Simple sum query I need help with please

Question

I need a query to do something like this:
select customer_site_use_id
from ar_payment_schedules_all ps
where ps.status = 'OP'
AND NVL(ps.receipt_confirmed_flag,'Y') = 'Y'
and exists (select (sum(ps1.acctd_amount_due_remaining) as amtdue)
from ar_payment_schedules_all ps1
where ps1.customer_site_use_id = ps.customer_site_use_id
and amtdue < 0)
and ps.customer_site_use_id = 1593
I may be making this too difficult. I don't know if I need the exists clause and the second select statement. In the exists statement, if the sum of all of the acctd_amount_due_remaining in ar_payment_schedules_all for the same customer_site_use_id is less than 0, then it is in the results.

Answer 1

Hi,
Whenever you have a problem, please post a little sample data (CREATE TABLE and INSERT statements, relevant columns only) from all tables.
Also post the results you want from that data, and an explanation of how you get those results from that data, with specific examples.
Always say which version of Oracle you're using.
I'm pretty sure you don't want an EXISTS sub-query. EXISTS returns TRUE if the sub-query finds any rows; it doesn't matter how many, or what's on them.
Perhaps you want something like this:
WITH     got_total_amount_due     AS
     SELECT       customer_site_use_id
     ,       SUM (acctd_amount_due)     AS total_amount_due
     FROM       ar_payment_schedules_all
     GROUP BY  customer_site_use_id
SELECT    ps.customer_site_use_id
FROM        ar_payment_schedules_all     ps
JOIN       got_total_amount_due          td  ON  ps.customer_site_use_id  = td.customer_site_use_id
WHERE       ps.status            = 'OP'
AND       NVL ( ps.receipt_confirmed_flag
           , 'Y'
           )                 = 'Y'
AND        ps.customer_site_use_id = 1593
AND       td.total_amount_due       < 0
;That gives you access to the total amount for each customer_site_id