Replacing a character in a string to another character

hi,
i need to write a function or procedure to replace the character of a string value suppose:
l_error:= 'abcdefghijklmnop' is a string
i need write a function or procedure to replace the character "c" to "z"
that data in l_error is not in any table.
thanks,
AJ

I want to Replace all the Existence of the word - "Test" in a string with "Test1" whereever a space exits before the word Test and someother alphabet after "Test" i.e. Test will be replaced with Test1 if a word starts with Test and contains more alphabets also. For example - TestName should be replaced with Test1Name while MyTest should not be updated to MyTest1.
I have tried to use below query which uses oracle regular expressions -
SELECT REGEXP_REPLACE('MYCOMPANY TEST TESTGEET INDIA PVT LTD TEST','\s(TEST)\w',' TEST1') FROM DUAL
Output -
"MYCOMPANY TEST *TEST1EET* INDIA PVT LTD TEST"
Here, it has also replaced the G also from TESTGEET and resulted in TEST1EET while i want TEST1GEET.
Can someone please suggest how can i do this..... may b m doing some silly mistake but sorry m a newbie to regular expression...
Thanks in advance..

Similar Messages

Replaces all occurnces of one String with another String in a given source

Hi all I had found that there is a lot of interest int this topic. there is a little piece of code that I wrote for myself recently, so I fgigured that it might be helpful for some...
This method will scan through a string "source", find all of the occurances of a String "before" and replace them with the "after".
Enjoy :-)
public static String replace(String source, String before, String after)
StringBuffer sb = new StringBuffer(source);
int startpos = source.indexOf(before);
int endpos = startpos + before.length();
int i = startpos;
while( i > -1 )
 if( startpos > -1 && endpos <= source.length() )
 source = sb.replace(startpos, endpos, after).toString();
 int lastReplace = source.lastIndexOf(after) + after.length();
 if(lastReplace <= source.length())
 startpos = source.substring(lastReplace, source.length() ).indexOf(before);
 endpos = startpos + before.length();
 i = startpos;
 else
 i = source.length();
 else
 i = -1;
return source;
Oh yeah if you want, you can visit my site http://www.infobrokery.com it is where this code is used to replace the text URL with html.

Since 1.4 the String class has a replaceAll method ...

Stepping through a query result set, replacing one string with another.

I want to write a function that replaces the occurance of a string with another different string. I need it to be a CF fuction that is callable from another CF function. I want to "hand" this function an SQL statement (a string) like this: (Please note, don't bother commenting that "there are eaiser ways to write this SQL..., I've made this simple example to get to the point where I need help. I have to use a "sub_optimal" SQL syntax just to demonstrate the situation)
Here is the string I want to pass to the function:
SELECT
[VERYLONGTABLENAME].FIRST_NAME,
[VERYLONGTABLENAME].LAST_NAME,
[VERYLONGTABLENAME].ADDRESSS
FROM
LONGTABLENAME [VERYLONGTABLENAME]
Here is the contents of the ABRV table:
TBL_NM, ABRV 
VERYLONGTABLENAME, VLTN
SOMEWHATLONGTALBENAME, SLTN
MYTABLENAME, MTN
ATABLENAME, ATN
The function will return the original string, but with the abreviations in place of the long table names, example:
SELECT
VLTN.FIRST_NAME,
VLTN.LAST_NAME,
VLTN.ADDRESSS
FROM
LONGTABLENAME VLTN
Notice that only the table names surrounded by brackets and that match a value in the ABRV table have been replaced. The LONGTABLENAME immediately following the FROM is left as is.
Now, here is my dum amatuer attempt at writing said function: Please look at the comment lines for where I need help.
 <cffunction name="AbrvTblNms" output="false" access="remote" returntype="string" >
 <cfargument name="txt" type="string" required="true" />
 <cfset var qAbrvs=""> 
 <cfset var output_str="#txt#"> 
 <cfquery name="qAbrvs" datasource="cfBAA_odbc" result="rsltAbrvs">
 SELECT TBL_NM, ABRV FROM BAA_TBL_ABRV ORDER BY 1
 </cfquery>
 
 <cfloop index="idx_str" list="#qAbrvs#"> 
 <cfset output_str = Replace(output_str, "#idx_str#", ) 
 </cfloop> 
 
 <cfreturn output_txt>
 </cffunction>
I'm mainly struggling with syntax here. I know what I want to happen, I know how to make it happen in another programming language, just not CF9. Thanks for any help you can provide.

