Scan String Problem

I got an error when I run the attached code. When I get rid o the comma after the last %s, the error would be gone though. What's going on?
yik
Kudos and Accepted as Solution are welcome!
Attachments:
Untitled 4.vi ‏8 KB

%s matches a string up to the next space, I believe. Since a comma is a valid character, %s is matching "C,". If you specify %1S then you can keep the comma because it will match only 1 character, and the comma will not be part of the match.
Wow, I'm actually learning this regular expression nightmare.
- tbob
Inventor of the WORM Global

Similar Messages

Scan String Token Problem with leading Tokens

Hi, I'm using the scan string for token to read in a string of tokens that contain a leading "*" char in front of each string and terminates when the token index = -2. This works great if I have say *12345*1234 and so forth, but if there is bad data, say 1234 without the leading "*" in front, the token index return value is still -1 and it returns data which I read in thinking it found the "*". Maybe I shouldn't use the string for token function since it's probably just designed for ending tokens and not data with leading tokens. Is there a way to make this work properly or should I use another method to search for leading tokens in a string?
Thanks.
Solved!
Go to Solution.

Here. Try this one. It does the same thing and uses exposed functions.
The string functions look for something to mark the end of a string. All languages that I know of do this. So, like I said, remove the first element. I recommend the Subarray function with the index set to 1 and length unwired.
There are only two ways to tell somebody thanks: Kudos and Marked Solutions
Unofficial Forum Rules and Guidelines
Attachments:
Parse Message.png ‏10 KB

VISA and Scan string for tokens

Hi there,
I am currently developing a piece of software which needs to take in data from an Arduino board via the serial port and parse the input accordingly.
I have the 2 pieces of code working perfectly well separately, but I can not seem to figure out why they are not functioning properly together.
Just now, the input is being retrieved fine and passed into the Scan string for tokens method, but it is not being split on the tokens, it is just outputting the string as a whole.
The input is in the form of 1:0 2:0 3:1 etc. so I am trying to split it on any spaces found. If I attach a string to the Scan strings for tokens it works fine, just not when I am attaching the data from the serial port to it.
Any help would be appreciated.
Attachments:
input manipulation.vi ‏16 KB

Hi,
In the output which you are getting from the serial port, is there space between 1:0 and 2:0 and 3:1? If there is no space between them, then it wont be able to scan for tokens and will output the whole string. I don't have the hardware here and so don't know what exactly is the output which you are receiving. Try to see in the read buffer indicator whether the tokens are seperated by a space or not.
I have attached your vi after adding a small part in it. If the problem is with the spacing then this will work fine for 1:0 2:0 3:1.
Regards,
Nitzz
(Give kudos to good Answers , Mark it as a Solution if your problem is Solved)
Attachments:
input manipulation.vi ‏18 KB

ScanFile with scanning string modifier %s[in]

For skipping over non-numeric characters by reading ASCII files I used to write, e.g.
ScanFile (fhandle, "%s[i8]>%f", &x);
This method works well with CVI 5.0 to 8.11 but no more with CVI 2009 and 2010. I have modified my old code using other scanning string modifiers:
ScanFile (fhandle, "%s>%s[dt#]%f", &x);    or
ScanFile (fhandle, "%s>R1= %f", &x);
The first one does not work with a string like “R1=200”. The second requires the exact string and is more inconvenient. Although the modified code works well now with CVI 2009, I would like to know why the scanning string modifier [in] does not work with CVI 2009 and 2010. Is there something wrong in my code, is it a feature of the new versions of CVI or is it a bug? How about CVI 2013?

