Showing path of tree which is in table

Question

Hello Everyone,
Can you examine this link?
http://www.adp-gmbh.ch/ora/sql/connect_by.html
I worked this query in this hiearchical tree table:
SELECT child, SYS_CONNECT_BY_PATH(lchild, '/') "Path"
FROM test_connect_by
START WITH parent is null
CONNECT BY PRIOR child = parent;
When you worked this query, you can see path of each child. For example child: 10
child-------------path
10--------------- /38/15/10
But, i wanna this path as seperate column. for example; level of this tree table is 4
child-------------path1----------------path2---------------path3---------------path4
10-----------------38-------------------15--------------------10-------------------(null)
Is there any way as showing seperate column??

Answer 1

Only if you know deepest level number upfront:
select  child,
        regexp_substr(sys_connect_by_path(child,','),'[^,]+',1,1) path1,
        regexp_substr(sys_connect_by_path(child,','),'[^,]+',1,2) path2,
        regexp_substr(sys_connect_by_path(child,','),'[^,]+',1,3) path3,
        regexp_substr(sys_connect_by_path(child,','),'[^,]+',1,4) path4
  from  test_connect_by
  start with parent is null
  connect by prior child = parent
     CHILD PATH1      PATH2      PATH3      PATH4
        18 18
         7 18         7
        11 18         11
        26 26
         1 26         1
        12 26         12
        13 26         13
        38 38
         6 38         6
        15 38         15
         5 38         15         5
     CHILD PATH1      PATH2      PATH3      PATH4
         3 38         15         5          3
        10 38         15         10
        17 38         17
         8 38         17         8
         9 38         17         9
16 rows selected.
SQL> And if you want just leafs:
     CHILD PATH1      PATH2      PATH3      PATH4
         7 18         7
        11 18         11
         1 26         1
        12 26         12
        13 26         13
         6 38         6
         3 38         15         5          3
        10 38         15         10
         8 38         17         8
         9 38         17         9
10 rows selected.
SQL> Or:
select  child,
        regexp_substr(sys_connect_by_path(child,','),'[^,]+',1,1) path1,
        regexp_substr(sys_connect_by_path(child,','),'[^,]+',1,2) path2,
        regexp_substr(sys_connect_by_path(child,','),'[^,]+',1,3) path3,
        regexp_substr(sys_connect_by_path(child,','),'[^,]+',1,4) path4
  from  test_connect_by
  where child = 10
  start with parent is null
  connect by prior child = parent
     CHILD PATH1      PATH2      PATH3      PATH4
        10 38         15         10
SQL> SY.