. REPLACE [{FIRST OCCURRENCE}|{ALL OCCURRENCES} OF]
pattern
          IN [section_of] dobj WITH new
          [IN {BYTE|CHARACTER} MODE]
          [{RESPECTING|IGNORING} CASE]
          [REPLACEMENT COUNT rcnt]
          { {[REPLACEMENT OFFSET roff]
             [REPLACEMENT LENGTH rlen]}
          | [RESULTS result_tab|result_wa] }.
Position-based replacement
2. REPLACE SECTION [OFFSET off] [LENGTH len] OF dobj WITH new
                  [IN {BYTE|CHARACTER} MODE].
Effect
This statement replaces characters or bytes of the variable dobj by characters or bytes of the data object new. Here, position-based and pattern-based replacement are possible.
When the replacement is executed, an interim result without a length limit is implicitly generated and the interim result is transferred to the data object dobj. If the length of the interim result is longer than the length of dobj, the data is cut off on the right in the case of data objects of fixed length. If the length of the interim result is shorter than the length of dobj, data objects of fixed length are filled to the right with blanks or hexadecimal zeroes. Data objects of variable length are adjusted. If data is cut off to the right when the interim result is assigned, sy-subrc is set to 2.
In the case of character string processing, the closing spaces are taken into account for data objects dobj of fixed length; they are not taken into account in the case of new.
System fields
sy-subrc Meaning
0 The specified section or subsequence was replaced by the content of new and the result is available in full in dobj.
2 The specified section or subsequence was replaced in dobj by the contents of new and the result of the replacement was cut off to the right.
4 The subsequence in sub_string was not found in dobj in the pattern-based search.
8 The data objects sub_string and new contain double-byte characters that cannot be interpreted.
Note
These forms of the statement REPLACE replace the following obsolete form:
REPLACE sub_string WITH
Syntax
REPLACE sub_string WITH new INTO dobj
        [IN {BYTE|CHARACTER} MODE]
        [LENGTH len].
Extras:
1. ... IN {BYTE|CHARACTER} MODE
2. ... LENGTH len
Effect
This statement searches through a byte string or character string dobj for the subsequence specified in sub_string and replaces the first byte or character string in dobj that matches sub_string with the contents of the data object new.
The memory areas of sub_string and new must not overlap, otherwise the result is undefined. If sub_string is an empty string, the point before the first character or byte of the search area is found and the content of new is inserted before the first character.
During character string processing, the closing blank is considered for data objects dobj, sub_string and new of type c, d, n or t.
System Fields
sy-subrc Meaning
0 The subsequence in sub_string was replaced in the target field dobj with the content of new.
4 The subsequence in sub_string could not be replaced in the target field dobj with the contents of new.
Note
This variant of the statement REPLACE will be replaced, beginning with Release 6.10, with a new variant.
Addition 1
... IN {BYTE|CHARACTER} MODE
Effect
The optional addition IN {BYTE|CHARACTER} MODE determines whether byte or character string processing will be executed. If the addition is not specified, character string processing is executed. Depending on the processing type, the data objects sub_string, new, and dobj must be byte or character type.
Addition 2
... LENGTH len
Effect
If the addition LENGTH is not specified, all the data objects involved are evaluated in their entire length. If the addition LENGTH is specified, only the first len bytes or characters of sub_string are used for the search. For len, a data object of the type i is expected.
If the length of the interim result is longer than the length of dobj, data objects of fixed length will be cut off to the right. If the length of the interim result is shorter than the length of dobj, data objects of fixed length are filled to the right with blanks or with hexadecimal 0. Data objects of variable length are adapted.
Example
After the replacements, text1 contains the complete content "I should know that you know", while text2 has the cut-off content "I should know that".
DATA:   text1      TYPE string       VALUE 'I know you know',
        text2(18) TYPE c LENGTH 18 VALUE 'I know you know',
        sub_string TYPE string       VALUE 'know',
        new        TYPE string       VALUE 'should know that'.
REPLACE sub_string WITH new INTO text1.
REPLACE sub_string WITH new INTO text2.

Replace a character in a String array

Similar Messages

Maybe you are looking for