Select only numbers from database

Hi All,
I need to retrieve numerical data's from the database. Data base table has both numerical and text values. now I want to retrieve only numerical data's.
Can any one help me on this,
Thanks and helps will be appreciated.

Hi,
did you try like this ?
SELECT * FROM database INTO t_inter WHERE field1 = crit1.
LOOP AT t_inter into w_intern WHERE field1 CO '0123456789'.
ENDLOOP.
or
LOOP AT t_inter into w_intern.
CHECK w_intern-field1 CO '0123456789'
ENDLOOP.
Regards,
David

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Help with this sql. Select only employees from a distinct Org??

Hi guys, simple query.
create table balancetest(emp_id number, balance_id number, balance number, org number);
insert into balancetest values (111, 1, 1, 0);
insert into balancetest values (111, 1, 1, 0);
insert into balancetest values (111, 2, 1, 1);
insert into balancetest values (222, 1, 2, 1);
insert into balancetest values (333, 3, 4, 3);
insert into balancetest values (333, 3, 4, 2);
commit;
SQL> select * from balancetest;
 EMP_ID BALANCE_ID BALANCE ORG
 111 1 1 0
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6 rows selected.As you can see, emp_id 111 appears on different Org (0 and 1). I need to calculate the balance but the requirement says that I need to retrieve employees appearing only in 1 org.. It won't matter which org is selected (the business rules ensure balance will be the same), as long as if an employee is in multiple org, this employee is selected only once for an org. So, my result will be something like:
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select * from balancetest bal1
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Hi,
You can find the lowest-numbered org for each employee like this:
SELECT emp_id
, MIN (org) AS min_org
FROM balancetest
GROUP BY emp_id;You can get the results you want by selecting only rows from balancetest that match a row in this the result set above. There are many ways to do that, such as a join:
WITH g AS
 SELECT emp_id
 , MIN (org) AS min_org
 FROM balancetest
 GROUP BY emp_id
SELECT b.*
FROM balancetest b
JOIN g ON b.emp_id = g.emp_id
 AND b.org = g.min_org;

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using JDBC..you want to
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Dear all experts,
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eg,
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Your help will be surely rewarded with points.
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Regards
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Hi Vinay ,
Adding to the below code , you can use some more fields in the select stmt as below:-
REPORT ychatest.
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please try & let me know .
Thanks & Regards,
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Hello,
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Hello
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How to log in with user credentials from database table

Hello all.
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Please, a step-by-step text would make me rather happy, instead of getting a link with information that I should read. I've read most of it, and it just doesn't make any sense to me, so I prefer a guide-trough.
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Hi Magali,
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is
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l_stored_password varchar2(4000);
l_count number;
begin
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if l_count > 0 then
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select your scheme and click make current
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Thanks,
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Cartesian selects after Update from 10.0.2.0.3 to 10.0.2.0.5

Hello,
we just installed the patch 10.0.2.0.5 on a 10.0.2.0.3 database and some selects didn't work as before. While changing the select clause, there are diffent counts.
There are 3 tables:
Detail_1 => MASTER_1 <= Detail_2
MASTER_1 has a primary and an unique Key. The 2 detail tables have FK. Now when selecting only columns from the detail tables (joined with master) we get cartesian selects. If i use one column of the master table in the select clause everything is fine.
Here is an example:
CREATE TABLE MASTER_1
( "KUNID" NUMBER NOT NULL ENABLE,
"CUSTOMER_NO" VARCHAR2(20 BYTE),
CONSTRAINT "PK_MASTER1" PRIMARY KEY ("KUNID"),
CONSTRAINT "UK_MASTER1" UNIQUE ("CUSTOMER_NO"));
CREATE TABLE DETAIL_1
( "CUSTOMER_NO" VARCHAR2(20 BYTE),
CONSTRAINT "FK_DETAIL1" FOREIGN KEY ("CUSTOMER_NO") REFERENCES "MASTER_1" ("CUSTOMER_NO"));
CREATE TABLE DETAIL_2
( "KUNID" NUMBER,
CONSTRAINT "FK_DETAIL2" FOREIGN KEY ("KUNID") REFERENCES "MASTER_1" ("KUNID")) ;
INSERT INTO MASTER_1 VALUES(1,'A');
INSERT INTO MASTER_1 VALUES(2,'B');
INSERT INTO DETAIL_1 VALUES ('A');
INSERT INTO DETAIL_1 VALUES ('B');
INSERT INTO DETAIL_2 VALUES ('1');
INSERT INTO DETAIL_2 VALUES ('2');
INSERT INTO DETAIL_2 VALUES ('1');
INSERT INTO DETAIL_2 VALUES ('2');
INSERT INTO DETAIL_2 VALUES ('1');
INSERT INTO DETAIL_2 VALUES ('2');
COMMIT;
SELECT a.*
FROM MASTER_1 b,
DETAIL_1 a,
DETAIL_2 c
WHERE a.CUSTOMER_NO = b.CUSTOMER_NO
AND b.KUNID = c.KUNID
AND a.CUSTOMER_NO = 'A';
The Result on a 10.0.2.0.3.0 Database for different select clauses
SELECT a.* => 3 Row Selected
SELECT b.* => 3 Row Selected
SELECT c.* => 3 Row Selected
The Result on a 10.0.2.0.5.0 Database for different select clauses
SELECT a.* => 6 Row Selected
SELECT b.* => 3 Row Selected
SELECT c.* => 6 Row Selected
So you see, we get different rows only by changing the select clause.
Note: It seemed to be important to have both FK. When deleting one of them - or both - we get the same correct results: 3 rows with any select clause.
IS this a bug or have we to change our sql?
Regards
Rudi Zugreif