RedOctober57 wrote:...
Thanks for any help you can provide.
One:
<cfset var output_str="#txt#"> 
No you do not need to create a local variable that is a copy of the arguments variable as the arguments scope is already local to the function, but you do not properly reference the arguments scope, so you leave yourself open to using a 'txt' variable in another scope. Thus the better practice would be to reference "arguments.txt" where you need to.
Two:
I know what I want to happen, I know how to make it happen in another programming language, just not CF9.
Then a better start would be to descirbe what you want to happen and give a simple example in the other programming language. Most of us are muti-lingual and can parse out clear and clean code in just about any syntax.
Three:
<cfloop index="idx_str" list="#qAbrvs#"> 
I think you want to be looping over your "qAbrvs" record set returned by your earlier query, maybe.
<cfloop query="qAbrvs">
Four:
<cfset output_str = Replace(output_str, "#idx_str#", ) 
Continuing on that assumption I would guess you want to replace each instance of the long string with the short string form that record set.
<cfset output_str = Replace(output_str,qAbrs.TBLNM,qAbrs.ABRV,"ALL")>
Five:
</cfloop> 
If this is true, then you are looping over the record set of tablenames and abreviations that you want to replace in the string.

Replacing a special character in a string with another string

Hi
I need to replace a special character in a string with another string.
Say there is a string - "abc's def's are alphabets"
and i need to replace all the ' (apostrophe) with &apos& ..which should look like as below
"abc&apos&s def&apos&s are alphabets" .
Kindly let me know how this requirement can be met.
Regards
Sukumari

REPLACE
Syntax Forms
Pattern-based replacement
1. REPLACE [{FIRST OCCURRENCE}|{ALL OCCURRENCES} OF]
pattern
          IN [section_of] dobj WITH new
          [IN {BYTE|CHARACTER} MODE]
          [{RESPECTING|IGNORING} CASE]
          [REPLACEMENT COUNT rcnt]
          { {[REPLACEMENT OFFSET roff]
             [REPLACEMENT LENGTH rlen]}
          | [RESULTS result_tab|result_wa] }.
Position-based replacement
2. REPLACE SECTION [OFFSET off] [LENGTH len] OF dobj WITH new
                  [IN {BYTE|CHARACTER} MODE].
Effect
This statement replaces characters or bytes of the variable dobj by characters or bytes of the data object new. Here, position-based and pattern-based replacement are possible.
When the replacement is executed, an interim result without a length limit is implicitly generated and the interim result is transferred to the data object dobj. If the length of the interim result is longer than the length of dobj, the data is cut off on the right in the case of data objects of fixed length. If the length of the interim result is shorter than the length of dobj, data objects of fixed length are filled to the right with blanks or hexadecimal zeroes. Data objects of variable length are adjusted. If data is cut off to the right when the interim result is assigned, sy-subrc is set to 2.
In the case of character string processing, the closing spaces are taken into account for data objects dobj of fixed length; they are not taken into account in the case of new.
System fields
sy-subrc Meaning
0 The specified section or subsequence was replaced by the content of new and the result is available in full in dobj.
2 The specified section or subsequence was replaced in dobj by the contents of new and the result of the replacement was cut off to the right.
4 The subsequence in sub_string was not found in dobj in the pattern-based search.
8 The data objects sub_string and new contain double-byte characters that cannot be interpreted.
Note
These forms of the statement REPLACE replace the following obsolete form:
REPLACE sub_string WITH
Syntax
REPLACE sub_string WITH new INTO dobj
        [IN {BYTE|CHARACTER} MODE]
        [LENGTH len].
Extras:
1. ... IN {BYTE|CHARACTER} MODE
2. ... LENGTH len
Effect
This statement searches through a byte string or character string dobj for the subsequence specified in sub_string and replaces the first byte or character string in dobj that matches sub_string with the contents of the data object new.
The memory areas of sub_string and new must not overlap, otherwise the result is undefined. If sub_string is an empty string, the point before the first character or byte of the search area is found and the content of new is inserted before the first character.
During character string processing, the closing blank is considered for data objects dobj, sub_string and new of type c, d, n or t.
System Fields
sy-subrc Meaning
0 The subsequence in sub_string was replaced in the target field dobj with the content of new.
4 The subsequence in sub_string could not be replaced in the target field dobj with the contents of new.
Note
This variant of the statement REPLACE will be replaced, beginning with Release 6.10, with a new variant.
Addition 1
... IN {BYTE|CHARACTER} MODE
Effect
The optional addition IN {BYTE|CHARACTER} MODE determines whether byte or character string processing will be executed. If the addition is not specified, character string processing is executed. Depending on the processing type, the data objects sub_string, new, and dobj must be byte or character type.
Addition 2
... LENGTH len
Effect
If the addition LENGTH is not specified, all the data objects involved are evaluated in their entire length. If the addition LENGTH is specified, only the first len bytes or characters of sub_string are used for the search. For len, a data object of the type i is expected.
If the length of the interim result is longer than the length of dobj, data objects of fixed length will be cut off to the right. If the length of the interim result is shorter than the length of dobj, data objects of fixed length are filled to the right with blanks or with hexadecimal 0. Data objects of variable length are adapted.
Example
After the replacements, text1 contains the complete content "I should know that you know", while text2 has the cut-off content "I should know that".
DATA:   text1      TYPE string       VALUE 'I know you know',
        text2(18) TYPE c LENGTH 18 VALUE 'I know you know',
        sub_string TYPE string       VALUE 'know',
        new        TYPE string       VALUE 'should know that'.
REPLACE sub_string WITH new INTO text1.
REPLACE sub_string WITH new INTO text2.

