Safari May Not Interpret Regular Expression in Compliance with W3C Standard

We are troubleshooting why some websites are no longer working when rendered with the Safari 2.0.4 browser. The failure begins when client entered data is validated using regular expressions.
We have localized the issue to Safari's not interpretting regular expressions consistently.
For example:
Does the regex \u00e9 match the literal character é? (Validates the regular expression engine understands Unicode escape sequences for extended characters.)? - NO, but it does on IE and FireFox
Does the regex \u0041 match the literal character A? (Validates the regular expression engine understands Unicode escape sequences for ASCII characters.)? - NO, but it does on IE and FireFox
Does the regex é match the literal character é? (Validates the regular expression engine understands literal characters outside the ASCII range – this is against ECMAScript spec.)? - Sometimes, but always on IE and FireFox
Write a Unicode escape sequence to the screen on the client side. (Validates the string parsing and display in the JS engine works.) - Works on all 3
Is escape sequence \u00e9 equivalent to literal character é? (Validates the string functionality in the JS engine works with extended characters.)? Yes on all 3.
Is escape sequence \u0041 equivalent to literal character A? (Validates the string functionality in the JS engine works with ASCII characters.)? Yes on all 3
Does the regex A match the literal character A? (Validates the regular expression engine understands literal characters in the ASCII range – this is ECMAScript spec.)? Yes on all 3
Please help. It's hard for me to believe that the regular expression / javascript interpreter(s) for Safari aren't working as they have in the past - but all roads are pointed that way....
Thank you for your review.
Mac OS X (10.4.7)

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Not able to install rtcxds database with Lync Standard Edition

Hello everybody,
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Does anyone have an idea, what causes this timeout/error?
Thanks in Advance!
Kind regards,
Fabio

Datei "\\lync01.lynctest.local\e$\csdata\BackendStore\rtc\DbPath\rtcxds.mdf" fehlt.
Fehler beim Anfügen der Datenbank, da eine der Dateien nicht gefunden wurde. Die Datenbank wird erstellt.
It looks like it can't find that file. Do you see it on your drive?
If you run Topology Builder, will it let you download the topology from the Central Management store and publish a tiny change at the moment?
Do you get the same error if you rerun step 2?
To confirm, this is your first Lync server in the environment?
Please remember, if you see a post that helped you please click "Vote As Helpful" and if it answered your question please click "Mark As Answer".
SWC Unified Communications

Match Regular Expression does not match what Match Pattern does

I have read through a lot of posts about how Match Pattern does not match what Match Regular Expression will due to not processing some characters.
However, I found a problem with the other way. A simple Reg-Ex that works in Match Pattern but not Match Regular Expression.
What I have here is just an example. I want to use Match Regular Expression so I can specify some sub-matches.
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Solved!
Go to Solution.

