Show Unix home directory in Java code

Does anyone know how to show Unix home directory in java?
Thanks a lot,

With that in mind, I must add that the [url http://java.sun.com/j2se/1.4.2/docs/api/java/lang/System.html#getProperty(java.lang.String)]System.getProperty() method will be handy.

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Get home directory of java

can any 1 help me on how to get the home directory of java??
either using java or batch file
thanks

thanks
it returns c:\Program Files\java\jdk1.6.0\jre
but
is there any way that can result in getting the bin folder(the 1 we usually compile program) or the jdk1.6.0 folder itself instead of
c:\Program Files\java\jdk1.6.0\jre ??
thanks

How to change the properties of a directory using java code

Hai All,
I need to change the properties of directory( websharing).
Can i do this using java code.
Regards,
Charan

I need to change the properties of
directory( websharing).
an i do this using java code.Depends on whether the server has a Java API to do it. Most likely it hasn't.

Using Unix command lines in java code

I was wondering if there was a way to run a unix command in java code. I know in C++ there is popen, but i don't know of a way in java. The command i need to run is the whois "domain name" command. Any help would be great!
jarad

try something like this:
public static String whois(String domain) throws IOException {
    BufferedReader is = null;
    Process p = null;
    String result = "";
    p = Runtime.getRuntime().exec("whois " + domain);
    is = new BufferedReader(new InputStreamReader(p.getInputStream()));
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}

Accessing ACTIVE DIRECTORY FROM JAVA CODE

I am trying to access the Active DIrectory user through a java code.
Kindly let me know the steps apart from creating the user in ADS to be followed so that the following java code may work.
presently it is giving the following error.
problem serching the directory
//package com.axa;
import java.util.Hashtable;
import javax.naming.ldap.*;
import javax.naming.directory.*;
import javax.naming.*;
public class AdHelper
     public static void main(String args[])
System.out.println("1");
          Hashtable env = new Hashtable();
          String adminName = "CN=user,CN=Users,DC=BDC4AXA.CO.IN";
          String adminPassword = "user";
          String ldapURL = "ldap://10.1.242.51:636";
System.out.println("2");
          env.put(Context.INITIAL_CONTEXT_FACTORY,"com.sun.jndi.ldap.LdapCtxFactory");
          env.put(Context.SECURITY_AUTHENTICATION,"simple");
          env.put(Context.SECURITY_PRINCIPAL,adminName);
          env.put(Context.SECURITY_CREDENTIALS,adminPassword);
          env.put(Context.PROVIDER_URL,ldapURL);
System.out.println("3");
          try {
               // Create the initial directory context
               DirContext ctx = new InitialLdapContext(env,null);
System.out.println("4");
               SearchControls searchCtls = new SearchControls();
          System.out.println("5");
               //Specify the attributes to return
               String returnedAtts[]={"sn","givenName","mail"};
               searchCtls.setReturningAttributes(returnedAtts);
               //Specify the search scope
               searchCtls.setSearchScope(SearchControls.SUBTREE_SCOPE);
               //specify the LDAP search filter
               String searchFilter = "(&(objectClass=user)(mail=*))";
System.out.println("6");
               //Specify the Base for the search
               String searchBase = "DC=ANTIPODES,DC=COM";
System.out.println("7");
               //initialize counter to total the results
               int totalResults = 0;
               // Search for objects using the filter
               NamingEnumeration answer = ctx.search(searchBase, searchFilter, searchCtls);
System.out.println("8");               //Loop through the search results
               while (answer.hasMoreElements()) {
          SearchResult sr = (SearchResult)answer.next();
               totalResults++;
System.out.println("9");
               System.out.println(">>>" + sr.getName());
               Attributes attrs = sr.getAttributes();
                    if (attrs != null) {
                         try {
                         System.out.println(" surname: " + attrs.get("sn").get());
                         System.out.println(" firstname: " + attrs.get("givenName").get());
                         System.out.println(" mail: " + attrs.get("mail").get());
                         catch (NullPointerException e)     {
                         System.out.println("Errors listing attributes: " + e);
               System.out.println("Total results: " + totalResults);
               ctx.close();
               catch (NamingException e) {
               System.err.println("Problem searching directory: " + e);
          catch(Exception e)
               System.out.println("Unhandled Exception: " + e);
}

