I want the minimum of the horizontal axis to be the first day of the month.

I have a situation where I want the minimum of the horizontal
axis(with date time axis) to be the first day of the month. I
attempt it like so:
var max:Date = new Date();//current date is our max from
which we will calculate the min
var min:Date = new Date(max.fullYear,max.month,1);
dateTimeAxis.minimum = min;
However this first date on this axis is the last day of the
previous month for example 31 August instead of 1 September. Any
ideas how to fix?

Nikos, the only thing I can think of (off hand) is that it's
defaulting to "zero" hour on that date, if you tried:
var min:Date = new Date(max.fullYear,max.month,1,13);
Would that make it work? That would set the date to 1pm.
Have you considered defining the axis with the data you are
binding to?
Cheers,
David

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Want to make Monday as the first day of the week in GregorianCalendar. how?

hi
I need to know what day is the first of the month is. for example the 1st of Nov 2004 is Moday and 1st of Dec 2004 is saturday.
I am using the GregorianCalendar:
1. GregorianCalendar calendar = new GregorianCalendar(2004,11,1); //set date to 1st Nov 2004
2. int firstDay = calendar.get(Calendar.DAY_OF_WEEK);now firstDay is 2. This is because the week starts from Sunday, so Monday is the 2nd day.
But I am in Uk and my Uk Calendar shows monday as the first day (even in Windows 2000 Calendar).
I would like the GregorianCalendar to have Monday as the first day of the week, so that the
int firstDay = calendar.get(Calendar.DAY_OF_WEEK);
returns 1 in the above case.
I also tried adding
calendar.setFirstDayOfWeek(Calendar.MONDAY); just between line 1 and line 2, but it did not help.
This is because i don't want to manually subtract 1. If i manually subtract one, then the program might not work in other locale and timezones.
Also if I subtract 1, then for 1 Feb 2004,
int firstDay = calendar.get(Calendar.DAY_OF_WEEK);
will return 1 as 1st Feb 2004 falls on Sunday. so if i subtract 1 it will be 0, so I have to do a extra checking for 0.
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hi
I need to know what day is the first of the month is.Why does this matter? Since we know that 1 == Sunday and 2 == Monday... Why do you need Monday to be == 1? and couldn't you just subtract 1 if it's so important?
for example the 1st of Nov 2004 is Moday and 1st of
Dec 2004 is saturday.
I am using the GregorianCalendar:
1. GregorianCalendar calendar = new
GregorianCalendar(2004,11,1); //set date to 1st Nov
2004
2. int firstDay = calendar.get(Calendar.DAY_OF_WEEK);now firstDay is 2. This is because the week starts
from Sunday, so Monday is the 2nd day.
But I am in Uk and my Uk Calendar shows monday as the
first day (even in Windows 2000 Calendar).
I would like the GregorianCalendar to have Monday as
the first day of the week, so that the
int firstDay = calendar.get(Calendar.DAY_OF_WEEK);
returns 1 in the above case.
I also tried adding
calendar.setFirstDayOfWeek(Calendar.MONDAY);[/cod
] just between line 1 and line 2, but it did not help.
This is because i don't want to manually subtract 1.
If i manually subtract one, then the program might not
work in other locale and timezones.
Also if I subtract 1, then for 1 Feb 2004,
int firstDay = calendar.get(Calendar.DAY_OF_WEEK);
will return 1 as 1st Feb 2004 falls on Sunday. so if i
subtract 1 it will be 0, so I have to do a extra
checking for 0.
Is there anyway to make the Calendar have Monday as
the first day of the week??
Tanveer

OS does not meet the minimum system requirements for this installer. 10.6.0 is the minimum required

How do I get my software? This is the message I am hitting before my download will complete:
OS does not meet the minimum system requirements for this installer.
10.6.0 is the minimum required for installation.

Hi,
May I know what are you trying to download ?
What is the MAC OS version you are using ?
It seems you are trying to download an application which needs atleast 10.6 MAC version
I think you are using lower version of MAC, let us know the version of your MAC , in order to help better .
To check the version : click on Apple Button on top left
select about this MAC, you will get to know the version over there.
If its something 10.5.x , then you need to upgrade your MAC in order to install that application which needs 10.6 MAC
Thanks,
Baljeet

On my iPad 3, how do I make calendar items lasting more than one day appear as such on the monthly view of my calendar? Right now only the first day of the item appears.