Thank you very much for your reply.
I would not use "%s[i8]>%f" to read the number 200 in string "R1=200". I just wanted to take this string as an example to say that I couldn't simply change all of "%s[in]>%f"s in my code to  “%s>%s[dt#]%f"s, somewhere I had to use a quite inconvenient "%s>R1= %f". Therefore I do hope that "%s[in]>%f" works by a new version of CVI.
In my code I use a lot of Scan (string, "%s[in]>%f", &x) and all of them work always correctly, also with CVI 2009-2010. But none of ScanFile (fhandle, "%s[in]>%f", &x) works with my CVI 2009, they work only with earlier versions.. That’s very strange to me as I couldn't find in the documentation/Help of CVI 2009-2010 a description that "%s[in]>%f" should not be used with the ScanFile function,
My further tests showed that this problem seems to be related to CVI Run-time. By reading the same ASCII file, the same executable created by CVI 8.11 works with CVI Run-time 8.1 but does not with Run-time versions 9.0 to 10.0.1.419.

Labview novice with a question about scanning strings

Hello, I'm a research assistant tasked with taking data received via TCP-IP and plotting it. I've had a couple of problems, probably because I've never used Labview before.
The data is sent in sets of six values separated using semicolons as delimiters, for example
"0.086842;0.00020341;0.00039838;-0.14057;-0.12614;-0.1327;" is one such data set
Receiving these strings through TCP connection is working just fine, however I just noticed that after passing a string such as my example into a 'Scan String for Tokens' block, the negative signs are dropped from the latter three values. I assumed it has something with setting '-' as an operator, but simply wiring negative sign in as an operator didn't change anything. I know there has to be a way to retain my negative signs, but I can't figure it.

Is this what you need?
Attachments:
SNAG-002.jpg ‏91 KB
SNAG-003.jpg ‏20 KB

HP LaserJet Pro M1217nfw Multifunction Printer scaner driver problem in windows 7

I have a HP LaserJet Pro M1217nfw Multifunction Printer. Printer is ok but Scaner has problem in Windows 7 scaner driver is deleted when i try to scan it show the error " Scaner not communicate " I have to reinstall driver after few minitus again same problem . Pls advise me what is the best solution for that

Hi KrunalPatel,
I'll paste a link to a troubleshooting document below - from what I've read, it has the best chance at fixing your scanner errors, as it has the most steps to try
http://h10025.www1.hp.com/ewfrf/wc/document?cc=us&lc=en&docname=c02917811
Please let me know how it goes
*** If my reply was helpful, please click on the "Kudos Thumbs-Up" on the right, as a way to say "Thanks!".
If this reply also fixed your issue - please click the "Accept as Solution" button, so that others can find the same answer. ***

Is Scan String for Tokens documented correctly?

I attempted to parse the following string using " as the only delimiter (no operators):
this "is a test" for "you and me"
The first call produced: "this " w/o the quotes.
I expected "is a test" w/o the quotes.
The documentation says the function will return tokens "surrounded by" delimiters. If this is not a bug, I think the documentation should be improved.
W. Brown

Thank you for commenting on the Scan String for Tokens documentation. We will look into this issue and try to make the documentation more clear about how this function works.
We're constantly striving to improve the documentation, so any specific suggestions you have are welcome. In the future, please send any comments on National Instruments documentation to [email protected] so we can address your concerns in a timely matter.
Kelly Holmes
LabVIEW Documentation Team
Kelly H
LabVIEW Documentation
National Instruments

Scan string for tokens

Can anyone help me out on how to detect a new line using the scan string for tokens function? I am using the "\n" delimiter but it is not working

Syntyche wrote:
I opened a text file and display it on string indicator. The following is an example of my text file
START
SETMASS 5
WAIT 5s
SETVELOCITY 10
WAIT 3s
END
So what I want to do is to obtain the string line by line.
I am thinking I can use scan string for tokens with delimeter \n.
So if i put this in while loop, in the first iteration, I would want the ouput to be START
Second iteration: SETMASS 5
Third iteration WAIT 5s. and etc....
In C programming i believe this can be done by using strtok. So i want to have a similar function.
See James' post above, which is what I was hinting at when I said it could be less complicated. And that's why I asked WHAT you were trying to do, instead of HOW. In this latest post, you show WHAT you wanted to do, and doing that in the first place would have made the thread a lot shorter.

