Searching for discontinuity in an array of timestamps
Hi,
I have a problem with an array of timestamps.
I wish to search the array for discontinuous times. i.e. there should be a time each minute and I wish to be able to seperate the data into differant arrays according to these discontinuities.
i.e. if I have a time of 13:00 then 13:01, 16:05,16:06 I want the first two to go into one array and the second two to go into another array etc......
Please help
Having not seen your vi i dont know if it suitable for your purpose, however have you thought about using the "Get Date / Time String" vi from the timing pallette and using that instead? If the time stamps are created from a measurement then you should be able to do as Lyn and Gerd have suggested above. If not try this vi i have attached which simple takes the mins and hours out of the time stamp.
Craig
Message Edited by craigc on 03-23-2007 11:47 AM
LabVIEW 2012
Attachments:
test2.vi 10 KB
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// ==========================================================
// Tool class
// Reads user input from keyboard and writes to text file a list of entered
// inventory items (tools)
// ==========================================================
import java.io.*;
import java.text.DecimalFormat;
public class Tool
private String name;
private double totalCost;
int units;
// int record;
double price;
// Constructor for Tool
public Tool(String toolName, int unitQty, double costPrice)
name = toolName;
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int recordNum = 1;
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String itemCost = "";
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input = stdin.readLine();
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Read user input (array search string)
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} // class
// ==========================================================
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// ==========================================================
import java.io.*;
import java.util.StringTokenizer;
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TOOL 1 1 1.21
TOOL 2 8 3.85
TOOL 3 35 6.92Ok, so you have an array of Strings. And if the string you are searching for is in the array, you need to remove it from the array.
Is that right?
Can you use an ArrayList<String> instead of a String[ ]?
To find it, you would just do:
for (String item : myArray){
if (item.equals(searchString){
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the above assumes you are using 1.5
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[edit2]
and kinda won't work it you have to use an array since you will need the array index to be able to remove it. See the previous post for that, then set the value in that array index to null.
Message was edited by:
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Search for a subarray in array
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Thank you!
Solved!
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I am working on a program that takes a user input of a job number (imported as a string).
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Henrik
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I am writing a program based on the six degrees of seperation theory.
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Thats just 2 lines!
what the program will do is take in a name (from a gui) of an actor/actress and find the smallest connection to a famous actor.
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import java.io.FileInputStream;
import java.io.IOException;
import java.io.File;
import java.io.FileNotFoundException;
public class FileSearch {
File aFile = new File("cast.06.txt");
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public void openFilm()
try
inFile = new FileInputStream(aFile);
catch(FileNotFoundException e)
System.out.println("Error");
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So whats the best way to search for an actor from that file and save the film title and the year of release?
Hope this makes sense? what I hope the final program will be like is like this http://oracleofbacon.org/I went away and looked at regular expressions and this is what I came up with
public class NameSearch{
public static void main(String[] args)
NameSearch ns = new NameSearch();
ns.runIt();
public void runIt()
java.util.Scanner fileScan = null;
try{
fileScan = new java.util.Scanner(new java.io.File("imdb.txt"));
}catch(java.io.FileNotFoundException e)
e.printStackTrace();
System.exit(0);
String token = null;
String actor = "Surname, Forename";
//real name will go in actor, left it like that for example
while(fileScan.hasNext()){
token = fileScan.next();
Pattern pattern = Pattern.compile(actor);
Matcher m = pattern.matcher(token);
while(m.find())
System.out.println(m.start() + m.end());
}This by any means not finished, I'm just trying to get to grips with regualr expressions. But when I run the program it doesn't return anything, from what I've tried to work out is it should return actor x amount of times they appear in the file. But when I run it nothing comes back (the actors name is in the text file) so I'm not too sure what I'm doing wrong, any suggestion please -
[CS3 JS] How to search for accented letters with GREP
Hello,
In the following script I have two words, each that has an accented letter. It appears that neither in the script nor in the Find and Replace dialog that GREP will recognize words with accents. It will replace accented characters however. I can do a search for words with no accents but that will lead to trouble when I only want to change the word if it has an accent.
Any advice would be great!
Tom
var myDoc = app.activeDocument;
var rawWordsAccented = ["André","Barrës"]; //find these words
var rawWordsAccentedDHyphens = ["~-Andr\\x{00E9}","~-Barr\\x{00EB}s"]; //replacement words
for(var k =0; rawWordsAccented.length > k; k++){
var numWords = theGrepChanger(myDoc,rawWordsAccented[k],rawWordsAccentedDHyphens[k]);
}//end for k
function theGrepChanger(docRef,grepFindIt,grepChangeIt){
app.findGrepPreferences = NothingEnum.NOTHING;
app.changeGrepPreferences = NothingEnum.NOTHING;
app.findGrepPreferences.findWhat = grepFindIt;
app.changeGrepPreferences.changeTo = grepChangeIt;
var arrGrepFindIt = myDoc.changeGrep();
return arrGrepFindIt;
}//end theGrepFinderJohn, perhaps it works in CS5 but not in CS3.
Peter, the problem is not in the replacement word or looping through that array backwards or forwards. The problem is finding a word with an accented character using the GREP mode.
In using the Find/Replace dialog I cannot find André. Nor Andr\x{00E9}, using Unicode. So if the dialog won't work it appears a script won't work. If I use "Andre" in the Search field it will find "Andre" and "André."
However I did find that if I change the GREP function in the script to the text mode I can find only words with accented characters and then replace them to my heart's content.