How to replace a character in a string with blank space.

Hi,
How to replace a character in a string with blank space.
Note:
I have to change string CL_DS_1===========CM01 to CL_DS_1 CM01.
i.e) I have to replace '=' with ' '.
I have already tried with REPLACE ALL OCCURRENCES OF '=' IN temp_fill_string WITH ' '
Its not working.

Hi,
Try with this..
call method textedit- >replace_all
exporting
 case_sensitive_mode = case_sensitive_mode
 replace_string = replace_string
 search_string = search_string
 whole_word_mode = whole_word_mode
changing
 counter = counter
exceptions
 error_cntl_call_method = 1
 invalid_parameter = 2.
Parameters Description Possible values
case_sensitive_mode Upper-/lowercase false Do not observe (default value)
 true Observe
replace_string Text to replace the
 occurrences of
 SEARCH_STRING
search_string Text to be replaced
whole_word_mode Only replace whole words false Find whole words and
parts of words (default
value)
 true Only find whole words
counter Return value specifying how
 many times the search string
 was replaced
Regards,
Jayaram...

Replace a character in a String array

I have an array of strings and am trying to replace the ' character with a space. I keep getting either a cannot be applied or cannot resolve symbol error. Can anyone help?
String arrayList = request.getParameter("field");
String newList = arrayList.replace("\'", " ");

the replace method of the String class takes two parameters and both of them are characters not strings use it like this
arrayList.replace('\'', ' ');that should fix it

Replacing the \ character in a string

I'm having trouble replacing a backslash in a string. I use .indexOf() to find the character, but I have to use an escape character and write .index("\\"), but it doesn't work - it returns -1.
Also, replace() doesn't work - gives me an java.util.regex.PatternSyntaxException. Any ideas?
thx

The escape is for the compiler, I think, and then you need to escape the backslash.
Try "\\\\".
� {�

Replacing a character in a String

Hi All,
How can I replace a character ' which appears in a String into \'

There is a method in String that replaces all
occurrences of one character with anothercharacter.
It's called, hold your breath now, "replace".But tho OP wants to replace one character with two
characters :)You're right, I missed that. Well, serves me right for being sarcastic. :-)

Is there an easy way to replace individual elements in one string array from another striing array?

I have a string array with elements as follows:
   00 00 00 00 00 00 00 00
   00 00 00 00 00 00 00 00
   00 00 00 00 5E 00 00 00
   00 00 50 00 30 00 33 00
   34 00 39 00 00 00 00 00
   00 00 00 00 00 00 00 00
   00 00 00 00 00 00 00 00
The array I want to use to replace values with is:
43 4E 31 30 30 33 30 30 31 41
Where 43 goes in the 3rd row fifth position
Where 4E goes in the 3rd row seventh position
Where 31 goes in the 4th row first position
Where 30 goes in the 4th row third position
Where 30 goes in the 4th row fifth position
Where 33 goes in the 4th row seventh position
Where 30 goes in the 5th row first position
Where 30 goes in the 5th row third position
Where 31 goes in the 5th row fifth position
Where 41 goes in the 5th row seventh position
So the final array looks as follows:
   00 00 00 00 00 00 00 00
   00 00 00 00 00 00 00 00
   00 00 00 00 43 00 4E 00
   31 00 30 00 30 00 33 00
   30 00 30 00 31 00 41 00
   00 00 00 00 00 00 00 00
   00 00 00 00 00 00 00 00
Is there an easy way to replace an element of a string within an array with another element of a string within a different array?
Thank you.
Solved!
Go to Solution.
Attachments:
CMM_Add_SCAN_SN_2_PAT_DATA (temp).vi ‏13 KB