"Scan String For Tokens" weird behaviour

I am trying to carry out the simple task of getting a string with
comma delimiters and produce a string_array with the values in between
the commas; this would simplify calling the different parts of the
string.
Example:
INPUT: this,is,an,example
OUTPUT: this|is|an|example (this would be an array of strings)
Using a while loop with the two VI "Scan String For Tokens" and
"Insert to array" should be enough to carry this task. I started
using a FOR loop as the number of tokens I´ll be using is fixed.
However I wanted to make the subVI more general by allowing any
#tokens in the input string and using the token index with a WHILE
loop to do this. The "token index" output from the "Scan String For
Tokens" is said to be use
d in a while loop to process the whole
string.
However,I´m getting -1 as an output even if I´ve got more tokens left
and the while loop therefore exits.
What am I doing wrong?
Should I use -2 as the comparison to decide whether I´m at hte end or
not of the string?
Cheers and TIA

Check the offset for -1, not the token index. (See attached image). If course if this is a multiline string, the you also need /n etc as delimiter.
If the string ends in a delimiter, you need to clip the last array element. I usually use "reshape array" with the output from [n] as input.
LabVIEW Champion . Do more with less code and in less time .
Attachments:
ScanForTokens.gif ‏17 KB

Missing HEX characters from scanned string

Hi everyone,
I have a program which scans a continuous string of serial data which is divided into header, data and checksum. I have replaced the serial part of my code with a simple string input to simulate the data input for testing and as in the diagram below you can see 0A, 0C and 0D are missing and I can't figure out why. Currently it is an exercise to parse out all the data I need for a data aquisition system. If anyone can help me out with this I would greatly appreciate it. This was in a different thread but it has dissapeared into the ether. Here is the picture illustrating the problem.
Thanks again
Stirling
Message Edited by stirlsilver on 04-09-2007 06:17 PM
Attachments:
Serial read v1.2.vi ‏85 KB

You are doing all this way too complicated. There is absolutely no need to use "scan from string" to simply chop up a string into parts. Use string subset instead (in a loop).
You also have way too much duplicate code. You can operate on arrays directly and use array indicators for the channels. This reduces the complexity of your diagram 10 fold!!!
I don't have your serial hardware, but attached is a small code fragment (LV 8.0) that seems to do about the same thing with your string using 10% of your code. Modify as needed. Let me know if anything is not clear.
LabVIEW Champion . Do more with less code and in less time .
Attachments:
Serial_read_v1.2MOD.vi ‏24 KB

Beginner : Array , String Problems continue.

Hi everybody I am so New in Java or rather not really able to understand Java yet.
I have assignment where I do not know how to think anymore..is probably very easy to those who understand programming but sadly I do not.
Program should do:
1. assign any amount of different strings.
2. user is giving any letter he/she wants and program to find it among given strings.
If searched letter is in any string/ strings , only these strings or string are printed.
3. If in given strings is not searched letter, program has to say it, for ex: there is not letter you search for.
As long as now I have only, strings assigning to array. So there are strings in array but I do not know how to write code where I can find given letter by user.
I just do not know how I should think(anymore at all ;)) here. I am really frustrated and desperate, how to understand this?? Once and for all!!!
I was thinking maybe I should use ArrayList? but how...or Can it be done both ways with Array or with ArrayList?
     public static void main(String[] args) {
          Scanner scan = new Scanner(System.in);
          System.out.print("How many strings ?");
          int antal= scan.nextInt();
          String [] str = new String[antal];
           String string = null;
          int x;
           scan.nextLine();
             for( x=0;x<str.length;x++){
                  System.out.print("String "+(x+1)+": ");
             string= scan.nextLine();
             str[x]= string;
            System.out.print("Write a letter you wish to find :");
            String letter = scan.nextLine();
            char check = letter.charAt(0);
//somthing in here ....