Tom
function theTextChanger(docRef,textFindIt,textChangeIt){
app.findTextPreferences = NothingEnum.NOTHING;
app.changeTextPreferences = NothingEnum.NOTHING;
app.findTextPreferences.findWhat = textFindIt;
app.changeTextPreferences.changeTo = textChangeIt;
var arrTextFindIt = myDoc.changeText();
return arrTextFindIt;
}//end theTextChanger -
How to search for a string in a DefaultListModel
I have a list of names stored in a DefaultListModel and would like to know how i can search for a particular name
i assume i would have to use the method below but not sure of how to implement it
so basically i would have a texfield where a user can type in a name to find in the list
public int indexOf(Object elem)
Searches for the first occurence of the given argument.
Parameters:
elem - an object.
or i might be wrong
Any ideas of how to write this mechanism
Can anyone please help on thisThe DefaultListModel uses a Collection of some sort (Vector at present) to store data. You can get this data in two ways:
DefaultListModel model = (DefaultListModel)list.getModel();
Enumeration e = model.elements();
while(e.hasMoreElements()) {
if (e.nextElement().equals(elem)) return;
}or
Object[] array = model.toArray();
for (int i = 0; i < array.length; i++) {
if (array.equals(elem)) return; -
How to search for words in a string?
I have a list of strings that I need to search for instances
of a certain word (or part of that word) is there a way of doing
this in flash please?Quickest and easiest way to do it is to search through an
array of manually entered words. -
Searching for an entry in a file that contains 2 words or more...
Hey :)
I created a Binary Search Tree that would hold a list of words located in a .txt file. So, basically, the objective of the program is to search through a typed up document for the words in the search tree, and if the word is found, return it to the user to see.
I have that part working, but what I'm having trouble with is one of the entries in the file. The entry is "data structure." All the other entries are 1 word, like queue, depth-first, etc...but this one is 2 words. I'm having trouble making it so that the search will detect the 2-word entry, "data structure." How do I go about searching for entries that are 2 or more words in length?
I have been struggling with this for some time, and I don't know if it's just me, but I'd really like to get this done since this is the only thing I'm having trouble with right now. I thought I could figure this out, but I'm just putting too much time into it, and I need to submit this tomorrow.
Any help would really be appreciated! :)
Take care,
AlexYea, I was thinking of doing that myself. Turning the two words into one word, so it'll end up like, "datastructure," but how do I do that? Would I use the substring method? Or is there something else that I can use to get rid of whitespace. I'll look that up now on google or something, but in the meantime, if anyone can help me out with this, it would be great.
Just for a reminder, this is my problem :: I need to be able to locate an entry in my document that has 2 words in it. In this case, the entry is, "data structure." How can I go about searching for this 2 word entry? It seems to be a bit more complex than merely searching for one word. Any help you can provide me would be great! :)
Here's the code for the Binary Search Tree:
import java.io.*;
import java.util.*;
public class KeywordBinarySearchTree
BinaryNode root;
//static String[] docWords; // captures each of the words into an array while ignoring punctuation
public KeywordBinarySearchTree()
root = null;
public void preOrderTraversal()
preOrderTraversal(root);
public void inOrderTraversal()
inOrderTraversal(root);
public Comparable findNode(Comparable node)
return dataOfNode(findNode(node, root));
public Comparable dataOfNode(BinaryNode node)
if (node == null)
return null;
else
return node.nodeData;
public BinaryNode insertInOrder(Comparable iNodeData)
BinaryNode nodeWalker; // used to walk through each of the nodes until the appropriate spot
// is found to insert the node of data
BinaryNode parentNode = new BinaryNode(iNodeData); // represents the new root node after each pass through the tree
if (root == null) // if it's a brand new tree with no nodes, then insert the new root of the tree
root = new BinaryNode(iNodeData);
else
nodeWalker = root; // sets current root of tree to nodeWalker
while (nodeWalker != null) // will start its first iteration of the loop at the top of the tree
parentNode = nodeWalker;
if (iNodeData.compareTo(nodeWalker.nodeData) < 0) // if the data to be inserted is less than the current
// node in the tree
nodeWalker = nodeWalker.leftChild; // set nodeWalker to the left child of that node
System.out.println("INSERT NODE: LEFT CHILD");
else
nodeWalker = nodeWalker.rightChild; // otherwise, set nodeWalker to the right child of that node
System.out.println("INSERT NODE: RIGHT CHILD");
} // this loop will determine where the node has to travel to get to the appropriate destination. once the nodeWalker
// has reached its final stop, the while loop exits into the statements below to insert the new node of data
if (iNodeData.compareTo(parentNode.nodeData) < 0)
parentNode.leftChild = new BinaryNode(iNodeData);
System.out.println("INSERT NODE: PARENT NODE LEFT CHILD");
else
parentNode.rightChild = new BinaryNode(iNodeData);
System.out.println("INSERT NODE: PARENT NODE RIGHT CHILD");
return parentNode;
public BinaryNode findNode(Comparable searchNode, BinaryNode bn)
if (bn == null)
return null;
else
while (bn != null)
if (searchNode.compareTo(bn.nodeData) < 0)
bn = bn.leftChild;
//System.out.println("FIND NODE: LEFT CHILD DETECTED");
else if (searchNode.compareTo(bn.nodeData) > 0)
bn = bn.rightChild;
//System.out.println("FIND NODE: RIGHT CHILD DETECTED");
else // word has been spotted in the tree!
System.out.println(bn.nodeData);
return bn;
return null;
public void preOrderTraversal(BinaryNode bn)
if (bn == null)
return;
System.out.println(bn.nodeData);
preOrderTraversal(bn.leftChild);
preOrderTraversal(bn.rightChild);
public void inOrderTraversal(BinaryNode bn)
if (bn == null)
return;
inOrderTraversal(bn.leftChild);
System.out.println(bn.nodeData);
inOrderTraversal(bn.rightChild);
// and then the code after this is the public static void main code, which I posted snippets of above.
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