Retreiving number and characters from string

Hello fellow developers,
Lets say i have the following string ER686 and want to split the string into a number and characterpart resulting in a String "ER" and an int "686". What is the best approach to accomplish this?
Thank you for any help offered.

The format is that there's a sequence of strings 2 or
3 and a squence of numbers 3 or 4You might use a Pattern matcher, using a regular expression like the following :"(\\D{2,3})(\\d{3,4})"This expressions represents "two or three non-digit characters followed by 3 or 4 digits". The parenthesis are here to allow getting the two elements (groups) separately.
Use the find() method of the matcher, then retrieve the two groups with group(1) and group(2).
Eventually, parse the latter if required.

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Removing non-numeric characters from string

Hi there,
I need to have the ability to remove non-numeric characters from a string and I do not know how to do this.
Does any one know a way?
Example:
Present String: (02)-2345-4607
Required String: 0223454607
Thanks in advance

Dear NickM
Try this this will work...........
create or replace function char2num(mstring in varchar2) return integer
is
-- Function to remove Special characters and alphebets from phone no. string field
-- Author - Valid Bharde.(India-Mumbai)
-- Date :- 20 Sept 2006.
-- This Function will return numeric representation.
-- The Folowing program is gifted to NickM with respect to his post on oracle site regarding Removing non-numeric characters from string on the said date
mstatus number :=0;
mnum number:=0;
mrefstring varchar2(50);
begin
mnum := length(mstring);
for x in 1..mnum loop
if (ASCII(substr(upper(mstring),x,1)) >= 48 and ASCII(substr(upper(mstring),x,1)) <= 57) then
mrefstring := mrefstring || substr(mstring,x,1);
end if;
end loop;
return mrefstring;
end;
copy the above program and use it at function for example
SQL> select char2num('(022)-453452781') from dual;
CHAR2NUM('(022)-453452781')
22453452781
Chao!!!

Reading in a certain number of characters from a file.

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I need some pointers on how to read in a specified number of characters from a text file.For example,how would I read in the first 100 characters to an array from a text file with an unspecfied number of characters (more than 100 rather than less!).
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java.lang.ArrayIndexOutOfBoundsException: 100.

post more code , this exception tells me nothing
without seeing what you are actually doing.
public String getText (String file)//textfile to be analyzed will be inputted as argument 150407 0356
   //15042007 0612 Check notes on overloaded getText method below.
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How to get customer number and name from the SD document

Hi All,
Can you please let me know how to get Customer Number and Name from the SD Document?
Thanks a lot....
Anil

Hi,
It will be displayed in the SD (BIlling document) itself, you clikc on the VF03. The customer name and number will also appear in the SO document also Tcode VA03
regards,
radhika
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Does LabView program behave differently under Traditional Chinese version from regular English version. The program reads in numbers and characters from input files.

Does LabView program behave differently under Traditional Chinese version from regular English version. The program reads in numbers and characters from input files.

Hope this helps,
Ankita

Day of year bug - format date/time string and scan from string?

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(I'm using Labview 2010 Service Pack 1)

I think the best idea is to use seconds since for your arithmetic, because it is going to be the most consistent and robust solution. Knowing that a day has 86400 seconds is all that is needed and you won't run in possible inconsistencies with date time implementations caused by our anything but logic calender. I would hazard that the functionality of converting a timestamp into year and day of year and back is impossible to make consistent without sacrificing other possibly conflicting transformation in the Timestamp into String and Timestamp from String manipulations.
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a division of Test & Measurement Solutions

Removing number of characters from end of string

Hi all....
Dooza very kindly helped me with trimming a string in an
earlier post, but
now i want to remove the last four characters from a string.
I really should know how to do this and will have to do some
bedtime reading
:-|
But, for now, could someone help!
Thanks
Andy

Ah Dooza - Thank You.
To the rescue again :-D
You're helping me to see the logic...
Thanks Again
Andy
"Dooza" <[email protected]> wrote in message
news:gbafel$ra3$[email protected]..
> Andy wrote:
>> Hi all....
>> Dooza very kindly helped me with trimming a string
in an earlier post,
>> but now i want to remove the last four characters
from a string.
>> I really should know how to do this and will have to
do some bedtime
>> reading :-|
>>
>> But, for now, could someone help!
>
> Hi Andy,
> Try something like this:
> <%
> myStr = "this is my really long string"
> Response.Write(LEFT(myStr,LEN(myStr) -4))
> %>
>
> Dooza

Return selected number of characters from a string

How do you select a certain number of charaters from a string?
For example:
I have a string that contains 51-108
I want to separate the string into two strings one containing 51 and another one containing 108.

A StringTokenizer will do it.
StringTokenizer strtok = new StringTokenizer(yourString, "-");

Removing characters from string after a certain point

Im very new to java programming, so if this is a realy stupid question, please forgive me
I want to remove all the characters in my string that are after a certain character, such as a backslash. eg: if i have string called "myString" and it contains this:
109072\We Are The Champions\GEMINI
205305\We Are The Champions\Queen
4416\We Are The Champions\A Knight's Tale
a00022723\We Are The Champions\GREEN DAYi would like to remove all the characters after the first slash (109072*\*We...) leaving the string as "109072"
the main problem is that the number of characters before and after is not the always the same, and there is often letters in the string i want, so it cant be separated by removing all letters and leaving the numbers
Is there any way that this can be done?
Thanks in advance for all help.

