RH_RELATION_MAINTAIN/RH_INSERT_INFTY

I am trying to insert a new HRP1001 Cost Center record in a program and have been trying to use the above Function Modules. The problem I am having is that when they encounter a CONFIG problem, like the Cost Center is not open for posting, instead of coming back with a Return-Code other than 0 they are giving me the message in real time and actually starting the Transaction (PO02) in the first case and exiting the program in the 2nd case. Neither is an acceptable solution. I want it to just let me know it didn't work and keep going. Is this the way these are supposed to work?

When you are calling your FM give an extra exception parameter ERROR_MESSAGE i.e. = 9.
Now when some message of type I,S, W will be raised it will automatically be skipped. Messages E, A will trigger that error so you can react accordingly outside FM. Message X will dump the systme out.
This way you can handle old function modules which don't use exceptions or simply call some message inside their body. This is a preety handful way to handle such situations.
As for calling tcode PO02 I am not sure about that. If the processing requires that you will likely be branched to this tcode anyway.
Regards
Marcin

Similar Messages

Replacement for RH_RELATION_MAINTAIN

Hello everybody,
I've been using RH_RELATION_MAINTAIN function to create relation between objects for quite a while now.
Problem is that this function is not released, and its hard to trace errors in it.
The function doesnt have a proper error reporting, and sometimes throws an "Action Canceled" error instead of catcheble exceptions.
This leads to an undesired behavior which cannot be caught in code.
Is there another function that does the same operation and Is released / has a proper dump catching ?
thanks in advance,
Eli.

Eli,
Try using any of the below function modules.
1) RH_PNNNN_MAINTAIN
2) RH_RELATION_WRITE
3) RH_INSERT_INFTY_1001_EXT
4) RH_INSERT_INFTY
Regards
Bala

Checking Lock Status of Object before passing it to FM RH_RELATION_MAINTAIN

hi all,
          While passing the object id to FM RH_RELATION_MAINTAIN if object id is locked i.e say open in a standard tcode then,this FM terminates.
          is there any way to detect whether this Object is Locked or not before passing it to FM ??? this way i cud give the status msg that the " given object is locked" without termination the program.

>
Ajay84 wrote:
> hi all,
>           While passing the object id to FM RH_RELATION_MAINTAIN if object id is locked i.e say open in a standard tcode then,this FM terminates.
>
>           is there any way to detect whether this Object is Locked or not before passing it to FM ??? this way i cud give the status msg that the " given object is locked" without termination the program.
Please check the FM 'HR_ENQUEUE_OBJECT', it is well documented.
Regards
Rajesh.

RH_INSERT_INFTY in update mode not working properly

I am calling the FM RH_INSERT_INFTY using IN UPDATE TASK in my Inbound part of my IDOC.
The IDOC is getting generated successfully in the Outbound part but getting errorred out in the Inbound side.
I have checked for the attributes of the FM where the type of FM is NORMAL FUNCTION MODULE.
any pointers on this will be of immense help to me.

This is the output of journalctl --all
May 12 20:55:04 egidiolaptop /usr/lib/gdm/gdm-x-session[19552]: Activating service name='org.gnome.Terminal'
May 12 20:55:04 egidiolaptop /usr/lib/gdm/gdm-x-session[19552]: Successfully activated service 'org.gnome.Terminal'
May 12 20:55:26 egidiolaptop gnome-session[19563]: 1431456926458 addons.update-checker WARN Update manifest for {972ce4c6-7e08-4474-a285-3208198ce6fd} did not contain an updates property
May 12 20:56:03 egidiolaptop systemd[19544]: [/home/egidio/.config/systemd/user/googledrive.service:2] Unknown lvalue 'Type' in section 'Unit'
May 12 20:56:03 egidiolaptop systemd[19544]: Cannot add dependency job for unit network-online.target, ignoring: Unit network-online.target failed to load: No such file or directory.
May 12 20:56:03 egidiolaptop systemd[19544]: Created slice -.slice.
May 12 20:56:03 egidiolaptop systemd[19544]: Starting -.slice.
May 12 20:56:03 egidiolaptop systemd[19544]: Started Google Drive mount.
May 12 20:56:03 egidiolaptop systemd[19544]: Starting Google Drive mount...
May 12 20:56:03 egidiolaptop fusermount[20547]: /usr/bin/fusermount: failed to unmount /home/egidio/Google Drive: Device or resource busy
May 12 20:56:03 egidiolaptop systemd[19544]: googledrive.service: control process exited, code=exited status=1
May 12 20:56:03 egidiolaptop systemd[19544]: Unit googledrive.service entered failed state.
May 12 20:56:03 egidiolaptop systemd[19544]: googledrive.service failed.