On iPad 3, all of my calendar items lasting more than one day do not appear correctly when looking at the monthly view of the calendar; only the first day of the appointment appears. For example, if I am taking a vacation for 4 days, only the first day of the vacation is marked on the calendar, instead of being listed on all 4 days. When I look at the weekly view, however, it is correct and is listed on all 4 days. The problem here of course is that at a glance, there is no way to look at my monthly schedule. On my iPhone, everything is correct, regardless of month or week view, so clearly this is an iPad problem I guess? Please advise on how this can be corrected. Thank you!

Unfortunately you can't do what you want. Many people have complained to Apple about this. I suggest you provide Apple feedback directly at http://www.apple.com/feedback/macosx.html. They will not provide a direct response but hopefully if enough people provide feedback Apple will fix this.

ABAP for the first day of the month

Hello BW users,
I have a scenario which uses an ODS with cumulative key figures with Addition update type. An infocube gets data from ODS by start routine in cube's update rule. I update this ODS first then infocube. All the loads are Full and are loaded daily. This is a snapshot scenario and I load the ods on itself then load from another infocube let's say Cube1. After successful load, I update infocube on itself again then update from the same infocube, Cube1, as in ODS. Infocube load sequence is same as ODS. In the scenario ODS and infocube are wanted to be updated daily. Therefore, I have to delete the ODS's (since it is addition update type) and infocube's overlapping data in the process chain that automates the load. At this point I need two things:
1- ABAP program that is going to give me the first day of each month.
2- ABAP program that is going to delete the overlapping data in ODS when I load it daily. Since I can do that for infocube in process chain with standard process type of Delete overlapping requests from infocube I need it only for ODS. Because there is no standard process type to delete overlapping requests in ODS (since its update type is Addition).
I appreciate your help. Thank you in advance.
Sincerely,

1- ABAP program that is going to give me the first day of each month.
if sy-datun+6(2) = 01.
SY-FDAYW should give you the day
endif.
2- ABAP program that is going to delete the overlapping data in ODS
REPORT <PGM NAME>.
TABLES: RSODSACTREQ , rsseldone.
Parameters : odsname type RSINFOCUBE default '<>ODS NAME'.
DATA: temp_REQUEST LIKE RSODSACTREQ-REQUEST,
      temp_REQUEST1 LIKE RSODSACTREQ-REQUEST,
      temp_RNR LIKE rsseldone-RNR.
DATA: BEGIN OF itab OCCURS 0,
      REQUEST LIKE RSODSACTREQ-REQUEST,
      TIMESTAMP LIKE RSODSACTREQ-TIMESTAMP,
      END OF itab.
DATA: BEGIN OF itab1 OCCURS 0,
      RNR LIKE rsseldone-RNR,
      seldate LIKE rsseldone-seldate,
      seltime LIKE rsseldone-seltime,
      END OF itab1.
SELECT REQUEST TIMESTAMP FROM RSODSACTREQ INTO TABLE itab
WHERE ODSOBJECT = '<ODS NAME>'.
SORT itab DESCENDING BY TIMESTAMP .
READ TABLE itab INDEX 1.
temp_REQUEST = itab-REQUEST.
SELECT RNR seldate seltime FROM rsseldone INTO TABLE itab1
WHERE source = '<Info Source Name for the ODS>'.
SORT itab1 DESCENDING BY seldate seltime .
READ TABLE itab1 INDEX 1.
temp_RNR = itab1-RNR.
*If   temp_REQUEST = temp_RNR .
CALL FUNCTION 'RSSM_PROCESS_REQUDEL_ODSO'
EXPORTING
    I_ODS             = odsname
    I_REQUEST         = temp_REQUEST
    I_JOBNAME         = 'i_jobname'
    I_VARIANT         =
    I_INSTANCE        =
IMPORTING
    E_ERROR           =
    E_T_MSG           = itab1
E_T_RNRLIST       =    ITAB1.
*else.
*raise exception.
*endif.
clear itab.
refresh itab.
SELECT REQUEST TIMESTAMP FROM RSODSACTREQ INTO TABLE itab
WHERE ODSOBJECT = '<ODS NAME>'.
SORT itab DESCENDING BY TIMESTAMP.
READ TABLE itab INDEX 1.
temp_REQUEST1 = itab-REQUEST.
if temp_REQUEST = temp_REQUEST1.
raise exception .
endif.

