Script to run a DB query, but have multiple DB servers (for failover) I want to loop through until I find one that is available

Question

Conceptually I'm not sure the best way to go about this, looking for some guidance.  I'm running a MySQL query and I have the code working against a single MySQL server.  However I want to build some redundancy into the code so if it tries one
DB and it's not available, it tries the next one.  I have come up with two ways to do this.
First one is basically an If statement looking at error[0] as a condition.  Tries to connect to the first server and if throws an error, it tries the second and if that fails it exits the code.  This is less scalable as I have to code in connection
strings for each server.
Second one is a loop that goes through connection to each DB server I setup in an array until the connection.state = "open", then it should proceed to the rest of the code.
Foreach ($MySQLHost in $SQLHostArray) {
$error.clear()
$ConnectionString = "server=" + $MySQLHost + ";port=3306;uid=" + $MySQLAdminUserName + ";pwd=" + $MySQLAdminPassword + ";database="+$MySQLDatabase
$Connection.ConnectionString = $ConnectionString
do {$connection.open()}
until ( $Connection.state -eq "open" )
However I don't know how to exit that loop if all servers fail. 
Which is the best bet for building failover into the script, or is there a better way I haven't thought of yet?

Answer 1

You could use a counter - 
$lexit = 0
$count = ($SQLHostArray.count -1)
Foreach ($MySQLHost in $SQLHostArray) {
$lexit++
$error.clear()
$ConnectionString = "server=" + $MySQLHost + ";port=3306;uid=" + $MySQLAdminUserName + ";pwd=" + $MySQLAdminPassword + ";database="+$MySQLDatabase
$Connection.ConnectionString = $ConnectionString
do {$connection.open()}
until ( $Connection.state -eq "open" -or $lexit -eq $count)