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purple='\e[0;35m'
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# We would want stop this function, on some big git repos it can take some time to cd into.
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git_check_if_workdir_path="${git_check_if_workdir_path:-/home}"
git_check_if_workdir_path_exclude="${git_check_if_workdir_path_exclude:-${HOME}/_sshfs}"
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if begin_with "${PWD}" ${=git_check_if_workdir_path//:/ }; then
if ! begin_with "${PWD}" ${=git_check_if_workdir_path_exclude//:/ }; then
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local git_pwd_is_worktree_match='false'
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fi
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git_pwd_is_worktree='false'
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man() {
if command -v vimmanpager >/dev/null 2>&1; then
PAGER="vimmanpager" command man "$@"
else
command man "$@"
fi
# Are we running under grsecurity's RBAC?
rbac_auth() {
local auth_to_role='admin'
if [ "${USER}" = 'root' ]; then
if ! grep -qE '^RBAC:' "/proc/self/status" && command -v gradm > /dev/null 2>&1; then
echo -e "\n${BLUE}*${NC} ${GREEN}RBAC${NC} Authorize to '${auth_to_role}' RBAC role."
gradm -a "${auth_to_role}"
fi
fi
#rbac_auth
# Check if we started zsh in git worktree, useful with tmux when your new zsh may spawn in source dir.
git_check_if_worktree
if [ "${git_pwd_is_worktree}" = 'true' ]; then
git_branch
git_dirty
git_prompt=" %F{blue}[%F{253}${git_branch}${git_dirty}%F{blue}]"
else
unset git_prompt
fi
# Le features!
# extended globbing, awesome!
setopt extendedGlob
# zmv - a command for renaming files by means of shell patterns.
autoload -U zmv
# zargs, as an alternative to find -exec and xargs.
autoload -U zargs
# Turn on command substitution in the prompt (and parameter expansion and arithmetic expansion).
setopt promptsubst
# Control-x-e to open current line in $EDITOR, awesome when writting functions or editing multiline commands.
autoload -U edit-command-line
zle -N edit-command-line
bindkey '^x^e' edit-command-line
# Include user-specified configs.
if [ ! -d "${ZSHDDIR}" ]; then
mkdir -p "${ZSHDDIR}" && echo "# Put your user-specified config here." > "${ZSHDDIR}/example.zsh"
fi
for zshd in $(ls -A ${HOME}/.config/zsh.d/^*.(z)sh$); do
. "${zshd}"
done
# Completion.
autoload -Uz compinit
compinit
zstyle ':completion:*' matcher-list 'm:{a-z}={A-Z}'
zstyle ':completion:*' completer _expand _complete _ignored _approximate
zstyle ':completion:*' menu select=2
zstyle ':completion:*' select-prompt '%SScrolling active: current selection at %p%s'
zstyle ':completion::complete:*' use-cache 1
zstyle ':completion:*:descriptions' format '%U%F{cyan}%d%f%u'
# If running as root and nice >0, renice to 0.
if [ "$USER" = 'root' ] && [ "$(cut -d ' ' -f 19 /proc/$$/stat)" -gt 0 ]; then
renice -n 0 -p "$$" && echo "# Adjusted nice level for current shell to 0."
fi
# Fancy prompt.
if over_ssh && [ -z "${TMUX}" ]; then
prompt_is_ssh='%F{blue}[%F{red}SSH%F{blue}] '
elif over_ssh; then
prompt_is_ssh='%F{blue}[%F{253}SSH%F{blue}] '
else
unset prompt_is_ssh
fi
case $USER in
root)
PROMPT='%B%F{cyan}%m%k %(?..%F{blue}[%F{253}%?%F{blue}] )${prompt_is_ssh}%B%F{blue}%1~${git_prompt}%F{blue} %# %b%f%k'
PROMPT='%B%F{blue}%n@%m%k %(?..%F{blue}[%F{253}%?%F{blue}] )${prompt_is_ssh}%B%F{cyan}%1~${git_prompt}%F{cyan} %# %b%f%k'
esac
# Ignore lines prefixed with '#'.
setopt interactivecomments
# Ignore duplicate in history.
setopt hist_ignore_dups
# Prevent record in history entry if preceding them with at least one space
setopt hist_ignore_space
# Nobody need flow control anymore. Troublesome feature.
#stty -ixon
setopt noflowcontrol
# Fix for tmux on linux.
case "$(uname -o)" in
'GNU/Linux')
export EVENT_NOEPOLL=1
esac
# Aliases
alias cp='cp -iv'
alias rcp='rsync -v --progress'
alias rmv='rsync -v --progress --remove-source-files'
alias mv='mv -iv'
alias rm='rm -iv'
alias rmdir='rmdir -v'
alias ln='ln -v'
alias chmod="chmod -c"
alias chown="chown -c"
if command -v colordiff > /dev/null 2>&1; then
alias diff="colordiff -Nuar"
else
alias diff="diff -Nuar"
fi
alias grep='grep --colour=auto'
alias egrep='egrep --colour=auto'
alias ls='ls --color=auto --human-readable --group-directories-first --classify'
# Keys.
case $TERM in
rxvt*|xterm*)
bindkey "^[[7~" beginning-of-line #Home key
bindkey "^[[8~" end-of-line #End key
bindkey "^[[3~" delete-char #Del key
bindkey "^[[A" history-beginning-search-backward #Up Arrow
bindkey "^[[B" history-beginning-search-forward #Down Arrow
bindkey "^[Oc" forward-word # control + right arrow
bindkey "^[Od" backward-word # control + left arrow
bindkey "^H" backward-kill-word # control + backspace
bindkey "^[[3^" kill-word # control + delete
linux)
bindkey "^[[1~" beginning-of-line #Home key
bindkey "^[[4~" end-of-line #End key
bindkey "^[[3~" delete-char #Del key
bindkey "^[[A" history-beginning-search-backward
bindkey "^[[B" history-beginning-search-forward
screen|screen-*)
bindkey "^[[1~" beginning-of-line #Home key
bindkey "^[[4~" end-of-line #End key
bindkey "^[[3~" delete-char #Del key
bindkey "^[[A" history-beginning-search-backward #Up Arrow
bindkey "^[[B" history-beginning-search-forward #Down Arrow
bindkey "^[Oc" forward-word # control + right arrow
bindkey "^[Od" backward-word # control + left arrow
bindkey "^H" backward-kill-word # control + backspace
bindkey "^[[3^" kill-word # control + delete
esac
bindkey "^R" history-incremental-pattern-search-backward
bindkey "^S" history-incremental-pattern-search-forward
if [ -f ~/.alert ]; then cat ~/.alert; fi
Thanks for all the help.
Last edited by Shark (2013-05-11 22:32:24)