Try this
Omar
Message Edited by Omar II on 03-24-2010 03:25 PM
Omar
Attachments:
CMM_Add_SCAN_SN_2_PAT_DATA%20(temp)[1].vi ‏17 KB

Replace a string with another string in a file

I have to replace a string with another string. Say for example in a html file it got a line like,
<a href="##"></a>
now i want to replace this ## with the full derived path like
"c;\\sample folder\\sample subfolder\\samplefile.html"
can someone help me to do this?
pls tell me from the file opening till closing the file.

I have to replace a string with another string. Say
for example in a html file it got a line like,
<a href="##"></a>
now i want to replace this ## with the full derived
path like
"c;\\sample folder\\samplesubfolder\\samplefile.html"
can someone help me to do this?
pls tell me from the file opening till closing the
file.
public class Buckel {
final static String CONST = "c:\\sample folder\\samplesubfolder\\samplefile.html";
public Buckel() {
public static void main ( String[] argv ) throws Exception {
 int idx = 0;
 String in = "<a href=\"##\"></a>", // We'll imagine this just gets here somehow. If it's on the i/p file then take the '\' out B4 and aft the '##'.
 out = "";
 idx = in.indexOf( "##" );
 if ( idx > 0 ) {
 out = in.substring( 0, idx ) + CONST + in.substring( idx+=2, in.length() );
 System.out.println( out );
}

Find/Replace Extended Character Set characters in filenames in one pipeline

Hello all,
I have to work with some very bored people. Instead of putting a dash (hex 2d) into a filename, they opt for something from this
set of extended characters, which makes my regular expressions fail. IS there a way I can efficiently find & replace anything outside the standard character set
in one pipelinewithout finding and replacing a character at a time?
So,I'd like something like:
get-childitem * | where-object $_.name -match '\x99' | rename-item -newname { $_.name -replace '\x99','='}
from hex 80 to hex FF rather than a for-each.
Thanks.

Answer would depend on the way you want to replace... Easier if you want replace any char in set with selected char:
$Name = -join (180..190|%{[char]$_})
New-Item -ItemType File -Name $Name
Get-ChildItem * | Rename-Item -NewName {
[regex]::Replace(
$_.Name,
'[\xB4-\xBE]',
} -WhatIf
But if you want it more complicated, you may do that too. E.g. defining hashtable that can be used to replace individual elements:
$Replacer = @{}
foreach ($Char in (180..190 | % { [char]$_ })) {
$Replacer.Add(
[string]$Char,
(echo _, -, =, . | Get-Random)
$Replacer
Get-ChildItem * | Rename-Item -NewName {
[regex]::Replace(
$_.Name,
'[\xB4-\xBE]',
$Replacer[$args[0].Value]
} -WhatIf
Using this syntax make it possible to include some logic in replace. E.g. you could easily use switch to decide what to do with given string:
Get-ChildItem * | Rename-Item -NewName {
[regex]::Replace(
$_.Name,
'[\xB4-\xBE]',
switch ($args[0].Value) {
º { "0" }
µ { "u" }
¹ { "1" }
¸ { "," }
Default { "_" }
} -WhatIf

Replace a character

Hi all
I have a ascii file should I replace a character with another. How can I do with form?
regards
Silvia

Open the file with a text editor would be the simplest solution:
client_host('cmd /c start myfile.txt');
The start command will cause the default application that is associated with the txt extension to open the file.

Replace single character and leave the ones in expressions

Hi,
I'm looking for nice and elegant solution to my problem. Let's say I have a string "e+exp(e)". I want to replace all "e" with "1", excepts the one in "exp". I was trying to use regular expressions but I've failed after an hour... The solution should be able to solve things like replace "a" in "rand(a)" without changing rand. Basically I need to replace single character without replacing the ones in words/expressions.
Any ideas?
Certified LabVIEW Developer, Certified TestStand Developer
Solved!
Go to Solution.

