Round a number to 2 decimal places

Hi,
I have a computed value that returns 10 plus digits after the decimal place, exampe: 2.2482352941176.
What is the easiest way to edit this value in TestStand to return a number that is rounded up to 2 decimal places (2.25)?
Thanks & Regards,
Don1.
Solved!
Go to Solution.

One way to do this is to use the TestStand functions Str and Val. The %.2f rounds the number to 2 decimal places.
Val(Str(Locals.MyValue, "%.2f"))
Peter

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Rounding a number upto two decimal places.

Hey !
My question is regarding the rounding of a number in such a way that answer that we get after the rouning comes upto two decimal places,no matter how small or the large the number before rounding was.
Somebody please help me.
thanks

hi,
use BigDecimal class in java.math package.
here is some code how to do it ..
BigDecimal bd = new BigDecimal(your number here);
bd.setScale(2,BigDecimal.ROUND_DOWN)
System.out.println(bd);
hope this helps ...
bye
ashok

Rounding a number to 2 decimal places

Is there anyway using the Round function to get it to .2
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I also have some that are like this-43.990002 and this-8.9899998.
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Do some experimentation. If you are using numberformat you
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Rounding up to a particular decimal place

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Hi,
Refer
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Hi All,
I have a Number 156 stired in a column having number(10,2);
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Edited by: 887268 on May 29, 2012 10:04 AM

Hi,
156
156.00
156.0000000000000 and
00000156.0000 are all the same NUMBER. There's nothing to convert.
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Rounding up doubles to 2 decimal places

I'm currently rounding up a double in my program using Math.round(double)
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Also I'm making my own function to round the doubles,
and they are returning doubles so I cannot return a
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How to convert a String Variable to a Number and retain decimal place

Hello!
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<cfset Price = "12,200.49">
<cfoutput>
#val(Price)#
<cfset Price = '#Replace(Price,",","","ALL")#'>
<BR />
#val(Price)#
<cfset Price = '#Replace(Price,".","","ALL")#'>
<BR />
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<cfset Price = #NumberFormat(Price, "_____.__")#>
<BR />
FINISHED WITH #Price#
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12
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HI
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Rounding numbers to 2 decimal places

Hello programming community,
I have the following code to round my answers to 2 decimal places:
double roundedValue;
DecimalFormat twoDForm = new DecimalFormat ("#.##");
roundedValue = Double.valueOf(twoDForm.format(value));The code works great and what i expect it to do. When I pass in really big decimal numbers (2.55555668) it correctly rounds it (2.56) but when it rounds the number and the last decimal is a zero it does not display this. (if the number ends up rounding to 4.50 , i want it to display it this way but it ends up getting rid of the 0. )
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the-java-guy-needs-help wrote:
i thought that my equation would be causing a problem and that i might need to do a cast -- I relized that this is not the problem
for the type of string i am using the ("0.00")
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Rounding off a float to two decimal places

I want to make a function where I shall pass a float and and integer.
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Regards
Hawker

I didn't mention any datatypes like float, double.True, but that is what the question is about, so you weren't answering the question. For a change.
As I mentioned, that was just a mathematical steps to round of the floating point value. (Not in any programming languages point of view).False. You didn't mention that at all.
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which seems to be working fine
Seems to. What evidence do you have that the float actually got rounded? As opposed to got displayed as rounded? Which is not what the OP asked for.
And of course all that code seems to do is round 0.01 to two decimal places, which again is not what the OP asked for.
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Round a number to 2 decimal places

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