Thank you very, very much for helping me, this is the first forum where I am getting any answers at all. Thanks guys!
Yes, that is true I have a problem to "see" things in code..I feel " lost in translation " :)...Sometimes I think I understand code and than suddenly code does total different thing than I thought. I have to pass 2 exams of Java basic and bit advance level of Java , all seems very dark now..but I have a hope that I at least pass those exams. Of course it could be fantastic to start understand Java (or any other computer language) and be able to code one day for real. To be honest, I envy you that you can understand Java. When, all code works is so cool and fun! ok, Back to code...
So I read your tips and advices , thanks.
Here is another problem, with help of indexOf(char) I got index for character I searched, fine.
The way i wrote the code I got separate answer for each string(check in code). What I need to have is, separate printed strings where given character is found and nothing else should be printed. Later, I need just one general comment ,only in case if character is NOT found in given strings.
import java.util.*;
public class upp9 {
     public static void main(String[] args) {
          Scanner scan = new Scanner(System.in);
          System.out.print("How many strings ?");
          int antal= scan.nextInt();
          String [] str = new String[antal];
          int x;
           scan.nextLine();
             for( x=0;x<str.length;x++){
                  System.out.print("String "+(x+1)+": ");
             str[x]= scan.nextLine();
            System.out.print("Write a letter you wish to find :");
            String letter = scan.nextLine();
            char check = letter.charAt(0);
               for( x=0;x<str.length;x++){
                   str[x].indexOf(check);
                 //     System.out.println("String "+(x+1)+" "+str[x].indexOf(check));
            if((str[x].indexOf(check))>=0)
                 System.out.println("String "+(x+1)+" "+str[x]);
            else
                 System.out.println("Nothing in this string");
System.out.println();
}is printed.
How many strings ?4
String 1: hello
String 2: other
String 3: alex
String 4: batman
Write a letter you wish to find :a
Nothing in this string
Nothing in this string
String 3 alex
String 4 batmanI should get printed (with other code)...where I don't know how to think here? what code I should use?, what I can what I can not do here...hmmm
//in case found
How many strings ?4
String 1: hello
String 2: other
String 3: alex
String 4: batman
Write a letter you wish to find :a
String 3 alex
String 4 batmanor....
//in case NOT found
How many strings ?4
String 1: hello
String 2: other
String 3: alex
String 4: batman
Write a letter you wish to find : j
Not found

Null String and Empty String problem

Hello everyone,
since i am totally new in JSP, i am getting problem in handling strings.
Suppose i have a variable users = ""; then
I want to ask when to use:
if (users.equals(""))
and
if(users == "")
in my code, variable users has value "regional" for regional users.
and i am checking this code as:
if (users.equals{"regional")) {
out.print ("I am inside code");
at that time, the code is throwing error (run time error)
and when i changed the code as:
if (users == "regional") {
out.print ("I am inside code");
this time, the code is not generating error but the part message "I am inside code " is not displaying. The code do not inserts inside the if condition
I hope u understand my problem. Can anybody help me out with this.

This has basically nothing to do with JSP, but with basic Java knowledge.
When using the '==' operator to compare Objects (yes, String is actually a subclass of Object), then it will look if they are of the same reference. Using the '==' operator to compare primitive datatypes (int, boolean, char, etc) will look if they have the same value.
That is why the Object class has the equals() method to give the ability compare with another objects. And you can only invoke it when the Object is actually instantiated. So if it is not null.
if (string != null && string.equals("somevalue")) {
// or
if ("somevalue".equals(string)) {
}should work.
Edit rym82: this will not throw a NPE, but an ordinary compilation error ;)
Message was edited by:
BalusC

