Selecting Single Rows that match to a column within group function output

Question

Trying to write a Query that will look through a data set that will return the Barcodes of CompoundNames that have a summed Quantity > 500.
So if it was ran against the sample table below the output would be
0005
0006
0007
0008
0009
0010
Barcode, CompoundName, BatchId, Quantity
0001, XE 1000, XE 1000 100, 100
0002, XE 1000, XE 1000 101, 100
0003, XE 1000, XE 1000 102, 100
0004, XE 1000, XE 1000 103, 100
0005, XE 2000, XE 2000 100, 100
0006, XE 2000, XE 2000 101, 100
0007, XE 2000, XE 2000 102, 100
0008, XE 2000, XE 2000 103, 100
0009, XE 2000, XE 2000 104, 100
0010, XE 2000, XE 2000 105, 100
0011, XE 3000, XE 3000 100, 100
I've got this far
Select CompoundName, SUM(QUANTITY) FROM Table
GROUP BY CompoundName
HAVING SUM(QUANTITY) > 500)
order by compoundname;
But I need each Barcode that corresponds to each batchid when the summed quantity of the batches is > 500.
TIA

Answer 1

Replacing a GROUP BY Aggregate function by analytic equivalent (using PARTITION BY)
will return every ROW (limited by where clause) but will not perform
actual "aggregation operation.
So it is possible that *selected result set* could contain duplicate row. Of course it depends on columns being seected and input data.
+Ofcourse OPs sample data returns the same result with or without DISTINCT+
For example...
*WITH DISTINCT*
{code}
sudhakar@ORCL>with t1 as
2 (select 0001 barcode,'XE0000' COMPOUNDNAME, 700 quantity FROM DUAL UNION ALL
3 select 0003 ,'XE1000' , 20 FROM DUAL UNION ALL
4 select 0003 ,'XE1000' , 280 FROM DUAL UNION ALL
5 select 0003 ,'XE2000' , 50 FROM DUAL UNION ALL
6 select 0003 ,'XE2000' , 100 FROM DUAL UNION ALL
7 select 0003 ,'XE2000' , 150 FROM DUAL UNION ALL
8 select 0003 ,'XE2000' , 200 FROM DUAL UNION ALL
9 select 0003 ,'XE2000' , 750 FROM DUAL UNION ALL
10 select 0003 ,'XE2000' , 120 FROM DUAL UNION ALL
11 select 0003 ,'XE1000' , 70 FROM DUAL
12 )
13 select distinct * from
14 (
15 Select Barcode, CompoundName, SUM(QUANTITY) over (partition by CompoundName) sumqty
16 FROM t1
17 )
18 where sumqty > 500
19 order by compoundname;
BARCODE COMPOU SUMQTY
1 XE0000 700
3 XE2000 1370
sudhakar@ORCL>
{code}
*WITHOUT DISTINCT*
{code}
sudhakar@ORCL>with t1 as
2 (select 0001 barcode,'XE0000' COMPOUNDNAME, 700 quantity FROM DUAL UNION ALL
3 select 0003 ,'XE1000' , 20 FROM DUAL UNION ALL
4 select 0003 ,'XE1000' , 280 FROM DUAL UNION ALL
5 select 0003 ,'XE2000' , 50 FROM DUAL UNION ALL
6 select 0003 ,'XE2000' , 100 FROM DUAL UNION ALL
7 select 0003 ,'XE2000' , 150 FROM DUAL UNION ALL
8 select 0003 ,'XE2000' , 200 FROM DUAL UNION ALL
9 select 0003 ,'XE2000' , 750 FROM DUAL UNION ALL
10 select 0003 ,'XE2000' , 120 FROM DUAL UNION ALL
11 select 0003 ,'XE1000' , 70 FROM DUAL
12 )
13 select * from
14 (
15 Select Barcode, CompoundName, SUM(QUANTITY) over (partition by CompoundName) sumqty
16 FROM t1
17 )
18 where sumqty > 500
19 order by compoundname;
BARCODE COMPOU SUMQTY
1 XE0000 700
3 XE2000 1370
3 XE2000 1370
3 XE2000 1370
3 XE2000 1370
3 XE2000 1370
3 XE2000 1370
7 rows selected.
sudhakar@ORCL>
{code}
vr,
Sudhakar B.