Raynman wrote:
"This expression doesn't work", "It doesn't work" ...
Could you try being a bit more specific?
Firstly, i am sorry i didn't post the output. I should have know better.
Secondly, chill out.
I have used above regex with grep command. Output from terminal is:
zsh: bad pattern: ^[^#]
In bash it works perfectly.
If i issue "setopt re_match_pcre" i have the same ouput as above.
EDIT: If i issue "unsetopt no_match" it actually works but i have to change the regex from "\^\[^#]" to "\^[^#]" otherwise i get the same output as above. In bash both options work.
Last edited by Shark (2013-05-11 22:07:21)

Regular Expressions in num-exp

Hello All,
I had a problem on my SRST gateway with num-exp insterting a repeating pattern into my 7-digit dialing when in fallback mode.
For a brief example, the 7digit internal dialing is 21621.. or 21622..
The num-exp statement of 'num-exp 2... 2162...' was not allowing me to 7-digit dial directly from one IP phone to another while in fallback mode.
When I dialed 2162154 the 2162 would hit the num-exp and be expended to 2162162.
I have a work around that uses a voice translation-rule, applied to the call-manager-fallback config that will translate a 7-digit dialed string to the 4 digit dialed string which then hits the 4-digit to 7-digit num-exp and it is working fine.
However, I was wondering if there is a way to use regular expressions in num-exp so that perhaps I can skip the intermediate step of using the translation-rule. Based off my existing translation-rules that are working properly, I figured something like this might work for num-exp:
'num-exp /^2$[12]..$$/ /2162\1/'
But when I try to issue a num-exp with a regular expression I get the following message.
Incorrect format for Number macro pattern
regular expression must be of the form ^((\+)?([0-9#*A-F.]|(\\\*))+(\$)?)$
I have tried a number of different combinations with no success. I always get the same message. The regular expression that I tried first was:
'num-exp ^2... 2162...'
This is when I first saw the "Incorrect format..." message and figured that is must be possible. Is this just a generic warning similar to when you try to use complex regular expressions with the 'translation-rule' command vs. the 'voice translation-rule' command and in reality you cannot use regular expressions in the num-exp command?
Thank you,
Leo