Hi,
thanks for your reply.
The alter session works, but even so I will contact ORacle Suppoer
The explain plan (before alter session):
Explain Plan for 10.2.0.5
SELECT a.* (6 Rows)
MERGE JOIN CARTESIAN
 TABLE ACCESS FULL DETAIL_1
 BUFFER SORT
 TABLE ACCESS FULL DETAIL_2
 TABLE ACCESS FULL DETAIL_1
 BUFFER SORT
 TABLE ACCESS FULL DETAIL_2
SELECT b.* (3 Rows)
 NESTED LOOPS
 TABLE ACCESS BY INDEX ROWID MASTER_1
 INDEX UNIQUE SCAN UK_MASTER1
 TABLE ACCESS FULL DETAIL_1
 TABLE ACCESS FULL DETAIL_2
HASH JOIN
 NESTED LOOPS
 TABLE ACCESS BY INDEX ROWID MASTER_1
 INDEX UNIQUE SCAN UK_MASTER1
 TABLE ACCESS FULL DETAIL_1
 TABLE ACCESS FULL DETAIL_2
Explain Plan for 10.2.0.3
SELECT a.* (3 Rows)
NESTED LOOPS
 TABLE ACCESS BY INDEX ROWID MASTER_1
 INDEX UNIQUE SCAN UK_MASTER1
 TABLE ACCESS FULL DETAIL_1
 TABLE ACCESS FULL DETAIL_2
HASH JOIN
 NESTED LOOPS
 TABLE ACCESS BY INDEX ROWID MASTER_1
 INDEX UNIQUE SCAN UK_MASTER1
 TABLE ACCESS FULL DETAIL_1
SELECT b.* (3 Rows)
HASH JOIN
 NESTED LOOPS
 TABLE ACCESS BY INDEX ROWID MASTER_1
 INDEX UNIQUE SCAN UK_MASTER1
 TABLE ACCESS FULL DETAIL_1
 TABLE ACCESS FULL DETAIL_2regards
Rudi
Edited by: gogetter on Jul 27, 2010 1:19 AM

HOWTO?: select a subset from a self defined static list

I have the follwing problem:
I have:
1- a list of numbers (outside of the database)
2- a database table with another list of numbers
I want:
- To select the numbers from the list outside of the database, that are not in the database table.
- It must be formatted into a single query.
- Without building a new table and preferably without loading the values.
Thx in advance guys

I have the follwing problem:
I have:
1- a list of numbers (outside of the database)Where? On a piece of paper? In a file? In your head? Recorded as an mp3?
2- a database table with another list of numbers
I want:
- To select the numbers from the list outside of the
database, that are not in the database table.
- It must be formatted into a single query.
- Without building a new table and preferably without
loading the values.
Thx in advance guysWell, lets say they're in a file like
1
2
5
6
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Use UTL_FILE to read in the file and then either do a lookup as each value is read in, or get fancy with collections and casting to table.

Select only the last 12 months

Hi all
I need to write a query that will select only records from the last 12 months, order them by customer ID, and show one column per month, and a Total column where I need to add monthly Values.
The table has the following fields
• YearMonth varchar(6)
• CustomerID varchar(15)
• Value integer
Records example
- 200809, 1, 10
- 200809,2,20
- 200808,1,15
- 200808,2,12
- 200501, ….
I need to write a query and place it in a view that will select only records from the last 12 months, order them by customer ID, and show one column per month, and a Total column where I need to add monthly Values.
The results should display the:
• CustomerID,
• one column per month displaying the Value
• and the total column (sum monthly values for a customer)
My questions are:
• How do I select records only from the last 12 months
• How do I name dynamically the columns, because today October,15 the list will start in November 2007 through October 2008, but next month it will move from December 2007 through October 2008
• How do I create a view with dynamic columns
• How do I create a column totals
Please advice