You must learn to use the Javadoc for the standard classes. You can download it or reference it on line. For example [http://java.sun.com/javase/6/docs/api/java/lang/String.html|http://java.sun.com/javase/6/docs/api/java/lang/String.html].

Strip Characters from String?

Hi,
How can I strip off some characters from the end of a string?
I am not very good at regular expressions but perhaps I may not
need one? Here is the data
first_name_510
last_name_2267
I need a function that will strip off everything from the
right including the underscore. I should be left with the below:
first_name
last_name
Any help highly appreciated
Regards

if it is always an underscore, and always the last one, this
should do
the trick:
#left(string, len(string)-len(listlast(string, "_"))-1)#
string is assumed to be the variable holding your text
Azadi Saryev
Sabai-dee.com
http://www.sabai-dee.com/

Extract 2 characters from string

Hello,
Can anyone help to create a formula to extract 2 characters from the left of "pp" in a field using CR XI?
Field = {MainEstimateDetails.JobDescription} (string)
Sample string details:
"Annual Report 96pp & Cover 12345" - want to be able to show only 96 (from 96pp)
"CTP A4 4pp" - want to be able to show only 4 (from 4pp)
The string length is variable and the "pp" will be in different places each time.
It is probably very simple, but I cannot get it

Hi,
You can use the InStr function for this. InStr returns the position of the string your are looking for.
NumberVar myPosition;
If InStr ({MainEstimateDetails.JobDescription}, "pp") > 0 Then
myPosition := InStr ({MainEstimateDetails.JobDescription}, "pp")
Else myPosition := 0;
If myPosition <> 0 Then
{MainEstimateDetails.JobDescription} [(myPosition - 2) To (myPosition - 1)]
Else "";
This is a bit longer than I would normally do it but... I use Instr to check if the field has "pp" in it. If it does it will return the character position in the field and I pass that to my variable myPosition.
If myPosition has a value then it parses out the two characters before "pp".
Good luck,
Brian

Avoid check for article number and price from ORDRSP inbound

Hi,
i m working on an integration (with PI) of a 3rd party vendor with a SAP ERP (7.1) backend system. The vendor sends a soap message which is transformed by PI to an IDoc ORDRSP.ORDERS05.
The vendor sends a purchase order confirmation but unfortunately without information regarding article number and price. Therefore the IDoc remains in status 51 with 2 errros:
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Is is possible to avoid the check so that the purchase order's article number and price are not updated by the IDoc?
Regards,
Udo

Hi Udo,
This error seems to be explicitly populated into Status records of IDOC processing from the include LEINMF2O, form "CHECK_MATERIAL_PO_IDOC" (For Material) & Include LEINMF2D, form "PRICE_CHANGE".
One way to suppress the error message is to populate the existing values in EKPO table to IDOC segment using enhancment component EXIT_SAPLEINM_007, which is called from include LEINMF2X, line number 113.
Documentation of enhancement component reads
Functionality
Reading of further IDoc segments at the time of acknowledgment receipt.
The current segment is passed on in the parameter segment.
Data can be stored in the structure CUSTOMER_EKPO.
As of Release 4.6A, modification of the program-internal table FEKPO is possible.
This is just a suggestion and don't know how far it will be helpful to your requirement.
Regards
Vinod

Regular expressions-how to replace [ and ] characters from a string

Hi,
my input String is "sdf938 [98033]". Now from this given string, i would like to replace the characters occurring within square brackets to empty string, including the square brackets too.
my output String needs to be "sdf938" in this case.. How should I do it using regular expressions? I tried several possible combinations but didn't get the expected results.

"\\s*\\[[^\\]]+\\]"

Removing last 2 characters from string field

I am trying to remove the last 2 characters of a string field.
there is no consistant length in the field
316R1
12364R1
i want to remove everything after R
i tried instrrev but i that didnt do it.
is there a way to say
start position1 and go the R
thanks

formula,
left (field, length_formula) is the solution
the length_formula is the number of chars form left
f.i
left(field, length (field)-2)
left (field, InstrRev, field,"R")
of course a combination with Right is also possible

Removing unicode control characters from string

Hi.
I have a webservice where I return an object (with some strings) back to the client. The information is read from a database, and the string can sometimes contain invalid xml characters (like unicode 0x13). This results in an error when parsing the information at the client side.
Is there someway a easy way to set up a filter or something that checks whether the string contains characters outside the valid range specified for XML's (lower than unicode 0x20 etc), and removes them/replace them with a different character?

If you have to get rid of the control chars then       String someText = "a\nb\nc\td\re\r\nf";
        String someTextWithoutControlChars = someText.replaceAll( "[\u0000-\u0020]","");
        System.out.println(someTextWithoutControlChars);but like kaj says, some control chars are valid.

Retreiving number and characters from string

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