Rounded Numbers Dont Add Up
I have a user who is complaining that the numbers on her report don't add up to the total that's printed at the bottom. I haven't seen a sample of this yet but I wanted to run this by you guys and see if this code makes sense.
function() {
NumberFormat nf = new DecimalFormat("#,##0.00");
double total = 0D;
for (...) {
double d = Math.random();
total += round(d);
print(nf.format(d));
print(nf.format(total));
double round(double d) {
return (double)(Math.round(d*100)/100D);
}Is my round() sound?
I have a user who is complaining that the numbers on
her report don't add up to the total that's printed at
the bottom. This could be a problem with the user in that they don't understand numerics.
Or it could b a problem with you in that you do not understand the problem domain.
Floating point numbers are always inaccurate. It doesn't matter whether humans or computers do this. That is because floating point numbers (when used correctly) are an approximate measure of something which can not be measured exactly.
For example a pound of hamburger might be marked as weighing 1.01 pounds. The inaccuracy is in that it might actually weigh 1.01015678 pounds (but is unlikely to weigh even that.) There is no way to get the exact weight.
Now if that is your situation then it is problem with the user - the user doesn't understand numerics and the inherit inaccuracies.
And it would probably be a bad idea for you to "fix" it for one user, when other users are expecting correct approximations.
(One way to fix this is to 'fiddle' with the numbers that make up your sum. Adjust one so everything 'looks' right.)
On the other hand maybe it is your problem. For example money. Money is not a floating point number, because money is always exact. Even when caculating interest it is always exact. You will never end up with a partial penny in your savings account, no matter how the interest rate is computed.
And since money is accurate a floating point number is not necessarily the best way to represent it. Care must be used in doing so. As a previous poster suggested the BigDecimal class can be used.
Or if your numbers are small then simply convert the money to integers by multiplying by 100 and rounding and then compute everything using that. And simply reformat the integer values so they look like floating point numbers rather than integers when you print them out.
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I don't think java.lang.Math.round() will do what the original post asked for, since it rounds to the nearest long number. So you still would have to write your own method to round 4.647 down to 4.5.
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How to round numbers using java script in Adobe Acrobat Pro?
For example:
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Thank you.Assuming you've already set the field to a Number format category and limited it to one digit to the right of the decimal, you can use the following custom Validate script:
// Custom Validate script
event.value = Math.round(event.value);
More info: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Math/roun d -
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Calculations with Rounded Numbers
I've created a form in Adobe X that has a few calculated fields. For ease of conversation, we'll call them Field A, Field B and Field C (see below). I need Fields A and B to be rounded to the nearest whole number so that Field C is also a whole number. I've tried formatting Fields A and B to show no decimals but the calculaton is still being performed on the non-rounded numbers. Can anyone help with this? Thanks.
Field A - Field B = Field CGeorge I must be missing something. I added the math.round functions as shown in your example but now it doesn't calculate at all. Can you look at the coding shown below and let me know where I went wrong? Thanks.
Updated Coding:
(function(){
var totalMiles = math.round(+this.getField("Total Miles DrivenRow1").value);
var homeMiles = math.round(+this.getField("Home Base MilesRow1").value);
var diff = totalMiles - homeMiles;
if (diff<0) diff = 0;
event.value = diff;})();
Original Coding:
var totalMiles = +this.getField("Total Miles DrivenRow1").value;
var homeMiles = +this.getField("Home Base MilesRow1").value;
var diff = totalMiles - homeMiles;
if (diff<0) diff = 0;
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How to round numbers in java?
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//Conversion and Calculation
principle = reader.readDouble("Enter Loan Amount: ");
interestRate = reader.readDouble("Enter YEARLY interest rate: ");
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monthlyRate = convertedRate / 12;
timePeriod = reader.readDouble("Enter the number of years for the repayment: ");
convertedPeriod = timePeriod * 12;
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solution doesn't work with negative numbers!