Hi,
user631364 wrote:
... My questions are:
• How do I select records only from the last 12 monthsThere a a couple of things you could mean by "the last 12 months".
Hkandpal showed you one way.
Another is
WHERE yearmonth >= TO_CHAR (ADD_MONTHS (SYSDATE, -11), 'YYYYMM')
AND yearmonth <= TO_CHAR ( SYSDATE, 'YYYYMM')Storing DATEs in a VARCHAR2 column (or in any type of column other than DATE) is a bad idea. At best, it will involve lots of conversions, like those above.
• How do I name dynamically the columns, because today October,15 the list will start in November 2007 through October 2008, but next month it will move from December 2007 through October 2008
• How do I create a view with dynamic columns
How to Pivot a Table with a Dynamic Number of Columns
For example, you want to make a cross-tab output of
the scott.emp table.
Each row will represent a department.
There will be a separate column for each job.
Each cell will contain the number of employees in
 a specific department having a specific job.
The exact same solution must work with any number
of departments and columns.
(Within reason: there's no guarantee this will work if you
want 2000 columns.)
PROMPT ========== 0. Basic Pivot ==========
SELECT deptno
, COUNT (CASE WHEN job = 'ANALYST' THEN 1 END) AS analyst_cnt
, COUNT (CASE WHEN job = 'CLERK' THEN 1 END) AS clerk_cnt
, COUNT (CASE WHEN job = 'MANAGER' THEN 1 END) AS manager_cnt
FROM scott.emp
WHERE job IN ('ANALYST', 'CLERK', 'MANAGER')
GROUP BY deptno
ORDER BY deptno
PROMPT ========== 1. Dynamic Pivot ==========
-- ***** Start of dynamic_pivot.sql *****
-- Suppress SQL*Plus features that interfere with raw output
SET FEEDBACK OFF
SET PAGESIZE 0
SPOOL p:\sql\cookbook\dynamic_pivot_subscript.sql
SELECT DISTINCT
 ', COUNT (CASE WHEN job = '''
|| job
|| ''' ' AS txt1
, 'THEN 1 END) AS '
|| job
|| '_CNT' AS txt2
FROM scott.emp
ORDER BY txt1;
SPOOL OFF
-- Restore SQL*Plus features suppressed earlier
SET FEEDBACK ON
SET PAGESIZE 50
SPOOL p:\sql\cookbook\dynamic_pivot.lst
SELECT deptno
@@dynamic_pivot_subscript
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GROUP BY deptno
ORDER BY deptno
SPOOL OFF
-- ***** End of dynamic_pivot.sql *****
EXPLANATION:
The basic pivot assumes you know the number of distinct jobs,
and the name of each one. If you do, then writing a pivot query
is simply a matter of writing the correct number of ", COUNT ... AS ..."\
lines, with the name entered in two places on each one. That is easily
done by a preliminary query, which uses SPOOL to write a sub-script
(called dynamic_pivot_subscript.sql in this example).
The main script invokes this sub-script at the proper point.
In practice, .SQL scripts usually contain one or more complete
statements, but there's nothing that says they have to.
This one contains just a fragment from the middle of a SELECT statement.
Before creating the sub-script, remember to turn off SQL*Plus features
that are designed to help humans read the output (such as headings and
feedback messages like "7 rows selected.", since we do not want these
to appear in the sub-script.
Remember to turn these features on again before running the main query.
• How do I create a column totalsIn SQL*Plus, use the BREAK command.
In SQL, "GROUP BY ROLLUP" or "GROUP BY GROUPING SETS"

How to get time specification detail from database

Dear All,
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""Local Interface:
*" IMPORTING
*"     VALUE(I_LOGSYS) TYPE LOGSYS
*"     VALUE(I_AWTYP) TYPE WFD_AWTYP
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Thanks,
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Yes I can see the pattern.
When I get the set of numbers from database UI doesn't know what is the the list of numbers database has. I need to choose some next available number that is not in database. In the list that u are talking about next available number is 7. Its something similar to when we try to create any mailid, while registration it gives some default id which is not existing which user can choose to create his mailid. How can I get similar feature?

Getting 10th oldest from database

Getting the oldest persons name from a database is easy.
SELECT name
FROM database
WHERE dob = ( SELECT MIN(dob) FROM database ) ;
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Regards

Hi,
Because of you can have more than one with the same age in database, you need to use dense_rank() function :
SQL> select name,age, rank() over(order by age asc) from age;
NAME              AGE RANK()OVER(ORDERBYAGEASC)
TOTO               10                         1
TRUC               10                         1
TITI               20                         3
TUTU               20                         3
SQL> With previous code, if I search the second oldest, I found nothing... also the following query can help :
SQL> select name,age, dense_rank() over(order by age asc) from age;
NAME              AGE DENSE_RANK()OVER(ORDERBYAGEASC)
TOTO               10                               1
TRUC               10                               1
TITI               20                               2
TUTU               20                               2
HTH,
Nicolas.
Message was edited by:
N. Gasparotto
In my queries, I replace yougest by oldest like requirements, sorry.

Select only numbers from database

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