This is what I have for my LDAP connection.
public Hashtable<String, String> env = null;
     public LdapContext ldapContext = null;
     public Control[] connCtls = null;
     Context ctx;
     DirContext dirContext;
public LDAPAuth(String ldapurl) {
          ldapurl = "ldap://" + serverIP + ":389";
          try {
               env = new Hashtable<String, String>();
               env.put(Context.INITIAL_CONTEXT_FACTORY,
                         "com.sun.jndi.ldap.LdapCtxFactory");
               env.put(Context.SECURITY_AUTHENTICATION, "simple");
               env.put(Context.PROVIDER_URL, ldapurl);
               env.put(Context.SECURITY_PRINCIPAL, "cn=username,cn=users" + baseName);
               env.put(Context.SECURITY_CREDENTIALS, "password" + baseName);
               env.put(Context.SECURITY_PROTOCOL, "ssl");
               ctx = new InitialContext(env);
          } catch (Exception e) {
               System.out.println(" bind error: " + e);
               e.printStackTrace();
          try {
               ldapContext = new InitialLdapContext(env, connCtls);
          } catch (AuthenticationException e) {
               System.out.println("Authentication exception " + e);
          } catch (NamingException e) {
               System.out.println("Naming exception " + e);
     public Attributes fetch(String username) throws NamingException {
          DirContext ctx = new InitialDirContext(env);
          Attributes attributes = ctx.getAttributes(username);
          try {
               System.out.println("fetching: " + username);
               Object obj = ctx.lookup("cn=" + username
                         + baseName);
               System.out.println("cn=" + username + baseName + "is bound to: " + obj);
               //attributes = obj.getAttributes("");
               for (NamingEnumeration<?> ae = attributes.getAll(); ae
                         .hasMoreElements();) {
                    Attribute attr = (Attribute) ae.next();
                    String attrId = attr.getID();
                    for (NamingEnumeration<?> vals = attr.getAll(); vals.hasMore();) {
                         String value = vals.next().toString();
                         System.out.println(attrId + ": " + value);
          } catch (NamingException e) {
               System.out.println(" Problem looking up " + username + baseName + ". " + e);
          return attributes;
Now, I'm sure it has something to do with how I'm passing in the username and the groups. But I want to have ANY user log in, not just this test. I may be a little confused on how this works, but if anyone could explain to me why what I am trying to do doesn't work, I would greatly appreciate it.
Thanks in advance,
Tetsuya.
Edited by: tetsuyamasamune on Sep 8, 2008 3:55 PM

Accessing Default Windows Directory thr java code

Hi all,
I want to access, Windows or windows\system directory on my PC through my java code
Plz help
Manoj

Compile this program:
public class SysProp {
public static void main(String[] args) {
System.out.println(System.getProperty("windir"));
}and execute it this way:
java -Dwindir=%windir% SysPropThis worked for me on Windows NT.
If you use Windows 95 or 98, you may have to put the above launch command in a .bat file otherwise the system variable %windir% does not get expanded.
On other versions of Windows (ME/2000/XP) I don't know.

Read SSH (Unix) dynamic file through Java code

Hi,
I am trying to create a java code which should read the dynamically changing content in the unix(SSH) system.
Could you please tell me which is the best way to create the above requirement.
Thanks in advance...

corlettk wrote:
but there are perl libraries... and (I was dumbfounded) a java-embedded-in-perl compiler. I feel a mashup delegate layer coming on.JCraft's JSch is, however, IMHO, a very good, flexible, and reliable implementation of SSH2 protocol (OpenSSH key formats). It allows your program to become an SSH client.
Edit: And to tell you the truth, the Perl Net::SSH module is simply a wrapper around OpenSSH's libraries, and the Net::SSH::Perl Module (which is complete Perl although many of the Encryption modules need to be compiled, at least on Unix) are much more complicated to get installed, if not necessarily used, than JSch is.
Edit Again: Although knowing the OP's history, I very much doubt his ability to implement either solution. ;-)

