Beginner : Array , String Problems continue.

Question

Hi everybody I am so New in Java or rather not really able to understand Java yet.
I have assignment where I do not know how to think anymore..is probably very easy to those who understand programming but sadly I do not.
Program should do:
1. assign any amount of different strings.
2. user is giving any letter he/she wants and program to find it among given strings.
If searched letter is in any string/ strings , only these strings or string are printed.
3. If in given strings is not searched letter, program has to say it, for ex: there is not letter you search for.
As long as now I have only, strings assigning to array. So there are strings in array but I do not know how to write code where I can find given letter by user.
I just do not know how I should think(anymore at all ;)) here. I am really frustrated and desperate, how to understand this?? Once and for all!!!
I was thinking maybe I should use ArrayList? but how...or Can it be done both ways with Array or with ArrayList?
     public static void main(String[] args) {
          Scanner scan = new Scanner(System.in);
          System.out.print("How many strings ?");
          int antal= scan.nextInt();
          String [] str = new String[antal];
           String string = null;     
          int x;
           scan.nextLine();
             for( x=0;x<str.length;x++){
                  System.out.print("String "+(x+1)+": ");                       
             string= scan.nextLine();
             str[x]= string;
            System.out.print("Write a letter you wish to find :");
            String letter = scan.nextLine();
            char check = letter.charAt(0);
  //somthing in here ....

Answer 1

Thank you very, very much for helping me, this is the first forum where I am getting any answers at all. Thanks guys!
Yes, that is true I have a problem to "see" things in code..I feel " lost in translation " :)...Sometimes I think I understand code and than suddenly code does total different thing than I thought. I have to pass 2 exams of Java basic and bit advance level of Java , all seems very dark now..but I have a hope that I at least pass those exams. Of course it could be fantastic to start understand Java (or any other computer language) and be able to code one day for real. To be honest, I envy you that you can understand Java. When, all code works is so cool and fun! ok, Back to code...
So I read your tips and advices , thanks.
Here is another problem, with help of indexOf(char) I got index for character I searched, fine.
The way i wrote the code I got separate answer for each string(check in code). What I need to have is, separate printed strings where given character is found and nothing else should be printed. Later, I need just one general comment ,only in case if character is NOT found in given strings.
import java.util.*;
public class upp9 {
     public static void main(String[] args) {
          Scanner scan = new Scanner(System.in);
          System.out.print("How many strings ?");
          int antal= scan.nextInt();
          String [] str = new String[antal];
          int x;
           scan.nextLine();
             for( x=0;x<str.length;x++){
                  System.out.print("String "+(x+1)+": ");                       
             str[x]= scan.nextLine();
            System.out.print("Write a letter you wish to find :");
            String letter = scan.nextLine();
            char check = letter.charAt(0);
               for( x=0;x<str.length;x++){
                   str[x].indexOf(check);
                 //     System.out.println("String "+(x+1)+" "+str[x].indexOf(check));
            if((str[x].indexOf(check))>=0)
                 System.out.println("String "+(x+1)+" "+str[x]);
            else
                 System.out.println("Nothing in this string");
  System.out.println();
}is printed.
How many strings ?4
String 1: hello
String 2: other
String 3: alex
String 4: batman
Write a letter you wish to find :a
Nothing in this string
Nothing in this string
String 3 alex
String 4 batmanI should get printed (with other code)...where I don't know how to think here? what code I should use?, what I can what I can not do here...hmmm
//in case found
How many strings ?4
String 1: hello
String 2: other
String 3: alex
String 4: batman
Write a letter you wish to find :a
String 3 alex
String 4 batmanor....
//in case NOT found
How many strings ?4
String 1: hello
String 2: other
String 3: alex
String 4: batman
Write a letter you wish to find : j
Not found