Replacing the \ character in a string

I'm having trouble replacing a backslash in a string. I use .indexOf() to find the character, but I have to use an escape character and write .index("\\"), but it doesn't work - it returns -1.
Also, replace() doesn't work - gives me an java.util.regex.PatternSyntaxException. Any ideas?
thx

The escape is for the compiler, I think, and then you need to escape the backslash.
Try "\\\\".
� {�

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Replacing a character in a string to another character

hi,
i need to write a function or procedure to replace the character of a string value suppose:
l_error:= 'abcdefghijklmnop' is a string
i need write a function or procedure to replace the character "c" to "z"
that data in l_error is not in any table.
thanks,
AJ

I want to Replace all the Existence of the word - "Test" in a string with "Test1" whereever a space exits before the word Test and someother alphabet after "Test" i.e. Test will be replaced with Test1 if a word starts with Test and contains more alphabets also. For example - TestName should be replaced with Test1Name while MyTest should not be updated to MyTest1.
I have tried to use below query which uses oracle regular expressions -
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Here, it has also replaced the G also from TESTGEET and resulted in TEST1EET while i want TEST1GEET.
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How to replace a character in a string with blank space.

Hi,
How to replace a character in a string with blank space.
Note:
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Try with this..
call method textedit- >replace_all
exporting
 case_sensitive_mode = case_sensitive_mode
 replace_string = replace_string
 search_string = search_string
 whole_word_mode = whole_word_mode
changing
 counter = counter
exceptions
 error_cntl_call_method = 1
 invalid_parameter = 2.
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 SEARCH_STRING
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Replace a character in a String array

I have an array of strings and am trying to replace the ' character with a space. I keep getting either a cannot be applied or cannot resolve symbol error. Can anyone help?
String arrayList = request.getParameter("field");
String newList = arrayList.replace("\'", " ");

the replace method of the String class takes two parameters and both of them are characters not strings use it like this
arrayList.replace('\'', ' ');that should fix it

How to replace the '&' character with '&' in xi

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Replace a character in a string

Hi,
I've been tearing my hair out trying to do something very simple, replace a backslash character in a string with an underscore. I've searched online and discovered the -replace parameter which you would think would work fine but no, it seems to get in a
tizzy because the character I want to replace is a backslash and I get an error: "Invalid regualr expression pattern".
Here's what I have which produces the error:
$str = 'start\end'
$str = $str -replace '\','_'
Can someone tell me how to do this? I simply want to replace a backslash with an underscore.
thanks
Jamie
http://sqlblog.com/blogs/jamie_thomson/ |
@jamiet |
About me

sod's law. I spend half an hour trying to figure this out and then as soon as I post this thread I figure it. The following works:
$str = 'start\end'
$str = $str -replace '\\','_'
$str
http://sqlblog.com/blogs/jamie_thomson/ |
@jamiet |
About me
"-replace" requires a regular expression for each argument, which is why you needed to escape your backslash with another backslash. If you use the replace() string method, you are not required to use regular expressions:
$str = $str.replace('\','_') will work exactly as you expect it to.

Replace a character from a string

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If you are in 9i:
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<cfif url.age eq 1>
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<cfswitch expression="#compareOperator#">
<cfcase value="less">
<
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>
</cfcase>
<cfcase value="between">
BETWEEN
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<cfdefaultcase>
=
</cfdefaultcase>
</cfswitch>
#askAge#
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Better answers available on the SQL-PLSQL forum. PL/SQL
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How to replace a character in a string

Hello Powerusers
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Okay i solved my problem but why arent the folder renamed?
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SQL> set line 1000
SQL> l
1     SELECT ename
2          , Letter_repetition
3          , COUNT(*)repetition_count
4     FROM ( SELECT ename
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6                FROM emp
7               MODEL
8                     RETURN UPDATED ROWS
9                     PARTITION BY (ename)
10                     DIMENSION BY (0 i)
11                     MEASURES (ename Letter_repetition)
12                     ( Letter_repetition[FOR i FROM 1 TO
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17      GROUP BY ename
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ENAME                               LETTER_REPETITION                   REPETITION_COUNT
SCOTT                               T                                                  2
TURNER                              R                                                  2
ALLEN                               L                                                  2
MILLER                              L                                                  2
ADAMS                               A                                                  2
SQL>

Replacing the \ character in a string

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