POI getCellStyle and empty string problem

I'm having a problem getting the style of a cell from and excel input file and setting to an output file.
I also have a problem recognizing blank cells that are not null in the input file here is my code any help would be great.
package Trace;
import java.io.*;
import org.apache.poi.hssf.usermodel.*;
import org.apache.poi.hssf.util.HSSFColor;
import java.util.StringTokenizer;
import org.apache.poi.poifs.filesystem.*;
import java.lang.Runtime;
public class Converter1 {
     private static short bhyvb= 0;
     private static short foreground, background;
     private static String[][] cellGridOut;
     private static int numRows, numColumns, clock;
     private static POIFSFileSystem fs;
     private static HSSFWorkbook wbin, wbout;
     private static HSSFSheet sheetIn, sheetOut;
     private static HSSFRow rowIn, rowOut;
     private static HSSFCell cellIn, cellIn1, cellOut;
     private static FileOutputStream fileOut = null;
     private static String rowIterator, rowIterator1;
     private static HSSFCellStyle style, style1;
     public static void main(String[] args) {
          //Take in 2 inputs mandatory, Input Event Trace excel file and Time Interval respectively
          if (args.length != 1)System.err.println("Input Excel File");
          //Create a new POI file system and HSSF workbook with your excel input file
          InputStream input = Converter.class.getResourceAsStream(args[0]);
          try{
               fs = new POIFSFileSystem(input);
               wbin = new HSSFWorkbook(fs);
          }catch (Exception e){System.err.println("File input error");}
          wbout = new HSSFWorkbook();
          sheetIn = wbin.getSheetAt(0);
          numRows = sheetIn.getLastRowNum();//numRows=723
          style = wbout.createCellStyle();
          //style.setFillForegroundColor(HSSFColor.LIGHT_YELLOW.index);
          //style.setFillPattern(HSSFCellStyle.SOLID_FOREGROUND);
          //get number of columns
          rowIn = sheetIn.getRow(0);
          boolean done = false;
          int testNullPointer;
          numColumns=0;
          while(!done){
               //System.out.println(ColumnInc);
               cellIn = rowIn.getCell((short)numColumns);
               numColumns+=1;
               try{
                    testNullPointer = cellIn.getCellType();
               }catch(NullPointerException npe){
                    done = true;
          numColumns-=1; //number of columns = 25
          converterIt();
          //Create new output file, if it exists delete it
          File myFile = new File("converted.xls");
          if(myFile.exists()){
               myFile.delete();
          //Create new file output stream
          try {
               fileOut = new FileOutputStream(myFile);
          } catch (IOException ioe) {}
          //write all conversion data to output file
          try{
               wbout.write(fileOut);
               fileOut.close();
          }catch (IOException ioe) {}
     public static void converterIt(){
          boolean nextDone = false;
          boolean nextDone1 = false;
          for(int i=0; i<numColumns; i++){
               clock =1;
               rowIn = sheetIn.getRow(0);
               cellIn = rowIn.getCell((short)i);
               String getTopRow = cellIn.getStringCellValue();
               sheetOut = wbout.createSheet(getTopRow+"_s"+i);
               sheetOut.setColumnWidth((short)0, (short)(13 * 256));
               sheetOut.setDefaultColumnWidth((short)25);
               for(int j=0; j<=numRows; j++){
                    if(j==0){
                         rowIn = sheetIn.getRow(j);
                         cellIn = rowIn.getCell((short)i);
                         String temp2 = cellIn.getStringCellValue();
                         rowOut = sheetOut.createRow((short)j);
                         cellOut = rowOut.createCell((short)j);
                         cellOut.setCellValue(temp2);
                         cellOut = rowOut.createCell((short)(j+1));
                         cellOut.setCellValue("CLOCK");
                    if(j==1){
                         rowIn = sheetIn.getRow(j);
                         cellIn = rowIn.getCell((short)i);
                         double temp3 = cellIn.getNumericCellValue();
                         rowOut = sheetOut.createRow((short)j);
                         cellOut = rowOut.createCell((short)0);
                         cellOut.setCellValue(temp3);
                         cellOut = rowOut.createCell((short)1);
                         cellOut.setCellValue("");
                    nextDone=false;
                    nextDone1=false;
                    if(j>1){
                         rowIn = sheetIn.getRow(j);
                         try{
                              cellIn = rowIn.getCell((short)i);
                         }catch(NullPointerException npe){
                              rowIterator = "";
                              nextDone=true;
                         if(!nextDone){
                              try{
                                   rowIterator = cellIn.getStringCellValue();
                                   style = cellIn.getCellStyle();
                              }catch(NullPointerException npe){}
                         if(j==2){
                              rowOut = sheetOut.createRow((short)(clock+1));
                              cellOut = rowOut.createCell((short)0);
                              cellOut.setCellValue(rowIterator);
                              cellOut = rowOut.createCell((short)1);
                              cellOut.setCellValue(j-1);
                              clock+=1;
                         }else{
                              rowIn = sheetIn.getRow(j-1);
                              try{
                                   cellIn = rowIn.getCell((short)i);
                              }catch(NullPointerException npe){
                                   rowIterator1 = "";
                                   nextDone1=true;
                              if(!nextDone){
                                   try{
                                        rowIterator1 = cellIn.getStringCellValue();
                                   }catch(NullPointerException npe){}
                         if(rowIterator1!=rowIterator && j>2){
                              rowOut = sheetOut.createRow((short)clock+1);
                              cellOut = rowOut.createCell((short)0);
                              cellOut.setCellValue(rowIterator);
                              //System.out.println(style);
                              cellOut.setCellStyle(style);
                              cellOut = rowOut.createCell((short)1);
                              cellOut.setCellValue(j-1);
                              clock+=1;
                    }//if
               }//for
          }//for
     }//converterIt
}//Converter1 CLASSEND