Hi Chris,
Thank you for taking the time to answer my question. It looks like the answer is no, num-exp does not support regular expressions.
I don't insist on using num-exp for this I was just hoping to kill two birds with one stone and possibly skip the intermediate step of translating the 7-digits dial to 4-digits using a translation-rule just to expand from 4-digit to 7 again. This is only an issue while in SRST if a user tries to dial using 7-digits. We have a 7-digit internal dialing scheme and normally my num-exp is just to expand the 4 digits sent from the telco to our 7-digit internal dialing. The problem is that both our prefix and part of our DID range start with 21 so while in SRST if a user tried to dial a 7-digit DN, say 2162154, after they dialed the 4th digit (2162) that pattern would hit the num-exp and get expanded to 2162162. I was hoping to create a num-exp using a regular expression that would only expand a four digit string that begins with a 2 to seven digits and not any string that begins with a 2. This would 1) expand the four digits sent from the telco and 2) not match a seven digit string that begins with a 2 such as 2162154 which may be dialed by a user.
Again, this is only an issue while in SRST and I have a pretty good work around so I'm fine with not being able to use a regular expression as part of my num-exp config. I just thought it would be a cool application of a regular expression if it was possible.
Thanks again for answering my question.
Leo

Introduction to regular expressions ... last part.