Exception Handling in RH_RELATION_MAINTAIN

can we use Try...Catch Blocks for Exception Handling in RH_RELATION_MAINTAIN.....coz i need to Track the Status message
coz most of the times it doesn't CATCH and Exception........and i need to send the status msg via Proxy n PI to the JAVA based system............
So i need to Catch the Exception ................Pls assist................:)
FORM create_a008 USING l_pernr l_plans l_begda
                 CHANGING l_success.
CALL FUNCTION 'RH_RELATION_MAINTAIN'
    EXPORTING
      act_fcode           = 'INSE'
      act_plvar           = '01'
      act_otype           = 'S'
      act_objid           = l_plans
      act_istat           = '1'
      act_rsign           = 'A'
      act_relat           = '008'
      act_sclas           = 'P'
      act_sobid           = l_pernr
      act_begda           = l_begda
      act_endda           = '99991231'
    EXCEPTIONS
      maintainance_failed = 1
      OTHERS              = 2.
IF sy-subrc EQ 0.
    l_success = 'X'.
ELSE.
    CLEAR : l_success.
ENDIF.
ENDFORM.

sdf

RH_INSERT_INFTY is not working in BADI

Hello.
I've got the following issue:
I'm using RH_INSERT_INFTY within a BADI, just to limit a record in INFTOTYPE 1000 and is not working, even i don't get any error messages.
The thing is that i'm using the same function within a single report and works fine, it looks like the behaviour of the FM is different within a BADI (I guess).
Any ideas?

I'm locking the object in a previous form.....
FORM infotipo_1010
            USING p_plaza TYPE objektid
                   p_fecha TYPE datum
                   p_plvar TYPE plvar..
DATA:    l_t_hrp1010         TYPE STANDARD TABLE OF p1010,
           l_t_aux_hrp1010     TYPE STANDARD TABLE OF p1010,
           l_wa_t_hrp1010      TYPE p1010,
           l_wa_t_aux_hrp1010 TYPE p1010,
           l_t_objects         TYPE STANDARD TABLE OF hrobject,
           l_wa_t_objects      TYPE hrobject.
l_wa_t_objects-plvar = p_plvar.
l_wa_t_objects-otype = 'S'.
l_wa_t_objects-objid = p_plaza.
APPEND l_wa_t_objects TO l_t_objects.
CALL FUNCTION 'RH_READ_INFTY'
   EXPORTING
   AUTHORITY                  = 'DISP'
   WITH_STRU_AUTH             = 'X'
     infty                      = '1010'
   ISTAT                      = ' '
   EXTEND                     = 'X'
   SUBTY                      = ' '
   BEGDA                      = '19000101'
   ENDDA                      = '99991231'
   CONDITION                  = '00000'
   INFTB                      = '1'
   SORT                       = 'X'
   VIA_T777D                  = ' '
   TABLES
     innnn                      = l_t_hrp1010
     objects                    = l_t_objects
    EXCEPTIONS
     all_infty_with_subty       = 1
     nothing_found              = 2
     no_objects                 = 3
     wrong_condition            = 4
     OTHERS                     = 5
IF sy-subrc = 0.
    SORT l_t_hrp1010 BY subty endda ASCENDING.
    LOOP AT   l_t_hrp1010
         INTO l_wa_t_hrp1010.
      l_wa_t_aux_hrp1010 = l_wa_t_hrp1010.
      AT END OF subty.
        l_wa_t_aux_hrp1010-endda = p_fecha.
        REFRESH: l_t_aux_hrp1010.
        APPEND l_wa_t_aux_hrp1010 TO l_t_aux_hrp1010.
        CALL FUNCTION 'RH_INSERT_INFTY'
           EXPORTING
             fcode                     = 'CUTI'
             vtask                     = 'B'
           ORDER_FLG                 = 'X'
           COMMIT_FLG                = 'X'
           AUTHY                     = 'X'
           PPPAR_IMP                 =
           OLD_TABNR                 = ' '
           REPID                     = ' '
           FORM                      = ' '
           KEEP_LUPD                 =
           WORKF_ACTV                = 'X'
           TABLES
             innnn                     = l_t_aux_hrp1010
             ilfcode                   = l_t_objects
          EXCEPTIONS
             no_authorization          = 1
             error_during_insert       = 2
             repid_form_initial        = 3
             corr_exit                 = 4
             begda_greater_endda       = 5
             OTHERS                    = 6.
      ENDAT.
    ENDLOOP.
ENDIF.

