Shared variables + timed loops + naming conventions + how to find all

Being almost halloween, thought I'd share some more eerie behavior I've noticed with shared variables.
1st strangeness with timed loops already mentioned here: http://forums.ni.com/ni/board/message?board.id=170&message.id=209475
2nd strangeness: If you have a shared variable that is network-enabled, it is OK to use a "?" in the name (eg, "RT_Simulate?").
However, should you decide to change that variable to single-process, or if you create it that way in the first place, you will get this dandy message from the broken arrow you now have:
"LabVIEW could not generate code for the shared variable. You must open the VI in the project that contains the library where the shared variable resides."
..............whaaa????? Loosely translated, this seems to mean "Don't use a "?" in your single-process variable names."
3rd strangeness: I don't know if this has been mentioned before....
If you have an application that references a network shared variable, and the library has NOT been deployed, the app will hang for some time (approx. 7 seconds! on my machine) before returning with an error. This seems to be the case whether or not the error ins/outs of the variable are wired. This looks bad to me, and I'm not sure what is causing it (some sort of timeout when attempting communication with the SVE I assume). Has anyone else noticed this? It should be easy to reproduce. Any ideas?
I haven't done any bug notifications yet, but will do if there are no positive solutions by next week some time.
-Have a Great Halloween Weekend

WHAVEman,
Currently (as of LabVIEW 8.20) there isn't a way to programmatically interact with the shared variable engine outside of using DSC. If you had DSC you could "hack" a way to determine if a shared variable was deployed.
I think the best way to get around your program hanging is to have an initialize state where you write a dummy value to each variable. If the variable isn't deployed, then you should get an error out of the shared variable. Problem is that there's probably going to be a timeout associated with determining if the shared variable is deployed. But at least you can use the information from your initialize state throughout the rest of your deployed application.
Chris C
Chris Cilino
National Instruments
LabVIEW Product Marketing Manager
Certified LabVIEW Architect

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