Continued from Introduction to regular expressions ... continued., here's the third and final part of my introduction to regular expressions. As always, if you find mistakes or have examples that you think could be solved through regular expressions, please post them.
Having fun with regular expressions - Part 3
In some cases, I may have to search for different values in the same column. If the searched values are fixed, I can use the logical OR operator or the IN clause, like in this example (using my brute force data generator from part 2):
SELECT data
FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE data IN ('abc', 'xyz', '012');There are of course some workarounds as presented in this asktom thread but for a quick solution, there's of course an alternative approach available. Remember the "|" pipe symbol as OR operator inside regular expressions? Take a look at this:
SELECT data
FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE REGEXP_LIKE(data, '^(abc|xyz|012)$')
;I can even use strings composed of values like 'abc, xyz , 012' by simply using another regular expression to replace "," and spaces with the "|" pipe symbol. After reading part 1 and 2 that shouldn't be too hard, right? Here's my "thinking in regular expression": Replace every "," and 0 or more leading/trailing spaces.
Ready to try your own solution?
Does it look like this?
SELECT data
FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE REGEXP_LIKE(data, '^(' || REGEXP_REPLACE('abc, xyz , 012', ' *, *', '|') || ')$')
;If I wouldn't use the "^" and "$" metacharacter, this SELECT would search for any occurence inside the data column, which could be useful if I wanted to combine LIKE and IN clause. Take a look at this example where I'm looking for 'abc%', 'xyz%' or '012%' and adding a case insensitive match parameter to it:
SELECT data
FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE REGEXP_LIKE(data, '^(abc|xyz|012)', 'i')
; An equivalent non regular expression solution would have to look like this, not mentioning other options with adding an extra "," and using the INSTR function:
SELECT data
FROM (SELECT data, LOWER(DATA) search
          FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE search LIKE 'abc%'
    OR search LIKE 'xyz%'
    OR search LIKE '012%'
SELECT data
FROM (SELECT data, SUBSTR(LOWER(DATA), 1, 3) search
          FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE search IN ('abc', 'xyz', '012')
; I'll leave it to your imagination how a complete non regular example with 'abc, xyz , 012' as search condition would look like.
As mentioned in the first part, regular expressions are not very good at formatting, except for some selected examples, such as phone numbers, which in my demonstration, have different formats. Using regular expressions, I can change them to a uniform representation:
WITH t AS (SELECT '123-4567' phone
             FROM dual
            UNION
           SELECT '01 345678'
             FROM dual
            UNION
           SELECT '7 87 8787'
             FROM dual
SELECT t.phone, REGEXP_REPLACE(REGEXP_REPLACE(phone, '[^0-9]'), '(.{3})(.*)', '(\1)-\2')
FROM t
;First, all non digit characters are beeing filtered, afterwards the remaining string is put into a "(xxx)-xxxx" format, but not cutting off any phone numbers that have more than 7 digits. Using such a conversion could also be used to check the validity of entered data, and updating the value with a uniform format afterwards.
Thinking about it, why not use regular expressions to check other values about their formats? How about an IP4 address? I'll do this step by step, using 127.0.0.1 as the final test case.
First I want to make sure, that each of the 4 parts of an IP address remains in the range between 0-255. Regular expressions are good at string matching but they don't allow any numeric comparisons. What valid strings do I have to take into consideration?
Single digit values: 0-9
Double digit values: 00-99
Triple digit values: 000-199, 200-255 (this one will be the trickiest part)
So far, I will have to use the "|" pipe operator to match all of the allowed combinations. I'll use my brute force generator to check if my solution works for a single value:
SELECT data
FROM TABLE(regex_utils.gen_data('0123456789', 3))
WHERE REGEXP_LIKE(data, '^(25[0-5]|2[0-4][0-9]|[01]?[0-9]{1,2})$')
; More than 255 records? Leading zeros are allowed, but checking on all the records, there's no value above 255. First step accomplished. The second part is to make sure, that there are 4 such values, delimited by a "." dot. So I have to check for 0-255 plus a dot 3 times and then check for another 0-255 value. Doesn't sound to complicated, does it?
Using first my brute force generator, I'll check if I've missed any possible combination:
SELECT data
FROM TABLE(regex_utils.gen_data('03.', 15))
WHERE REGEXP_LIKE(data,
                   '^((25[0-5]|2[0-4][0-9]|[01]?[0-9]{1,2})\.){3}(25[0-5]|2[0-4][0-9]|[01]?[0-9]{1,2})$'
; Looks good to me. Let's check on some sample data:
WITH t AS (SELECT '127.0.0.1' ip
             FROM dual
            UNION
           SELECT '256.128.64.32'
             FROM dual
SELECT t.ip
FROM t WHERE REGEXP_LIKE(t.ip,
                   '^((25[0-5]|2[0-4][0-9]|[01]?[0-9]{1,2})\.){3}(25[0-5]|2[0-4][0-9]|[01]?[0-9]{1,2})$'
; No surprises here. I can take this example a bit further and try to format valid addresses to a uniform representation, as shown in the phone number example. My goal is to display every ip address in the "xxx.xxx.xxx.xxx" format, using leading zeros for 2 and 1 digit values.
Regular expressions don't have any format models like for example the TO_CHAR function, so how could this be achieved? Thinking in regular expressions, I first have to find a way to make sure, that each single number is at least three digits wide. Using my example, this could look like this:
WITH t AS (SELECT '127.0.0.1' ip
             FROM dual
SELECT t.ip, REGEXP_REPLACE(t.ip, '([0-9]+)(\.?)', '00\1\2')
FROM t
; Look at this: leading zeros. However, that first value "00127" doesn't look to good, does it? If you thought about using a second regular expression function to remove any excess zeros, you're absolutely right. Just take the past examples and think in regular expressions. Did you come up with something like this?
WITH t AS (SELECT '127.0.0.1' ip
             FROM dual
SELECT t.ip, REGEXP_REPLACE(REGEXP_REPLACE(t.ip, '([0-9]+)(\.?)', '00\1\2'),
                            '[0-9]*([0-9]{3})(\.?)', '\1\2'
FROM t
; Think about the possibilities: Now you can sort a table with unformatted IP addresses, if that is a requirement in your application or you find other values where you can use that "trick".
Since I'm on checking INET (internet) type of values, let's do some more, for example an e-mail address. I'll keep it simple and will only check on the
"[email protected]", "[email protected]" and "[email protected]" format, where x represents an alphanumeric character. If you want, you can look up the corresponding RFC definition and try to build your own regular expression for that one.
Now back to this one: At least one alphanumeric character followed by an "@" at sign which is followed by at least one alphanumeric character followed by a "." dot and exactly 3 more alphanumeric characters or 2 more characters followed by a "." dot and another 2 characters. This should be an easy one, right? Use some sample e-mail addresses and my brute force generator, you should be able to verify your solution.
Here's mine:
SELECT data
FROM TABLE(regex_utils.gen_data('a1@.', 9))
WHERE REGEXP_LIKE(data, '^[[:alnum:]]+@[[:alnum:]]+(\.[[:alnum:]]{3,4}|(\.[[:alnum:]]{2}){2})$', 'i'); Checking on valid domains, in my opinion, should be done in a second function, to keep the checks by itself simple, but that's probably a discussion about readability and taste.
How about checking a valid URL? I can reuse some parts of the e-mail example and only have to decide what type of URLs I want, for example "http://", "https://" and "ftp://", any subdomain and a "/" after the domain. Using the case insensitive match parameter, this shouldn't take too long, and I can use this thread's URL as a test value. But take a minute to figure that one out for yourself.
Does it look like this?
WITH t AS (SELECT 'Introduction to regular expressions ... last part. URL
             FROM dual
            UNION
           SELECT 'http://x/'
             FROM dual
SELECT t.URL
FROM t
WHERE REGEXP_LIKE(t.URL, '^(https*|ftp)://(.+\.)*[[:alnum:]]+(\.[[:alnum:]]{3,4}|(\.[[:alnum:]]{2}){2})/', 'i')
Update: Improvements in 10g2
All of you, who are using 10g2 or XE (which includes some of 10g2 features) may want to take a look at several improvements in this version. First of all, there are new, perl influenced meta characters.
Rewriting my example from the first lesson, the WHERE clause would look like this:
WHERE NOT REGEXP_LIKE(t.col1, '^\d+$')Or my example with searching decimal numbers:
'^(\.\d+|\d+(\.\d*)?)$'Saves some space, doesn't it? However, this will only work in 10g2 and future releases.
Some of those meta characters even include non matching lists, for example "\S" is equivalent to "[^ ]", so my example in the second part could be changed to:
SELECT NVL(LENGTH(REGEXP_REPLACE('Having fun with regular expressions', '\S')), 0)
FROM dual
;Other meta characters support search patterns in strings with newline characters. Just take a look at the link I've included.
Another interesting meta character is "?" non-greedy. In 10g2, "?" not only means 0 or 1 occurrence, it means also the first occurrence. Let me illustrate with a simple example:
SELECT REGEXP_SUBSTR('Having fun with regular expressions', '^.* +')
FROM dual
;This is old style, "greedy" search pattern, returning everything until the last space.
SELECT REGEXP_SUBSTR('Having fun with regular expressions', '^.* +?')
FROM dual
;In 10g2, you'd get only "Having " because of the non-greedy search operation. Simulating that behavior in 10g1, I'd have to change the pattern to this:
SELECT REGEXP_SUBSTR('Having fun with regular expressions', '^[^ ]+ +')
FROM dual
;Another new option is the "x" match parameter. It's purpose is to ignore whitespaces in the searched string. This would prove useful in ignoring trailing/leading spaces for example. Checking on unsigned integers with leading/trailing spaces would look like this:
SELECT REGEXP_SUBSTR(' 123 ', '^[0-9]+$', 1, 1, 'x')
FROM dual
;However, I've to be careful. "x" would also allow " 1 2 3 " to qualify as valid string.
I hope you enjoyed reading this introduction and hope you'll have some fun with using regular expressions.
C.
Fixed some typos ...
Message was edited by:
cd
Included 10g2 features
Message was edited by:
cd