RH_INSERT_INFTY not creating new records

Hi All,
I am using the FM RH_INSERT_INFTY to insert new records in HRP1000.
See the below FM call :
CALL FUNCTION 'RH_INSERT_INFTY'
     EXPORTING
         fcode               = 'INSE'
         vtask               = 'D'
          order_flg           = 'X'
          commit_flg          = 'X'
          authy               = 'X'
          PPPAR_IMP           =
          OLD_TABNR           = ' '
          REPID               = ' '
          FORM                = ' '
            keep_lupd           = keep_lupd
     TABLES
          innnn               = it_i1000
     EXCEPTIONS
          no_authorization    = 1
          error_during_insert = 2
          repid_form_initial = 3
          corr_exit           = 4
          begda_greater_endda = 5
          OTHERS              = 6.
But instead of creating new records it is changing the existing record in HRP1000.
Actually I want to create new records with different long text and short text in different languages so in case object id and object type even the dates can be same but the language would be different.
So I need to create a new records with a different language key and different short text. But this function module is changing the existing object short text,long text and language.
Could you please reply at the earliest.
Thanks & Regards,
Poonam

Hi,
you're right, this function didn't create new record when i want to create a record with same object but have different language.
you can use this function for your problem : RH_INSERT_INFTY_DIRECT
i tried and it works.
CALL FUNCTION 'RH_INSERT_INFTY_DIRECT'
EXPORTING
    vtask                     = 'V'
KEEP_LUPD                 =
tables
    innnn                     = p1000
EXCEPTIONS
   NO_AUTHORIZATION          = 1
   ERROR_DURING_INSERT       = 2
   REPID_FORM_INITIAL        = 3
   CORR_EXIT                 = 4
   BEGDA_GREATER_ENDDA       = 5
   OTHERS                    = 6
Regards,

RH_INSERT_INFTY

I'm trying to create a new infotype 1028 for one of the object of the structure.
Unfortunatly I cannot use the function module RH_INSERT_INFTY... Is there any other function modules to be used?
data : lit_1028 type standard table of hrp1028,
         lwt_1028 like line of lit_1028.
lwt_1028-begda = c_begda.
lwt_1028-endda = c_endda.
lwt_1028-stras = c_stras.
lwt_1028-hausn = c_hausn.
lwt_1028-pstlz = c_pstlz.
lwt_1028-ort01 = c_ort01.
lwt_1028-land1 = c_land1.
lwt_1028-infty = '1028'.
append lwt_1028 to lit_1028.
call function 'RH_INSERT_INFTY'
    exporting
*   FCODE                     = 'INSE'
      vtask                     = 'S'
*   ORDER_FLG                 = 'X'
*   COMMIT_FLG                = 'X'
    AUTHY                     = space
*   PPPAR_IMP                 =
*   OLD_TABNR                 = ' '
*   REPID                     = ' '
*   FORM                      = ' '
*   KEEP_LUPD                 =
*   WORKF_ACTV                = 'X'
    tables
      innnn                     = lit_1028
   exceptions
     no_authorization          = 1
     error_during_insert       = 2
     repid_form_initial        = 3
     corr_exit                 = 4
     begda_greater_endda       = 5
     others                    = 6.

