Regular Expression wierdness - problem with $ character

If I use the following KM code in Beanshell Technology - it works correctly and replaces "C$_0MYREMOTETABLE RMTALIAS, MYLOCALTABLE LOCALIAS, " with "C$_0MYREMOTETABLE_000111 RMTALIAS, MYLOCALTABLE LOCALIAS, "
But when I try to use the same exact code in 'Undefined' technology - it does not match anything in the source string - and does not replace anything.
If I change the regular expression to not use the $ it still does not work.
But if I change the source string to remove the $ - then the regular expression works.
If I use the same code in Beanshell technology - it works fine - but then I can't use the value in a later 'Undefined' technology step.
Does anyone know if the java technology does something special with $ characters when ODI parses the KM code?
Does anyone know if there is a way to use the value from a Beanshell variable in a 'Undefined' technology step?
String newSourceTableList = "";
String sessionNum ="<%=odiRef.getSession("SESS_NO") %>";
String sourceTableList = "<%=odiRef.getSrcTablesList("", "[WORK_SCHEMA].[TABLE_NAME] [POP_TAB_ALIAS]" , ",", ",") %>";
String matchExpr = "(C\\$_\\S*)"; (should end with two backslashes followed by 'S*' - this editor mangles it)
String replaceExpr = "$0_"+sessionNum+ " ";
newSourceTableList = sourceTableList.replaceAll(matchExpr,replaceExpr);
---------------------------------------------------

Phases of substitution in ODI:
The way ODI works allows for three separate phases of substitution, and you can use them all. The three phases are:
- First Phase: <% %> You will see these appear in the knowledge moduiles etc and these are substituted on generation. (when you generate a scenario, or tell ODI to execute an interface directly) this phase is used to generate the column names, table names etc which are known from the metadata at that phase.
- Second Phase: <? ?> This phase is substituted when the scenario is instatntiuated as an excution - session generation. At this point, ODI has the additional information which allows it to generate the schema names, as it has resolved the Logical/Physical Schemas through the use of the Context (which is provided for the execution to take place. All the substitutions at this point are written to the execution log.
- Third Phase <@ @> This phase is substituted when the execution code is read from the session log for execution. You will note that anything substituted in this phase is NEVER written to the execution log. (see PASSWORDS as a prime example, you don't want those written to the logs, with the security risks associated with that!)
Anything in <@ @> is always interpreted for substitution by the java beanshell, it does not have to be a Java Beanshell step, it can be any kind of step, it will be interpreted at that run-time point.

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Hi all,
Well as you know characters such as '*' and '?' are reserved characters in regular expression so I suppose if I want to find the exact character (a '?' for example) in a string, I have to escape it with a backslash:
str=str.replaceAll("\?","a");
In the statement above, I need to replace all question marks with another character but it has a compile error:
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I think you're right.
The point is that java first interprets the String and handle its own scape characters then the result would be passed on to reqular expression parser.
so I guess in order to search for one occurance of the '\' character or nothing at all the java string would be:
so that the input to reqular expression parser would be:
while in the first situation:
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Message was edited by:
nerssi
Message was edited by:
nerssi

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Hi,
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However, if I'm presented with this; '%word0 word1% wo%d2 word3', then I need to treat % as special case and leave the word as is, so result here would be; - '%word0 word1% wo%d2 myprefixword3', is this achievable using regexp ?

And for those who don't know, I guess we should explain why we're having to expand single spaces to double spaces...
(I'll use the "¬" character to represent spaces to make it clearer to see)
If we have a string such as
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¬word1¬word2¬word3¬However, when we specify what we want to search for we are going to say we want a space, followed by a number of characters (not spaces), followed by a space...
¬[^¬]*¬So, ideally, you'd expect it to look through the string and say
¬word1¬word2¬word3¬
\_____/... found word1
¬word1¬word2¬word3¬
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¬word1¬word2¬word3¬
            \_____/... found word3
Unfortunately, there is a problem. Once the first word has been found the pointer for searching the rest of the string is located on the next character after the match i.e.
¬word1¬word2¬word3¬
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SQL> ed
Wrote file afiedt.buf
1 with t as (select ' word1 word2 word3 ' as txt from dual)
2 --
3 select regexp_replace(txt, ' [^ ]* ', 'xxxxx') as txt
4* from t
SQL> /
TXT
xxxxxword2xxxxx
SQL>In order to deal with this, if we replace the single spaces with double spaces (not required at the start and end) our string looks like...
¬word1¬¬word2¬¬word3¬So as it searches it finds word1 as a match and then the pointer in the string is located...
¬word1¬¬word2¬¬word3¬
       ^... so the next match for the pattern of space-characters-space is word2 and then the pointer is located...
¬word1¬¬word2¬¬word3¬
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SQL> ed
Wrote file afiedt.buf
1 with t as (select ' word1 word2 word3 ' as txt from dual)
2 --
3 select regexp_replace(txt, ' [^ ]* ', 'xxxxx') as txt
4* from t
SQL> /
TXT
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;)

