Servlet controller unavailable

I am getting the error as follows in my web application.Can anybody tell me the reason.Thanks in advance
HTTP Status 503 - Servlet controller is currently unavailable
type Status report
message Servlet controller is currently unavailable
description The requested service (Servlet controller is currently unavailable) is not currently available.
Apache Tomcat/4.1.27

Are you sure you have mentioned the servlet in the web.xml file.
This web.xml file lets Tomcat know which servlets exist and where to look for it.
So, you should have the following tags in the web.xml file of your web application.
<servlet>
<servlet-name>MopoController</servlet-name>
<servlet-class>org.gertcuppens.controller.MopoController</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>MopoController</servlet-name>
<url-pattern>/MOPO</url-pattern>
</servlet-mapping>

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You're missing a closing curly bracket in the JSP page.
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ie request.setAttribute("theException", ex);
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Check the documentation on error pages. You are able to set up an error page in the web.xml, that all exceptions/errors get directed to.
something like:
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You then write the JSP page something like this
<%@ page language="java" %>
<%@ page isErrorPage="true" %>
<%@ page import="java.util.*, java.io.*" %>
<h1>Programming error <BR> FOR DEBUGGING PURPOSES ONLY</h1>
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<table border = 1 width=200>
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Servlet Currently Unavailable !!

Hello,
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<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
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Hoping for ur replies
Mani.

Hi
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bye for now
sat

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You can get a Bean stored in a Session by
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Use Struts to solve all these issues and let struts do the work for you...

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Hi,
I have a problem whereby whenever i run the servlet, my serlvlet was marked as unavailable. have Stripped down the servlet to bare minimum and was able to run it. It was only after i placed the following code that it was unable to run.
+public void doGet (HttpServletRequest request, HttpServletResponse response, String additionalParameter) throws ServletException, IOException, Exception {+
+     +
+     int which = 0;+
+     String name = request.getParameter( "name" );+
+     try {+
+          Oracle oracle = new Oracle(jdbcUrl, user, password);+
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+               ModelOracleSem model3 = new ModelOracleSem(graph);+
Part of the error is as follow:
Jun 22, 2010 9:44:50 AM org.apache.catalina.core.ApplicationContext log
INFO: Marking servlet ExpertFinderServlet as unavailable
Jun 22, 2010 9:44:50 AM org.apache.catalina.core.StandardWrapperValve invoke
SEVERE: Allocate exception for servlet MyServlet
java.lang.ClassNotFoundException: com.hp.hpl.jena.rdf.model.Model
     at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1516)
     at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1361)
Unable to find explaination or solution to this problem. Would appreciate any help here. Thank You.

Hi,
Looks to me that the Jena related jar files are not loaded by Tomcat. You should include them in the corresponding lib directory.
Regards,
Vladimir

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You do not remove exceptions. You fix the cause of the exception.
You said, it is caused by the Class#forName() call on the MySQL JDBC driver class? Is it a ClassNotFoundException? If so, then put the MySQL JDBC driver class in the classpath. It is available in the MySQL Connector/J JAR file which you can download from the manfacturer's website.

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Hello All!
I am rather new to the programming field and have already completed a web-project in Java only with Servlets. (no jsp). I have a login procedure, means I have a user management for users and admins. If an admin is logged in, he/she should be able to deactivate the servlet with a mouse-click as long he activates it again with the same. if the servlet is deactivated, other users/admins trying to access the servlet should get a "servlet is currently unavailable" message. but the admin, who is logged in, still should be able to work with the servlet! how can i realise that?
in other words, by clicking that particular button, the servlet should be made "non-multi-thread" and other way round by activating it.
any ideas??? how can the standard "servlet currently unavailable" page be displayed? I have tomcat 4 on a linux machine! i'd be really grateful if someone oculd help me.
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<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>
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shortname
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<servlet-class>
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lisa

Ok,
You'll need to find a tutorial on servlet filters. Its not that hard a concept.
http://java.sun.com/j2ee/1.4/docs/tutorial/doc/Servlets8.html#wp64572
Filters need to be configured in the web.xml.
Basically they are a buffer between a request and your servlet.
Any requests for the servlet, go through the filter first. It lets you do some processing before/after the servlet gets called. Its a good way of putting in some generic code that need to be run for many servlets - security checks are often implemented in this fashion.
This should give you an idea of the sort of thing you need. I haven't really written one before, so I copied this out of the tutorial and did some basic framework for it....
public final class TestFilter implements Filter {
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Servlet Faces Servlet is currently unavailable

Hi,
I get the following error when deploying my webapp to Tomcat 4.0:
[Thu Dec 18 12:03:16 EST 2003] stdout: StandardWrapper[DeployApp:Faces Servlet]: Marking servlet Faces Servlet as unavailable
[Thu Dec 18 12:03:16 EST 2003] stdout: StandardContext[DeployApp]: Servlet /BULDeployApp threw load() exception: javax.servlet.ServletException: Wrapper cannot find servlet class javax.faces.webapp.FacesServlet or a class it depends on
[Thu Dec 18 12:03:16 EST 2003] stdout: javax.servlet.ServletException: Wrapper cannot find servlet class javax.faces.webapp.FacesServlet or a class it depends on
The jsf-ri.jar is copied in $tomcat_home/common/lib (to solve the ConfigListener error) and following libraries are a part of web-inf/lib:
commons-beanutils.jar, commons-collections.jar, commons-digester.jar, commons-logging.jar, jsf-api.jar, jstl.jar, standard.jar.
Please help.