HI GOOD
go through this link,which might help you to solve your problem.
http://help.sap.com/printdocu/core/Print46c/en/data/pdf/PE/PE.pdf
thanks
mrutyun^

Unable to create org unit using RH_INSERT_INFTY

All,
We are using internal number range to create Org Units in the SAP System. However, there are some org objects present in a legacy SAP system that we need to upload to the new ECC system and create relationships for them .
Following is my code for the RH_INSERT_INFTY function module :
w1000-mandt = sy-mandt.
w1000-plvar = '01'.
w1000-otype = 'O'.
w1000-OBJID = ''.
w1000-infty = '1000'.
w1000-ISTAT = '1'.
w1000-begda = '20090101'.
w1000-endda = '99991231'.
w1000-langu = 'E'.
w1000-short = 'HR_AST5'.
w1000-stext = 'HR Assistant 5'.
append w1000 to i1000.
CALL FUNCTION 'RH_INSERT_INFTY'
EXPORTING
   FCODE                     = 'INSE'
    VTASK                     = 'S'
   ORDER_FLG                 = 'X'
   COMMIT_FLG                = 'X'
TABLES
    INNNN                     = i1000
IF SY-SUBRC <> 0.
ENDIF.
I am however unable to create the org units as i get an error saying "Creation of object ID 00000000 is not allowed".
I know im getting this error because im leaving the objid field blank, but I figured since it is internal number range, i would have to give this as blank .
Could somebody please help me figure out how to load these Organizational Objects and their Relationships ?
Thanks,
Amit

Hi Amit
try to use 'D' as a value of VTASK
or use FM
call function 'RH_OBJECT_CREATE'
    exporting
      langu                     = l_langu
      plvar                     = plvar
      otype                     = c_otype
    EXT_NUMBER                = '00000000'              "???
    SHORT                     = ' '
      stext                     = stext
      begda                     = begda
      endda                     = endda
      ostat                     = l_istat
      vtask                     = 'B'
    GUID                      =
    KEEP_LUPD                 = ' '
   importing
      objid                     = objid
   exceptions
      text_required             = 1
      invalid_otype             = 2
      invalid_date              = 3
      error_during_insert       = 4
      error_ext_number          = 5
      undefined                 = 6
      others                    = 7.
In this FM u dont need to pass the Object ID and call function
*---if the above steps are succesful update the database
call function 'RH_UPDATE_DATABASE'
    exporting
      vtask              = vtask
BUFFER_UPD         = ' '
ORDER_FLG          = 'X'
COMMIT_FLG         = 'X'
CLEAR_BUFFER       = 'X'
KEEP_LUPD          =
WORKF_ACTV         = 'X'
   exceptions
     corr_exit          = 1
     others             = 2 .
as VTASK 'B' will create the entry in buffer and it will only commit to database after the secondFM
or u can try with 'D' as VTASK
Hope this will resolve ur issue
Regards
Guds

On using RH_INSERT_INFTY to change HRP1000 status

Dear Gurus,
I'm using RH_INSERT_INFTY to change the status(ISTAT) of HRP1000.
According to the FM documentation: In the case of a status change, however, note the following: The fact that the record is deleted with the old status (except PLVO).
But the result seems that, when I change the ISTAT by using RH_INSERT_INFTY, the record with the old status is still there in the DB table HRP1000. I think the time constraint of HRP1000 must be set to 1.
Could you please advise how could I delete the record with the old status in this case?
Thanks & Best Regards,

Thanks for the advice.
Finally, I have to delete the record by myself by calling FM RH_DELETE_INFTY_DIRECT.
Even if I changed only the ISTAT field of the HRP1000 record, say, from 1 to 2, the old record with ISTAT = 1 would not be deleted after I inerted the ISTAT = 2 record.
If we don't delete the record with ISTAT = 1 before hand, there will be 2 record in the HRP1000 table, all the fileds' value are the same except the ISTAT field.
But it's also very tricky that, it seems that if I change the ISTAT and the BEGDA/ENDDA in 1 FM call of RH_INSERT_INFTY, the ISTAT = 2 record will be delimited too.
Thanks anyway!