Can I write this condition with only one reg expr in Oracle (regexp_substr in my example)?I meant to use only regexp_substr in select clause and without regexp_like in where clause.
but for better understanding what I'd like to get
next example:
a have strings of two blocks separated by space.
in the first block 5 symbols of [01] in the second block 3 symbols of [01].
In the first block it is optional to meet one (!), in the second block it is optional to meet one (>).
The idea is to find such strings with only one reg expr using regexp_substr in the select clause, so if the string does not satisfy requirments should be passed out null in the result set.
with t as (select '10(!)010 10(>)1' num from dual union all
select '1112(!)0 111' from dual union all --incorrect because of '2'
select '(!)10010 011' from dual union all
select '10010(!) 101' from dual union all
select '10010 100(>)' from dual union all
select '13001 110' from dual union all -- incorrect because of '3'
select '100!01 100' from dual union all --incorrect because of ! without (!)
select '100(!)1(!)1 101' from dual union all -- incorrect because of two occurencies of (!)
select '1001(!)10 101' from dual union all --incorrect because of length of block1=6
select '1001(!)10 1011' from dual union all) --incorrect because of length of block2=4
select '10110 1(>)11(>)0' from dual union all)--incorrect because of two occurencies of (>)
select '1001(>)1 11(!)0' from dual)--incorrect because (!) and (>) are met not in their blocks
--end of test data

The Regular Expressions and GUID.