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I am trying to use JDK 1.4's regular expression classes to match text that appears with curly braces (e.g. {field1}) using the following regular expression:
[{]([0-9A-Za-z]+)[}]
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[{]([0-9A-Za-z]+)[}]
^
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at java.util.regex.Pattern.range(Pattern.java:2052)
at java.util.regex.Pattern.clazz(Pattern.java:1991)
at java.util.regex.Pattern.sequence(Pattern.java:1529)
at java.util.regex.Pattern.expr(Pattern.java:1489)
at java.util.regex.Pattern.compile(Pattern.java:1257)
at java.util.regex.Pattern.<init>(Pattern.java:1013)
at java.util.regex.Pattern.compile(Pattern.java:760)
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Hello,
Let's look at what you've done.
[\\{]([0-9A-Za-z]+)[}]Okay, first you escape the opening curly brace, but you did not escape the closing curly brace.
[\\{]([0-9A-Za-z]+)[\\}]Next, you use the square brackets, but you only have one thing in the brackets, so, they are unnecessary:
\\{([0-9A-Za-z]+)\\}Next, I am going to contract all that stuff inside your remaining square brackets to \\w, since that covers 0-9A-Za-z_
\\{(\\w+)\\}Now, are you expecting any sort of spaces within the curly brackets? If so, you didn't specify them. I'll assume you didn't.
Now you did all this, but it still doesn't match what you thought it would match. Did you use Matcher.matches or Matcher.lookingAt?
If you look at the API for these methods, you'll see that
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b) Matcher.lookingAt(...) only returns true if the start of the input sequence matches the pattern.
In either of these cases, if your string didn't start with the opening bracket, then the Pattern (in its current form) won't match. For example:
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"blah blah {text3}"             // matches() == false
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import java.util.*;
import java.util.regex.*;
public class RegExample
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Hello.
There were difficulties with character set change, using function convert ()
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BANNER
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NLSRTL Version 10.2.0.1.0 - Production
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3 v_o clob;
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We have localized the issue to Safari's not interpretting regular expressions consistently.
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i work with XI3.0 sp19
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ftp adapter send a xml file.
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This has been discussed lately:
Ampersand ('&') in XML - Mapping error
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senderEmail = "[email protected]"
senderName = "Patrik Hällman"
sendToEmail = "[email protected]"
sendToName = "Patrik Hällman"
clientId = (null)
contentType = "application/x-www-form-urlencoded"
destination = "DefaultHTTP"
headers = (Object)#2
httpHeaders = (Object)#3
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http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
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messageId = "5624FC90-E89E-2B47-92B9-F7328A8CB993"
timestamp = 0
timeToLive = 0
This is catastrophic when you working with cms and databases.
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Well, using UNICODE for upload/download files I think is most suitable way. If in AL11 you don't see it being displayed correctly (odd characters appear), that doesn't necessary mean it has wrong encoding set. Maybe AL11 is using different decoding type by default. Normally storage of file on AS is not its final destination, right? You place it there i.e. for customer's job to read it back and send via email. So just make sure that downloading program uses same decoding you used for encoding (UTF-8). Then the characters in the output stream (i.e. frontend file, mail body) should be displayed correctly
What I mean is don't worry how it is dispalyed in AL11, just ensure that after you download it, the characters are correctly decoded.
PS: Make sure that you metion encoding type explicitly both for upload and download programs
OPEN DATASET dset .... IN TEXT MODE ENCODING/DECODING UTF-8.
Regards
Marcin

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null

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Hi,
I have a text area that I want to use a regular expression
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source="{entryField}"
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flags="gi"
expression="{/[a-zA-Z0-9][a-zA-Z0-9][a-zA-Z0-9][a-zA-Z0-9][a-zA-Z0-9][a-zA-Z0-9][a-zA-Z0- 9][a-zA-Z0-9][a-zA-Z0-9](
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entryField.setStyle("borderColor", "green");
entryField.setStyle("borderThickness", "2");
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entryField.setStyle("borderColor", "red");
entryField.setStyle("borderThickness", "2");
The problem is the handler function always comes back
invalid, even when it should be valid, such as: 123456789 a12345678
lk231jkop
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Thanks!

This is weird, i just tried your RegExp using the Adobe's
Live Docs example and it worked perfectly.
Try it at:
http://livedocs.adobe.com/flex/201/langref/mx/validators/RegExpValidator.html
Scroll down to the end of the page, then type your RegExp and
your TestValue and click the Validate button, it works. I am
guessing that maybe it is your
i
flag, try removing it from your validator.
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Regular Expression wierdness - problem with $ character

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