Executing an hp unix command by using java code

i'm trying to execut the "chmod" command on my jsp as follows :
String cmd = "chmod 644 "+fileName;
Process process;
process=Runtime.getRuntime().exec(cmd);
but i got the following exception:
java.io.IOException: chmod: not found
     at java.lang.UNIXProcess.forkAndExec(Native Method)
     at java.lang.UNIXProcess.<init>(UNIXProcess.java:86)
     at java.lang.Runtime.execInternal(Native Method)
     at java.lang.Runtime.exec(Unknown Source)
     at java.lang.Runtime.exec(Unknown Source)
     at java.lang.Runtime.addShutdownHook(Unknown Source)
     at java.lang.Runtime.addShutdownHook(Unknown Source)
     at receiveJobAppInput.jspService(_receiveJobAppInput.java:358)
     at com.orionserver.http.OrionHttpJspPage.service(OrionHttpJspPage.java, Compiled Code)
     at oracle.jsp.runtimev2.JspPageTable.compileAndServe(JspPageTable.java, Compiled Code)
     at oracle.jsp.runtimev2.JspPageTable.service(JspPageTable.java, Compiled Code)
     at oracle.jsp.runtimev2.JspServlet.internalService(JspServlet.java, Compiled Code)
     at oracle.jsp.runtimev2.JspServlet.service(JspServlet.java, Compiled Code)
     at javax.servlet.http.HttpServlet.service(HttpServlet.java, Compiled Code)
     at com.evermind.server.http.ResourceFilterChain.doFilter(ResourceFilterChain.java, Compiled Code)
     at oracle.security.jazn.oc4j.JAZNFilter.doFilter(JAZNFilter.java, Compiled Code)
     at com.evermind.server.http.ServletRequestDispatcher.invoke(ServletRequestDispatcher.java, Compiled Code)
     at com.evermind.server.http.ServletRequestDispatcher.forwardInternal(ServletRequestDispatcher.java, Compiled Code)
     at com.evermind.server.http.HttpRequestHandler.processRequest(HttpRequestHandler.java, Compiled Code)
     at com.evermind.server.http.AJPRequestHandler.run(AJPRequestHandler.java, Compiled Code)
     at com.evermind.server.http.AJPRequestHandler.run(AJPRequestHandler.java, Compiled Code)
     at EDU.oswego.cs.dl.util.concurrent.PooledExecutor$Worker.run(PooledExecutor.java, Compiled Code)
     at java.lang.Thread.run(Unknown Source)
can anyone give me a hint why this happend?

What about exec'ing this?
String [] {"chmod" ,"644" , "fileName" }

Problems With FTP Users home directory

Hello Everyone,
I recently ran into a problem when setting the home directory of an ftp user. What I want to be able to do is for example I have two users, one user is User1, and the other is FTPUser. Now when people ftp into the user FTPUser I want to set the home directory to be a certain path in User1. Now I was able to successfully do this on one box when creating the FTPUser I just set the home directory to be the path in User1. And when people ftped into FTPUser they were in the right directory under User1.
I tried to do this same procedure on another box, and after creating the FTPUser and setting its home directory to a path under User1. Now when they ftped into FTPUser it was showing that the home directory was "/". I examined /etc/passwd and it presents the right home directory that I want, yet when people ftp into FTPUser its showing the home directory to be "/". Any help would be appreciated. Thanks in advance.
-Kevin

Sorry for such a late reply, but I figured out my problem and will put it on here in case other people run into the same problem. You must make the FTPUser be in the same group of the normal users directory path you wish to FTP into. For example the command will look like this when making the FTP user:
useradd -g "users group number" -d /path/to/file -s /bin/sh ftpusername
so if user1 group id was 110 you would put 110 after -g and set the home dir of the ftpusername to be some path in user1. Thanks all for the help.
-Kevin
Edited by: kratkinson on Jun 22, 2009 6:46 AM

How to specify a file path in java code to run on Unix machine?

Hi
I have a problem when running my project Swing on Unix machine.
In my code, the user will press a button and then the program will look for the file "ReadMe" in the folder "Documentation" , and reads the content of this file. My code is "Documentation\\ReadMe" and it works well on PC. (The folder "Documentation" is in the same directory with my Java code).
But when I try on Unix, the program can not read the file. It can only read the file "ReadMe" if I take this file and put it in the same directory with my Java code ( this means not through another folder). So how can we make it read the file in a folder ? It seems that "Documentation\\ReadMe" does not work in Unix, or the symbol "\\" does not work.
I would be thankful if anybody can help me with this.
Thank you very much

You really shouldn't use any path method, as neither are very consistant or platform independent. The JVM provides a way to grab resources from the classpath. These resources can be any data at all, in fact, it's how java itself locates classes. Here's an example how you would do this in a non-static method.
public URL getReadMe() {
// In this context the forward slash is universal
String docDirectory = "Documentation/"
// We have to use the classloader to grab the resource
ClassLoader cl = this.getClass().getClassLoader();
// Next we get the resource
URL readMeURL = cl.getResource(docDirectory + "ReadMe");
return readMeURL;
}The URL can be used in whatever way you need to get the information out of the resource. If it was an image you might use the "Toolkit" to make an image object out of it. The great thing about this method is it will work even if your loading the program out of a Jar file. The resource paths start at the top of the classpath, just like classes.

Using unzip from unix in java-code ...

