Display gif files using servletoutputstream (again)

Question

Hello,
I'm trying to display several gifs files in a html file. I extract all the files from an oracle database. I'm trying to use a servletoutputstream, but it does not difference between text and image.
Process:
1. Select html file from database
2. Go through each line of html file to find the links to gif files
- if gif :
3. Ask for the gif file detected and select from database
4. use servletoutputstream to display the file
- end of if
-else
5. display the line of text.
Is it possible to use a servletoutputstream to display several gifs and text content?
Is there one other solution to do it correctly?
Thanks in advance,
Angela.
The code I use is:
private void retrieveFile()
FileWriter fwHtml=null;
oracle.sql.BLOB blob=null;
InputStream in=null;
ServletOutputStream out=null;
ResultSet rsGif=null;
try
//Extract html file from the database
String query="SELECT * FROM DBFiles WHERE FILENAME='"+file+"'";
PreparedStatement ps = connection.prepareStatement (query);
ResultSet rs=ps.executeQuery();
rs.next();
String fileName=rs.getString("FILENAME");
if (fileName.indexOf("html")!=-1)
InputStream fis=rs.getAsciiStream(5);
//I read each line to know where the html file calls the links to the gif files
BufferedReader reader= new BufferedReader(new InputStreamReader(fis));
String line;
String mimeType="";
try{
while ((line=reader.readLine()) !=null)
if((line.indexOf("img src="))!=-1)
int imgIndex=line.indexOf("img src=");
int altIndex=line.indexOf(" alt=");
//I obtain the name of the gif file that I obtain from the database
String gifFile=line.substring(imgIndex+9,altIndex-1);
query="SELECT * FROM DBFiles WHERE FILENAME='"+gifFile+"'";
ps.clearParameters();
ps = connection.prepareStatement (query);
rsGif=ps.executeQuery();
rsGif.next();
blob=((OracleResultSet)rsGif).getBLOB("GIF");
String gifName=rsGif.getString("FILENAME");
mimeType = context.getMimeType(gifName);
response.setContentType(mimeType);
out = response.getOutputStream();
in=blob.getBinaryStream();
int bufferSize=blob.getBufferSize();
byte[] buffer = new byte[bufferSize];
int bytesRead=0;
int intBuffer=in.read(buffer);
while ((bytesRead=intBuffer)!= -1)
out.write(buffer,0,bytesRead);
in.close;
else
byte[] bString =line.getBytes();
mimeType = context.getMimeType(fileName);
response.setContentType(mimeType);
out.write(bString,0,line.length());
catch (IOException ioe) {
System.out.println("Unable to open Image file "); ioe.printStackTrace();
finally {
if (out != null) {
out.flush();
out.close();
ps.clearParameters();
connection.commit();
rsGif.close();
rs.close();
ps.close();
catch (SQLException sqle)
sqle.printStackTrace();
catch (Exception e)
e.printStackTrace();

Answer 1

Let's put it this way, since I don't have the patience to look at your code. HTML cannot have images embedded in it, it can only have links to images. So you could have a servlet that sends an image, but only a single image and nothing else. I see you have code to set the MIME type of the image, so I don't have to tell you about that.