No time for elegance right now, just brute force. I would pad the string with spaces on each end to remove end cases and then search for the character surrounded by non-word characters.
Message Edited by Darin.K on 04-14-2010 04:06 PM
Attachments:
VariableParsingRegex.png ‏18 KB

Replace Number of Occurences in String

Hi All,
I just wanted to know what is the best way to replace a string within another string for certain number of times.
I dont want to replace only the first one.
I dont want to replace all of them either.
i'm looking for something like this:
replace(input_str, old_str, new_str, nb_occurences)
e.g: replace("1xxxx0xxxx4","xx",HH,3) should print 1HHHH0HHxx4
Thanks a lot in advance.

Better to use regex. I'd throw this away.Actually, he is using regex, but that just makes it worse. I'd throw it away, too.
What's wrong with java.lang.String's replaceAll method?He's doing a specific number of replacements, i.e., more than one, but not all.
There's so much wrong with that code, all I can say is to re-read the last line of my previous reply and DON'T USE RECURSION! Also, please abide by the Java naming conventions: method and variable names should start with lowercase letters and should always use camelCase, not under_scores. In the meantime, here's a somewhat radical solution: public class Test
public static void main(String... args)
 String str = "One and two and three and four and five";
 System.out.println(replaceSome(str, "and", "OR", 0));
 System.out.println(replaceSome(str, "and", "OR", 2));
 System.out.println(replaceSome(str, "and", "OR", 3));
 System.out.println(replaceSome(str, "and", "OR", -1));
static String replaceSome(String orig, String oldStr, String newStr, int reps)
 String[] parts = orig.split("\\Q" + oldStr + "\\E", reps + 1);
 int n = parts.length - 1;
 if (n > 0)
 StringBuilder sb = new StringBuilder();
 for (int i = 0; i < n; i++)
 sb.append(parts).append(newStr);
sb.append(parts[n]);
return sb.toString();
else
return parts[0];

Replacing Unicode characters in a String

I have a text as a String and in this text which is foreign language appears sometimes characters in Unicode format as &#246; or &#214;
The question is, how can I convert this String so these Unicode characters would become readable characters.
Thank you for any lead...

:-) Interesting - twice in 10 minutes I'm recommending the use of Elliott Hughes' class. See http://elliotth.blogspot.com/2004/07/java-implementation-of-rubys-gsub.html .
You just have to write a regular expression to match the terms ( "&#(\\\d+)"), extract the number as a string (group(1)) then use the Integer.parseInt(the numeric string) and cast to a char.
Edited by: sabre150 on Feb 9, 2012 9:53 AM
This is an example I wrote a couple of years ago (and published on the old Sun site forums) that does pretty much exactly what you need
import e.util.Rewriter;
public class Sabre20090919
    public static void main(String[] args) throws Exception
        String title = "& #26412;& #26399;& #28136;& #21033;\n" +
                "& #22522;& #26412;& #27599;& #32929;& #30408;& #39192;\n" +
                "& #32380;& #32396;& #29151;& #26989;& #21934;& #20301;& #28136;& #21033;\n" +
                "& #26371;& #35336;& #21407;& #21063;& #35722;& #21205;& #32047;& #31309;& #24433;& #38911;& #25976;\n" +
                "& #26222;& #36890;& #32929;& #27599;& #32929;& #30408;& #39192;\n" +
                "& #31232;& #37323;& #27599;& #32929;& #30408;& #39192;\n";
        Rewriter rewriter = new Rewriter("&\\s*#(\\d+);")
            @Override
            public String replacement()
                return Character.toString((char) Integer.parseInt(group(1)));
        title = rewriter.rewrite(title);
        System.out.println(title);
        System.out.print("Unicode :\"");
        for (char ch : title.toCharArray())
            System.out.printf("\\u%04x", (int) ch);
        System.out.println("\"");
        byte[] asBytes = title.getBytes("big5");
        for (byte b : asBytes)
            System.out.printf("%02x ", (int) (b & 0xff));
        System.out.println();
}The rest is just a test harness.
Edited by: sabre150 on Feb 9, 2012 10:02 AM
Removed redundant code

Replacing a character in a string to another character

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