How to find first day of the year

Big picture: trying to determine how many pay periods are left in the year. There are 52 weeks in a year, and our company pay out each week.
The first pay week of the year always starts on a Friday. So If Janurary 1 is a friday, then the 1st week of pay period starts that week. If Jan 1 is a Thursday, then the first pay week will start on Janurary 2.
I need to figure out what day the first day of any year it is. By day, i mean Mon, Tue, Wed, Thur, Fri, Sat, or Sun.
Then when I figure out what day it is, i will write an if/then statement saying if Jan 1 is a monday, then add 4 days to that date and that will be the first day of a pay period.
Then when i figure out the first day of the first week, I wanted to add 7 days to create week2, week3.... week 52.
Then take todays date and if it was between week x and week y, then it would determine that z many pay periods are left...
is this the best way to go about this? anything easier?

You can use the getDay method of a Date object to determine the day of the week. Any decent JavaScript reference will have more information.
George

How i can change te first day of the week?

By default the week start in sunday and i want monday.
In the siebelOnDemnad documentation i find some about one parameter named FIRST_DAY_OF_THE_WEEK in NQSConfig.INI but i don't know how to change it.

I don't believe its possible to change the first day of the week.

Can I change the first day of the week on my ipod touch

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Thanks

The International Region Format controls the start day of your calendar display. UK region format sets the display to start on Monday. US region format will start the calendar on Sunday. However, that setting also controls your date, time and phone number formats, so using it would only cause you more problems.
Tell Apple you want the option to set the calendar week start independent of the international region format using the feedback page. http://www.apple.com/feedback/ipodtouch.html

Changing the first day-of-the-week on the MyTimesheets app

IN the SAP ECC and Portal implementations of the timesheet app, we were recently able to change the display so the first day of the week is listed as Monday, rather than Sunday. I would like to do the same thing with Fiori.
That is, when the app starts up the first view a calendar view of the whole month. If a person wants to enter time manually, they click the button labeled "manual" and a data entry screen pops up. The first day of the week listed across the top is Sunday, which does not reflect our settings in ECC. We need the 1st day of the week to be Monday.
Is there a configuration change we can make to force the 1st day of the week to be Monday, as it is in ECC?
thanks for your help!
-Rob Solomon

Hi Rob,
Are you using Wave2 app? You could change the setting for first day of the week in CAC1 and Fiori Timesheet app will adjust te calendar accordingly.
Nothing needs to be done for Fiori app.
Please update UIX01HCM to SP03 if you are using Wave2 app?
Best Regards
Pankaj

From where to get "First day of the week" data for all the locales, is it present in CLDR spec 24?

I am trying to get "First day of the week" data from CLDR spec24 but cannot find where to look for it in the spec. I need this data to calculate numeric value of "LOCAL day of the week".
This data to implement "c" and "cc" day formats that equals numeric local day of the week.
e.g if "First day of the week" data for a locale is 2 (Monday) , it means numeric value for local day of the week will be 1 if it is Monday that day, 2 if it is Tuesday that day and likewise.

Hi
If you want to week to be started with Sunday then use the following formula:
TimestampAdd(SQL_TSI_DAY, 1-DAYOFWEEK(Date'@{var_Date}'), Date'@{var_Date}') if it's retail week(starts from Monday) then the follow below:
TimestampAdd(SQL_TSI_DAY, 1-DAYOFWEEK(Date'@{var_Date}'), Date'@{var_Date}')
I'm assuming var_Date is the presentation variable for prompt...
Edited by: Kishore Guggilla on Jan 3, 2011 4:48 PM

How to set first day of the week?

I'm trying to set up my iPad calendar so that my week view starts on Monday. My calendar on my desktop & MoblieMe starts the week on Monday which is what I want but my iPad starts on Sunday (even though it has been synced with my desktop & MoblieMe too). Please help! Thanks!