Hello gurus, I hope you can help me!
I am needing to select GUIDS from a table and for this, I need the Regular Expression. My
Perl is not good and not good Regular Expression. My database is Oralce 11.2.0.2.0 and
the Operating System of the Machine is Linux (Oracle Version 6). If you require the further information,
I will watch closely. Thank you. Jehangir.

>
Hi Jehangir and welcome to the forums.
I am needing to select GUIDS from a table and for this,Well, the first thing you should do is read the forum FAQ and also the post by BluShadow
at the top of the posts on the forum home page. You should have provided code (DDL
and DML) showing your particular problem, but since this is your first time, I'll be gentle ;)
We have done this - sometimes clients have GUIDs as PKs and we need to send data to
their systems, but it isn't as simple as it may first appear.
GUIDs can come in three formats.
The Oracle one - SELECT Sys_GUID() from DUAL which is just a string of 32 Hexadecimal characters.
Then the string with hyphens and then the string with hypens and {} at beginning and end (see
sample data).
with datax as
SELECT '79A864CCD8E44CD8B0A2765DF9EF337B' as guid FROM DUAL UNION ALL
SELECT '79A864CFD8E44CD7B0A2765DF9EF337B' FROM DUAL UNION ALL
SELECT '8gdfsgsgfdg' FROM DUAL UNION ALL -- dummy for testing
SELECT '21EC2020-3AEA-1069-A2DD-08002B30309D' FROM DUAL UNION ALL
SELECT '21EC5550-3AEA-1069-A2FF-08002B30309D' FROM DUAL UNION All
SELECT '{21CC2020-3AFA-1A69-A2DD-08002B30309D}' FROM DUAL
-- first one is the Oracle format
select * from datax where regexp_like(guid, '[0-9a-fA-F]{32}'); -- Oracle select sys_guid();
-- second one is with hyphens
select * from datax where regexp_like(guid, '[0-9a-fA-F]{8}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{12}');
-- third one is with hyphens and curly brackets.
select * from datax where regexp_like(guid, '^\{[0-9a-fA-F]{8}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{12}\}$');
-- This converts both of the last two formats back into Oracle format, which is what
-- we use. Notice, that I haven't used regualar expressions to do this. Regexes are
-- computationally expensive, and you should use Oracle's string furnctions if possible
SELECT REPLACE(REPLACE(REPLACE(GUID, '{', ''), '}', ''), '-', '') FROM Datax;HTH,
Paul...
Jehangir.

Safari will not open, quit unexpectedly

I cannot open Safari anymore. It will open to apple.com for about 1 second and then quit unexpectedly. Using Firefox now, but would like to know why safari is not working. I have already installed all of the available software updates.
Here is the error report:
Date/Time: 2008-08-22 21:21:57.734 -0400
OS Version: 10.4.11 (Build 8S2167)
Report Version: 4
Command: Safari
Path: /Applications/Safari.app/Contents/MacOS/Safari
Parent: WindowServer [68]
Version: 3.1.2 (4525.22)
Build Version: 6
Project Name: WebBrowser
Source Version: 45252200
PID: 844
Thread: Unknown
Link (dyld) error:
no suitable image found. Did find:
/usr/lib/libz.dylib: not a file
/usr/lib/libz.dylib: not a file /usr/lib/libz.dylib
Model: iMac4,1, BootROM IM41.0055.B08, 2 processors, Intel Core Duo, 2 GHz, 512 MB
Graphics: ATI Radeon X1600, ATY,RadeonX1600, PCIe, 128 MB
Memory Module: BANK 1/DIMM1, 512 MB, DDR2 SDRAM, 667 MHz
AirPort: spairportwireless_card_type_airportextreme (0x14E4, 0x89), Broadcom BCM43xx 1.0 (4.170.46.9)
Bluetooth: Version 1.9.5f4, 2 service, 1 devices, 1 incoming serial ports
Network Service: AirPort, AirPort, en1
Serial ATA Device: WDC WD2500JS-40NGB2, 232.89 GB
Parallel ATA Device: MATSHITADVD-R UJ-846, 3.96 GB
USB Device: Keyboard Hub, Apple, Inc., Up to 480 Mb/sec, 500 mA
USB Device: Apple Keyboard, Apple, Inc, Up to 1.5 Mb/sec, 100 mA
USB Device: Built-in iSight, Micron, Up to 480 Mb/sec, 500 mA
USB Device: Apple Optical USB Mouse, Primax Electronics, Up to 1.5 Mb/sec, 500 mA
USB Device: Bluetooth USB Host Controller, Apple, Inc., Up to 12 Mb/sec, 500 mA
USB Device: IR Receiver, Apple Computer, Inc., Up to 12 Mb/sec, 500 mA
Message was edited by: Sibster

