Show several gifs files using servletOutputstream

Question

Hello,
I'm trying to display several gifs files in a html file. I extract all the files from an oracle database. I'm trying to use a servletoutputstream, but it does not difference between text and image.
Process:
1. Select html file from database
2. Go through each line of html file to find the links to gif files
- if gif :
3. Ask for the gif file detected and select from database
4. use servletoutputstream to display the file
- end of if
-else
5. display the line of text.
Is it possible to use a servletoutputstream to display several gifs and text content?
Is there one other solution to do it correctly?
Thanks in advance,
Angela.
The code I use is:
private void retrieveFile()
FileWriter fwHtml=null;
oracle.sql.BLOB blob=null;
InputStream in=null;
ServletOutputStream out=null;
ResultSet rsGif=null;
try
//Extract html file from the database
String query="SELECT * FROM DBFiles WHERE FILENAME='"+file+"'";
PreparedStatement ps = connection.prepareStatement (query);
ResultSet rs=ps.executeQuery();
rs.next();
String fileName=rs.getString("FILENAME");
if (fileName.indexOf("html")!=-1)
InputStream fis=rs.getAsciiStream(5);
//I read each line to know where the html file calls the links to the gif files
BufferedReader reader= new BufferedReader(new InputStreamReader(fis));
String line;
String mimeType="";
try{
while ((line=reader.readLine()) !=null)
if((line.indexOf("img src="))!=-1)
int imgIndex=line.indexOf("img src=");
int altIndex=line.indexOf(" alt=");
//I obtain the name of the gif file that I obtain from the database
String gifFile=line.substring(imgIndex+9,altIndex-1);
query="SELECT * FROM DBFiles WHERE FILENAME='"+gifFile+"'";
ps.clearParameters();
ps = connection.prepareStatement (query);
rsGif=ps.executeQuery();
rsGif.next();
blob=((OracleResultSet)rsGif).getBLOB("GIF");
String gifName=rsGif.getString("FILENAME");
mimeType = context.getMimeType(gifName);
response.setContentType(mimeType);
out = response.getOutputStream();
in=blob.getBinaryStream();
int bufferSize=blob.getBufferSize();
byte[] buffer = new byte[bufferSize];
int bytesRead=0;
int intBuffer=in.read(buffer);
while ((bytesRead=intBuffer)!= -1)
out.write(buffer,0,bytesRead);
in.close;
else
byte[] bString =line.getBytes();
mimeType = context.getMimeType(fileName);
response.setContentType(mimeType);
out.write(bString,0,line.length());
catch (IOException ioe) {
System.out.println("Unable to open Image file "); ioe.printStackTrace();
finally {
if (out != null) {
out.flush();
out.close();
ps.clearParameters();
connection.commit();
rsGif.close();
rs.close();
ps.close();
catch (SQLException sqle)
sqle.printStackTrace();
catch (Exception e)
e.printStackTrace();

Answer 1

I may be wrong, but I don't think HTML supports inlining image data for a page. I think you need to let the client process the HTML and make requests to your servlet for specific images; it is at this point they should be read from the database and returned to the client.
So I'll change your algorithm to
1. Select html from the database
2. Return it to the client
3. Client makes request for an image (<img src="servlet?image=name">) maybe
4. Servlet reads image from the db
5. Servlet set appropriate header information (image/gif etc)
6. Servlet outputs image data.