Hi people,
i have problem, i want to use the command unzip from unix, to unzip a zip-file, the commend unzip must invoke from java-code. Can someone help me. I use the zip-api, but i have 100Mb zip-file, it needs very long time to unzip the zip-file.
thanks for your help ...

ok, not sure how much improvement this will give in general, but its given a reliable 25% speed increase on my mini tests
using the nio libraries will also get you a lot further, and is the way to go if you are very keen on speed
asjf
import java.awt.*;
import java.io.*;
import java.util.*;
import java.util.zip.*;
import javax.swing.*;
public class Unzipper {
     private Unzipper() {}
     private static byte[] buffer = new byte[16384];
     public static void unzip(File file, Component parentComponent,     File outputDir) throws ZipException, IOException {
          unzip(new ZipFile(file), parentComponent, outputDir);
     public static void unzip(File file, int mode, Component parentComponent, File outputDir) throws IOException {
          unzip(new ZipFile(file, mode), parentComponent, outputDir);
     public static void unzip(String name, Component parentComponent, File outputDir)     throws IOException {
          unzip(new ZipFile(name), parentComponent, outputDir);
     public static void unzip(ZipFile zip, Component parentComponent, File outputDir)     throws IOException {
          if ( zip == null) {
               throw new NullPointerException("outputDir is null");
          int size = zip.size();
          if (size > 0) {
               if (outputDir == null) {
                    throw new NullPointerException("outputDir is null");
               if (!outputDir.exists()) {
                    outputDir.mkdirs();
               ProgressMonitor monitor =
               new ProgressMonitor(parentComponent,
               "Unpacking " + zip.getName() + "...", "", 0, size);
               monitor.setMillisToDecideToPopup(0);
               monitor.setMillisToPopup(0);
               Enumeration entries = zip.entries();
               for ( int i = 0; entries.hasMoreElements(); ) {
                    ZipEntry entry = (ZipEntry) entries.nextElement();
                    /*if (entry.getMethod() == ZipEntry.DEFLATED)
                    System.out.println(" Inflating: "+entry.getName());
                    else
                    System.out.println(" Extracting: "+entry.getName());*/
                    monitor.setNote(entry.getName());
                    File File = new File(outputDir, entry.getName());
                    File.getParentFile().mkdirs();
                    if (!entry.isDirectory()) {
                         InputStream in = null;
                         OutputStream out = null;
                         try {
                              in = zip.getInputStream(entry);
                              out = new FileOutputStream(File);
                              for (int n = 0; (n = in.read(buffer)) > -1; )
                                   out.write(buffer, 0, n);
                              monitor.setProgress(++i);
                         } finally {
                              if (out != null) {
                                   try {
                                        out.close();
                                   } catch (IOException e) {
     public static void main(String[] args) throws ZipException, IOException
          if (args.length !=2) {
               System.err.println("Usage: java Unzipper <zip file> <output dir>");
               System.exit(1);
          long start = -System.currentTimeMillis();
          unzip(args[0], null, new File(args[1]));
          System.out.println(start+System.currentTimeMillis());
          System.exit(0);

How to get the user's home directory in Unix if I know the username?

I have a problem to determine a user's home directory in Solaris system.
for example, I know the username as "smith", how can I know smith's
home directory (the absolute path string)? pls help me...

if the user is the one running the program, you can always get the home directory using System.getProperties ("user.home");
If you are trying to get the properties of another user, you could try using setProperties to change the user name first, before getiting the home directory, but it probably won't work because of the security manager. You could read the /etc/passwd file and parse the path out, but once again, the user of the code would have to have appropriate permission.

Retrieving user data from Directory Server using java code

Can anyone send java code to bind to directory server and retrieve the user information from server instance.

To CRabel,
My company have restriction on using the open sources product/code, but i will take a look on netscape ldap sdk as a reference~
To raghu1978 ,
i find a product call Directory Editor 1 2005Q1, I hope it is useful.
thz all~

Java code to show current date & time on PDF

Hi,
I have no experience with Java whatsoever and I am hoping somebody out there will be able to help me. Basically we are in the process of uploading all our SOP's to a public share on our Network. Due to regulatory reasons everytime the document is opened it will need to show the current date which will also show when printed. I have adobe 9 pro and see there is a area that you can input Java code so with the power of Java im sure this can be done. Ideally this would be like a watermark across all the page diagonally faded into the background of each page on the PDF.
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Date Printed: <Current Date>
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Are you sure you haven't committed one of the cardinal sins of the Java-ignorant by confusing it with Javascript?

How can I write java code in web dynpro to show KM content document?

Dear all developer
SDN developer who have any easy example java code for get and show KM content documents(documents/com.xx.km/.). We are develop this project by Netweaver Studio 7.0 and using WEB Dynpro application.
Thank for all comment and advice.
Jumnong Boonma

Hi
i dont have the exact code but yes..i can refer to the link for Web Dynpro applications for the Portal.
[http://help.sap.com/erp2005_ehp_03/helpdata/EN/42/fa080514793ee6e10000000a1553f7/frameset.htm]
Here look out for Absolute Navigation.
Hope it helps...
Thanks..

Show Unix home directory in Java code

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