I am not sure about the cell style as it looks like you are doing it right. For the null or blank cells it looks like you are only checking for null not "".

Photosmart d110 copy/scan & installation problems on Windows 8.1

I have a few issues with my d110... First, I have successfully gotten it to print from Windows 8.1 but it does nothing else. I tried using the installation disc and the setup screen literally only shows Exit as an option... no install option whatsoever. I even removed the device and everything and tried it again to no avail.
Next, I tried to make a scan or copy and it shows a Scanner Failure error message saying "Unable to Copy or Scan".
I've read through several of the forums and nobody seems to encounter the same problem I am.
I have had this printer for a few years and have had nothing but problems with it from the beginning. Most of them are solved through hours of troubleshooting, but this printer is the biggest hassle. I'm not sure if at this point I should just replace it or what.... So frustrating.

Hi,
The first issue happens due to incompatibility, the original CD is not intended for Windows 8.1 and therefore you did not see any Install option... any supported OS is listed on the CD label, Windows 8 is not listed among the options...
As you describe a scanner failure, we will need to troubleshoot such n hardware issue first, scanning would not be possible if the hardware is faulty...
Turn the printer off and unplug any cable but the power to avoid any affect.
Turn it on and try copying.
If the same error appear, the scanner hardware misfunction.. follow these steps to troubleshoot a such.. if those does not resolve the Scanner Failure issue it will require you to service the printer:
http://h10025.www1.hp.com/ewfrf/wc/document?docname=c00587971&tmp_task=solveCategory&cc=us&dlc=en&lc...
If you were able to resolve the hardware failure by following the steps above, download and install the Windows 8.1 software below:
http://h10025.www1.hp.com/ewfrf/wc/softwareDownloadIndex?softwareitem=mp-109779-2&cc=us&dlc=en&lc=en...
Regards,
Shlomi
Say thanks by clicking the Kudos thumb up in the post.
If my post resolve your problem please mark it as an Accepted Solution

Printing and scanning size problems (half size)

Hello,
I am having an issue with my Pixma MP170. When printing multiple pages or scanning a paper document, the size come out really small all of a sudden and two pages will be together in one print or scan. I looked for updated drivers but that doesn't look to be the issue and the problem pesists.
I tried to reset the printer to default but nothing.
Not sure how to proceed.
Thanks for any suggestion.

I have had something very like your problem.
Mine is printing quarter size in landscape and is also not scanning or doing copies at the moment..
I can find no way of setting it and it ignores all settings sent from the computer.
It printed one test page correctly and once I tried printing a small text file it came out small and in landscape and now even the test page is also small and also in landscape.
I am tempted to look inside for an engineering jumper or backup battery.
Mine is an MP270.

Scan String Problem

Similar Messages

Maybe you are looking for