Actually, I tried both UK and Australia, and Sunday was still the first day of the week.
HOWEVER!!!
Woohoo!! American Samoa works, and doesn't seem to change any other formats (although admittedly I have not made an exhaustive search - just checked the International Example thing recommended by Matthias suggested.
Matthias, thanks very much by the way!!
OZones

Is there any funcions available to pick up first day of the month?

I want to show the first month of the year given any date time stamp as input..
eg:
select sysdate from dual
assume sysdate is 10 Mar 2005
the output should be 10 Jan 2005.
We can take the last day of the month by using last_day
how to take the first day of the month given a input datetime?

I want to show the first month of the year given any date time stamp as input..There is a little confusion with the thread's title.
We all answered you about your title question : how to obtain the first day of month, not the first month of year. For which you can test something like this :
SQL> select col1,add_months(col1,(-1*to_char(col1,'MM'))+1)
2 from (select to_date('10032007','DDMMYYYY') col1 from dual union all
3* select to_date('05012007','DDMMYYYY') col1 from dual )
SQL> /
COL1 ADD_MONT
10/03/07 10/01/07
05/01/07 05/01/07
SQL> Nicolas.

Function for finding first day of the month !!

Hi,
I know we have function to find the last day(DD) of the month. Do we have any functions for finding the first day of the month ??? if not is there any way i can find the first date(DD) of the month .
Bcoz i m trying to incorporate the logic for finding the first day of the month partition.
Thank you!!!

Shahid Ali Tcs wrote:
There are many solution given by member in relation with your question, and all are correct .
I want to make u know something else.
Have you ever think why oracle has given function for last_day but no function for first.....
I u think this question u will get the answer of your "first day finding " question.
Because first day is alwasy 01 of every, while last day can be 30,31,29,28.....
Got my words ........
One more solution from my side,,,,
SQL> select '01' || to_char(sysdate,'-MON-YY') from dual;
'01'||TO_
01-SEP-09Which is a completely poor way of doing it.
Using TRUNC or LAST_DAY(..) + 1 will return a DATE datatype result.
Your method is converting the DATE into a VARCHAR2, which then prevents further processing/date based calculations unless it is explicitly converted back to a DATE again.
The reason Oracle hasn't provided a FIRST_DAY is because the TRUNC function already caters for it as this works with DATE's as well as NUMBER's, not because the first day is always 1.

DATE FOR FIRST DAY OF THE WEEK

I am new to Oracle and am looking for a procedure that will calculate the first day of the week given today's date.
Given 1/23/2000 I need to find Sunday 1/21/2000.

Hi there,
I don't think there's a built-in Oracle procedure for what you want. However...
In SQL (at least, Oracle's SQL), you have the function TO_CHAR and TO_DATE that allow you to convert a date to a string and vice-versa. They work pretty much in a similar way, that is :
TO_<something>( <data_to_convert>, <format> )
eg.: To have the day of the week for the current date, you can do
SELECT TO_CHAR( SYSDATE, 'D' ) FROM DUAL;
Wednesday, January 24th, 2001 would then return 4.
To have the day of the year, you would do
TO_CHAR( SYSDATE, 'DDD' )
Then, to have the day of the year of the first day of the week, you then could subtract the day of the week of your date from the day of the year of your date, and then add one. To be able to do math stuff of char value, you must use TO_NUMBER.
In one ugly line, you could do this by doing the following :
select to_date( (to_char(sysdate,'YYYY') | | to_char( to_number( to_char(sysdate,'DDD')) - to_number( to_char(sysdate,'D')) + 1)),'YYYYDDD') from dual;
Eurk.
Or you could write a function that would return the date of the first day of the week of a specific date, like :
create or replace
FUNCTION FDOW (P_DATE DATE) RETURN DATE
IS
R_FDOW DATE;
BEGIN
R_FDOW := to_date( (to_char(P_DATE,'YYYY') | | to_char( to_number( to_char(P_DATE,'DDD')) - to_number( to_char(P_DATE,'D')) + 1)),'YYYYDDD');
return R_FDOW;
END;
(FDOW : First Day Of Week - not really original, I know)
Then, you can call it wherever you want:
SELECT FDOW(SYSDATE) FROM DUAL;
Have fun!
Frederic Denis

I want the minimum of the horizontal axis to be the first day of the month.

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