Scheule a job that runs on first day of every month
Hi i want to schedul a job (run a procedure ) on first day of every month . I have done something lije this
declare
nextdate date;
begin
SELECT trunc(add_months(sysdate,1),'MM') into nextdate FROM DUAL ;
dbms_output.put_line(nextdate);
dbms_job.submit(
what=>'someprocedure',
next_date=>nextdate,
interval=>'30');
end;
is interval mandatory ? how can i define that interval ??
Hi,
You can define an interval as follows:
SQL> alter session set nls_date_format='dd-mm-yyyy hh24:mi:ss';
Session altered.
SQL> select add_months(trunc(sysdate, 'mm'), 1) from dual;
ADD_MONTHS(TRUNC(SY
01-09-2009 00:00:00
1 row selected.
SQL> select add_months(trunc(sysdate, 'mm'), 1) + 7/24 from dual;
ADD_MONTHS(TRUNC(SY
01-09-2009 07:00:00So, if you want your job to start at 07.00 every month you submit:
declare
nextdate date;
begin
SELECT trunc(add_months(sysdate,1),'MM') into nextdate FROM DUAL ;
dbms_output.put_line(nextdate);
dbms_job.submit(
what=>'begin someprocedure; end;',
next_date=>sysdate,
interval=>'add_months(trunc(sysdate, ''mm''), 1) + 7/24');
end; untested
Check the docs: http://tahiti.oracle.com
and/or http://asktom.oracle.com
and/or this forum as well.
Do some searches and you'll find lots of examples.
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I have recently written my first stored procedure.
Its rather a bunch of SQL statements.
I had to hard code lot of dates. most of them are first day of the current monthe or last day of current month etc.
I thot of parametrizing all the dates, but if a business person has to include all the parameters they could go wrong and get the wrong results.
Now, I want to use date functions to achieve these requirements:
Can any one please throw some insght into this:....
1) First day of current month,
2) last day of current month.
3) first day of previious month
4) last day of previous month
5) first day of a month that is 3 months from now.
6) last day of a month that is 3 months from now.
7).....
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AcHi there,
1) First day of current month
select trunc(sysdate, 'MM') from dual;
2) last day of current month.
select trunc(add_months(sysdate, 1), 'MM') - 1 from dual;
3) first day of previious month
select trunc(add_months(sysdate, -1), 'MM') from dual;
4) last day of previous month
select trunc(sysdate, 'MM') - 1 from dual;
5) first day of a month that is 3 months from now.
select trunc(add_months(sysdate, 3), 'MM') from dual;
6) last day of a month that is 3 months from now.
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if sy-datun+6(2) = 01.
SY-FDAYW should give you the day
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REPORT <PGM NAME>.
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DATA: temp_REQUEST LIKE RSODSACTREQ-REQUEST,
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DATA: BEGIN OF itab1 OCCURS 0,
RNR LIKE rsseldone-RNR,
seldate LIKE rsseldone-seldate,
seltime LIKE rsseldone-seltime,
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IMPORTING
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if temp_REQUEST = temp_REQUEST1.
raise exception .
endif. -
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data: w_date type sy-datum ,
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Date for first day of current month
How can i get the date for first day of current month ?
select trunc(sysdate,'MM'),to_char(trunc(sysdate,'MM'),'DD'),to_char(trunc(sysdate,'MM'),'Day') from dual;
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How to get the first day in the month from a domain date ?
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StephenHi Gokul...
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Its similar to the above one but instead of writing case statement you can achive the following.
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Function module to get the 'first day of next month'
Hi
I have a selection screen with input fields
1. period (month eg: 07)
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Please help me in this regard.
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Rama.Mekalahi try this FM ...
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it gives the Begin Date and End date of the month
rewards points if found useful
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How to get the first day of current month
hi guys,
i am trying to get the first day of current month which get from the date i input at the selection screen. my method is not so good, so i was wondering if there is better way to get the this,
thanks.Try this .
data : DAYNR LIKE HRVSCHED-DAYNR,
DAYTXT LIKE HRVSCHED-DAYTXT.
data langu like sy-langu value 'EN'.
Parameters PDATE LIKE SY-DATUM.
PDATE+6(02) = '01'.
CALL FUNCTION 'RH_GET_DATE_DAYNAME'
EXPORTING
LANGU = LANGU
DATE = PDATE
CALID =
IMPORTING
DAYNR = DAYNR
DAYTXT = DAYTXT
DAYFREE =
EXCEPTIONS
NO_LANGU = 1
NO_DATE = 2
NO_DAYTXT_FOR_LANGU = 3
INVALID_DATE = 4
OTHERS = 5
IF SY-SUBRC <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.
WRITE :/ PDATE, DAYNR, DAYTXT.
Cheers -
How to - get first DAY of the month from the date ?
Hi
pls helphi,
data : DAYNR LIKE HRVSCHED-DAYNR,
DAYTXT LIKE HRVSCHED-DAYTXT.
data langu like sy-langu value 'EN'.
Parameters PDATE LIKE SY-DATUM.
PDATE+6(02) = '01'.
CALL FUNCTION 'RH_GET_DATE_DAYNAME'
EXPORTING
LANGU = LANGU
DATE = PDATE
CALID =
IMPORTING
DAYNR = DAYNR
DAYTXT = DAYTXT
DAYFREE =
EXCEPTIONS
NO_LANGU = 1
NO_DATE = 2
NO_DAYTXT_FOR_LANGU = 3
INVALID_DATE = 4
OTHERS = 5
IF SY-SUBRC <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.
WRITE :/ PDATE, DAYNR, DAYTXT.
(OR)
Try..
DATA:DAYNR LIKE HRVSCHED-DAYNR,
DAYTXT LIKE HRVSCHED-DAYTXT,
DAYFREE LIKE HRVSCHED-NODAY.
DATA:LANGU LIKE SY-LANGU ,
DATE LIKE SY-DATUM,
CALID LIKE P1027-CALID VALUE 'US'.
date = sy-datum.
date+6(2) = 01. "----->to get the first day .
*first day of the month
write:/ 'First date of the month', date.
*Day name
CALL FUNCTION 'RH_GET_DATE_DAYNAME'
EXPORTING
langu = SY-LANGU
date = DATE
CALID = CALID
IMPORTING
DAYNR = DAYNR
DAYTXT = DAYTXT
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EXCEPTIONS
NO_LANGU = 1
NO_DATE = 2
NO_DAYTXT_FOR_LANGU = 3
INVALID_DATE = 4
OTHERS = 5
IF sy-subrc <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
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WRITE:/ DAYTXT.
Don't forget to reward if useful.... -
Is there any funcions available to pick up first day of the month?
I want to show the first month of the year given any date time stamp as input..
eg:
select sysdate from dual
assume sysdate is 10 Mar 2005
the output should be 10 Jan 2005.
We can take the last day of the month by using last_day
how to take the first day of the month given a input datetime?I want to show the first month of the year given any date time stamp as input..There is a little confusion with the thread's title.
We all answered you about your title question : how to obtain the first day of month, not the first month of year. For which you can test something like this :
SQL> select col1,add_months(col1,(-1*to_char(col1,'MM'))+1)
2 from (select to_date('10032007','DDMMYYYY') col1 from dual union all
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SQL> /
COL1 ADD_MONT
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05/01/07 05/01/07
SQL> Nicolas.
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