And by the way, if you had a little bit more of the
good old klue2k, you wouldn't be embarassing yourself
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Rounding numbers to 2 decimal places
Hello programming community,
I have the following code to round my answers to 2 decimal places:
double roundedValue;
DecimalFormat twoDForm = new DecimalFormat ("#.##");
roundedValue = Double.valueOf(twoDForm.format(value));The code works great and what i expect it to do. When I pass in really big decimal numbers (2.55555668) it correctly rounds it (2.56) but when it rounds the number and the last decimal is a zero it does not display this. (if the number ends up rounding to 4.50 , i want it to display it this way but it ends up getting rid of the 0. )
If anyone has any ideas for a way to fix this please let me know.
Thanks.the-java-guy-needs-help wrote:
i thought that my equation would be causing a problem and that i might need to do a cast -- I relized that this is not the problem
for the type of string i am using the ("0.00")
After trying various things the string does work if im just outputing it to the screen but i also use this rounding in a method that needs to return a double so i still need to convert it to a double.
I have tried various ways of converting string to double (Double.parseDouble) and i tried one that involved a trim() but both methods drop the zero.You've got a basic misconception still going on here. If you convert it to a double, there is no such thing as a trailing zero -- it's meaningless since it only has meaning for a String representation of a double and not the intrinsic number itself. -
When i add some songs they dont add and another thing
when i add some songs the space amount will sometimes jump from eg. 12.45 to 12.51 and the file size is only 4mb. than after that it will jump back down to 12.46 and continue like nothing has happened. than i go to listen to some songs old/new on itunes or my ipod and on itunes it shows ! which i know means its gone but i dont know how and on the ipod it goes on it but skips. any help thanks
If I understand you correctly, iTunes is not transferring songs to your iPod. Before you sync again, make sure that the selections you want transferred are selected (by clicking the box next to each selection from your library in iTunes). Also try this, when your ipod is connected, click it under devices and select 'Music'. Then make sure 'Sync Music' and 'All Songs and Playlists' are selected. Good luck
Dell Windows XP -
Creating x random numbers that add up to a certain number
How would I go about creating 3 random numbers from x - y that add up to a certain number.
Or how would i create a set of numbers that are random but not repeating.How would I go about creating 3 random numbers fromx
- y that add up to a certain number.Create 2 random numbers. Number 3 = certain
number - (random number 1 + random number 2)
http://java.sun.com/j2se/1.5.0/docs/api/java/util/Rand
om.html
Or how would i create a set of numbers that are
random but not repeating.Create a List and fill it with numbers 1 - n. Shuffle
the list with the Collections.shuffle(...) method.
http://java.sun.com/j2se/1.5.0/docs/api/java/util/Coll
ections.htmlOr use a Set instead of a List, since Sets do not contain duplicates.
http://java.sun.com/j2se/1.5.0/docs/api/java/util/Set.html
? {? -
How to round numbers in RTF templates?
Hello!
I'm using BI Publisher for Word (Oracle BI Publisher Builder for Word 10.1.3.4.1) to build a template to my BI Publisher report and I want to calculate this:
avg(X)/(avg(Y)-avg(Z)/0.9)
The result should be rounded to 3 places.
I tried:
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<?xdofx:round((sum(X) div count(X)) div ((sum(Y) div count(Y))-(sum(Z) div count(Z)) div 0.9),3)?>
I obtain 0 when is expected other value.
Can someone help me?Hi ,
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Type :Number
Number Format :#,##0.000
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How to round numbers to the nearest .25
I would like to enter a number in one field and have it rounded to the nearest .25 in another column - (whether that's rounding up or down)
Example:
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Any help would be appreciated.
Thanks!Hi c,
The ROUND function limits the precision choices to powers of 10, so we need to work within that limitation:
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Formula in column B: =ROUND(A*4,0)/4
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Regards,
Barry -
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