Script to read files in a directory

Dear Experts,
I am new to UNIX and I have a requirement to read the names of a file in a directory. I have some script below and in this test case I am reading the names of the files in the present directory into a variable and then looping through each file name and displaying the name back to the screen. The problem I have is although there are 5 files in the directory, it only ever displays the name of the first file and then stops. Can you assist?
Many thanks,
Mark
#!/bin/csh
set files = `ls`
foreach file ( $files )
echo 'File name:' $file
end

The script is correct.
You may have odd results if you have an alias like "alias ls='/bin/ls $LS_OPTIONS'"
and if you have "hidden" files starting whith a single .
An example:
obelix:~ # ls
. .bash_history .gconf .history .rnd tnt
.. .dmrc .gconfd .kbd .skel
.DCOPserver_obelix_:0 .exrc .gnome .kde .viminfo
.DCOPserver_obelix__0 .fonts .gnome2 .mcop .xsession-errors
.ICEauthority .fonts.cache-1 .gnome2_private .mozilla Desktop
.Xauthority .fvwm .gnupg .qt bin
obelix:~ # \ls
Desktop bin tnt
obelix:~ #
--------------------------

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