Any other suggestions?
Just to supplement Barrry's valuable advice:
If your Safari won't open, one or more of the following procedures should fix it:
1. Go to Home/Library/Safari/ folder and remove the following two files:
• history.plist
• lastsession.plist
(Safari may not load properly If these two files are corrupted.)
2. Go to Home/Library/Caches/Metadata/Safari/ and remove the contents of that folder.
(These are just webhistory files and are not required for Safari to run. However, similar to preference files, problems can arise if they have become corrupt.)
3. Locate the cookies.plist file that's located in the Home/Library/Cookies/ folder and remove it.
(Again, faults in stored cookies may interfere with Safari's launch.)
4. Check whether any of your third-party internet plug-ins may be interfering with the launch of Safari by carefully moving them to the desktop (do NOT delete them at this stage). You can find these in two places:
Home/Library/Internet Plug-Ins/ folder, and Global plug-ins are located in the Macintosh HD/Library/Internet Plug-ins/ folder.
Restart Safari and place them back in the correct folders, one at a time, closing and re-opening Safari each time. If you discover that one of them was causing the problem with launching Safari, trash it and download and install a fresh copy.

Safari will not open in OS 10.3.9

Hi:
I cannot get my Safari app to open. I have Safari 2.0.3. I originally had 1.0.
I have a Powerbook G4, 512 Ram, 40 GB. I tried to upgrade from Panther 10.3.9 to Tiger 10.4.6. The upgrade failed and I re-loaded the original Panther 10.3.5 and updated back to 10.3.9. (In the process, my Quark Xpress 6.1 license corrupted and I had to re-load that, which is a different story.)
Whenever I click on Safari, it bounces once in the Dock, and then the spinning ball of death keeps spinning until I force-quit. I tried replacing the app with another one, I tried deleting files in the Library but nothing seems to work.
I also cannot get Firefox to open.
I am using AOL and Netscape 9.0 browsers at the moment but I like the simultaneous downloading capability of Safari.
Any explanations out there?

Hi Again macyue!
Rachel R posted:
"...there's also a chance that your failed installation of Tiger and return to Panther has resulted in other problems."
I suspect that as well, that is why I asked:
"What procedure did you use to replace the Safari application?
And what procedure did you use to reinstall Panther 10.3.x, after the failed upgrade?"
I also suspect that if, after the failed Tiger 10.4.x upgrade, you performed an Archive & Install of Panther 10.3.x, and chose to "preserve your user and network settings", there could be some corruption of the system.
See this KB Article for info How to reinstall a prior version
Quoted from there:
"Important: You should only perform an Archive and Install installation over the same major version of Mac OS X. For example, if your Mac OS X Install disc has Mac OS X 10.3, then you should only perform an Archive and Install over version 10.3 through 10.3.9. "Downgrading" your operating system version to an earlier major version may lead to issues. For example, downgrading Mac OS X 10.4 or later by performing an Archive and Install installation with Mac OS X 10.3.9 or earlier Install discs could lead to:..."
Could you please also post, how the Tiger 10.4.x upgrade failed?
And review the KB Articles linked to below.
Applications don't work after reinstalling Mac OS X
Safari may not work after an Archive and Install
ali b

Safari May Not Interpret Regular Expression in Compliance with W3C Standard

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