Seemingly simple, yet annoying reg. expression issue

Hey guys,
Im considerably familiar with the use of regular expressions in Java (and other languages), yet seem to be having a very simple problem.
I wish to match a full stop character occuring after a space in a string, once that space does not occur after a digit.
e.g. "went to the shop . This is another sentence"
The code I'm using is this:
String s = "went to the shop. This is another sentence"
s = s.replaceAll("([^0-9]+)\\s+\\.","$1.");This doesn't seem to work, neither does:
String s = "went to the shop. This is another sentence"
s = s.replaceAll("(\\D+)\\s+\\.","$1.");It seems that there's a problem with the first + symbol, but I'm not sure exactly what the problem is.
Any insights?
Edited by: SuperGrover on Jan 19, 2009 12:35 PM

SuperGrover wrote:
The problem seems to occur when there's more than one occurance of the space before a fullstop in the string, so the above code doesn't work for the following string:
"went to the shop . This is another sentence . And another"
It only replaces the final occurance, despite using the replaceAll method.When I tested your pattern (using JRET), it matched both occurrences in the sample string!
The matching was done by repeated invocations of the method [Matcher.find|http://java.sun.com/javase/6/docs/api/java/util/regex/Matcher.html#find()].
Maybe [String.replaceAll|http://java.sun.com/javase/6/docs/api/java/lang/String.html#replaceAll(java.lang.String, java.lang.String)] does something different internally?
Anyway, are you aware that your expression always matches the entire string preceding the space and the dot?
This is probably not really what you are looking for. You may want to try this expression instead, which uses negative lookbehind:
(?<!\d)\s+\.Edited by: McNepp on 20.01.2009 09:47

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