Exception "NO AUTHORIZATION" in FM "RH_INSERT_INFTY"

Hi all,
          My requirement is to create the Infotypes by simulating the PP01 transaction. I used the FM RH_INSERT_INFTY. I am able to create the OBJECT Infotype and ADDRESS Infortype. But, When i am trying to create the Reletionship Infotype with Relation type A002. It is returning an exception as "NO AUTHORIZATION" and created an Infotype with relation B027, which i did ot ask for.
          Does creation of Relationship needs any authorization?. Please help me out in this...
         It would be gr8 help......
Thanks & Best Regards,
   Vishnu

Hi,
   After getting the no-authorization error, go to transaction SU53 and there u can see what authorization object is needed .you can take the snapshot of the SU53 and tell the basis consultant to give the particular authorization object to ur user.
regards,
Santosh Thorat

Function module RH_RELATION_MAINTAIN

Hi Experts,
I am using the function module RH_RELATION_MAINTAIN to create relation between position and costcenter. The relationship (a011) is getting created but the percentage field PROZT is not getting updated in HRP1001 table. Can anyone tell me why is this happening and how to update this particular field.
Thanks and Regards,
Shilpa

Thanks sir,
Ok with out percentage it is working fine.. I will upload without percentage.
Thanks and regards,
shilpa

Using RH_RELATION_MAINTAIN from RFC causes dumps

Hello,
We had a need to make the "RH_RELATION_MAINTAIN" function to be an RFC function.
What we've done in order to do this, is to copy the code from the original function into a Z function.
We are using the visual composer to call this function using RFC
Most of the times, it works without a problem, but sometimes creating a relation between a person and an position causes a dump
what we're getting is a weird system dump, that reads "CNTL_SYSTEM_ERROR".
If the same data is run through R3 without rfc, everything works fine.
Is there anything we can do about this?
thanks in advance, Udi.

im bumping this up after a week with no replies.
sorry.

RH_RELATION_MAINTAIN...getting Action Canceled...

I have a loop in my program to create relationship of positions (created by RH_OBJECT_CREATE).. If I run debug mode ... position objects and relationship infotypes are created using functions RH_OBJECT_CREATE and RH_RELATION_MAINTAIN... but if I execute the program GUI displays 'action canceled'... I am not able to trap where this message is coming from. May you help me with this issue if you have encoutered as such? Thanks...
Message was edited by:
MILJO

Hi Miljo,
I'm looking for a program by which I can delimit a relationship and create new relation . It seems u worked on such program, can u send me the program for same , its urgent
Kavi

RH_RELATION_MAINTAIN no dialog

Hi all,
it's the first time I use this FM RH_RELATION_MAINTAIN.
I use this FM in a loop. When there is an error, the screen with this error appears and stop all for a user input.
I have to develop a batch programm (I have to create something like 150000 position) so I need the error was catched and the report has to go on with the next record.
Is there a way to put the FM in a no dialog mode (like call transaction ) ?
thanks in advantage
enzo

Enzo,
You might try function module RH_INSERT_INFTY_1001_EXT. There is also a function module called RH_UPDATE_INFTY_1001_EXT. Insert creates new, update modifies existing.
RH_RELATION_MAINTAIN call function module RH_PNNNN_MAINTAIN. In this call the "suppress_dialog" exporting paramter is hard coded to '1'. A '1' in this field will automatically stop when there is an error.
The other option would be to call RH_PNNN_MAINTAIN directly and skip the call to RH_RELATION_MAINTAIN. You would just need to incorporate the lines of code prior to RH_PNNN_MAINTAIN in your program.
Best Regards,
Chris H.

RH_RELATION_MAINTAIN/RH_INSERT_INFTY

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