The jsf-ri.jar is copied in $tomcat_home/common/lib
(to solve the ConfigListener error) and following
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commons-beanutils.jar, commons-collections.jar,
commons-digester.jar, commons-logging.jar,
jsf-api.jar, jstl.jar, standard.jar.
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>
Please help.Craig

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Dear Members,
I would like to do the following but I am not quite sure how to proceed.
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public void doGet(HttpServletRequest req, HttpServletResponse res)
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-----------------------------------------------------------------------------------

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<filter>
<filter-name>TestFilter</filter-name>
<filter-class>test.TestFilter</filter-class>
</filter>
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<filter-name>TestFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>

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============================================================
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System.out.println("Subject:"+subject.toString()+"\n");
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Subject.doAs(subject, sampleAction);
System.out.println("4\n");
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========================================================
void doPost(
HttpServletRequest req,
HttpServletResponse resp) {
Principal p =
req.getUserPrincipal();
auditCall(p.getName());
if (req.isUserInRole(
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"SalesRole")) {
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I'll describe where JAAS fits in to the web app model but please note that some of this should be automatically handled by your Servlet container.
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The JAAS Module checks to see if the credentials are valid, if not, it throws an authentication exception.
Once control is returned to the Login Servlet, the Login Servlet would add the authenticated "Subject" to the HttpSession and if necessary, an authentication "token".
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username: joeuser
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<May 25, 2002 11:05:20 PM PDT> <Error> <HTTP> <[WebAppServletContext(2169486,exa
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java.lang.SecurityException: Attempting Privileged Action With Unauthenticated S
ubject
at javax.security.auth.Subject.doAs(Subject.java:74)
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pl.java:265)
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pl.java:200)
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rvletContext.java:2495)
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>

If anyone of you, has got any answers related to the above mentioned problem, Post it here, Will folks from SUN respond to this at any time.
Regards
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Can a Servlet be used for Storing Objects with both JSP and JSF used on it?

Hi,
Pages I have:
SearchEmployee.jsp
This page has a search engine that search out the Employee. This Employee Object will be stored inside a Servlet(controller) for future references by other pages. I used JSP, html tags for forms, and request.getParameter() to built this search engine.
Problem:
I have a JSF Form that wants to DISPLAY the employee which I have found in my Search Engine. How can I get the JSF's value="#{Controller.employeeObj.name}" to get the value from the object?
This seems logical as my JSF form is just retrieving the stored object in the Controller. I currently cant seem to output it

The servlet shouldn't be used to store ANY data, let alone data to be accessed by other sevlets. Put the object into the Session object.

How to pass a JavaBean from servlet to JSP?

Hi there,
I am working on a project that needs to handle quite a few client requests and I want to use the Front Controller pattern that is described in the J2EE pattern page.
The steps described in the front controller pattern is that:
1. A servlet (controller) process the client request.
2. It calls the appropriate cammand object and the cammand object gets the data from the data source and returns a JavaBean that contains the required data.
3. The servlet dispatch to the appropriate View (jsp page)
4. The JSP page displays the data in the JavaBean to the user.
However, I don't know how to pass the JavaBean from the servlet to the JSP page when the servlet forwards the control to the JSP page. Should I make the JavaBean with a request scope or higher? If so, how to uses it in the JSP page? Just refer by the ID of the JavaBean.
If any one knows there is an example or tutorial on how to use this pattern, please let me know.
Thank you !
Regards
Edmund

Could you please give more info? i tried to do this, but always get a "Class not found exception":
response$jsp.java:65: Class org.apache.jsp.TestBean not found. TestBean bean = null;
although the class TestBean (no package name => defalt package) is in the WAR file and the Servlet seems to instantiate it (otherwise an exception would occur sooner in the TestServlet code).
my JSP code is:
<%@ page language="java" info="Response page" %>
<jsp:useBean id="bean" class="TestBean" />
<%
TestBean bean2 = (TestBean) request.getAttribute("TheBean");
%>
<html>
<body>
Your value: <%= bean2.getValue() %><BR>
My val: <%= bean2.getNewValue() %><BR>
<P>
Date: <%= new Date() %>
<P>
Neuen Wert eingeben
</body>
</html>
--------------

Servlet controller unavailable

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